Distance between miniatures
Hi, how can I modify distance between miniatures in a presentation? I succeded in change dimension but I'm not able to change the space from each miniature.
Thank's
To achieve this, you may use the commands in the spacing.panel
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HP Envy 17t-j100 Distance between USB Slots suggestion
I intended this post as a recommandation for HP.
I have an HP Envy Touchsmart 17t-j100 and everything is excelent up until now.
The only thing that is very annoying is the distance between USB ports. PLEASE increase the distance between USB ports for the future models. I have a lot of problems tryng to connect everything I need.
Even if I try to open the DVD drive, it will stuck in my USB device. I mean how much difficult is to put a distance of 1 cm between them?
If the USB cables are the standard size, there are no problems but most of the USB devices nowadays are much more wider than a standard USB cable and I keep having problems.
I mean it's a 17" laptop, there is plenty of space on the sides. In the end, it's better to drop the DVD drive and put a VGA slot instead, but with bigger distance between USB ports.
I am planning to buy another ENVY in the future but I really want my new laptop to have USB ports with a wider distance bewtween them.
Thank you very much and I hope HP will take care of this little problem on the future models.
Have a nice day.
This question was solved.
View Solution.Hi @catapara89 ,
Thank you for visiting the HP Support Forums and Welcome. Thanks so much for taking the time to let us know of your suggestions on the USB slots. It is important and has been viewed.
Have a great week.
Thanks.
Please click “Accept as Solution ” if you feel my post solved your issue, it will help others find the solution.
Click the “Kudos, Thumbs Up" on the bottom to say “Thanks” for helping! -
Calculating co-ordinate distances between specific atoms
Hi,
Below is some code to calculate distances between all pairs of atoms. However, i need to make it slightly more specific by only calculating the distance between certain pairs of atoms
input
ATOM 5 CA PHE 1 113.142 75.993 130.862
ATOM 119 CA LEU 7 113.101 72.808 140.110
ATOM 138 CA ASP 8 109.508 74.207 140.047
ATOM 150 CA LYS 9 108.132 70.857 141.312
ATOM 172 CA LEU 10 110.758 70.962 144.119
e.g distance between all pairs for atoms 5, 119, 150 and 172 (say), last three columns are x,y and z co-ordinates
code it self
import java.util.*;
import java.io.*;
public class Distance {
public static void main(String[] args) {
System.out.println("***Campbells PDB Distance Calculator***" + "\n");
new Distance();
System.out.println("\nResults printed to file DistanceCalculations" + "\n");
System.out.println("\nDue to nature of code, if rerun results will be appended to the end of previous run.");
public Distance() {
Vector atomArray = new Vector();
String line;
try{
System.out.println("Enter PDB file:" + "\n");
BufferedReader inputReader =new BufferedReader (new InputStreamReader(System.in));
String fileName = inputReader.readLine();
if ( fileName !=null) {
BufferedReader inputDistance = new BufferedReader (new FileReader (fileName));
while (( line = inputDistance.readLine()) !=null && !line.equals(""))
Atom atom = new Atom(line);
atomArray.addElement(atom);
for (int j=0; j<atomArray.size(); j++) {
for (int k=j+1; k<atomArray.size(); k++) {
Atom a = (Atom) atomArray.elementAt(j);
Atom b = (Atom) atomArray.elementAt(k);
Atom.printDistance (a,b);
} //if
} //try
catch (IOException e) {
System.out.println("Input file problem");
} catch (Exception ex) {
System.out.println (ex);
class Atom {
public double x, y, z;
public String name;
public Atom(String s) throws IllegalArgumentException {
try {
StringTokenizer t = new StringTokenizer (s, " ");
t.nextToken();
this.name = t.nextToken();
for (int j=0; j<3; j++) t.nextToken();
this.x = new Double(t.nextToken()).doubleValue();
this.y = new Double(t.nextToken()).doubleValue();
this.z = new Double(t.nextToken()).doubleValue();
catch (Exception ex) {
throw new IllegalArgumentException ("Problem!!!! :-(");
public String toString() {
return "atom : " + name + "(x=" + x + " y=" + y + " z=" + z + ")";
public double distanceFrom (Atom other) {
return calculateDistance (x, y, z, other.x, other.y, other.z);
public static double calculateDistance (double x1, double y1, double z1, double x2, double y2, double z2) {
return Math.sqrt(Math.sqrt(Math.pow(Math.abs(x1-x2),2)+Math.pow(Math.abs(y1-y2),2))+Math.pow(Math.abs(z1-z2),2));
public static void printDistance (Atom a, Atom b) {
try{
FileWriter fw = new FileWriter("DistanceCalculations", true);
PrintWriter pw = new PrintWriter (fw, true);
if
(a.distanceFrom(b) <9){
pw.println("Distance between " + a.toString() + " and " + b.toString() + " is " + a.distanceFrom(b));
pw.flush();
pw.close();
} // if??
} //try loop
catch(IOException e) {
System.out.println("System error");
}ok, essentially
want to calculate distance between to ranges. Say
range 1 is the first three, range 2 the rest. THen
calculate distance between all possible pairs between
these two rangesYes - and no doubt that any number of people here could write it for you. But that's not what the forum is about. So what, exactly, is preventing you from doing it?
Sylvia. -
What is the maximum distance between a time capsule and an airport express?
What is the maximum distance between a time capsule and an airport express?
You can only "extend" the signal one time, so you need to have the AirPort Express located approximately 1/2 to 2/3 of the distance from the Time Capsule to the area that needs more wireless coverage.
I doubt that this will help much since you have a very challenging setup. Wireless is really only for "same room" or "nearby rooms" around the corner.
To do this correctly you will need to use an Ethernet cable connection from the Time Capsule to the AirPort Express, which could then be located close to the xBox.
If it is not possible to run the Ethernet cable, you might look at a pair of Ethernet powerline adapters to send a "psuedo" Ethernet signal over the AC wiring in your home.
This will not be anywhere near the performance of a regular Ethernet cable, but it will likely be much better than wireless.
Since Ethernet over powerline (EOP) is somewhat unpredictable, you would want to have a very clear understanding of the store's return policy in case things don't work out as hoped. Any computer / electronics superstore will have a selection of powerline adapters to choose from. -
How do I cancel the distance between the numbers?
I'm having trouble copy phone numbers from the phone book and send it via SMS
This problem I've found in the Arabic language, numbers appear in reverse
Please help
System 6.0.1MPEG-4 should not be used in FCP unless it is converted first or optimized in the application.
Trash your preferences. Trash your project render files. Switch off background rendering. Do not re-render. Export your projects.
Ignore the last frame and first frame indicators. -
Calculate distance between Latitude and Longitude
Hi All,
I have one Latitude and Longitude points. I need to calculate distance between them.
Right now we are using HAVERSINE formula but the query takes longer time to complete.
Reference: http://www.movable-type.co.uk/scripts/latlong.html
Please assist on this.
Thanks in advance.Check this link...
http://www.mrexcel.com/forum/excel-questions/202255-calculating-distance-between-two-latitude-longitude-points.html
I never did this before, but gave it a try using the formula mentioned in that link..
Data:
Lat Long R = 6,371 (Radius of earth (approximated))
Origin: 44.844263(B2) -92.914803(C2)
Destination: 44.822075(B3) -92.912498(C3)
Formula used:
A: =SIN(ABS(B3-B2)*PI()/180/2)^2+COS(B2*PI()/180)*COS(B3*PI()/180)*SIN(ABS(C3-C2)*PI()/180/2)^2
B: =2*ATAN2(SQRT(1-A),SQRT(A))
C: =R*B ---> DISTANCE!!!!
WITH t AS
(SELECT POWER (
SIN (ABS (44.822075 - 44.844263) * ( (22 / 7) / 180 / 2)),
2)
+ COS (44.844263 * ( (22 / 7) / 180))
* COS (44.822075 * ( (22 / 7) / 180))
* POWER (
SIN (
ABS (-92.912498 - (-92.914803))
* ( (22 / 7) / 180 / 2)),
2)
E2
FROM DUAL)
SELECT (2 * ATAN2 (SQRT ( (1 - E2)), SQRT (E2))) * 6371
FROM t;
Check if this gives correct values... (I did not verify this properly.. ) And this is faster in my opinion..
Please post your code for better suggestions from volunteers...
Cheers,
Manik. -
Calculating distance between Lat Long points
I'm wondering if anyone out there has done this before in LabVIEW. Does anyone have a model of the "Great Circle" calculation? I have a file of lat/long points that I need to calculate the distance between. Any help??
V/r,
ChrisI haven't done it in LV, but if you go to Wikipedia and search for Great Circle Distance you'll find the formual and an example.
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Is there any css to vary the distance between two items in apex
Hi,
Is there any css to vary the distance between two items ie two columns horizontally / vertically in apex application at page line level
Regards,
PavanHi ,
I done what u suggested above but i ll tel u clearly
i have name,plot no,street,city,distict,state,country,phone no,pincode items.. i need to align this items like
--------------------------------------------------------------------------main region----------------------------------------------------------------------------
--left region-------------------------------------------middle region------------------------------------------------------right region-------------------
name,___________
plot no,_________
street,________
city,___________ distict,_________
state,__________ country,_________ nothing in it
phone no,__________ pincode_________
to achieve this wat i have to do
Thanks,
pavan -
Find driving distance between two points without using API by use of Lat & Long?
Using Google geocode API : http://maps.googleapis.com/maps/api/geocode/xml?address=thane&sensor=true
We performed get distance between search criteria entered by user and all related clubs by lat & long stored at db.
2. Two different points such as
(origin: Lat1 & Long1) and (destination: Lat2 & Long2)
We tried for to get distance between these two points,
(Lat2 & Long2) to (Lat1 & Long1)
But distance which we get by calculation is simple straight line distance
Origin Destination
(Lat1 & Long1) (Lat2 & Long2)
3. This is not driving distance as google shows in exact Km
4. For that Google provide another API (distancematrix API)
http://maps.googleapis.com/maps/api/distancematrix/xml?origins=Thane&sensor=true&destinations=khopat&mode=driving&language=en%20-%20EN
5. But there is limit for DistanceMatrix-Service without ClientID and client key
100 elements per query.
100 elements per 10 seconds.
2 500 elements per 24 hour period.
But as element request exceeds it shows : OVER_QUERY_LIMIT error
6. In case of Client ID and Client key
In Distance Matrix 100 000 elements per 24 hour period,a maximum of 625 elements per query and a maximum of 1 000 elements per 10 seconds.
As per this one there is option to get purchase these API but basic question is remain same for us if we are requesting single origin and multiple destination then how element calculation done by google?
But in document google says :
Elements
The information about each origin-destination pairing is returned in an element entry. An element contains the following fields:
Status: See Status Codes for a list of possible status codes.
Duration: The duration of this route, expressed in seconds (the value field) and as text. The textual representation is localized according to
the query's language parameter.
Distance: The total distance of this route, expressed in meters (value) and as text. The textual value uses the unit system specified with the
unit parameter of the original request, or the origin's region.Any information that you see in a google map webpage can be retrieved using the API. The best way of finding the tags on the webpage is to manually perform the query using an IE webpage. Then capture the source and save to a file so you
can use a text editor to look at results. I often on a webpage use the menu : View - Source and then copy the source to a text file.
jdweng -
Customizing distance between data Points on x-Axis
Hi,
I want to draw a LineChart.
I have these Timestamps [84, 1000, 34000, 34699, 439999] who
are represanting the x-Value of DataPoints along the X-Axis.
Unfortunately the distance between 2 datapoints along the
x-Axis is always the same, that means that between the points with
x-values 84 and 1000 is the same distance along the axis as between
the points with x-values 34699 and 439999.
But the distance between points with x-values of 34699 and
439999 should be much greater than between 84 and 1000.
How can I customize the distance between data Points on a
LineChart to solve my Problem?
I really dont know right now!
Greeting,
Z."zidaninho" <[email protected]> wrote in
message
news:gls479$nkt$[email protected]..
> Hi,
>
> I want to draw a LineChart.
> I have these Timestamps [84, 1000, 34000, 34699, 439999]
who are
> represanting
> the x-Value of DataPoints along the X-Axis.
>
> Unfortunately the distance between 2 datapoints along
the x-Axis is always
> the
> same, that means that between the points with x-values
84 and 1000 is the
> same
> distance along the axis as between the points with
x-values 34699 and
> 439999.
> But the distance between points with x-values of 34699
and 439999 should
> be
> much greater than between 84 and 1000.
>
> How can I customize the distance between data Points on
a LineChart to
> solve
> my Problem?
>
> I really dont know right now!
What happens if you convert the time stamps to Dates and use
a DateAxis? -
Report format - distance between rows
Hi,
After formatting a output(report), the distance between rows is much bigger than on output w/o format.
What parameter controls the distance between rows?
How to make the output/report more dense in row sense?
Thx,Use BREAK ON column-name SKIP n
where n is how many lines to skip:
sql>create table t (one varchar2(3), two number );
Table created.
sql>insert into t values ('aaa', 1 );
1 row created.
sql>insert into t values ('aaa', 2 );
1 row created.
sql>insert into t values ('bbb', 3 );
1 row created.
sql>break on one skip 2;
sql>select * from t;
ONE TWO
aaa 1
2
bbb 3
(note: this doesn't display in "preview" with correct formatting so just try it and you'll see) -
PDF TEMPLATES ISSUE...DISTANCE BETWEEN LINES
Hello People... after a read the manual i tried to do a pdf template based on a legal asset map.
in Manual i read this
'Note: The placement of this field in relationship to the
BODY_START tag defines the distance between the repeating rows
for each occurrence. See Placement of Repeating Fields, page 8-15.'
My template have fixed lines and what i want to do is for each ocurrence put the data inside of line of the template. i tried to adjust commanding the space of start body form field and the repeating group field. Some rows stay's inside of the lines of my template but some rows don't. someone know's a way to do this? i dont understand why the distance between the rows have variations and dont stay always at the same distance of the previous line. I can send my output to anyone.
Tks in advance.Kenoli,
The objects are interacting because they are Inline (Moves with Text) and/or you have "Causes Wrap" turned on.
With the object selected, go to the Format Pane and the Arrange Tab, set the Object Placement the way you want it and adjust Text Wrap to None.
Jerry -
Distance between buttons (Flow Layout)
Hi people,
I Have 100 buttons inside a JPane with Flow Layout.
How do I set the distance between the buttons to 0(width and height)?
Regards.
Thank's.Yes, I did!
I have a class "Board" that extends JPanel with GridLayout.
This class has a constructor that takes the rows, cols, number of mines and size of squares!
package view;
import java.awt.Dimension;
import java.awt.GridLayout;
import java.util.Random;
import javax.swing.JPanel;
import model.Square;
import control.SquareHandler;
public class Board extends JPanel {
private Square square[][] = new Square[16][30];
private int mines, width, height;
Board(int width, int height, int mines, int size) {
Dimension dimension = new Dimension(size,size);
//FlowLayout layout = new FlowLayout();
GridLayout layout = new GridLayout();
//layout.setHgap(0);
//layout.setVgap(0);
layout.setRows(height);
layout.setColumns(width);
this.mines = mines;
this.width = width;
this.height = height;
setLayout(layout);
for (int j = 0; j < height; j++){
for (int i = 0; i < width; i++){
square[j] = new Square(i,j);
square[j][i].setPreferredSize(dimension);
square[j][i].addActionListener(new SquareHandler(this, i, j));
add(square[j][i]);
makeMines();
public void makeMines() {
Random randomizer = new Random();
int randomX, randomY;
for (int i = 0; i < mines; i++){
while (true) {
randomX = randomizer.nextInt();
randomX = Math.abs(randomX);
randomX = randomX % width;
randomY = randomizer.nextInt();
randomY = Math.abs(randomY);
randomY = randomY % height;
if(!square[randomY][randomX].getMine()){
square[randomY][randomX].setMine();
break;
public Square getSquare(int x, int y){
if (x < 0 || x >= width || y < 0 || y >= height ){
// Error
return new Square(-1,-1);
return square[y][x]; -
Shortest distance between two line segments
Hi.
I am looking for the code of the "Shortest distance between two line segments". I would appreciate if anyone has and willing to share.
I can find some in the net but its in VB and i am not familiar with it.
THanks a lot.
regards,There are a couple of things that are not clear:
What determines the rotation speed and lenght of each stick at any given time?
What is the program allowed to do to prevent collision (change speed/direction, change radius, stop everything)
Since you want to prevent collision, you need a predictive algorithm. Once they overlap, the collision has already happened. Too late!
What information does your algorithm get (e.g. r1, r2, theta1, theta2, delta-thetat1, delta-theta2, etc.), i.e. does the program only get static information and need to construct the trajectory from sequential history data or does it get dynamic information about speed and direction?
The trivial answer would be to just keep r1+r2 < distance(P1,P2). This will prevent all "potential" collisions.
LabVIEW Champion . Do more with less code and in less time . -
27" iMac: distance between stand base and screen glass?
I searched high and low, but can't find this info anywhere..
On photos of new 27" iMacs, it looks like the front bottom aluminum part of the screen (with Apple logo on it), became narrower comparing to 24" iMacs. Meaning that screen itself is probably positioned lower than on 24" iMacs (which would be terrific)
I wonder if any of 27" iMac owners could be so kind to put their display in vertical 90 degree position and measure the distance between stand base (the top of the table) and the screen glass? I have attached the picture of the measurement I need.
http://img.skitch.com/20091113-r8w77fdkp3aeetukcnw95g44ya.png
Thanks in advance!I think the answer is 16.3cm. It's the same distance as on the new 21.5" iMacs. I already started a topic myself, asking the same question:
http://discussions.apple.com/message.jspa?messageID=10532444#10532444
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