Different parts for the same ID

Question

Hi,
TABLE1 contains informations about programs, these include:
PROGRAM_ID (fk of program table), PART_NO, MEDIA_ID
A program can be made of different parts (PART_NO i.e., part 1, 2, 3, 4, or 5).
The media_id is the unique identifier or a VHS tape where the program is recorded on.
Parts of a program will have the same Media_id as long as the sum of their lenght does not exceed the VHS length, if that happens, the media_id for the part which does not fit the VHS will be different:
i.e. Program1 has 4 parts of 1 hour each. Part 1 and 2 will be on the same VHS (2 hours), hence will have the same media_id; part 3 and 4 will have a different media_id associated to program1.
TABLE2 contains information about the media:
MEDIA_ID (pk), MEDIA_NAME
If one program has more than one media associated to it, I need to be able to display both media_names on the same row as the program_id under the same column called VHS_Number (I asssume by using concat).
Can anyone suggest anything so that I can move in the right direction?
thanks
Message was edited by:
user564568

Answer 1

create table table1(program_id number(2),part_no number(2),media_id varchar2(3));
insert into table1 values(1,1,'m1');
insert into table1 values(1,2,'m2');
insert into table1 values(1,3,'m2');
insert into table1 values(1,4,'m1');
insert into table1 values(2,1,'m3');
insert into table1 values(2,2,'m2');
insert into table1 values(3,1,'m1');
insert into table1 values(3,2,'m2');
table1
program_id part_no media_id
1          1     m1
1          2     m2
1          3     m2
1          4     m1
2          1     m3
2          2     m2
3          1     m1
3          2     m2
create table table2(media_id varchar2(3),media_name varchar2(9));
insert into table2 values('m1','media1');
insert into table2 values('m2','media2');
insert into table2 values('m3','media3');
insert into table2 values('m4','media4');
insert into table2 values('m5','media5');
table2
media_id media_name
m1          media1
m2          media2
m3          media3
m4          media4
m5          media5
select program_id,distinct media_name
from table2 A,(select media_id,program_id,part_no,dense_rank() over ( partition by program_id order by media_id) rn from table1) B
where A.media_id=B.media_id
is this kind of data you are looking for