Duplicate rows from DB adapter
Ok this is a weird one.
I have a query that is working off the DB adapter, and it is querying for multiple rows. The row count is correct. However every single row is a duplicate of the first one. It is coming out this way because when i view the trace I can see this as the output from my partner link.
Any idea why this would be? Alternatively, is there a way to view the SQL that is being sent?
Message was edited by:
alan.delimon
Hi Alan,
This sounds like a possible primary key issue. Does your table have composite primary key (not necessarily defined as PK in the database but a logical PK). If so, is this PK defined also in the adapter?
This issue could exist if each row is unique by the combination of more than one field, but the adapter descriptor only defines the PK is a single field.
hth,
~ronen
Similar Messages
-
How to update duplicate row from table
Hi,
how to update duplicate row from table?
First to find duplicate row then update duplicate row with no to that duplicate row in oracle.
can you give me suggestion on it?
Thanks in advance.
your early response is appreciated...In order to find a duplicate row, see:
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:1224636375004
(or search this forum, your question has been asked before)
In order to update it, just create and use an Oracle sequence, have it start and increment at a value that doesn't exist in your table.
If that doesn't get you going, post some CREATE TABLE + INSERT INTO statements, and the results you want from them, in other words: a complete testcase. -
First attempt to remove duplicate rows from a table...
I have seen many people asking for a way to remove duplicate rows from data. I made up a fairly simple script. It adds a column to the table with the cell selected in it, and adds the concatenation of the data to the left into that new column. then it reads that into a list, and walks through that list to find any that are listed twice. Any that are it marks for DELETE.
It then walks through to find each one marked for delete and removes them (you must go from bottom to top to do this, otherwise your row markings for delete don't match up to the original rows anymore). Last is to delete the column we added.
tell application "Numbers"
activate
tell document 1
-- DETERMINE THE CURRENT SHEET
set currentsheetindex to 0
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of (tables whose selection range is not missing value)
end tell
if x is not 0 then
set the currentsheetindex to i
exit repeat
end if
end repeat
if the currentsheetindex is 0 then error "No sheet has a selected table."
-- GET THE TABLE WITH CELLS
tell sheet currentsheetindex
set the current_table to the first table whose selection range is not missing value
end tell
end tell
log current_table
tell current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
repeat with i from 1 to (z - 1)
set m to m & value of (cell i of row j)
end repeat
set value of cell z of row j to m
end repeat
set MyRange to value of every cell of column z
repeat with i from 1 to (count of items of MyRange)
set n to item i of MyRange
if n is in list1 then
set end of list1 to "Delete"
else
set end of list1 to n
end if
end repeat
repeat with i from (count of items of list1) to 1 by -1
set n to item i of list1
if n = "Delete" then remove row i
end repeat
remove column z
end tell
end tell
Let me know how it works for y'all, it worked good on my machine, but I know localization is causing errors sometimes when I post things.
Thanks,
Jason
Message was edited by: jaxjasonHi jason
I hope that with the added comments it will be clear.
Ask if something is always opaque.
set {current_Range, current_table, current_Sheet, current_Doc} to my getSelection()
tell application "Numbers09"
tell document current_Doc to tell sheet current_Sheet to tell table current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
tell row j
repeat with i from 1 to (z - 1)
set m to m & value of cell i
end repeat
set value of cell z to m
end tell
end repeat
set theRange to value of every cell of column z
repeat with i from (count of items of theRange) to 1 by -1
(* As I scan the table backwards (starting from the bottom row),
I may remove a row immediately when I discover that it is a duplicate *)
set n to item i of theRange
if n is in list1 then
remove row i
else
set end of list1 to n
end if
end repeat
remove column z
end tell
end tell
--=====
on getSelection()
local _, theRange, theTable, theSheet, theDoc, errMsg, errNum
tell application "Numbers09" to tell document 1
set theSheet to ""
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of tables
if x > 0 then
repeat with y from 1 to x
(* Open a trap to catch the selection range.
The structure of this item
«class
can't be coerced as text.
So, when the instruction (selection range of table y) as text
receive 'missing value' it behaves correctly and the lup continue.
But, when it receive THE true selection range, it generates an error
whose message is errMsg and number is errNum.
We grab them just after the on error instruction *)
try
(selection range of table y) as text
on error errMsg number errNum (*
As we reached THE selection range, we are here.
We grab the errMsg here. In French it looks like:
"Impossible de transformer «class
The handler cuts it in pieces using quots as delimiters.
item 1 (_) "Impossible de transformer «class » "
item 2 (theRange) "A2:M25"
item 3 (_) " of «class NmTb» "
item 4 (theTable) "Tableau 1"
item 5 (_) " of «class NmSh» "
item 6 (theSheet) "Feuille 1"
item 7 (_) " of document "
item 8 (theDoc) "Sans titre"
item 9 ( I drop it ) " of application "
item 10 ( I drop it ) "Numbers"
item 11 (I drop it ) " en type string."
I grab these items in the list
{_, theRange, _, theTable, _, theSheet, _, theDoc}
Yes, underscore is a valid name of variable.
I often uses it when I want to drop something.
An alternate way would be to code:
set ll to my decoupe(errMsg, quote)
set theRange to item 2 of ll
set theTable to item 4 of ll
set theSheet to item 8 of ll
set theDoc to item 10 of ll
it works exactly the same but it's not so elegant.
set {_, theRange, _, theTable, _, theSheet, _, theDoc} to my decoupe(errMsg, quote)
exit repeat (*
as we grabbed the interesting datas, we exit the lup indexed by y.*)
end try
end repeat -- y
if theSheet > "" then exit repeat (*
If we are here after grabbing the datas, theSheet is not "" so we exit the lup indexed by i *)
end if
end tell -- sheet
end repeat -- i
(* We may arrive here with two kinds of results.
if we grabbed a selection, theSheet is something like "Feuille 1"
if we didn't grabbed a selection, theSheet is the "" defined on entry
and we generate an error which is not trapped so it stops the program *)
if theSheet = "" then error "No sheet has a selected table."
end tell -- document
(* Now, we send to the caller the interesting datas :
theRange "A2:M25"
theTable "Tableau 1"
theSheet "Feuille 1"
theDoc "Sans titre" *)
return {theRange, theTable, theSheet, theDoc}
end getSelection
--=====
on decoupe(t, d)
local l
set AppleScript's text item delimiters to d (*
Cut the text t in pieces using d as delimiter *)
set l to text items of t
set AppleScript's text item delimiters to "" (*
Resets the delimiters to the standard value. *)
(* Send the list to the caller *)
return l
end decoupe
--=====
Have fun
And if it's not clear enough, you may ask for more explanations.
Yvan KOENIG (from FRANCE mardi 27 janvier 2009 21:49:19) -
i have a table A suppose it has 3 columns
id name sal
==========
1 A 100
1 A 100
2 B 200
2 B 200
2 B 200
3 C 300
I want to find duplicate rows from the above table without passing any column in to the where clause .
please help me to find out this query.maybe you should try the database forum...
-
Identifying and reporting Duplicate rows from table
I want to fetch all the duplicate row from the table and need to report all of it.
I am trying to run the below query but and not getting the expected output. Please help me.
Query
SELECT * FROM ADDT_RPT_REQ A WHERE
TRIM(A.EMAIL_ADDR) IN
(SELECT TRIM(EMAIL_ADDR) FROM ADDT_RPT_REQ B
WHERE TRIM(B.EMAIL_ADDR) = TRIM(A.EMAIL_ADDR)
AND A.ph_num IN
(SELECT PH_NUM FROM ADDT_RPT_REQ B
WHERE TRIM(A.PH_NUM ) = TRIM(B.PH_NUM)
There are in all 7 columns in the table where id is Unique Id.
The expected output is something like.
FST_NAME LAST_NAME EMAIL_ADDR WORK_PH_NUM ROW_ID LAST_UPD BU_ID
VALERIE HALL [email protected] 7819370177 2-21N-4312 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4327 29-JAN-04 0-R9NH
VALERIE HALL [email protected] 6034272034 2-21N-4309 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4317 04-APR-03 0-R9NH
VALERIE HALL [email protected] 8563748820 2-21N-4329 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4319 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4326 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4324 04-APR-03 0-R9NH
VALERIE HALL [email protected] 8604237395 2-21N-4330 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373731 2-21N-4314 31-AUG-04 0-R9NH
VALERIE HALLORAN [email protected] 6194771101 2-21N-4331 31-OCT-05 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4316 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4321 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 7-1W4N-293 15-MAY-04 0-R9NH
VALERIE HALL [email protected] 2032341604 2-21N-4307 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4325 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4315 29-JAN-03 0-R9NH
VALERIE HALL [email protected] 7819373737 7-1W4N-291 15-MAY-04 0-R9NH
VALERIE HALLORAN [email protected] 6194771101 2-21N-4332 31-OCT-05 0-R9NH
VALERIE HALL [email protected] 6038885349 2-21N-4310 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373737324 2-21N-4328 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819370177324 2-21N-4313 31-AUG-04 0-R9NHHi again!
Try that:
SELECT rowid, fst_name, last_name, email_addr, work_ph_num, row_id, last_upd, bu_id
FROM ADDT_RPT_REQ A
WHERE rowid > (SELECT MIN(rowid)
FROM ADDT_RPT_REQ B
WHERE B.fst_name = A.fst_name
AND B.last_name = A.last_name
AND B.email_addr = A.email_addr
AND B.work_ph_num = A.work_ph_num
AND B.row_id = A.row_id
AND B.last_upd = A.last_upd
AND B.bu_id = A.bu_id);This query should show you all duplicate rows. Use the rowid and DELETE to get rid of these rows.
DELETE FROM addt_rpt_req A
WHERE rowid IN (SELECT rowid
FROM (SELECT rowid, row_number() OVER (PARTITION BY fst_name, last_name, email_addr, work_ph_num, row_id, last_upd, bu_id
ORDER BY row_id) dup
FROM addt_rpt_req)
WHERE dup > 1);Yours sincerely
Florian W.
Edited by: Florian W. on 17.06.2009 14:17 -
Removing duplicate rows from SELECT
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For example, given this data:
PC_ID SERIAL_NBR CUSTOMER_NO
1234567 AAA C345
1234567 AAA C567
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only the 1st and 3rd rows would be returned.
Any ideas?Try something like this:
select * from your_table yt
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and yt2.serial_nbr = yt.serial_nbr); -
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Nicolas. -
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Name Null? Type
ROW_ID NOT NULL VARCHAR2(15 CHAR)
LAST_UPD NOT NULL DATE
PAR_ROW_ID NOT NULL VARCHAR2(15 CHAR)
ATTRIB_17 NUMBER(22,7)
ATTRIB_26 DATE
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SQL> select * from customer where rowid != (select min(rowid) from customer C where C.cust_id = customer.cust_id);
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SQL> -
Eliminate duplicate rows from the report 6i output
Hi All,
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Please help me in this ASAP.
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YEAR EM NAME PO
2001 02 Scott 91
2001 02 Scott 01
2001 02 Scott 07
2001 03 Tom 81
2001 03 Tom 84
2001 03 Tom 87
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2 row_number() over (partition by year, empcode, name
3 order by year, empcode, name, position) as rn
4 from employees;
YEAR EM NAME PO RN
2001 02 Scott 01 1
2001 02 Scott 07 2
2001 02 Scott 91 3
2001 03 Tom 81 1
2001 03 Tom 84 2
2001 03 Tom 87 3
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2 From (Select year, empcode, name, position,
3 row_number() over (partition by year, empcode, name
4 order by year, empcode, name, position) as rn
5 From employees) emp
6 Where rn = 1;
YEAR EM NAME PO
2001 02 Scott 01
2001 03 Tom 81
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3 From (Select year, empcode, name, position,
4 rowid as rid,
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Remove Duplicate Rows from Left Outer Join
Hi All,
I am new to Oracle..I have two tables as follow:
TableA(EmpID, Empname)
TableB(EmpID, DeptID, DeptName). A employee can work in multiple dept.
table A has 1 row as EmpID 1 and TableB has two rows for EmpID 1.
I have a search page which takes dept ID as parameter and return employee name...Dept ID is not mandatory feld for Search. If DeptID is passed it should return the employee who belongs to that Dept otherwise it should return 1 employee..
Now I have used as follow:
:IN_DEPTID is passed as parameter
Select EmpName from TableA Left Join tableB on a.EmpID = B.EmpID
WHERE
CASE WHEN :IN_DEPTID IS NULL
IN_DEPTID IS NULL
ELSE|
DEPTID = :IN_DEPTID
Now problem is when Dept ID is passed it correctly returns a row but if no deptid is passed it returns 2 rows but i want ony one row as there is only one employee.
Please help;
Edited by: user10239708 on 10 Sep, 2008 12:24 AM
Edited by: user10239708 on 10 Sep, 2008 12:28 AMTry this
Select
from
tableA a
where
(exists (select 1 from tableB b where a.empid = b.empid and deptid = :IN_DEPTID )
or
:IN_DEPTID is null) you database design is not good you should keep the emp, department mapping in different table.
Regards
Singh -
How to delete the duplicate rows from the table
Hi,
I have 2 tbales namely component, component_audit
For each record in component table there are multiple entries in component_audit table.
I need to keep the first record and delete the others from the component_audit table
say for example
select a.component_id,a.dt_ti_stamp,a.component_name,a.column_before,b.comments from component_audit a,component b where a.component_id=b.component_id
( on the above result set only I shold apply the actual delete query )
PLease help me in this regards.
Thanks.delete from component_audit a where dt_ti_stamp not in (select
min(b.dt_ti_stamp)
from
component_audit b
where
a.component_id = b.component_id) -
Need to remove duplicate rows from distinct query
Hello,
I have the following query:
SELECT tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886)
ORDER BY tiab.ABNR )
ORDER BY abnr;
It returns the following:
14684940 Pizza Station Inc The Lafayette 26170 St Marys 304 684-2411
15123161 Chris Test 554 Easy St n 43333 Columbus 614 555-5555
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 2553304 --> keep this one
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 -- not show this
I have tried several different things as well as looking through the forums but have not found anything that will only give me unique records based only on the first column. This query works fine as long as there
are not 2 records returned with column1 being identical.
Final results should look like this:
14684940 Pizza Station Inc The Lafayette 26170 St Marys 304 684-2411
15123161 Chris Test 554 Easy St n 43333 Columbus 614 555-5555
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 2553304
Thanks in advance for the assistance.Hello,
Try:
SELECT abnr, namn, ADR, boxpnr, boxort,RIKTNR, TELNR,tigilopnr
FROM (
SELECT tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr,
ROW_NUMBER () OVER (PARTITION BY tiab.abnr ORDER BY (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) NULLS LAST) row_num
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886))
WHERE row_num <= 1
ORDER BY abnr;Or, with your current query:
SELECT abnr, namn, ADR, boxpnr, boxort,RIKTNR, TELNR,tigilopnr
FROM (
SELECT distinct tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr,
ROW_NUMBER () OVER (PARTITION BY tiab.abnr ORDER BY (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) NULLS LAST) row_num
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886))
WHERE row_num <= 1
ORDER BY abnr; -
How to delete duplicate rows in oracle and retaining last duplicate rows
Hi,
I'm having millions of records in the table .Some duplicate values/rows are inserted in it.
I just want to delete duplicate rows but also want to retain the last duplicate row.
For eg if one record is found three times ,i want to delete first and second record and retain
the third one i.e the last inserted one.
Regards
Paramdeep Singhuser13310594 wrote:
Hi,
I'm having millions of records in the table .Some duplicate values/rows are inserted in it.
I just want to delete duplicate rows but also want to retain the last duplicate row.
For eg if one record is found three times ,i want to delete first and second record and retain
the third one i.e the last inserted one.Hi Paramdeep,
To start with, since you do not wish to keep multiple rows with same values, why allow them to get inserted in the first place?
Wouldn't it be easier to block duplicate rows from inserting by creating a Unique constraint on Column(s) that define a row as duplicate, then rather deleting duplicate rows periodically?
For deleting duplicate rows, there are N number of techniques available. Always remember, you need to have a rigid criteria that marks row as duplicate.
[url http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:15258974323143]this is one recomended by tom for large tables.
Vivek L
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