Disadvantages of Distinct

Can anyone discuss the disadvantages of using distinct clause in select statement ?

And did you all notice that option 3 gave the wrong
result !!!.I didn't take a look at #3.
Since deptno 40 has no employees then it would not
show in select distinct(deptno) from emp or group by
however:
select deptno from dept d
where exists ( select null
from emp e
where e.deptno = d.deptno )
would answer the questionAnd so would the the DISTINCT or GROUP BY. The initial question was about the disadvantages of using distinct in a select statement. Without specific requirements I wouldn't consider the use of distinct as a disadvantage for certain tasks.
C.

Similar Messages

How to find distinct words in Oracle Text index

We have a requirement to fetch all distinct words in the CLOB field for all records
and find the no. of records in which each word appears.
DR$<Index Name>$I table stores exactly such information. Is it ok to use this table in queries?
Are there any disadvantages in using it?
Help is very much appreciated.

the disadv -
with every sync index the contents will change.
with every release the structure may change without any prior information - your application may go bad.
It is not advisable to use them in your applications. For your own investigation etc you can always use its contents.
thanks

Advantage and Disadvantage of user login ID

Dear SAP expert,
I need some advice whether to use "employee no." or "name" to create SAP login.
What is the advantage and disadvantage of using employee no. ?
Thanks.
Rgds,

Hi Nitin,
A view can be thought of as either a virtual table or a stored query. The data accessible through a view is not stored in the database as a distinct object. What is stored in the database is a SELECT statement. The result set of the SELECT statement forms
the virtual table returned by the view. A user can use this virtual table by referencing the view name in Transact-SQL statements the same way a table is referenced.
For more information about the advantages and disadvantages of views in SQL Server, please refer to the following two articles:
http://www.c-sharpcorner.com/Blogs/10575/advantages-and-disadvantages-of-views-in-sql-server.aspx
http://www.toadworld.com/platforms/sql-server/w/wiki/10274.views-advantages-and-disadvantages.aspx
Regards,
Katherine Xiong
Katherine Xiong
TechNet Community Support

Advantage and disadvantage of view over physical table

Hi,
Can you explain me Advantage and disadvantage of view over physical table

Hi Nitin,
A view can be thought of as either a virtual table or a stored query. The data accessible through a view is not stored in the database as a distinct object. What is stored in the database is a SELECT statement. The result set of the SELECT statement forms
the virtual table returned by the view. A user can use this virtual table by referencing the view name in Transact-SQL statements the same way a table is referenced.
For more information about the advantages and disadvantages of views in SQL Server, please refer to the following two articles:
http://www.c-sharpcorner.com/Blogs/10575/advantages-and-disadvantages-of-views-in-sql-server.aspx
http://www.toadworld.com/platforms/sql-server/w/wiki/10274.views-advantages-and-disadvantages.aspx
Regards,
Katherine Xiong
Katherine Xiong
TechNet Community Support

Query help in select Distinct on one column.

CREATE GLOBAL TEMPORARY TABLE Table1 (
ID1 varchar2(100) ,
Name1 varchar2(100),
Name11 varchar2(100)
insert into Table1 values ('a','n1','h3');
insert into Table1 values('b','n2','h2');
insert into Table1 values('a','n3','h1');
insert into Table1 values('c','n4','h5');
insert into Table1 values ('c','n5','h4');
insert into Table1 values('d','n6','h6');
select * from Table1;
ID1,NAME1,     NAME11
a,     n1,     h3
b,     n2,     h2
a,     n3,     h1
c,     n4,     h5
c,     n5,     h4
d,     n6,     h6
I am trying to select distinct ID1 and all values associated with it which is max row.I want to result as -
ID1,NAME1,     NAME11
a,     n3,     h1
b,     n2,     h2
c,     n5,     h4
d,     n6,     h6
Can you please help me to write simple query to get above result.
Edited by: 871447 on Jul 25, 2011 9:42 AM
Edited by: 871447 on Jul 25, 2011 9:45 AM

Hi,
Do a self-join, to combine the two rows for each value of id1 onto one output row.
Make it an outer join, in case there is only one row with a vlaue for id1.
SELECT l.id1
,     l.name1
,     NVL ( r.name11
         , l.name11
         )          AS name11
FROM              table1     l
LEFT OUTER JOIN     table1     r ON l.id1     = r.id1
                          AND l.name1     < r.name1
;Edited by: Frank Kulash on Jul 25, 2011 12:57 PM
Sorry, I mis-read the problem.
Lee's solution, above, assumes that name1 is unique, as it is in your sample data.
What output would you want if that's not the case?
If name1 is not unique, but the combination of (id1, name1) is unique, then you can modify Lee's solution like this:
SELECT *
FROM    table1
WHERE   (id1, name1) IN (
                    SELECT    id1
                    ,       MAX (name1)
                           FROM          table1
                    GROUP BY id1
;Or, if you can't make any assumptions about uniqueness, you might need something like this:
WITH     got_r_num     AS
     SELECT id1, name1, name11
     ,     ROW_NUMBER () OVER ( PARTITION BY id1
                               ORDER BY         name1     DESC
                         ,                name11     DESC
                       )      AS r_num
     FROM     table1
SELECT id1, name1, name11
FROM     got_r_num
WHERE     r_num     = 1
;

No distinction between NULL and space

No distinction between NULL and space. When you see the resultset, in PL/SQL developer, you will see that the NULL value is in yellow colour while column data having spaces is in white colour. In the new tool, there is not distinction between the two, so each time we will have to use the NVL function to determine the value in the column, which I would not like to do.

An option in Preferences could be created, so that it was possible to choose as values NULL would be shown, as already it occurs in other tools.

ORA-1489 error but only sometimes...when not having distinct or another function working

So when I enter:
SELECT opened_by from(
SELECT ps."NUMBER",
ps.opened_by,
ps.assignee_name,
ps.closed_by,
listagg(att.type,',') within group(order by att.type) actions,
listagg(att.description_txt,',') within group (order by att.description_txt) descs
from tableps ps
LEFT JOIN activity_txt att ON ps."NUMBER" = att."NUMBER" and att.type in('Assignment','Reassignment')
where open_time between to_date('01-OCT-2012','DD-MON-YYYY') and to_date('31-OCT-2013','DD-MON-YYYY')
and ((ps.opened_by=ps.closed_by) and (ps.closed_by=ps.assignee_name) and (ps.assignee_name=ps.opened_by))
group by ps."NUMBER",ps.opened_by,ps.assignee_name,ps.closed_by
where (actions not like '%Reass%'or actions is null)
and (descs like ('%NONE to '|| opened_by ||'%') or descs is null)
and (descs not like '%,%' or descs is NULL);
All is well in the world...however when I add distinct to the outer select I get the
ORA-01489: result of string concatenation is too long
01489. 00000 - "result of string concatenation is too long"
*Cause:    String concatenation result is more than the maximum size.
*Action:   Make sure that the result is less than the maximum size.
I don't understand the difference why one would work and one doesn't.

I little changed your quesry,
Please try, if you are getting same error, then it means you have very large desciptions in description_txt column.
Pleasech check :
https://forums.oracle.com/thread/2596075
https://forums.oracle.com/message/10601105#10601105
SELECT T."NUMBER",
    T.opened_by,
    T.assignee_name,
    T.closed_by,
    listagg(T.type,',') within GROUP(ORDER BY T.type) actions,
    listagg(T.description_txt,',') within GROUP (ORDER BY T.description_txt) descs
FROM
(SELECT
    ps."NUMBER",
    ps.opened_by,
    ps.assignee_name,
    ps.closed_by,att.type, att.description_txt
FROM tableps ps LEFT JOIN activity_txt att ON ps."NUMBER" = att."NUMBER" AND att.type IN('Assignment','Reassignment')
WHERE open_time BETWEEN to_date('01-OCT-2012','DD-MON-YYYY') AND to_date('31-OCT-2013','DD-MON-YYYY')
    AND ((ps.opened_by   =ps.closed_by)
    AND (ps.closed_by    =ps.assignee_name)
    AND (ps.assignee_name=ps.opened_by))
     and (att.type NOT LIKE '%Reass%' OR att.type IS NULL)
     AND (att.description_txt LIKE ('%NONE to '|| opened_by ||'%') OR att.description_txt IS NULL)
     AND (att.description_txt NOT LIKE '%,%'OR att.description_txt IS NULL)) T
Group by T."NUMBER",
    T.opened_by,
    T.assignee_name,
    T.closed_by
And carefully read Solomon Yakobson's and Frank Kulash's replies.
Regards
Mahir M. Quluzade

Removing the Duplicate Values from output without using Keyword DISTINCT

Hi,
I'm running the below query without DISTINCT Keyword and getting Duplicate results. can you please tell me what needs to be done if I want unique values without using Distinct.
select hra.Location_code
,hra.Description
,hra.Address_line_1
,hra.Address_line_2
,hra.Address_line_3
,hra.town_or_city
,hra.Region_1
,hra.Postal_Code
,hra.country
,hra.attribute1
,hra.attribute5
,hra.attribute6
,hra.attribute8
,hra.attribute9
,hra.attribute2
,hra.attribute3
,hra.attribute4
,hra.attribute7
,hra.attribute10
from hr_locations_all hra
,per_all_people_f papf
,per_person_types ppt
, per_person_type_usages_f pptuf
,hr_all_organization_units haou
,hr_all_organization_units haou1
where 1=1
and hra.business_group_id = papf.business_group_id
and hra.business_group_id = ppt.business_group_id
and pptuf.person_id = papf.person_id
and pptuf.person_type_id = ppt.person_type_id
and ppt.system_person_type = 'EMP'
and ((hra.inactive_date is null) or (trunc(hra.inactive_date)>= to_date('01/01/2012','mm/dd/yyyy')))
and to_date('01/01/2012','mm/dd/yyyy') between trunc(pptuf.effective_start_date) and trunc(pptuf.effective_end_date)
and((papf.effective_end_date is null) or (trunc(papf.effective_end_date)>= to_date('01/01/2012','mm/dd/yyyy')))
and ((haou1.date_to is null) or (trunc(haou1.date_to)>= to_date('01/01/2012','mm/dd/yyyy')))
and papf.business_group_id = haou.organization_id
and hra.location_id = haou1.location_id;

Hi,
Try using this Code
select hra.Location_code
,hra.Description
,hra.Address_line_1
,hra.Address_line_2
,hra.Address_line_3
,hra.town_or_city
,hra.Region_1
,hra.Postal_Code
,hra.country
,hra.attribute1
,hra.attribute5
,hra.attribute6
,hra.attribute8
,hra.attribute9
,hra.attribute2
,hra.attribute3
,hra.attribute4
,hra.attribute7
,hra.attribute10
from hr_locations_all hra
,per_all_people_f papf,
per_all_assignments_f paaf,
per_person_types ppt
, per_person_type_usages_f pptuf
,hr_all_organization_units haou
--,hr_all_organization_units haou1
where 1=1
and
hra.business_group_id = papf.business_group_id
and hra.business_group_id = ppt.business_group_id
and pptuf.person_id = papf.person_id
and papf.person_id=paaf.person_id
and pptuf.person_type_id = ppt.person_type_id
and ppt.system_person_type = 'EMP'
--and ((hra.inactive_date is null) or (trunc(hra.inactive_date)>= to_date('01/01/2012','mm/dd/yyyy')))
and to_date('01/01/2012','mm/dd/yyyy') between trunc(pptuf.effective_start_date) and trunc(pptuf.effective_end_date)
--and((papf.effective_end_date is null) or (trunc(papf.effective_end_date)>= to_date('01/01/2012','mm/dd/yyyy')))
--and((paaf.effective_end_date is null) or (trunc(paaf.effective_end_date)>= to_date('01/01/2012','mm/dd/yyyy')))
and to_date('01/01/2012','mm/dd/yyyy') between trunc(papf.effective_start_date) and trunc(papf.effective_end_date)
and to_date('01/01/2012','mm/dd/yyyy') between trunc(paaf.effective_start_date) and trunc(paaf.effective_end_date)
--and ((haou1.date_to is null) or (trunc(haou1.date_to)>= to_date('01/01/2012','mm/dd/yyyy')))
--and papf.business_group_id = haou.organization_id
and paaf.location_id=hra.location_id
and paaf.organization_id=haou.organization_id
--and papf.employee_number='1010008830'
and hra.location_id = haou.location_id;

How to get distinct values from a list and display in a ListView webpart.

Hi,
I have a requirement in which I need to pull unique/distinct values from a custom list and then display it via a listview webpart. Can any one suggest how this can be done.
If possible please share the CAMEL query to fetch distinct values from a custom list.
Thanks,
Ankit

Hi Ankit,
Is there any particular reason that the values need to be shown in a list view web part? Are you going to use that web part for filtering via web part connections?
I ask because the enterprise site collection features include the SharePoint List Filter web part, which may accomplish what you're looking for.
If you just need to display the values in a grid view, you might have more luck with the JavaScript Client Object Model. Try putting the following in a text file:
<style>
.CustomTableClass{display:table;table-layout:fixed}
.CustomRowClass{display:table-row;}
</style>
<div id="distinct_values_div" class="CustomTableClass">
<img src="/_layouts/loading.gif" />
</div>
<script language="JavaScript" type="text/JavaScript">
var siteUrl = '/sitecollection/web'; //use the actual subsite URL here
var listName = 'mylist'; // use the actual list name here
var field = "Title" // use the actual field you want to display here
var divToUpdate = document.getElementById("distinct_values_div");
var rowClass = "CustomRowClass";
ExecuteOrDelayUntilScriptLoaded(function(){
var clientContext = new SP.ClientContext(siteUrl);
var web = clientContext.get_web();
var lists = web.get_lists();
var list = lists.getByTitle(listName);
var camlQuery = new SP.CamlQuery();
camlQuery.set_viewXml('<View><Query></Query><RowLimit>500</RowLimit></View>');
this.collListItem = list.getItems(camlQuery);
clientContext.load(collListItem,"Include ("+field+")");
clientContext.executeQueryAsync(
Function.createDelegate(this, this.onQuerySucceeded),
Function.createDelegate(this, this.onQueryFailed));
},"sp.js");
function onQueryFailed(sender, args){
divToUpdate.innerHTML = 'Unable to retrieve values: '+args.get_message());
function onQuerySucceeded(sender, args){
var allValues = [];
var listItemEnumerator = collListItem.getEnumerator();
divToUpdate.innerHTML = "";
while(listItemEnumerator.moveNext()){
var listItem = listItemEnumerator.get_current();
if(!containsString(allValues,listItem.get_item(field)){
var value = listItem.get_item(field);
allValues.push(value);
var newDiv = document.createElement("div");
newDiv.className = rowClass;
newDiv.innerHTML = value;
divToUpdate.appendChild(newDiv);
function containsString(strArray, text){
var contains = false;
for (var i=0; i<strArray.length; i++){
if(strArray[i]==text){contains = true; break;}
return contains;
</script>
Upload the text file to a library on the site, then add a content editor web part to a page where you want the distinct values to appear. In the content editor web part's properties, edit the Content Link so that it links directly to the text file. This
will cause the JavaScript to run on the page.

Get distinct values from a coma seperated string variable

Hi ,
I am getting an comma seperated string as in parameter, now i want to get the distinct values from that string and will use those values to pass it to a query.
any help

try this:
sorry about the messiness - it's just quickly copied from some badly formatted code....
TYPE T_FieldArray IS TABLE OF varchar2(255) INDEX BY BINARY_INTEGER;
function SPLIT_CSV_FIELDS (
p_Input_Str in varchar2,
p_Delimiter in varchar2,
p_Quote_Char in varchar2)
return t_fieldarray is
v_FieldArray T_FieldArray;
v_input_str varchar2(4000);
v_field_str varchar2(255);
v_pos number;
e number := 0;
v_delim_str varchar2(3);
cur_pos number;
begin
loop
-- find each delimiter char in string
v_pos := INSTR(v_input_str, p_Delimiter);
-- each time delimiter char is found
if v_pos > 0 then
-- current field value is current string to position prior to delimiter char
v_field_str := UPPER(SUBSTR(v_input_str, 1, v_pos - 1));
-- remove quote char from end of field (if any)
v_field_str := TRIM(TRANSLATE(v_field_str, NVL(p_Quote_Char, p_Delimiter), ' '));
-- increment element number
e := e + 1;
-- get remainder of input string to check
v_input_str := SUBSTR(v_input_str, v_pos + 1, LENGTH(v_input_str) - v_pos);
v_FieldArray(e) := v_field_str;
else
-- increment element number
e := e + 1;
-- last field value is what's left of input string less quote char (if any)
v_field_str := TRIM(TRANSLATE(UPPER(v_input_str), NVL(p_Quote_Char, p_Delimiter), ' '));
v_FieldArray(e) := v_field_str;
exit;
end if;
end loop;
return v_FieldArray;
end;

"How to get distinct values of sharepoint column using SSRS"

Hi,
    I have integrated sharepoint list data to SQL Server reporting services. I am using the below to query sharepoint list data using sql reporting services.
<Query>
   <SoapAction>http://schemas.microsoft.com/sharepoint/soap/GetListItems</SoapAction>
   <Method Namespace="http://schemas.microsoft.com/sharepoint/soap/" Name="GetListItems">
      <Parameters>
         <Parameter Name="listName">
            <DefaultValue>{GUID of list}</DefaultValue>
         </Parameter>
         <Parameter Name="viewName">
            <DefaultValue>{GUID of listview}</DefaultValue>
         </Parameter>
         <Parameter Name="rowLimit">
            <DefaultValue>9999</DefaultValue>
         </Parameter>
      </Parameters>
   </Method>
<ElementPath IgnoreNamespaces="True">*</ElementPath>
</Query>
By using this query, I am getting a dataset which includes all the columns of sharepoint list. Among these columns, I wanted to display only 2 columns (i.e Region and Sales type) using chart. I have created a Region parameter but when I click preview, the drop down box is giving me all the repeatative values of region like RG1,RG1,RG1,RG2,RG2,RG2,RG2,RG3.......... I wanted to display only distinct values of Region parameter so that whenever end user select region from the parameter drop down, it will display the respective value of Sales type column.
Also when I select only RG1 parameter, it is giving me a chart including the sales type of all the Regions. (it should display me only the sales type of RG1) How can I link these 2 columns so that they will display the values respectively.
          I would really appreciate if anyone can help me out with this.
Thanks,
Sam.

Hi Sam,
By code, the CAML language doesn’t have any reserved word (or tag) to set this particular filter to remove duplicate results.
In this case, we could use the custom code to get distinct records.
Here are the detailed steps:
1.         Create a hidden parameter that gets all the records in one field.
Note: Please create another dataset that is same of the main dataset. This dataset is used for the parameter.
2.         Create a function that used to remove the duplicate records.
Here is the code:
Public Shared Function RemoveDups(ByVal items As String) As String
Dim noDups As New System.Collections.ArrayList()
Dim SpStr
SpStr = Split(items ,",")
For i As Integer=0 To Ubound(Spstr)
If Not noDups.Contains(SpStr(i).Trim()) Then
noDups.Add(SpStr(i).Trim())
End If
Next
Dim uniqueItems As String() = New String(noDups.Count-1){}
noDups.CopyTo(uniqueItems)
Return String.Join(",", uniqueItems)
End Function
3.         Create another parameter that will be used for filtering the maindata.
Please set the available value to be =Split(Code.RemoveDups(JOIN(Parameters!ISSUE_STATUS_TEMP.Value, ",")), ",")
And the default value to be the value you what such as the first value:
=Split(Code.RemoveDups(JOIN(Parameters!ISSUE_STATUS_TEMP.Value, ",")), ",").(0)
4.         Go to the main dataset. Open the property window of this dataset.
5.         In the “Filters” tab, set the filter to be:
Expression: <The field to be filter>
Operator: =
Value: =Parameters!Region.Value
The parameter “Region” should be the parameter we created in the step3.
Now, we should get distinct values of SharePoint columns.
If there is anything unclear, please feel free to ask.
Thanks,
Jin
Jin Chen - MSFT

Get distinct values from plsql array

Hi,
I have declared a variable as below in plsql proc.
type t_itemid is table of varchar2(10);
inserted set of items in to this using a program
now i want distinct values from that array how can i get it.

I am using 9i so i cannot use set operator and more over my problem is that i am declaring the variable inside the plsql block . when i tried i am getting the below errors:
SQL> r
1 declare
2 type t_type is table of varchar2(10);
3 v_type t_type;
4 begin
5 v_type := t_type('toys','story','good','good','toys','story','dupe','dupe');
6 for i in (select column_value from table(v_type)) loop
7 dbms_output.put_line(i.column_value);
8 end loop;
9* end;
for i in (select column_value from table(v_type)) loop
ERROR at line 6:
ORA-06550: line 6, column 41:
PLS-00642: local collection types not allowed in SQL statements
ORA-06550: line 6, column 35:
PL/SQL: ORA-22905: cannot access rows from a non-nested table item
ORA-06550: line 6, column 10:
PL/SQL: SQL Statement ignored
ORA-06550: line 7, column 22:
PLS-00364: loop index variable 'I' use is invalid
ORA-06550: line 7, column 1:
PL/SQL: Statement ignored

CE function to get distinct values from Column table

Hi All,
Could you please let me know the appropriate CE function to get the distinct values from column table.
IT_WORK = SELECT DISTINCT AUFNR FROM :IT_WO_DETAILS;
Thank you.

Hi,
If you have 10g, you can use Model( with model performance is better than connect by )
Solution
========================================================================
WITH t AS
(SELECT '0989.726332, 1234.567432, 3453.736379, 3453.736379, 0989.726332, 3453.736379, 1234.567432, 1234.567432, 0989.726332'
txt
FROM DUAL)
SELECT DISTINCT TRIM(CHAINE)
FROM T
MODEL
RETURN UPDATED ROWS
DIMENSION BY (0 POSITION)
MEASURES (CAST( ' ' AS VARCHAR2(50)) AS CHAINE ,txt ,LENGTH(REGEXP_REPLACE(txt,'[^,]+',''))+1 NB_MOT)
RULES
(CHAINE[FOR POSITION FROM 1 TO NVL(NB_MOT[0],1) INCREMENT 1] =
CASE WHEN NB_MOT[0] IS NULL THEN TXT[0] ELSE REGEXP_SUBSTR(txt[0],'[^,]+',1,CV(POSITION)) END );
=========================================================================
Demo
=======================================================================
SQL> WITH t AS
2 (SELECT '0989.726332, 1234.567432, 3453.736379, 3453.736379, 0989.726332, 3453.736379, 123
4.567432, 1234.567432, 0989.726332'
3 txt
4 FROM DUAL)
5 SELECT DISTINCT TRIM(CHAINE)
6 FROM T
7 MODEL
8 RETURN UPDATED ROWS
9 DIMENSION BY (0 POSITION)
10 MEASURES (CAST( ' ' AS VARCHAR2(50)) AS CHAINE ,txt ,LENGTH(REGEXP_REPLACE(txt,'[^,]+',''))+1 NB_MOT)
11 RULES
12 (CHAINE[FOR POSITION FROM 1 TO NVL(NB_MOT[0],1) INCREMENT 1] =
13 CASE WHEN NB_MOT[0] IS NULL THEN TXT[0] ELSE REGEXP_SUBSTR(txt[0],'[^,]+',1,CV(POSITION)) END );
TRIM(CHAINE)
3453.736379
1234.567432
0989.726332
SQL>
========================================================================

How to get Distinct Values from Answers

Hi,
How to get Distinct values from answers, i've tried to put some functions on it.
Thanks,
Malli

Malli,
Are you trying to fetch data from Dimension Attr OR Fact Measures? Did you try the advance tab - > Advanced SQL Clauses - > Check this box to issue an explicit Select Distinct.

Distinct values from dynamic internal tabls

Hi All,
I have a dynamic internal tables like <dy_table> , i want to get distinct values from this internal tables,
how to do that, structure of dynamic internal tables is dynamic acc. to user conditions.
regards,
Anuj

Hi Anuj
Just try this,
CALL METHOD cl_alv_table_create=>create_dynamic_table
EXPORTING
it_fieldcatalog = tb_fields_for_it
IMPORTING
ep_table = gp_dyn_table.
ASSIGN gp_dyn_table->* TO <gt_table>.
ASSIGN LOCAL COPY OF INITIAL LINE OF <gt_table> TO <fs_table>.
LOOP AT tb_output.
*To assign value for serial number.
ASSIGN COMPONENT 1 OF STRUCTURE <fs_table> TO <ls_field>.
<ls_field> = tb_output-sno.
UNASSIGN <ls_field>.
*To assign value for Sales Organization.
ASSIGN COMPONENT 2 OF STRUCTURE <fs_table> TO <ls_field>.
<ls_field> = tb_output-vkorg.
UNASSIGN <ls_field>.
*To assign Rate for its respective Condition type.
LOOP AT tb_konp WHERE knumh = tb_output-knumh.
READ TABLE tb_fieldcat1 WITH KEY fieldname = tb_output-kschl.
IF sy-subrc EQ 0.
lv_count = tb_fieldcat1-col_pos.
ASSIGN COMPONENT lv_count OF STRUCTURE <fs_table> TO <ls_field>.
IF tb_konp-konwa EQ '%'.
tb_konp-kbetr = tb_konp-kbetr / co_10.
<ls_field> = tb_konp-kbetr.
ELSE.
<ls_field> = tb_konp-kbetr.
ENDIF.
ENDIF.
ENDLOOP.
lv_count = lv_count + 1.
APPEND <fs_table> TO <gt_table>.
CLEAR <fs_table>.
ENDLOOP.
Hope this proves helpful to you.

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