Do Weblogic 5.1 support servlet 2,2 web.xml?

Found that a lot of tags in web.xml according to Java servlet 2.2 API didn't work in Weblogic server 5.1, tags such as <session-mapping>, <session-timeout> didn't work at all. Is these tags didn't support in 5.1?
          

          Thank for your correction on the <servlet-mapping>, it is a typing error, it works
          after I correct it.
          But the <session-timout> tag still didn't work.
          I set it up as follow in my web.xml:
          <session-config>
          <session-timeout>30</session-timeout>
          </session-config>
          My testing servlet code as follows, it always shows a timeout value of 1800 seconds
          instead of my preset 30 seconds in the web.xml:
          public void doGet(HttpServletRequest request, HttpServletResponse response) throws
          ServletException, IOException {
               HttpSession session = request.getSession();
               response.setContentType("text/html");
               OutputStreamWriter osw = new OutputStreamWriter(response.getOutputStream());
               PrintWriter out = new PrintWriter (response.getOutputStream());
               out.println("<html>");
               out.println("<head><title>HelloWorld</title></head>");
               out.println("<body>Hello From HelloWorld doGet()");
               out.println("<P>Session will be timeout for " + session.getMaxInactiveInterval()
          + " secs.");
               out.println("</body></html>");
               out.close();
          Kumar Allamraju <[email protected]> wrote:
          ><!doctype html public "-//w3c//dtd html 4.0 transitional//en">
          ><html>
          >Do you mean servlet mapping? I can't seem to find out session-mapping
          >in
          >the dtd
          ><br>Yes we do support session-timeout in 5.1
          ><br>see http://www.weblogic.com/docs51/classdocs/webappguide.html
          ><p>--
          ><br>Kumar
          ><p>Alfred Leung wrote:
          ><blockquote TYPE=CITE>Found that a lot of tags in web.xml according to
          >Java servlet 2.2 API didn't work in Weblogic server 5.1, tags such as
          ><session-mapping>,
          ><session-timeout> didn't work at all. Is these tags didn't support
          >in
          >5.1?</blockquote>
          ></html>
          >
          

Similar Messages

  • Is there any alternative for adding servlet name in Web.xml?

    Hi,
    I am new to Weblogic and I have an application(Ear file) which was developed
    in Websphere and I am trying to install in weblogic 8.1. I have installed my application
    in Websphere without adding servlet entries in Web.xml and it was working fine.
    I have installed the same Ear file in Tomcat and added the
    following to make all my all servlets work.
    <servlet-mapping>
    <servlet-name>invoker</servlet-name>
    <url-pattern>/servlet/*</url-pattern>
    </servlet-mapping>
    Is there any alternative of doing like that in WebLogic instead of adding each
    and every servlet entry in web.xml because my application has around 200 servlets
    Thanks&Regards,
    Gopi.

    Is Servlet servlet same as weblogic.servlet.ServletServlet?
    Deepak
    Rob Woollen <[email protected]> wrote:
    Yes, you could register weblogic.servlet.ServletServlet.
    -- Rob
    Gopi Krishna wrote:
    Hi,
    I am new to Weblogic and I have an application(Ear file) whichwas developed
    in Websphere and I am trying to install in weblogic 8.1. I have installedmy application
    in Websphere without adding servlet entries in Web.xml and it was workingfine.
    I have installed the same Ear file in Tomcat and added the
    following to make all my all servlets work.
    <servlet-mapping>
    <servlet-name>invoker</servlet-name>
    <url-pattern>/servlet/*</url-pattern>
    </servlet-mapping>
    Is there any alternative of doing like that in WebLogic instead ofadding each
    and every servlet entry in web.xml because my application has around200 servlets
    Thanks&Regards,
    Gopi.

  • How to run java servlet without using Web.xml?

    How to run servlet without using Web.xml? From a book, I know that web.xml descriptor is optional, but the book doesn't tell us how to run java servelet without web.xm descriptor. So how to do that? Thanks a lot.

    How to run servlet without using Web.xml?But Tomcat now uses a web.xml for its global server-wide configuration.
    If you'd like to invoke a servlet with:
    http://host/servlet/ServletName
    you have to enable the invoker servlet.
    [from an HTML]
      <FORM METHOD="POST" ACTION="/servlet/HGrepSearchSJ">
    [from resin.conf of Resin Web Server 2.1.12]
      <!--
         - The "invoker" servlet invokes servlet classes from the URL.
         - /examples/basic/servlet/HelloServlet will start the HelloServlet
         - class.  In general, the invoker should only be used
         - for development, not on a deployment server, because it might
         - leave open security holes.
        -->
      <servlet-mapping url-pattern='/servlet/*' servlet-name='invoker'/>
    [from TOMCAT5.0.19/conf/web.xml, a global server-wide web.xml file]
      <!-- The "invoker" servlet, which executes anonymous servlet classes      -->
      <!-- that have not been defined in a web.xml file.  Traditionally, this   -->
      <!-- servlet is mapped to URL pattern "/servlet/*", but you can map it    -->
      <!-- to other patterns as well.  The extra path info portion of such a    -->
      <!-- request must be the fully qualified class name of a Java class that  -->
      <!-- implements Servlet (or extends HttpServlet), or the servlet name     -->
      <!-- of an existing servlet definition.     This servlet supports the     -->
      <!-- following initialization parameters (default values are in square    -->
      <!-- brackets):                                                           -->
      <!--                                                                      -->
      <!--   debug               Debugging detail level for messages logged     -->
      <!--                       by this servlet.  [0]                          -->
        <servlet>
            <servlet-name>invoker</servlet-name>
            <servlet-class>
              org.apache.catalina.servlets.InvokerServlet
            </servlet-class>
            <init-param>
                <param-name>debug</param-name>
                <param-value>0</param-value>
            </init-param>
            <load-on-startup>2</load-on-startup>
        </servlet>
    ---comment out below----------------------------------------------------------
        <!-- The mapping for the invoker servlet -->
    <!--
        <servlet-mapping>
            <servlet-name>invoker</servlet-name>
            <url-pattern>/servlet/*</url-pattern>
        </servlet-mapping>
    -->

  • Order of servlet mapping in web.xml

    Hello,
    is the order of multiple <servlet-mapping> in web.xml important? Or it doesn't matter in which order they are declared?
    For example, if i have two controllers, one is
    <servlet-name>Faces Servlet</servlet-name>
      <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
      <load-on-startup>1</load-on-startup>
    </servlet>
    and the second:
      <servlet>
        <servlet-name>FrontController</servlet-name>
        <servlet-class>servlets.FrontController</servlet-class>
      </servlet>
    and the mapping are:
       <servlet-mapping>
        <servlet-name>FrontController</servlet-name>
        <url-pattern>/jsf/*</url-pattern>
      </servlet-mapping>
    <servlet-mapping>
        <servlet-name>Faces Servlet</servlet-name>
        <url-pattern>*.jsf</url-pattern>
      </servlet-mapping>where /jsf/ contains jsp pages containing jsf components.
    is the order important?
    And may second question is:
    if i call the jsp page test.jsf in /jsf/test.jsp , which controller is responseble? Faces servlet or Frontcontroller?

    Here is what the 2.4 specification says on the matter (section SRV.11.1):
    >
    The path used for mapping to a servlet is the request URL from the request
    object minus the context path and the path parameters. The URL path mapping rules below are used in order. The first successful match is used with no further matches attempted:
    1. The container will try to find an exact match of the path of the request to the
    path of the servlet. A successful match selects the servlet.
    2. The container will recursively try to match the longest path-prefix. This is done by stepping down the path tree a directory at a time, using the �/� character as a path separator. The longest match determines the servlet selected.
    3. If the last segment in the URL path contains an extension (e.g. .jsp), the servlet container will try to match a servlet that handles requests for the extension. An extension is defined as the part of the last segment after the last �.� character.
    4. If neither of the previous three rules result in a servlet match, the container will attempt to serve content appropriate for the resource requested. If a "default" servlet is defined for the application, it will be used.
    The container must use case-sensitive string comparisons for matching.
    It also notes that in prior versions of the specification these were only a suggestion so if you are on servlet 2.3 or prior, you need to consult the documentation for your container.
    So, to answer your questions, no, order in the descriptor is not important.
    Also, based on the rules above, using your mappings, any URL starting with /jsf will be handled by FrontController including /jsf/test.jsp and /jsf/test.jsf.

  • Servlet mappings in web.xml is not picking up propelry

    Hi,
    I am developing on java web application in Jdeveloper and trying to deploy in integrated wls.
    i have one jsp page, and one java servlet. and added url-pattern and servlet mappings in web.xml, but when running the jsp, it is not picking up the servelt . I am getting the error saying 'The server has not found anything matching the Request-URI.'
    Can you help me in fixing this issue.
    Thanks in advance.

    Hi,
    I have one Test.html file under public_html folder, and in that html form action url is as below:
    <form action="/servlet/testServlet" method="post">
    .</form>
    and my web.xml content is:
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    version="2.5" xmlns="http://java.sun.com/xml/ns/javaee">
    <servlet>
    <display-name>TestServlet</display-name>
    <servlet-name>TestServlet</servlet-name>
    <servlet-class>oracle.apps.servlet.TestServlet</servlet-class>
    </servlet>
    <servlet-mapping>
    <servlet-name>TestServlet</servlet-name>
    <url-pattern>/servlet/testServlet</url-pattern>
    </servlet-mapping>
    </web-app>
    When i run the HTML page, the URL is : http://local:7101/Application1-Test-context-root/Test.html
    and when click on button, its redirecting to http://local:7101/servlet/testServlet and getting the error saying that 'The server has not found anything matching the Request-URI' ideally it shuld redirect to http://local:7101/Application1-Test-context-root/servlet/testServlet.
    let me know what could be the problem?

  • Weblogic.servlet.reloadCheckSecs in web.xml not working

    Given the following web.xml file:
              <!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application
              1.2//EN" "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd">
              <web-app>
              <context-param>
              <param-name>weblogic.servlet.reloadCheckSecs</param-name>
              <param-value>100</param-value>
              </context-param>
              <servlet>
              <servlet-name>CookieCounter</servlet-name>
              <servlet-class>servlets.CookieCounter</servlet-class>
              </servlet>
              <servlet-mapping>
              <servlet-name>CookieCounter</servlet-name>
              <url-pattern>monster</url-pattern>
              </servlet-mapping>
              <welcome-file-list>
              <welcome-file>hello.html</welcome-file>
              </welcome-file-list>
              <error-page>
              <error-code>404</error-code>
              <location>/error.jsp</location>
              </error-page>
              </web-app>
              It seems the weblogic.servlet.reloadCheckSecs property is not taking effect.
              The
              default value of -1 is always used. I did stop and restart weblogic.
              I also trid to set the servlet classpath in the web.xml file with
              weblogic.servlet.classpath
              property and it did not change the classpath for the servlet. It seems that
              other
              items are working such as adding new servletrs to the web application. Note
              that
              this is the cookie sample application that installes with the beta 2
              download.
              Thanks,
              Dan.
              

    Hi All:
    Thanks for all your help regarding the adfAuthentication success_url. Now I am able to configure to make this work. But now I am facing another issue i.e. I am getting 401 Not authorized message when the success_url is pointed to the jspx page.
    Note: I am using custom login module similar to DBProcOraDataSourceLoginModule so my roles are stored in the custom Role class. So I am not sure how to pass this role info to the security in ADF in order to authorize the page to be viewed.
    Could you please help and can you point me to any specific link.
    Thanks & Regards
    Sridhar Doki

  • Servlet registration in web.xml with weblogic 5.1 sp10

    I've been developing this site using one "dispatch"
              servlet as my traffic cop for my framework. i now
              have to do this charting thing and i plan to
              stream in an image from a servlet. this means adding
              another servlet to the application. i've edited the
              web.xml according to the standerd and WL still pukes
              on startup saying
              "Error parsing descriptor in Web application
              'c:/workspace/com/somthing/'
              org.xml.sax.SAXParseException: Element "web-app" does
              not allow "servlet" here."
              below is my web.xml file...
              <?xml version="1.0" encoding="ISO-8859-1"?>
              <!DOCTYPE web-app
              PUBLIC "-//Sun Microsystems, Inc.//DTD Web
              Application 2.2//EN"
              "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd">
              <web-app>
              <description>
              blah blah
              </description>
              <servlet>
              <servlet-name>
              WebDispatcher
              </servlet-name>
              <servlet-class>
              com.somthing.somthin.WebDispatcher
              </servlet-class>
              </servlet>
              <servlet-mapping>
              <servlet-name>
              WebDispatcher
              </servlet-name>
              <url-pattern>
              /dispatch
              </url-pattern>
              </servlet-mapping>
              <servlet>
              <servlet-name>
              AssetChartServlet
              </servlet-name>
              <servlet-class>
              com.something.somthn.charts.ChartServlet
              </servlet-class>
              </servlet>
              <servlet-mapping>
              <servlet-name>
              ChartServlet
              </servlet-name>
              <url-pattern>
              /Chart
              </url-pattern>
              </servlet-mapping>
              some jsp tags
              </web-app>
              What am I doing wrong? Do I have to register the
              servlet in the weblogic.properties file? If so do I add the line
              weblogic.httpd.register.chart=com.somthing.somthin.charts.ChartServlet
              And the the (local)url would be http://localhost:7001/Chart ? And if
              this is the case where/how do I do the url mapping bit for this?
              Any help would be greatly appreciated.
              thanks,
              -Gabe
              

    To answer Mike's follow-up question, yes. From the DTD for the web.xml
              file:
              <!ELEMENT web-app (icon?, display-name?, description?, distributable?,
              context-param*, servlet*, servlet-mapping*, session-config?,
              mime-mapping*, welcome-file-list?, error-page*, taglib*,
              resource-ref*, security-constraint*, login-config?, security-role*,
              env-entry*, ejb-ref*)>
              The ordering of elements must be followed if they are specified in the DTD.
              Move your first <servlet-mapping> element to after the second <servlet>
              element and it should work just fine.
              -chris
              "Mike Reiche" <[email protected]> wrote in message
              news:[email protected]...
              >
              >
              >
              > Hmmm... do all the <servlet> </servlet> need to come before all the
              <servlet-mapping>
              > ?
              >
              > Mike
              >
              >
              > [email protected] (gabe) wrote:
              > >I've been developing this site using one "dispatch"
              > >servlet as my traffic cop for my framework. i now
              > >have to do this charting thing and i plan to
              > >stream in an image from a servlet. this means adding
              > >another servlet to the application. i've edited the
              > >web.xml according to the standerd and WL still pukes
              > >on startup saying
              > >
              > >"Error parsing descriptor in Web application
              > >'c:/workspace/com/somthing/'
              > >org.xml.sax.SAXParseException: Element "web-app" does
              > >not allow "servlet" here."
              > >
              > >below is my web.xml file...
              > >------------------------------
              > >
              > ><?xml version="1.0" encoding="ISO-8859-1"?>
              > >
              > ><!DOCTYPE web-app
              > > PUBLIC "-//Sun Microsystems, Inc.//DTD Web
              > >Application 2.2//EN"
              > > "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd">
              > >
              > ><web-app>
              > >
              > > <description>
              > > blah blah
              > > </description>
              > >
              > > <servlet>
              > > <servlet-name>
              > > WebDispatcher
              > > </servlet-name>
              > > <servlet-class>
              > > com.somthing.somthin.WebDispatcher
              > > </servlet-class>
              > > </servlet>
              > > <servlet-mapping>
              > > <servlet-name>
              > > WebDispatcher
              > > </servlet-name>
              > > <url-pattern>
              > > /dispatch
              > > </url-pattern>
              > > </servlet-mapping>
              > >
              > > <servlet>
              > > <servlet-name>
              > > AssetChartServlet
              > > </servlet-name>
              > > <servlet-class>
              > > com.something.somthn.charts.ChartServlet
              > > </servlet-class>
              > > </servlet>
              > > <servlet-mapping>
              > > <servlet-name>
              > > ChartServlet
              > > </servlet-name>
              > > <url-pattern>
              > > /Chart
              > > </url-pattern>
              > > </servlet-mapping>
              > >
              > > ...
              > > some jsp tags
              > > ...
              > >
              > ></web-app>
              > >---------------------------------
              > >What am I doing wrong? Do I have to register the
              > >servlet in the weblogic.properties file? If so do I add the line
              > >
              > >weblogic.httpd.register.chart=com.somthing.somthin.charts.ChartServlet
              > >
              > >And the the (local)url would be http://localhost:7001/Chart ? And if
              > >this is the case where/how do I do the url mapping bit for this?
              > >
              > >Any help would be greatly appreciated.
              > >
              > >thanks,
              > >
              > >-Gabe
              >
              

  • Can i run a servlet without a web.xml file for servlet mapping?

    Hello everyone.
    The code i want to run compiles and everythink looks ok.
    It produces the .class file.
    I run Tomcat 4.1 and i build my Web site with Dreamweaver.
    I have a form in a page and i want to send the data upon form completion to a database i already have build with MySql.
    The database is up and running and the server is set-up ok.
    I have changed the port in Tomcat to run on port 80.
    The directory i have my site is
    Tomcat41\webapps\ROOT\se
    and the directory where i keep the servlet class is
    Tomcat41\webapps\ROOT\se\WEB-INF\servlet
    I have a web.xml file to map the servlet and placed it in
    Tomcat41\webapps\ROOT\se\WEB-INF
    In the Form action i write action:"/servlets/Classes/GroupRegistration"
    and I RECEIVE AN 404 ERROR FROM APACHE.
    Somethink is wrong .
    The following is the code from the GroupRegistration.java file
    and follws the web.xml file.
    Please Help.
    import java.sql.*;
    import java.io.*;
    import javax.servlet.*;
    import javax.servlet.http.*;
    public class GroupRegistration extends HttpServlet
    Connection con;
    public void doPost (HttpServletRequest req, HttpServletResponse res)
                             throws ServletException, java.io.IOException
         handleForm(req, res);
    public void init() throws ServletException {
         try{
         /* Loading the driver for the database */
         Class.forName("com.mysql.jdbc.Driver");
         Connection Con = DriverManager.getConnection("jdbc:mysql://localhost/se?user=luser&password=");
         catch (ClassNotFoundException e) {
         throw new UnavailableException("Couldn't load JdbcOdbcDriver");
         catch (SQLException e) {
         throw new UnavailableException("Couldn't get db connection");
         private void handleForm(HttpServletRequest req, HttpServletResponse res)
         throws ServletException {
         //ServletOutputStream out = res.OutputStream();
         //res.setContentType("text/html");
         //Extract the form Data Here
         String group = req.getParameter("GroupNo");
         String Name1 = req.getParameter("Name1");
         String LoginID1 = req.getParameter("LoginID1");
         String Name2 = req.getParameter("Name2");
         String LoginID2 = req.getParameter("LoginID2");
         String Name3 = req.getParameter("Name3");
         String LoginID3 = req.getParameter("LoginID3");
         String Name4 = req.getParameter("Name4");
         String LoginID4 = req.getParameter("LoginID4");
         String URL = req.getParameter("URL");
         String Title2 = req.getParameter("Title2");
         String date = req.getParameter("date");
         String INSERT = "INSERT INTO registration (groupno, name1, loginid1, name2, loginid2, name3, loginid3, name4, loginid4, url, topic, date) VALUES (" + group + "," + Name1 + "," + LoginID2 + "," + Name2 + "," + LoginID2 + "," + Name3 + "," + LoginID3 + "," + Name4 + "," + LoginID4 + "," + URL + "," + Title2 + "," + date + ")";
         PreparedStatement pstmt = null;
         try{
         pstmt = con.prepareStatement(INSERT);
         pstmt.executeUpdate();
         catch (SQLException e) {
         throw new ServletException(e);
         finally {
         try {
         if (pstmt != null)pstmt.close();
         catch (SQLException ignored){
    The web.xml file
    <?xml version="1.0" encoding="ISO-8859-1"?>
    <web-app xmlns="http://java.sun.com.xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
    <servlet>
    <servlet-name>GroupRegistration</servlet-name>
    <servlet-class>GroupRegistration</servlet-class>
    </servlet>
    <servlet-maping>
    <servlet-name>GroupRegistration</servlet-name>
    <url-pattern>/myGroupRegistration</url-patern>
    </servlet-mapping>
    </web-app>
    I apreciate your time.
    Thanks for any help.

    and the directory where i keep the servlet class is
    Tomcat41\webapps\ROOT\se\WEB-INF\servletOthers have pointed out that "servlet" should be "classes", but there is another mistake that hasn't been spotted. If you want your servlet to appear in the root context, you should use:
    Tomcat41\webapps\ROOT\WEB-INF\classes
    If you want your servlet to appear under the /se context, then you should use:
    Tomcat41\webapps\se\WEB-INF\classes
    and also, in the latter case, your form action should be /se/myGroupRegistration.

  • JDev 10.1.3 compile error in servlet 2.4 web.xml

    I built a Servlet 2.4/JSP 2.0 application in JDev 10.1.3. When I try to make/compile/deploy it the compiler gives me errors like the following for every JSP file that has a JSTL 1.1 taglib:
    Error(2,9): Element "web-app' used but not declared
    Error(2,63): Attribute 'xmlns:xsi' used but not declared
    Error(3,103): Attribute 'xsi:schemaLocation' used but not declared
    Error(4,16): Attribute 'version' used but not declared
    Error(4,56): Attribute 'xmlns' used but not declared
    Error(4,57): Can not build schema 'http://java.sun.com/xml/ns/j2ee' located at 'http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd'
    Error(5,15): Element 'description used but not declared
    It is obviously havng problems with the web.xml file (which is in the servlet 2.4 format) and is probably not finding the web.xml DTD document. How do I fix it?
    Installation is on Solaris 9 using J2SDK 1.4.2_04-b05
    By the way, this system is on a disconnected network. How do I get JDeveloper updates for a system not connected to the Internet?

    Allen,
    A JSP with web.xml web-app element
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee">
    runs in JDeveloper 10.1.3
    thanks,
    Deepak

  • Do I must put ALL my servlets inside the web.xml file?

    Hello everybody,
    I am trying to migrate from Webshere to TOMCAT a project with severals packets, one of those have 15 servlets and some classes.
    Is there any way to use the servlets without have to declare each one inside the web.xlm file ?
    Thanks in advance.

    All servlet definitions go into web.xml, though not the actual servlets themselves :) . Say if you wanted servlet A to have a different mapping you would define the mapping in web.xml to something other than the standard one.

  • Servlet 2.4 web.xml error - Cant load the Schema

    i have coded the web.xml for my application as below,
    i am using Servlet 2.4 and Tomcat 5.5
    when i viewed the same in XML editor, it gave the following error -
    "Can't Load the W3C XML Schema" , cant figure what is the reason for this error. Any help would be greatly appreciated
    <?xml version="1.0" encoding="UTF-8"?>
    <web-app
    xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
    version="2.4">
         <display-name>Rdp</display-name>
         <servlet>
              <servlet-name>action</servlet-name>
              <servlet-class>com.rdp.util.RDServlet</servlet-class>
              <init-param>
                   <param-name>config</param-name>
                   <param-value>/WEB-INF/config/struts-config.xml</param-value>
              </init-param>
              <init-param>
                   <param-name>debug</param-name>
                   <param-value>2</param-value>
              </init-param>
              <init-param>
                   <param-name>detail</param-name>
                   <param-value>2</param-value>
              </init-param>
              <init-param>
                   <param-name>validate</param-name>
                   <param-value>true</param-value>
              </init-param>
              <init-param>
                   <param-name>programe-name</param-name>
                   <param-value>Rdp</param-value>
              </init-param>
              <init-param>
                   <param-name>application</param-name>
                   <param-value>ApplicationResources</param-value>
              </init-param>                              
              <load-on-startup>2</load-on-startup>
         </servlet>
         <servlet-mapping>
              <servlet-name>action</servlet-name>
              <url-pattern>*.do</url-pattern>
         </servlet-mapping>
         <welcome-file-list>
              <welcome-file>index.html</welcome-file>
              <welcome-file>index.htm</welcome-file>
              <welcome-file>index.jsp</welcome-file>
              <welcome-file>default.html</welcome-file>
              <welcome-file>default.htm</welcome-file>
              <welcome-file>default.jsp</welcome-file>
         </welcome-file-list>
         <taglib>
              <taglib-uri>/WEB-INF/struts-bean.tld</taglib-uri>
              <taglib-location>/WEB-INF/struts-bean.tld</taglib-location>
         </taglib>
         <taglib>
              <taglib-uri>/WEB-INF/struts-html.tld</taglib-uri>
              <taglib-location>/WEB-INF/struts-html.tld</taglib-location>
         </taglib>
         <taglib>
              <taglib-uri>/WEB-INF/struts-logic.tld</taglib-uri>
              <taglib-location>/WEB-INF/struts-logic.tld</taglib-location>
         </taglib>
    </web-app>

    i have coded the web.xml for my application as below,
    i am using Servlet 2.4 and Tomcat 5.5
    when i viewed the same in XML editor, it gave the
    following error -
    "Can't Load the W3C XML Schema" , cant figure what is
    the reason for this error. Any help would be greatly
    appreciated
    <?xml version="1.0" encoding="UTF-8"?>
    <web-app
    xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
    version="2.4">
    <display-name>Rdp</display-name>
         <servlet>
              <servlet-name>action</servlet-name>
              <servlet-class>com.rdp.util.RDServlet</servlet-class
    >
              <init-param>
                   <param-name>config</param-name>
                   <param-value>/WEB-INF/config/struts-config.xml</par
    am-value>
              </init-param>
              <init-param>
                   <param-name>debug</param-name>
                   <param-value>2</param-value>
              </init-param>
              <init-param>
                   <param-name>detail</param-name>
                   <param-value>2</param-value>
              </init-param>
              <init-param>
                   <param-name>validate</param-name>
                   <param-value>true</param-value>
              </init-param>
              <init-param>
                   <param-name>programe-name</param-name>
                   <param-value>Rdp</param-value>
              </init-param>
              <init-param>
                   <param-name>application</param-name>
                   <param-value>ApplicationResources</param-value>
              </init-param>                              
              <load-on-startup>2</load-on-startup>
         </servlet>
         <servlet-mapping>
              <servlet-name>action</servlet-name>
              <url-pattern>*.do</url-pattern>
         </servlet-mapping>
         <welcome-file-list>
              <welcome-file>index.html</welcome-file>
              <welcome-file>index.htm</welcome-file>
              <welcome-file>index.jsp</welcome-file>
              <welcome-file>default.html</welcome-file>
              <welcome-file>default.htm</welcome-file>
              <welcome-file>default.jsp</welcome-file>
         </welcome-file-list>
         <taglib>
              <taglib-uri>/WEB-INF/struts-bean.tld</taglib-uri>
              <taglib-location>/WEB-INF/struts-bean.tld</taglib-lo
    cation>
         </taglib>
         <taglib>
              <taglib-uri>/WEB-INF/struts-html.tld</taglib-uri>
              <taglib-location>/WEB-INF/struts-html.tld</taglib-lo
    cation>
         </taglib>
         <taglib>
              <taglib-uri>/WEB-INF/struts-logic.tld</taglib-uri>
              <taglib-location>/WEB-INF/struts-logic.tld</taglib-l
    ocation>
         </taglib>
    </web-app>
    <?xml version="1.0" encoding="UTF-8"?>
    <web-app xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee web-app_2_4.xsd"
    version="2.4">
    It looks the schema specified in your application is slightly different or wrong.
    Please correct it !!

  • Adding servlet entry in web.xml of j2ee engine

    Hi ,
    I want a servlet to be loaded on startup of the j2ee engine SAP WAS which is basically flex based (MessageBrokerServlet). 
    The init param for the servlet is not accessible or cannot be initialized in init method of the servlet using the servletconfig object.
    This is when the servlet is used as a portal component of type servlet.
    So as to load the servlet and the servlet being able to access the init param i would be changing the web.xml of the sap j2ee engine (NW CE 7.1). are there any other effects of the same or is it fine if i just add this param in the web.xml
        <servlet>
            <servlet-name>MessageBrokerServlet</servlet-name>
            <display-name>MessageBrokerServlet</display-name>
            <servlet-class>flex.messaging.MessageBrokerServlet</servlet-class>
            <init-param>
                <param-name>services.configuration.file</param-name>
                <param-value>/WEB-INF/flex/services-config.xml</param-value>
           </init-param>
            <load-on-startup>1</load-on-startup>
        </servlet>

    Hi ,
    Vivek in case my servlet is part of the Portal Application as PortalComponent how do i define init parameters  that can be accessed in the servlet.
    The config file would be accessed in the init method of the servlet how do i do that when the servlet is added as PortalComponent in PortalApplication. The servlet config file needs to accessed in t he init method.
    The load on startup thing would be taken care of by setting parameter startup = true of application properties.
    Regards
    Srikumar V

  • Weblogic 10 jaas and login.jsp and web.xml/weblogic.xml security constaints

    Hello,
    I struggled through and got the examples.security.jaas.SampleCallbackHandler.java and examples.common.utils.ExampleUtils.java/ExampleConstants.java into eclipse where they compile. A bean I made can call SambleCallbackHandler like such:
    mybean.logmein(username,password,url). I can then do a mybean.getStatus() or even a mybean.returnCode(). It does seem to correctly identlify that it is authenticating me (I see in stdout logs that it shows success or failures. The problem I have is I do not know how to apply this weblogic and web.xml/weblogic.xml so that if authentication works it redirects me to the page requiring the authentication. In web.xml I have the following set up:
    <security-role>
         <role-name>Admins</role-name>
    </security-role>
    <login-config>
         <auth-method>FORM</auth-method>
         <realm-name>default</realm-name>
         <form-login-config>
              <form-login-page>/login.jsp</form-login-page>
              <form-error-page>/badlogin.html</form-error-page>
         </form-login-config>
    </login-config>
    <security-constraint>
         <web-resource-collection>
              <web-resource-name>empower</web-resource-name>
              <description>These pages are only accessible by authorized users.</description>
              <url-pattern>/admin/*</url-pattern>
              <http-method>GET</http-method>
              <http-method>POST</http-method>
         </web-resource-collection>
    <auth-constraint>
    <description>These are the roles who have access</description>
    <role-name>Administrators</role-name>
    </auth-constraint>
         <user-data-constraint>
         <description>This is how the user data must be transmitted</description>
         <transport-guarantee>NONE</transport-guarantee>
         </user-data-constraint>
    </security-constraint>
    My weblogic.xml has:
    <?xml version="1.0" encoding="UTF-8"?>
    <wls:weblogic-web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:wls="http://www.bea.com/ns/weblogic/90" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd http://www.bea.com/ns/weblogic/90 http://www.bea.com/ns/weblogic/90/weblogic-web-app.xsd">
    <wls:security-role-assignment>
    <wls:role-name>Admins</wls:role-name>
    <wls:principal-name>Administrators</wls:principal-name>
    <wls:principal-name>dashap</wls:principal-name>
    </wls:security-role-assignment>
    </wls:weblogic-web-app>
    With this set up, if I try to go to a page in /admin folder in my application, it correctly pops up the login page. The jaas in the bean is doing a loginContext.login(), which I thought does authentication too, but it never goes back to the /admin page I was going to that needed the authentication. With jaas, can I not use the web.xml FORM security option? Do I Need to use j_security in the login.jsp's form's action= option and j_username and j_password for the input type names? How do I use j_username/j_password things if I am using jaas? I could just ignore using the web.xml security stuff and put something in the pages that need authentication, but it would be easier if I could use jaas with the security featurs without doing all that. Note that my code above is using a realm called default just because that was what was in the example I got from the web. Does that need to be something else?

    Hi John,
    I would like magic of course. However, in this case I want something special: my authentication provider uses special means and contents of headers, cookies and service from external identity management systems to determine the user's identity.
    I do not want the application to present the login dialog! I want to derive the identity and the fact that the user is logged in from whatever the authentication provider returns in terms of Subject.
    Ideally, the flow is something like:
    - user accesses an unprotected resource - resource is shown, no interaction with authentication provider
    - user presses a link or button that takes him/her to a protected resource
    - the authentication provider is contacted to work with the identity asserter to establish the identity of the current user and create a subject object for this user
    - the application can access the subject and principals
    - ADF Security recognizes the identity and the roles (based on the principals) and coordinates access based on this.
    the authentication method is client certificate. presumably this prompts WebLogic/OPS to use an identity asserter to work with custom headers and cookies ("... when you configure a web application to use CLIENT-CERT authentication. In this case, WebLogic can perform identity assertion based on values from request headers and cookies. If the header name or cookie name matches the active token type for the provider, the value is passed to the provider."). No login form should be presented to the user, as all information required to perform the authentication is already available.
    I am trying to understand what I must do to have the ADF application adopt the subject set by the authentication provider - if anything?!
    If you more ideas to share - I would love to hear them.
    best regards,
    Lucas

  • Servlet parameters in web.xml file

    Hi Guys
    What is ctx:dynamo: in web.xml why we have to use this one in servlet parameters
    Please give me a clear picture on this
    <init-param>
        <param-name>jumpServlet</param-name>
        <param-value>
          ctx:dynamo:/atg/dynamo/servlet/dafpipeline/JumpServlet
        </param-value>
      </init-param>

    Hi Guys
    What is ctx:dynamo: in web.xml why we have to use this one in servlet parameters
    Please give me a clear picture on this
    <init-param>
        <param-name>jumpServlet</param-name>
        <param-value>
          ctx:dynamo:/atg/dynamo/servlet/dafpipeline/JumpServlet
        </param-value>
      </init-param>

  • JSP Servlet Mapping  in web.xml

    Hi!
    I have a JSP page by name "ContactUs.jsp" located in the folder <root>/jsp/info and I am using Tomcat Server. As I want to access this file using the URL "http://localhost:8080/<webapp>/ContactUs.jsp" instead of "http://localhost:8080/<webapp>/jsp/info/ContactUs.jsp". For this I added the follwing lines to web.xml file of my web app.
    <servlet>
    <servlet-name>org.apache.jsp.jsp.info.ContactUs_jsp</servlet-name>
    <servlet-class>org.apache.jsp.jsp.info.ContactUs_jsp</servlet-class>
    </servlet>
    <servlet-mapping>
    <servlet-name>org.apache.jsp.jsp.info.ContactUs_jsp</servlet-name>
    <url-pattern>/ContactUs.jsp</url-pattern>
    </servlet-mapping>
    But I am getting the error saying that
    "ClassNotFoundException: org.apache.jsp.jsp.info.ContactUs_jsp"
    Is there any thing else to be modified? Please help me.
    Thanks in advance
    Geethanadh.K

    I'm no expert on this but I have a hunch. 1st of all, your using a servlet mapping for a JSP. That's good and well but it seems that the container is complaining that there is no servlet named org.apache.jsp.jsp.info.ContactUs_jsp. In other words it looks like the JSP has not been compiled. At least not yet. Maybe try two things. Visit the JSP once with a browser at it's actual path "http://localhost:8080/<webapp>/jsp/info/ContactUs.jsp" the coerce a page compile. Then try it with your new mapped path. You see, just telling the container that there is a servlet mapped to the new URL doesn't force the container to generate the class. Something or someone must generate the servlet class file.
    Honestly, I'm not sure of what your end goal is but maybe you might consider using a JSP pre-compiler? Or even better, register a servlet at the mapped path that fowards all requests into the desired folder.
    Cliff

Maybe you are looking for