Enable the Number of Elements in the Array

once the Un-Initializing the array(1D or Multi) Placed ,we can not select the Number of element to Enable.
byproviding the below option we can easily Enable the Elements in any array dimention.

Already possible by typing a value (usually the default value) once you've set the indices to the size you want to initialize

Similar Messages

Total number of elements in an array

Hello,
I am trying to count the total number of elements in an array.
I have a simulate signal VI, that simulates a square pulse, this is being written into an excel file using the write to measurement VI, all for a given period of time.
I want to further chop a window of the signal depending on different paramenters (a trigger, which I intend to incorperate later, for now I am working of learning how to chop the data)
In order to chop the data I need to know the array size, I use the array size funtion, I right click on the appeneded array in the front pannel and click show last element (array size -1) it doesnt match with the number of rows in the excel file written by the write to measurement VI, in fact it macthes with the "number of samples" I selected in the simulate signal VI.
Am I doing something wrong?
Why is there a miss match??
I have attached my VI, Please help
Thank You
SP
Attachments:
FlashERGTrialVI 150218.vi ‏93 KB

Hello RavensFan
Thank you for the reply, I did incorperate the changes, but the same number is displayed in the indicator. I've attahced my VI
SP
Attachments:
FlashERGTrialVI 150218.vi ‏106 KB

Number of elements in an array

Hi,
I have been trying looking for a simple function to get number of elements is an array. Have gone though older posts but could not find answer to it.
The function should work for following examples:
char* name = "nInstruments"
float state[] = {1.0, 2.0}
I tried sizeof but it returns size of "type" in bytes. For example in example 2, it will just return 4.
Does someone know a way to do it?
Ciao
RB
Solved!
Go to Solution.

RB,
In C, if an array is declared on the heap, as opposed to on the stack as in your example above, the sizeof operator only returns the length of the pointer that holds the array which, in a 32-bit program, is always 4 bytes. This is because the compiler has no way of knowing how many elements that array actually holds. The length of a C array is a fairly fluid concept. The real size of the array is usually determined by some memory manager somewhere (usually, malloc), but it's not something that the language itself has anything to say about.
When you declare the entire array as a local variable, however, the compiler must create room for the full array on the stack, and therefore it is able to return the true size of the array via the sizeof operator. (The same is true if it's a global variable, even if it's not on the stack, in that case)
For this reason, using the sizeof(array) / sizeof(array[0]) trick is iffy. It might work, or it might not work, depending on how the array is declared.
For this reason, most C APIs that accept or return arrays, will usually also have some method of communicating the length of the array, usually as an additional parameter of some function. Because .NET APIs usually have no need to do this, the C wrapper for a .NET API in CVI does this for you when it handles .NET arrays. For example, here's what a function signature might look like:
int CVIFUNC Namespace1_Class1_Test1DArrays (Namespace1_Class1 __instance, int * inA, int __inALength, char *** outA, int * __outALength, Namespace1_Class2 ** refA, int * __refALength, double ** __returnValue, int * ____returnValueLength, CDotNetHandle * __exception);
Luis

How Do I Print the Number of Elements in An Array

How do I print: "There are ____ number of elements in the array?"

If you have a String holding a sentence, and if you split on non-empty sequences of whitespace (if the string has newlines in it, you'd probably need to pass the argument that makes \s match newlines, and for that you would probably need to use java.util.regex.Pattern -- see the docs and try some tests), when you'd get an array of Strings that were the non-whitespace parts of the original String. That makes for a reasonably good definition of the words in the sentence, although you could arguably get into some gray areas (does "isn't" count as one or two words? Does a sequence of numbers or punctuation qualify as a word?). In that case, counting the number of elements in the resulting array of String. using .length, would be a reasonable way to get the number of words in that sentence, yes.
But rather than asking for confirmation on forums, why don't run some tests?
import java.io.*;
public class TestWordCount {
public static void main(String[] argv) {
    try {
      BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
      String line;
      while((line = in.readLine()) != null) {
        int count = // your code here, to count the words
        System.out.println("I see " + count + " words.");
    } catch (IOException e) {
      e.printStackTrace();
}Put your word-counting code in there, then run it from the command line. Type in a sentence. See how many words it thinks it found. Does it match with your expectation, or the examples given (hopefully) with your homework assignment?

Actively changing number of elements in an array

How do you use a control in the front panel to actively change the number of rows in an array which full of numeric controls?
Is it possible to have this happen without the program to be running? Thanks for any help.
Solved!
Go to Solution.

Chris B. wrote:
Is it possible to have this happen without the program to be running? Thanks for any help.
So you want this to work at edit time? Are you talking about the number of visible elements or are you talking about the actual size of the array (these numbers are unrelated!).
In order for something to happen, "something" needs to be running. You could run another VI and use scripting to make changes to the array structure.
You could also make an Xcontrol containing an array and a numeric. Xcontrols are fully operational even if the VI itself is in edit mode.
If this is a program to run standalone, simply make sure the program is always running, but is in an idle state if nothing needs to be done at the moment. Now you can handle resize events if needed.
LabVIEW Champion . Do more with less code and in less time .

Iterating through every other (or specified number) of element in an array using a for loop

I am trying to go through an array but instead of autoindexing I want to skip every other element or maybe a number of elements that will be specified for the user.
Basic functionality that I want to acheive is the following in C code.
int temp_var = 10;
int i=0;
for(i=0; i<=1000; i=i+temp_var)
I am very new to LabVIEW and I did not know how to use internal variables.
Can this be acheived using shift registers?
I am attaching the code I currently have for this. Let me know what you think.
Thanks guys.
Solved!
Go to Solution.
Attachments:
24_Sep_NchanNSamp.vi ‏44 KB

tbob wrote:
I have been asking for a new For Loop style that would allow us to specify start, stop, and step conditions, but it seems that many people are just not for this idea. Don't know why?
See here.
I wouldn't say there aren't many people for it. The idea you linked to was one of a half dozen of basically duplicate ideas, including another one of your own.
These two ideas have a fairly large number of kudoes showing people want the idea.
Smart Iterators with Loops
For Loop Increment

Counting number of elements in an array which aren't empty?

i tried using this method to count an array which has 100 elements but it doesn't go past the while statement which i cant figure out?
public static void countCust()
int cntr = 0;
int z;
for (int c = 0; c < 100; c++)
while (customer[c].indexOf(':') != -1)
cntr++;
javax.swing.JOptionPane.showMessageDialog(null, "There are " + cntr + " customers on record");
}

Are you getting NullPointerExceptions?
Are you sure customer[] has been allocated?
Are you sure each element in the array is non-null?
BTW, it's traditional to use variables in loops that are closer to their mathematical usage. I mean, for an array index, usually you'd use variables named i or j, unless the indices map to coordinates in space, in which case you'd use x, y, and z.
If neither of these is applicable, use a variable with a more meaningful name.

Get the number of elements in Array

Hi everyone,
Could anyone give me idea on how to get the number of elements in an Array (not number of rows) ?
I tried to find that in both property node and array functions but nothing.
Thanks,
-Kun

You are going to have to provide some proof that the Array Size does not work correctly. Right click on the input to it and select 'Create Indicator'. Run the VI. Go to the front panel and select 'Edit>Make Current Values Default'. Save the VI and attach it to your post.
You can also check the array size yourself. Right click on the index display of the array and select 'Advanced>Show Last Element'. I will bet you that number shown is equal to Array Size -1.
p.s. The number of elements in an array is equal to the number of rows in a 1D array. If you define the number of elements as anything else, you are mistaken.
Message Edited by Dennis Knutson on 04-21-2009 10:40 AM

How to find the elements of an array

I want to find the number of elements in an array, and I can't find the tutorial that shows how to find it. If anyone could point me in the right direction, it would be greatly appreciated.

warnerja wrote:
flounder wrote:
DrLaszloJamf wrote:
You mean x.length?<pbs>
Depends upon your interpretation of "number of elements in the array"
int[] numbers = new int[10];
numbers[0] = 42;
numbers[1] = 666;Number of elements in the array is 2 not 10.
</pbs>If you used something other than a primitive type for the array element type you could have a case. A value of integer zero for the other elements is still a value, so there are indeed 10 elements there.Even if it were not primitive, every element would have a value. That value would either be null or a reference.

How do I find the total number of elements in a multi dim array

How do I find the total number of elements in a single or multi dim array?
For example, a 2x3 array has 6 elements, and a 2x3x4 has 24. How do I compute this very easily - is there a single VI that does this?
David
Solved!
Go to Solution.

Use "array size" (array palette) followed by "multiply array elements" (numeric palette)
(Works also equally well for 3D arrays and higher)
For a 1D array, just use "array size".
Message Edited by altenbach on 02-05-2009 05:57 PM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
NumberOfElements.png ‏3 KB

Help get the array number fo a element

Hi
1. This program does the following: Ask for three numbers, print them in a row and show the largest number of the three.
2. I also would like the program to: Print out the position of the array, whre the largest number is. Please give me a hint where to begin.
import java.util.*;
public class Ovning5 {
     public static void main (String [] arg) {
          Scanner scan = new Scanner (System.in);
          int [] numbers = new int [3]; // New array
          int x; // Numbers in array
          int largestNumber; // Largest number in the array
          // Ask for numbers
          System.out.print("Put in (three) numbers");
          for (x=0; x<numbers.length; x++) {
               numbers[x]=scan.nextInt ();
          // Print numbers in a row
          for (x=0; x<numbers.length; x++) {
               System.out.print (numbers[x]+ " ");
          // Put a new line before next function
          System.out.println (); {
               // Find the largest number
               largestNumber = 0; // Set the highest number to 0
               for (x=0; x<numbers.length; x++) { // Use the first number in the array.
                    if (x == 0) {
                         largestNumber = numbers[0];
                    // if the current number we're
                    // looking at in the array is bigger than the highest number,
                    // set the highest number to this current number
                    if (numbers[x] > largestNumber) {
                         largestNumber = numbers[x];
               }     // Close new line function
            // Print out the largest number
               System.out.println("The biggest number is " + largestNumber);
}

"As you iterate over the array, looking for the largest element, keep track of the index of the largest element as well as it's value. Whenever you set the largest to array[n], also store n."
It took a while to figure out, but it is something like this you meen :)
// Find the largest number and the position in the array
               largestNumber = 0; // Set the highest number to 0
               for (x=0; x<numbers.length; x++) { // Use the first number in the array.
                    if (x == 0) {
                         largestNumber = numbers[0];
                    // if the current number we're
                    // looking at in the array is bigger than the highest number,
                    // set the highest number to this current number
                    if (numbers[x] > largestNumber) {
                         largestNumber = numbers[x];
                         y=x; // Since we look at all the numbers in the loop
                         // and we started from zero, y is going to be compared to xDo you think my comments make sense?

Can I replace several elements of an array within one time? The number of elements are not fixed

Hi all,
I want to replace some elements of a 2D array, but the number of elements are not known beforehand. I dont want to do it with a loop, which may slow down the speed, and the update of elements will not happen simultaneously. The indexes of elements to be updated are not continuous. I wonder if there is a way to do that efficiently? Do I have to programme it in LabWindows/CVI? Thank you.
Best wishes,
Bo
My blog Let's LabVIEW.

Use the replace elements function. For non-continuous replacements of of multiple elements you would nee to iterate at least the number of continous pieces.
For example:
1,2,3,4,5,6,7,8,9
Replace elements 1,2,5,6,8
You would need 3 iterations in which you can replace (1,2), (5,6) and (8).
Regards,
André
Using whatever version of LV the customer requires. (LV5.1-LV2012) (www.carya.nl)

How can I offset all elements of an array by the same number

I'd like to know the quickest way to add a number to all elements of an array. In other word, offset the whole array by a number.

You just use the normal add function. Wire the array to one input and the constant to the other input. After wiring the array, do not click on the other terminal and select Create>Constant because by default it will create an array. Just select a Numeric Constant from the Numeric palette or wire it to a control.
Attachments:
add_constant_to_array.jpg ‏3 KB

How to get the number of elements in a tilelist

I'm writing test cases for a flex application using FlexSelenium and I need to get the number of elements displayed in the tilelist.
I know that that the tilelist is fed by an array. but i can't access that array from my test case.
Can anyone tell me how I can get the number of elements in a tilelist on the application? which property of the tilelist can provide that number?

try tileList.dataProvider.length;

How to change the properties of individulal elements in an array?

Hi all,
I have an array (size is 25) of string and I want to disable and grayout half of them. But how do I do it? How do I change the properties of individual elements in an array? I have tried to use some of the examples given in the discussion forums, but it didint work for the task mentioned above. Anybody would be able to help me with a suitable example that can be specifically used for disable or enable the individual array elements?
Dev

Telemaque wrote:
The user will see the first half of the string elements filled-in and the lower half grayed-out (to be filled in later). Make a test VI, play around.
... except that all elements "greyed out" with this method contain the default string for the array element (blank by default, but changeable). There is no way to have meaningful, unique text in the greyed out elements.
I would suggest to use a listbox as control/indicator. Here elements can easily be disabled programmatically.
LabVIEW Champion . Do more with less code and in less time .

Enable the Number of Elements in the Array

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