E17 configuration help needed for UK keyboard [RESOLVED]

I downloaded and installed reverie's packages for Enlightenment DR17 at  http://ftp.takhis.net/arch (ie. 'pacman -Sy e17-cvs efl-cvs e17-extra-cvs'). 
Thanks for taking the time and effort to make the packages available reverie
I've been exploring E17 for about the past 2-3 days now and IT ROCKS!
However, I've noticed that its default keyboard layout is US (Shift+2 gives @ instead of ").  I tried Configuration > Configuration Panel > Language Settings but I could see no other options (in fact the list was completely blank).  I presume this is where I set the keyboard. 
Please could someone tell me how I can get my E17 install configured for my UK keyboard?

US is simply the default layout for X.org, you need to add
Option "XkbLayout" "uk"
to the InputDevice section for your keyboard in /etc/X11/xorg.conf.
I'm not sitting in front of an E desk right now, but if I recall there was also a keyboard switching module? (enable under modules then add to a shelf (hit shelves//configure shelf contents)). Dunno if it works though, or, well, if it's there at all So... go the xorg route...
Oh, and thx mon

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    This would be used for the HDD and the SSD would be moved to main HDD location.
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    Thank you in advanced for your time and all suggestions are welcomed.
    Cheers,
    Chris
    Solved!
    Go to Solution.

    I installed 32GB (4x8GB) of Corsair Vengeance RAM, and it has been working wonderfully since day 1.
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    Thanks very much!

    wangy26, welcome to the forum,
    Have a look at this thread to see if my post there helps. The problem seems to mostly occur at the start of a month, why I don't know. Unfortunately the member didin't report back whether or not this was a viable solution for them.
    Andy  ______________________________________
    Please remember to come back and mark the post that you feel solved your question as the solution, it earns the member + points
    Did you find a post helpfull? You can thank the member by clicking on the star to the left awarding them Kudos Please add your type, model number and OS to your signature, it helps to help you. Forum Search Option T430 2347-G7U W8 x64, Yoga 10 HD+, Tablet 1838-2BG, T61p 6460-67G W7 x64, T43p 2668-G2G XP, T23 2647-9LG XP, plus a few more. FYI Unsolicited Personal Messages will be ignored.
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    Pl see following thread
    I am stuck
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    See the issue here is HOLD feature in PO should not be there if it meets the error condition.
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    Hello,
    I have to produce XML to look like:
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      <enterprise>
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            <id>PHYS_101_001_FA2007</id>
          </sourcedid>
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          <sourcedid>
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          </sourcedid>
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        <member>
          <sourcedid>
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          <role roletype="Sample Role">
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    Is there some other way I can produce the nesting I need for the vendor's schema?
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    AVFT209-13307-201210   201210
    AVFT210-13308-201210   201210enrollments_fall_sfrstca:
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    AVFT209-13307-201210    FULLERC8
    AVFT209-13307-201210    SHUPEK
    AVFT209-13307-201210    NOMAN
    AVFT210-13308-201210    SHUPEK
    AVFT210-13308-201210    PELLONMWhen I have the query without the XML (with the subquery as a column of the outer query), this returns the correct data quickly (a couple of minutes).
    I have tried various permutations of XMLFOREST, XMLELEMENT, XMLAGG but either I get syntax errors, or the data is wrong (e.g. repeated '<membership>' for each '<member>', or I have to create an invalid tag '<members>' to be filtered later).
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    Thanks,
    Anita Lees

    Hi Anita,
    Have you tried with a GROUP BY and no subquery?
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    I've used the same tag names and structure so that you can see the analogy :
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               XMLElement("membership",
                 XMLElement("sourceid", xmlelement("id", d.deptno))
               , XMLAgg(
                   XMLElement("member",
                     XMLElement("sourceid",
                       XMLElement("id", e.empno)
                   , XMLElement("role",
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                     , XMLElement("status", '1')
    FROM scott.dept d
         LEFT OUTER JOIN scott.emp e ON e.deptno = d.deptno
    WHERE d.deptno IN (10,20)
    GROUP BY d.deptno
    ;which gives :
    <enterprise>
      <membership>
        <sourceid>
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        </sourceid>
        <member>
          <sourceid>
            <id>7782</id>
          </sourceid>
          <role roletype="MANAGER">
            <status>1</status>
          </role>
        </member>
        <member>
          <sourceid>
            <id>7934</id>
          </sourceid>
          <role roletype="CLERK">
            <status>1</status>
          </role>
        </member>
        <member>
          <sourceid>
            <id>7839</id>
          </sourceid>
          <role roletype="PRESIDENT">
            <status>1</status>
          </role>
        </member>
      </membership>
      <membership>
        <sourceid>
          <id>20</id>
        </sourceid>
        <member>
          <sourceid>
            <id>7369</id>
          </sourceid>
          <role roletype="CLERK">
            <status>1</status>
          </role>
        </member>
        <member>
          <sourceid>
            <id>7902</id>
          </sourceid>
          <role roletype="ANALYST">
            <status>1</status>
          </role>
        </member>
        <member>
          <sourceid>
            <id>7566</id>
          </sourceid>
          <role roletype="MANAGER">
            <status>1</status>
          </role>
        </member>
      </membership>
    </enterprise>

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