Drop down menu not appearing right

Question

Hi
i have a dynamic drop down menu on one of my site pages (
http://www.mantle.co.uk/investment.php?ID=1),
the menu optionss are appearing outside of the menu?
i cannot see why,
below is my code:
<form action="<?php print $_SERVER['PHP_SELF'];?>"
method="get">
<label for="menu"></label>
<select name="ID" class="dropdown" id="menu"
onchange="this.form.submit()">
<noscript><input type="submit" value="Go"
/></noscript>
<option value="" selected="selected">Jump To Another
Project</option>
<?php
do {
?>
<option value="<?php echo
$row_rsOtherDevs['devID']?>"><?php echo
$row_rsOtherDevs['title']?></option>
<?php
} while ($row_rsOtherDevs = mysql_fetch_assoc($rsOtherDevs));
$rows = mysql_num_rows($rsOtherDevs);
if($rows > 0) {
mysql_data_seek($rsOtherDevs, 0);
$row_rsOtherDevs = mysql_fetch_assoc($rsOtherDevs);
?>
</select>
</form>
please could you help me!

Answer 1

On Tue, 28 Nov 2006 11:38:59 +0000 (UTC), "Kamesh192"
<[email protected]> wrote:
> <form action="<?php print
$_SERVER['PHP_SELF'];?>" method="get">
> <label for="menu"></label>
>
> <select name="ID" class="dropdown" id="menu"
onchange="this.form.submit()">
> <noscript><input type="submit" value="Go"
/></noscript>
> <option value="" selected="selected">Jump To
Another Project</option>
> <?php
> do {
> ?>
> <option value="<?php echo
$row_rsOtherDevs['devID']?>"><?php echo
>$row_rsOtherDevs['title']?></option>
> <?php
> } while ($row_rsOtherDevs =
mysql_fetch_assoc($rsOtherDevs));
> $rows = mysql_num_rows($rsOtherDevs);
> if($rows > 0) {
> mysql_data_seek($rsOtherDevs, 0);
> $row_rsOtherDevs = mysql_fetch_assoc($rsOtherDevs);
> }
> ?>
>
> </select>
> </form>
Change the above to:
<form action="<?php print $_SERVER['PHP_SELF'];?>"
method="get">
<select name="ID" class="dropdown" id="menu"
onchange="this.form.submit()">
<option value="" selected="selected">Jump To Another
Project</option>
<?php
do {
?>
<option value="<?php echo
$row_rsOtherDevs['devID']?>"><?php echo
$row_rsOtherDevs['title']?></option>
<?php
} while ($row_rsOtherDevs =
mysql_fetch_assoc($rsOtherDevs));
$rows = mysql_num_rows($rsOtherDevs);
if($rows > 0) {
mysql_data_seek($rsOtherDevs, 0);
$row_rsOtherDevs = mysql_fetch_assoc($rsOtherDevs);
?>
</select>
<noscript><input type="submit" value="Go"
/></noscript>
</form>
Gary