Distribution Group Membership - Find and Replace.

Hello,
I am looking for a way in Powershell to return the distribution groups that a user is a member of. Using that information I'd ideally like to replace that user with another, or remove that user from all groups, then add another to those same groups. *EDIT*
This is needed for Exchange Online and is not linked with AD.
Is this possible?

Hi,
Yes, you can do that. Take a look at these cmdlets for a starting point/examples:
http://ss64.com/ps/get-adprincipalgroupmembership.html
http://ss64.com/ps/add-adprincipalgroupmembership.html
http://ss64.com/ps/remove-adprincipalgroupmembership.html
http://ss64.com/ps/get-adgroupmember.html
http://ss64.com/ps/add-adgroupmember.html
http://ss64.com/ps/remove-adgroupmember.html
Let us know if you run into problems or have any specific questions.
EDIT: I should mention, these are AD cmdlets, not Exchange specific.
Don't retire TechNet! -
(Don't give up yet - 13,085+ strong and growing)

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george,
> when I 'Debug the Movie' (Ctrl-Shift-Enter), it still
> tries to access port 8080! Obsiously, my replace
> command did not do what I thought it would do.
Agreed.
> I opened the FLA file in a binary editor, and saw 4
> more references to 8080, One if them in 'Properties'
> of a WebServicesConnector, but I cannot figure out
> how to find the other occurences.
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> Checking on google, I see lots of people having
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That's really odd, actually. I'm on these boards every day,
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http://www.sephiroth.it/python/sepy.php
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David
stiller (at) quip (dot) net
Dev essays:
http://www.quip.net/blog/
"Luck is the residue of good design."

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Hi,
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Having 46 people view a post without replying is not unusual. Some people look at a question to see if it's something they'd like to know the answer to, and then come back when it has eventually been answered.
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How to do this find and replace?

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As you have worked out, a capturing group is created by wrapping part of the regex in parentheses.
If you want to match exactly 38 characters, you can use [\S\s]{38}. That includes spaces, newline characters, symbols, everything.
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(<\/tag_name>)([^<]+)
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In the Find field of the Find and Replace dialog box, enter this:
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Message was edited by: David_Powers (adding explanation of double quote).

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ls

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I'm using a if statement in my template, but i need to change a value within this statement. It's being used multiple times, therefor it would be easier to do a find and replace, is there a way to do a find and replace within the RTF template? Already openede it in Notepad++, but no luck
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Hi All,
I am doing find and replace using GREP. While using the expression like $1, $2 (Found Items) in the change to field it changes the placement of tag marker. If the found item is a part of two of more xml elements, I am getting a serious problem while replacing it. (ie. The xml tag markers are moved.)
See the screen shot below, then you may get better idea. And help me to overcome this issue.
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Original text/ Before doing find replace
After replacing
Green4ever

Hi Peter and John,
but it seems to me that the example is looking for any space that
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Hi All,
I have a requirement, where i need to find and replace values in delimited string.
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for example (Assumption: the abbreviated month is the first occurance of 3 consecutive alphabetic charachters)
with testdata as (
select 'GL~1001~157747~FEB-13~CREDIT~A~N~USD~NULL~' str from dual
select
str
,regexp_substr(str, '[[:alpha:]]{3}') part
,to_date('01'||regexp_substr(str, '[[:alpha:]]{3}')||'2013', 'DDMONYYYY') part_date
,replace (str
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) res
from testdata
STR
PART
PART_DATE
RES
GL~1001~157747~FEB-13~CREDIT~A~N~USD~NULL~
FEB
02/01/2013
GL~1001~157747~JAN-13~CREDIT~A~N~USD~NULL~
with year included
with testdata as (
select 'GL~1001~157747~JAN-13~CREDIT~A~N~USD~NULL~' str from dual
select
str
,regexp_substr(str, '[[:alpha:]]{3}-\d{2}') part
,to_date(regexp_substr(str, '[[:alpha:]]{3}-\d{2}'), 'MON-YY') part_date
,replace (str
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         ,to_char(add_months(to_date(regexp_substr(str, '[[:alpha:]]{3}-\d{2}'), 'MON-YY'),-1),'MON-YY')
) res
from testdata
STR
PART
PART_DATE
RES
GL~1001~157747~JAN-13~CREDIT~A~N~USD~NULL~
JAN-13
01/01/2013
GL~1001~157747~DEC-12~CREDIT~A~N~USD~NULL~
Message was edited by: chris227 year included

Using applescript for Find and Replace All in Pages 2.0

i saw that Pages 2.0 is scriptable
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ibook G3 Mac OS X (10.4.6)

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try
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end if
end try
end if
end repeat
end tell</PRE>
Titanium PowerBook Mac OS X (10.4.6)

Distribution Group Membership - Find and Replace.

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