Doubts about Thread

Question

Hi Friends,
I am a beginner in Java.So plz excuse for my ignorance.
Qa .1. Extending the Thread class**
public class BasicThread1 extends Thread {
public void run() {
//........My code
public class Main extends Thread {
public static void main(string... arg){
Thread thread = new BasicThread1();
thread.start();
How run method invokes while calling thread.start(); ?
QA 2. Implement the Runnable interface**
public class BasicThread2 implements Runnable {
public void run() {
public class Main{
public static void main(string... arg){
Runnable runnable = new BasicThread2();
Thread thread = new Thread(runnable);
thread.start();
How run method invokes while calling thread.start(); ?
Thanks

Answer 1

Dinil wrote:
In Thread class start method shows
public synchronized void start() {
       This method is not invoked for the main method thread or "system"
       group threads created/set up by the VM. Any new functionality added
       to this method in the future may have to also be added to the VM.
       A zero status value corresponds to state "NEW".
if (threadStatus != 0)
throw new IllegalThreadStateException();
group.add(this);
start0();
if (stopBeforeStart) {
         stop0(throwableFromStop);
private native void start0();I am invoking start method without parameters ( Thread.start();)
Then how run() method invokes from start() ?That is the magic that happens in the native start0() method.