Equivalent of Hierarchy SQL in Oracle

Hi All,
We have some performance issues with 'CONNECT BY PRIOR' SQL statement and trying to find an alternate SQL which gives the same output.
Example:
ENum Mgr
Julie
Andrew Julie
Mark Andrew
Matt Andrew
Wyatt Julie
Jenny Wyatt
SELECT enum, mgr FROM <table> START WITH enum IS NULL
CONNECT BY PRIOR enum = mgr;
Output:
Julie
---Andrew
------Mark
------Matt
---Wyatt
------Jenny
---Joel
How do I get the same output without using CONNECT BY PRIOR command. I dont mind creating a new table that will keep all the possible combinations between enum and mgr columns.
Please provide your solution. I really appreciate it.
Thanks in advance,
Rao

We have some performance issues with 'CONNECT BY PRIOR' SQL statementWhat is the explain plan for the query?
what is the tkprof output for the query?
what optimizer is in use?
how stats are generated, if they are?
what is the data volume in the source table?
how much time does the query take currently?
where is the resultset of the query consumed - asp, jsp, java, vb.net ....?

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  • Embedded SQL against Oracle Question

    Software: Forte 3.0.J.
    Server Platform: HPUX 10.2
    Database: Oracle
    Problem Description: During the course of development, I ran into a
    problem using multiple columns in an sql UPDATE/SET statement. I was trying
    to update a.COLUMN_1 and a.COLUMN_2, which constitute part of the primary
    key of associative TABLE_A (a). In order for me to make the update, I
    needed to use the existing value of a.COLUMN_1 to lookup the new b.COLUMN_1
    in TABLE_B (b). Where a.COLUMN_1 = b.RELATED_COLUMN_1, I am able to find
    each b.COLUMN_2 that correspond to each a.COLUMN_2.
    I was able to resolve the issue by separating the two columns so
    that each had it's own select statement. Theoretically, it appears that
    this shouldn't work, because the SET statement for a.COLUMN_1 would cause
    the a.COLUMN_1 reference in the select statement of a.COLUMN_2 to be
    overwritten.
    In spite of this, I tried it, and it worked. I would like to
    understand why the sql works, and how sql actually executes the statement.
    Here is the sql:
    UPDATE TABLE_A a
    SET a.COLUMN_1 =
    (SELECT DISTINCT b1.COLUMN_1
    FROM TABLE_B b1
    WHERE b1.RELATED_CASE_ID =
    a.COLUMN_1 AND
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    (SELECT DISTINCT b2.COLUMN_2
    FROM TABLE_B b2
    WHERE b2.RELATED_COLUMN_1=
    a.COLUMN_1 AND
    b2.RELATED_COLUMN_TYPE_CD = 'NEPHI' AND
    b2.RELATED_COLUMN_2= a.COLUMN_2)
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    The table structure is as follows:
    TABLE_A: (primary keys are bolded) This is an associative table.
    Column_1 and Column_2 comprise the pk of one table; Column_3 and Column_4
    comprise the pk of another table. Assume that the Column_1 and Column_2
    values replacing the original values already exist in the parent table of
    which they form the pk).
    COLUMN_1
    COLUMN_2
    COLUMN_3
    COLUMN_4
    COLUMN_5
    TABLE_B: (primary keys are bolded) This is a reference table.
    COLUMN_1
    COLUMN_2
    RELATED_COLUMN_1
    RELATED_COLUMN_2
    RELATED_COLUMN_TYPE_CD
    To unsubscribe, email '[email protected]' with
    'unsubscribe forte-users' as the body of the message.
    Searchable thread archive <URL:http://pinehurst.sageit.com/listarchive/>

    If you do an explain plan or set autotrace on against this update statement,
    you'll find that the select operations are actually executed first by Oracle
    - I believe because of the nature of the transaction. Thus, no problem.
    Brian Wilson
    U.S. Bancorp Piper Jaffray
    [email protected]
    Phone (612) 342-5682
    From: David Pettit[SMTP:[email protected]]
    Reply To: David Pettit
    Sent: Friday, April 30, 1999 1:58 PM
    To: '[email protected]'
    Subject: Embedded SQL against Oracle Question
    Software: Forte 3.0.J.
    Server Platform: HPUX 10.2
    Database: Oracle
    Problem Description: During the course of development, I ran into a
    problem using multiple columns in an sql UPDATE/SET statement. I was
    trying
    to update a.COLUMN_1 and a.COLUMN_2, which constitute part of the primary
    key of associative TABLE_A (a). In order for me to make the update, I
    needed to use the existing value of a.COLUMN_1 to lookup the new
    b.COLUMN_1
    in TABLE_B (b). Where a.COLUMN_1 = b.RELATED_COLUMN_1, I am able to find
    each b.COLUMN_2 that correspond to each a.COLUMN_2.
    I was able to resolve the issue by separating the two columns so
    that each had it's own select statement. Theoretically, it appears that
    this shouldn't work, because the SET statement for a.COLUMN_1 would cause
    the a.COLUMN_1 reference in the select statement of a.COLUMN_2 to be
    overwritten.
    In spite of this, I tried it, and it worked. I would like to
    understand why the sql works, and how sql actually executes the statement.
    Here is the sql:
    UPDATE TABLE_A a
    SET a.COLUMN_1 =
    (SELECT DISTINCT b1.COLUMN_1
    FROM TABLE_B b1
    WHERE b1.RELATED_CASE_ID =
    a.COLUMN_1 AND
    b1.RELATED_COLUMN_TYPE_CD = 'NEPHI'),
    a.COLUMN_2=
    (SELECT DISTINCT b2.COLUMN_2
    FROM TABLE_B b2
    WHERE b2.RELATED_COLUMN_1=
    a.COLUMN_1 AND
    b2.RELATED_COLUMN_TYPE_CD = 'NEPHI' AND
    b2.RELATED_COLUMN_2= a.COLUMN_2)
    WHERE a.COLUMN_1 = 100
    The table structure is as follows:
    TABLE_A: (primary keys are bolded) This is an associative table.
    Column_1 and Column_2 comprise the pk of one table; Column_3 and Column_4
    comprise the pk of another table. Assume that the Column_1 and Column_2
    values replacing the original values already exist in the parent table of
    which they form the pk).
    COLUMN_1
    COLUMN_2
    COLUMN_3
    COLUMN_4
    COLUMN_5
    TABLE_B: (primary keys are bolded) This is a reference table.
    COLUMN_1
    COLUMN_2
    RELATED_COLUMN_1
    RELATED_COLUMN_2
    RELATED_COLUMN_TYPE_CD
    To unsubscribe, email '[email protected]' with
    'unsubscribe forte-users' as the body of the message.
    Searchable thread archive <URL:http://pinehurst.sageit.com/listarchive/>
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  • What is equivalent to 'with clause' in oracle

    what is equivalent to 'with clause' in oracle
    thanks

    My reqirement is :
    I have a table named egroup. I have to find the name of the egroup different from "other" that can be found in the most countries in Africa
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         percent number(4,2), -- percentage of population
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         constraint egroup_pk primary key(c_id,egroup)
    insert into egroup values('AF','Pashtun', 42 );
    insert into egroup values('AF','Tajik',27 );
    insert into egroup values('AF','Hazara',9 );
    insert into egroup values('AF','Uzbek',9 );
    insert into egroup values('AF','Aimak',4 );
    insert into egroup values('AF','Turkmen',3 );
    insert into egroup values('AF','Baloch',2 );
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    insert into egroup values('AL','other',2 );
    insert into egroup values('AG','Arab-Berber', 99 );
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