Difference between two timestamp.
Hi,
I want to find difference between two timestamp in minutes.
Actually i want to retrieve difference between current timestamp and the timestamp taken from the table
select log_time from serv_info where server_id = 1;
Can anyone tell me the query to find difference between two timestamps in minutes.
-haifriends
SQL> WITH serv_in AS
(SELECT SYSTIMESTAMP - 1 / 4 log_time,
SYSTIMESTAMP now
FROM DUAL)
SELECT log_time,
now,
24 * 60 * EXTRACT (DAY FROM (now - log_time))
+ 60 * EXTRACT (HOUR FROM (now - log_time))
+ EXTRACT (MINUTE FROM (now - log_time))
+ 1 / 60 * EXTRACT (SECOND FROM (now - log_time)) diff_in_minutes
FROM serv_in
LOG_TIME NOW DIFF_IN_MINUTES
01-MRZ-07 01-MAR-07 03.47.42.107462 PM +01:00 360,001791
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I have a database table where it keeps record of the transaction when it starts at StartTime and when it ends at EndTime. Both these entries are having the timestamp entries. Say for example, I have a tuple with Entries like 'Transaction A' starts at '2014-05-07
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You can use below script which calculates difference as DD:HH:MM:SS. You can modify the same:
DECLARE @startTime DATETIME
DECLARE @endTime DATETIME
SET @startTime = '2013-11-05 12:20:35'
SET @endTime = '2013-11-10 01:22:30'
SELECT [DD:HH:MM:SS] =
CAST((DATEDIFF(HOUR, @startTime, @endTime) / 24) AS VARCHAR)
+ ':' +
CAST((DATEDIFF(HOUR, @startTime, @endTime) % 24) AS VARCHAR)
+ ':' +
CASE WHEN DATEPART(SECOND, @endTime) >= DATEPART(SECOND, @startTime)
THEN CAST((DATEDIFF(MINUTE, @startTime, @endTime) % 60) AS VARCHAR)
ELSE
CAST((DATEDIFF(MINUTE, DATEADD(MINUTE, -1, @endTime), @endTime) % 60)
AS VARCHAR)
END
+ ':' + CAST((DATEDIFF(SECOND, @startTime, @endTime) % 60) AS VARCHAR),
[StringFormat] =
CAST((DATEDIFF(HOUR , @startTime, @endTime) / 24) AS VARCHAR) +
' Days ' +
CAST((DATEDIFF(HOUR , @startTime, @endTime) % 24) AS VARCHAR) +
' Hours ' +
CASE WHEN DATEPART(SECOND, @endTime) >= DATEPART(SECOND, @startTime)
THEN CAST((DATEDIFF(MINUTE, @startTime, @endTime) % 60) AS VARCHAR)
ELSE
CAST((DATEDIFF(MINUTE, DATEADD(MINUTE, -1, @endTime), @endTime) % 60)
AS VARCHAR)
END +
' Minutes ' +
CAST((DATEDIFF(SECOND, @startTime, @endTime) % 60) AS VARCHAR) +
' Seconds '
Reference:
http://sqlandme.com/2013/12/23/sql-server-calculating-elapsed-time-from-datetime/
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SqlAndMe.com -
How to find the difference between two timestamp column
Dear All,
please Solve my issue,
I have Table name Record which has the following columns,
Empid in number column, dat in timestamp
which has the following values
Expand|Select|Wrap|Line Numbers
empid dat
====== ====
101 4/9/2012 9:48:54 AM
101 4/9/2012 9:36:28 AM
101 4/9/2012 6:16:28 PM
101 4/10/2012 9:33:48 AM
101 4/10/2012 12:36:28 PM
101 4/10/2012 8:36:12 PM
101 4/11/2012 9:36:28 AM
101 4/11/2012 4:36:22 PM
Here I need to display the following columns,
empid,min(dat) as start,max(dat) as end and difference(max(dat)-min(dat) for each day,
for eg,
Empid Strart end difference
101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
like this.
Here 3 different days are exists so It should return 3 records with the above mentioned columns,
Please Help me to get this.
Thank you,
Regards,
Gurujothi
Edited by: Gurujothi on Apr 25, 2012 4:45 AM>
101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
>
why 4/9/2012 9:48:54?
why not 4/9/2012 9:36:28 AM ?
SQL>
SQL> with t as
2 (select 101 empid, to_timestamp('4/9/2012 9:48:54 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
3 select 101, to_timestamp('4/9/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
4 select 101, to_timestamp('4/9/2012 6:16:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
5 select 101, to_timestamp('4/10/2012 9:33:48 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
6 select 101, to_timestamp('4/10/2012 12:36:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
7 select 101, to_timestamp('4/10/2012 8:36:12 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
8 select 101, to_timestamp('4/11/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
9 select 101, to_timestamp('4/11/2012 4:36:22 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual
10 )
11 select empid, min(dat) as start_dat
12 , max(dat) as end_dat
13 , max(dat)-min(dat) diff
14 from t
15 group by empid, trunc(dat)
16 /
EMPID START_DAT END_DAT DIFF
101 04.09.12 09:36:28,000000000 04.09.12 18:16:28,000000000 +000000000 08:40:00
101 04.11.12 09:36:28,000000000 04.11.12 16:36:22,000000000 +000000000 06:59:54
101 04.10.12 09:33:48,000000000 04.10.12 20:36:12,000000000 +000000000 11:02:24
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Difference between two date in bex query
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Ex:
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Difference between two dates in seconds/milliseconds with Expressions
Hi,
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The functions are defined in the Expression class, you can try,
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TYPE t_col
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TABLE OF VARCHAR2 (30)
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status VARCHAR2 (30);
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BEGIN
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LOOP
j := j + 1;
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How to get the difference between two columns in a column group
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PeriodNumber
Account 1 2
1) Cash 10,000 15,000
2) Receivables 12,000 11,500
3) Equipment 5,000 5,500
Total Assets 27,000 32,000Hi yabgestopa,
From your description, you want to get the difference between two columns in a column group. After testing it in my environment, we can use custom code to achieve your requirement. For more details, you can refer to the following steps:
Copy the custom code below and paste it to your report. (Right-click report>Report Properties>Code)
Dim Shared Num1 As Integer
Dim shared Num2 As Integer
Public Function GetAmount(Amount as Integer, Type as String)
If Type = "1" Then
Num1=Amount
Else
Num2=Amount
End If
Return Amount
End Function
Public Function GetDif()
Return Num1-Num2
End function
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Katherine Xiong
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Better estimation of phase difference between two signals with variable frequency!
Hello LabView Gurus,
Being a power engineer and having just a little knowledge of signal processing and labview, I have been pulling my hair out for the last couple of days to get a better estimation of phase difference between two signals.
We have two analog voltage signals; 1. sine wave (50Hz ± 1Hz) and 2. a square wave with exactly half of sine wave frequency at any time.
At the starting point of operation (and simulation/acquisition) both signals will have no phase difference. However, the square wave's frequency changes unpredictably for a just a few millisecond but then it gets synchronized with sine wave's frequency again. This means that the square wave will be phased out from its original position. The task of the labview is to find the phase difference between the two signals continuously.
My approach to determine the phase difference is to measure the time when sine wave crosses zero amplitude and the time when the very next square wave changes amplitude from zero volts to +ve voltage (I have a 0.5volts threshold just to avoid any dramas from small line noise). The difference between these times is then divided by the time period and multiplied by 360 to get this phase difference in angles.
As this part is just a small block of a big project, I can only allow 5000Hz sampling rate each for both signals. I read 500 samples (which means I read data from 5 cycles of sine wave and 2.5 cycles of square wave).
Now the problem is, as long as the frequency of sine wave stays constant at exactly 50Hz, I get a good estimation of the phase difference but when the frequency changes even a little (and it will happen in the real scenario i.e 50Hz ± 1Hz and the square wave's frequency is dependent of sine wave's frequency), the estimation error increases.
I have attached my labview program. From front panel, you can set the phase of square wave (between -180 and 0) and you should see the labview's calculated phase in the indicator box named 'Phase'. Then you can press 'Real Frequency' switch that would cause the frequency to change like it would in real operation.
You can observe that the estimation error increases after you push the button.
All I need to do is to reduce this estimation error and make it as close to the actual phase difference as possible. Any help would be greatly appreciated.
I am using LabView 2009 for this task.
The application is for electric machines and the stability/performance of machines under different faults.
Thank you for reading this far!
Regards,
Awais
Attachments:
v603.png 320 KB
v603.vi 186 KBJeff Bohrer wrote:
Basic math gives me a bit of pause on this approach. You are sampling at 50 times the frequency of interest so you get 50 samples per cycle. your phase resolution is 1/50th cycle or 7.2 degrees +/- noise. You will need to samlpe faster to reduce phase resolution or average multiple readings (at a time cost that is signifigant)
Jeff- (Hardly Working)
I am sampling at 100 times the sine wave's frequency and 200 times the square wave's frequency. Increasing the sampling rate completely solves my problem. But since I am acquiring several other inputs, I cannot afford a sampling rate higher than 5kHz.
F. Schubert wrote:
I'm not a signal processing expert, but here my basic understanding.
If you simulate sampling with 5kHz and a frequency of 50 Hz (and both are 'sync' by design), you always get an exact 5 periods. Any variation of your signals frequency gives you a propability to get 4 or 6 'trigger' events. That's an up or down of 20%!
The one measure to reduce such problems is using 'window functions'. They don't fit your current approach (counting instead of a DSP algorithm), so this needs to be reworked as well.
My approach would be to use the concept of a Locki-In amplifier. You need to phaseshift your ref-signal by 90°. Then multiply your measurement signal with the ref signal and the phase shifted ref signal. The obtained values for x/y coordinates of a complex number. Calculate the theta of the complex number (with the LV prim). Feed this in a low pass filter.
The trick on this is, that the square wave has harmonics in it, in this you are interested in the second harmonic which is the sine wave.
To get rid of the effect that the sync between sampling rate and ref signal frequency gives an error, you then can use the window I mentioned above (place it before the lock-in).
For a design that really plays well, use a producer-consumer design pattern to get the calculations done in parallel with the DAQ.
I suggest you to check on wikipedia for some of the keywords I mentioned. Go also for the external links which lead to great tutorials and AppNotes on the signal processing basics.
Sorry, it's not a simple solution I offer and we will have quite some conversation on this forum if you follow this path. Maybe someone else knows a simpler way.
Felix
www.aescusoft.de
My latest community nugget on producer/consumer design
My current blog: A journey through uml
An interesting view. the sine wave can indeed be looked as a second harmonic of the square wave. I will implement your idea and get back to you as soon as I get some results. But since I have very limited knowledge of signal processing, it might take me a while to get my hear around the solution you mentioned. -
Date difference between two dates
hi All,
i have to right a stored proc to find the difference between two dates.
for example of i give
startdate as 4/1/2015 and enddate 14/1/2015
i should get 1 year , 10 days and 0 months .
i have tried the DateDiff function but it does not calculate the leap year.
please help.DECLARE @from datetime
DECLARE @to datetime
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SELECT DATEDIFF(minute,@from, @to) % 60 as Minutes
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SELECT DATEDIFF(month,@from, @to) as Months
SELECT DATEDIFF(year,@from, @to) as Year
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Find the difference between two internal table
how can i see the difference between two interal tables?
The requirement is as follows
1. We have a transparent table, which stores the employee data with EMP ID as key.
2. We load the transp table data into a interal table (B).
3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
We want to do followign things
I = A - B
D = B - A
Both A and B will have around 40k records. Hence we are trying to avoid the looping.
Please suggest the best option for us.
Thank you in advance.
Raghavendra>
RAGHAV URAL wrote:
> how can i see the difference between two interal tables?
> The requirement is as follows
>
> 1. We have a transparent table, which stores the employee data with EMP ID as key.
> 2. We load the transp table data into a interal table (B).
> 3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
>
> Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
>
> We want to do followign things
> I = A - B
> D = B - A
>
> Both A and B will have around 40k records. Hence we are trying to avoid the looping.
>
> Please suggest the best option for us.
>
> Thank you in advance.
> Raghavendra
Hi Raghavendra,
Currently as of my knowledge, these operations are only possible through LOOPs. But LOOPign can be really fast here if you properly utilize the SORTING, READ with BINARY SEARCH and FIELD-SYMBOLS usage. I would say:-
Steps for Insert:-
SORT: A, B.
LOOP AT A ASSIGNING <WA_A>.
READ TABLE B WITH TABLE KEY key = <WA_A>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_A> TO I.
ENDIF.
ENDLOOP.
Steps for Delete:-
SORT: A, B.
LOOP AT B ASSIGNING <WA_B>.
READ TABLE A WITH TABLE KEY key = <WA_B>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_B> TO D.
ENDIF.
ENDLOOP.
Regards,
Ravi.
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