ERROR-- 9 [Motor unable to stabilize between min and max limits] -- (2708) TEST FAILED
Re: ERROR -- 9 [Motor unable to stabilize between min and max limits] -- (2708) TEST FAILED
Please Somebody Tell me What Is The Issue.
It might be helpful if indicated exactly what you were doing when the error appeared.
Similar Messages
-
Select just the values between min and max of an accumulated value over day
Hello Forum,
a value is accumulated over a day and over a period of time. Next day the value is reseted and starts again to be accumulated:
with sampledata as (select to_date('09.09.2012 00:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 01:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 02:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 03:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 04:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 05:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 06:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 23 val from dual union all
select to_date('09.09.2012 07:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 29 val from dual union all
select to_date('09.09.2012 08:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 30 val from dual union all
select to_date('09.09.2012 09:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 45 val from dual union all
select to_date('09.09.2012 10:12:12', 'dd.mm.yyyy hh24:mi:ss') ts, 60 val from dual union all
select to_date('09.09.2012 11:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 75 val from dual union all
select to_date('09.09.2012 12:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 95 val from dual union all
select to_date('09.09.2012 13:21:26', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 14:21:27', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 15:21:30', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 16:21:32', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 17:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 21:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 23:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 00:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 01:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 02:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 03:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 04:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 05:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 06:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 14 val from dual union all
select to_date('10.09.2012 07:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 34 val from dual union all
select to_date('10.09.2012 08:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 58 val from dual union all
select to_date('10.09.2012 09:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 70 val from dual union all
select to_date('10.09.2012 10:12:12', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('10.09.2012 11:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 12:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 13:21:26', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 14:21:27', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 15:21:30', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 16:21:32', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 21:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual)
select ts, val
from sampledata
order by ts asc;How should I change the select statement to skip all data sets before the first minimum and the duplicates after the maximum of a day in order to get such a result:
TS VAL
09.09.12 06:12 23
09.09.12 07:12 29
09.09.12 08:12 30
09.09.12 09:12 45
09.09.12 10:12 60
09.09.12 11:12 75
09.09.12 12:21 95
09.09.12 13:21 120
09.09.12 14:21 142
10.09.12 06:12 14
10.09.12 07:12 34
10.09.12 08:12 58
10.09.12 09:12 70
10.09.12 10:12 120
10.09.12 11:12 142
10.09.12 12:21 153Thank youThis solution works perfectly when the accumulated value has its low and its high on the same day. But I found out :( , that there is also data, which has its low yesterday and its high today. For a better understandig of the case, there is a machine, wich is working over 3 Shifts with irregular start and end time. For example Shift1 cann start at 5:50 or at 7:15. The accumulated value of the worked time is accumuated for each shift extra. This solution works for the shift 1 (approximate between 06:00-14:00) and for the shift 2(approximate between 14:00-22:00), because there is the low and the high of the accumulated value on the same day. This solution does not work for the shif 3(approximate between 22:00-06:00), because the high of the accumulated value is or can be the next day.
So the thread title should be: "Select just the values between min and max of an accumulated value over the same day(today) or over two successive days (yesterday and today)
Sampledata for shift 1 or shift 2:
{code}
with sampledata as (select to_date('09.09.2012 00:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 01:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 02:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 03:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 04:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 05:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 06:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 23 val from dual union all
select to_date('09.09.2012 07:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 29 val from dual union all
select to_date('09.09.2012 08:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 30 val from dual union all
select to_date('09.09.2012 09:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 45 val from dual union all
select to_date('09.09.2012 10:12:12', 'dd.mm.yyyy hh24:mi:ss') ts, 60 val from dual union all
select to_date('09.09.2012 11:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 75 val from dual union all
select to_date('09.09.2012 12:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 95 val from dual union all
select to_date('09.09.2012 13:21:26', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
select to_date('09.09.2012 14:21:27', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 15:21:30', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 16:21:32', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 17:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 21:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('09.09.2012 23:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 00:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 01:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 02:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 03:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 04:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 05:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 06:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 143 val from dual union all
select to_date('10.09.2012 07:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 144 val from dual union all
select to_date('10.09.2012 08:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 145 val from dual union all
select to_date('10.09.2012 09:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 10:12:12', 'dd.mm.yyyy hh24:mi:ss') ts, 147 val from dual union all
select to_date('10.09.2012 11:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 148 val from dual union all
select to_date('10.09.2012 12:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 13:21:26', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 14:21:27', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 15:21:30', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 16:21:32', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
select to_date('10.09.2012 21:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual)
, got_analytics AS
SELECT ts, val
, MIN (val) OVER ( PARTITION BY TRUNC (ts)
ORDER BY ts DESC
) AS min_val_after
, CASE
WHEN ROW_NUMBER () OVER ( PARTITION BY TRUNC (ts)
ORDER BY val
, ts
) = 1
THEN -1 -- Impossibly low val
ELSE LAG (val) OVER ( PARTITION BY TRUNC (ts)
ORDER BY ts
END AS prev_val
, MIN (val) OVER (PARTITION BY TRUNC (ts))
AS low_val_today
, NVL ( LAST_VALUE (val) OVER ( ORDER BY ts
RANGE BETWEEN UNBOUNDED PRECEDING
AND ts - TRUNC (ts) PRECEDING
, -1
) AS last_val_yesterday
FROM sampledata
SELECT ts
, val
FROM got_analytics
WHERE val <= min_val_after
AND val > prev_val
AND ( val > low_val_today
OR val != last_val_yesterday
ORDER BY ts
{code}
with the expected results:
{code}
1 09.09.2012 06:12:02 23
2 09.09.2012 07:12:03 29
3 09.09.2012 08:12:04 30
4 09.09.2012 09:12:11 45
5 09.09.2012 10:12:12 60
6 09.09.2012 11:12:13 75
7 09.09.2012 12:21:24 95
8 09.09.2012 13:21:26 120
9 09.09.2012 14:21:27 142
10 10.09.2012 06:12:02 143
11 10.09.2012 07:12:03 144
12 10.09.2012 08:12:04 145
13 10.09.2012 09:12:11 146
14 10.09.2012 10:12:12 147
15 10.09.2012 11:12:13 148
16 10.09.2012 12:21:24 153
{code}
And the sampledata for shift 3 is:
{code}
with sampledata as (select to_date('08.09.2012 00:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 23 val from dual union ALL
select to_date('08.09.2012 02:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 45 val from dual union all
select to_date('08.09.2012 05:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 78 val from dual union all
select to_date('08.09.2012 06:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 90 val from dual union all
select to_date('08.09.2012 08:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 90 val from dual union all
select to_date('08.09.2012 10:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 90 val from dual union all
select to_date('08.09.2012 12:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 90 val from dual union all
select to_date('08.09.2012 16:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 90 val from dual union all
select to_date('08.09.2012 17:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 90 val from dual union all
select to_date('08.09.2012 19:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 90 val from dual union all
select to_date('08.09.2012 21:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 90 val from dual union all
select to_date('08.09.2012 22:00:12', 'dd.mm.yyyy hh24:mi:ss') ts, 24 val from dual union all
select to_date('08.09.2012 22:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 40 val from dual union all
select to_date('08.09.2012 23:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 68 val from dual union all
select to_date('09.09.2012 01:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 79 val from dual union all
select to_date('09.09.2012 02:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 124 val from dual union all
select to_date('09.09.2012 03:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 125 val from dual union all
select to_date('09.09.2012 04:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 126 val from dual union all
select to_date('09.09.2012 05:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 06:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 07:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 08:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 09:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 10:12:12', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 11:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 12:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 13:21:26', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 14:21:27', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 15:21:30', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 16:21:32', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 17:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union all
select to_date('09.09.2012 21:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 127 val from dual union ALL
select to_date('09.09.2012 22:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 5 val from dual union ALL
select to_date('09.09.2012 22:51:33', 'dd.mm.yyyy hh24:mi:ss') ts, 23 val from dual union all
select to_date('09.09.2012 23:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 40 val from dual union all
select to_date('10.09.2012 00:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 50 val from dual union all
select to_date('10.09.2012 01:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 60 val from dual union all
select to_date('10.09.2012 02:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 78 val from dual union all
select to_date('10.09.2012 03:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
select to_date('10.09.2012 04:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 145 val from dual union all
select to_date('10.09.2012 05:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 06:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 07:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 08:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 09:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 10:12:12', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 11:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 12:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 13:21:26', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 14:21:27', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 15:21:30', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 16:21:32', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual union all
select to_date('10.09.2012 21:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 146 val from dual)
, got_analytics AS
SELECT ts, val
, MIN (val) OVER ( PARTITION BY TRUNC (ts)
ORDER BY ts DESC
) AS min_val_after
, CASE
WHEN ROW_NUMBER () OVER ( PARTITION BY TRUNC (ts)
ORDER BY val
, ts
) = 1
THEN -1 -- Impossibly low val
ELSE LAG (val) OVER ( PARTITION BY TRUNC (ts)
ORDER BY ts
END AS prev_val
, MIN (val) OVER (PARTITION BY TRUNC (ts))
AS low_val_today
, NVL ( LAST_VALUE (val) OVER ( ORDER BY ts
RANGE BETWEEN UNBOUNDED PRECEDING
AND ts - TRUNC (ts) PRECEDING
, -1
) AS last_val_yesterday
FROM sampledata
SELECT ts
, val
FROM got_analytics
WHERE val <= min_val_after
AND val > prev_val
AND ( val > low_val_today
OR val != last_val_yesterday
ORDER BY ts
{code}
with the unexpected results:
{code}
- ts val
1 08.09.2012 00:04:08 23
2 08.09.2012 22:12:13 40
3 08.09.2012 23:21:24 68
4 09.09.2012 22:21:33 5
5 09.09.2012 22:51:33 23
6 09.09.2012 23:21:33 40
7 10.09.2012 00:04:08 50
8 10.09.2012 01:03:08 60
9 10.09.2012 02:54:11 78
10 10.09.2012 03:04:08 142
11 10.09.2012 04:04:19 145
12 10.09.2012 05:04:20 146
{code}
The result should be:
{code}
- ts val
1 08.09.2012 00:04:08 23
2 08.09.2012 02:04:08 45
3 08.09.2012 05:03:08 78
4 08.09.2012 06:54:11 90
5 08.09.2012 22:00:12 24
6 08.09.2012 22:12:13 40
7 08.09.2012 23:21:24 68
8 09.09.2012 01:03:08 79
9 09.09.2012 02:54:11 124
10 09.09.2012 03:04:08 125
11 09.09.2012 04:04:19 126
12 09.09.2012 05:04:20 127
13 09.09.2012 22:21:33 5
14 09.09.2012 22:51:33 23
15 09.09.2012 23:21:33 40
16 10.09.2012 00:04:08 50
17 10.09.2012 01:03:08 60
18 10.09.2012 02:54:11 78
19 10.09.2012 03:04:08 142
20 10.09.2012 04:04:19 145
21 10.09.2012 05:04:20 146
{code}
Thank you for your help! -
Transactions between Min and Max dates
Hey all,
I have a requirement to extract data between min(transdate) and max(transdate), i got to do this using a single query, i used two queries, ie. 1 select for selecting the max and min dates and my second query to get the transactions. Can some one give me an idea to solve this, as Max & Min functions are not allowed in the where clause.
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Hi,
I have a scenario where I am Selecting the values BETWEEN MIN and MAX values:
SELECT * FROM ABC WHERE CODE BETWEEN MIN(CODE) AND MAX(CODE)
ITS GETTING Error as:ORA-00934: group function is not allowed here
Any help will be needful for me.select substr(no,1,3)||to_char(substr(no,4,1)+1) "first missing number"
from
with t as
(select 'ABC1' no from dual
union select 'ABC2' from dual
union select 'ABC3' from dual
union select 'ABC5' from dual
union select 'ABC6' from dual
union select 'ABC8' from dual
select no, lead(no,1,0) over (order by no) next_no from t
where substr(next_no,4,1) - substr(no,4,1) > 1
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Difference of value of a dimension based on min and max
Database: Oracle 10g
BO-BOXIr3
Let me explain the exact problem again.
As per the below code, I have the data in this format in my table:
Code:
Date Site ID KWH
1/2/2009 00:00 IN-1 22
1/2/2009 01:00 IN-1 28
1/3/2009 03:00 IN-2 25
1/3/2009 04:00 IN-2 46
1/4/2009 00:00 IN-3 28
1/4/2009 10:00 IN-3 34
1/5/2009 08:00 IN-4 31
1/5/2009 09:00 IN-4 55
1/5/2009 11:00 IN-4 77
1/6/2009 00:00 IN-5 34
Now want to build a report with following columns:
Site Count KWH
IN-1 2 6 (ex.-28-22)
IN-2 2 21
IN-3 2 6
IN-4 3 46 (ex.-77-31)
IN-5 2 34
SITE- distinct site name.
COUNT-count is number of repetitions of site id between min and max date.
KWH -(Delta between the min and max date)
To get the above result I have created 3 report from different queries since not able to get these al in a single report viz Count, Max Value and Min value. Well I have all these 3 reports or table on a single page.
Count-this report will give the count between the dates
Max Value-this report will give me the values of kwh for max dates for each site id
Min Value-this report will give me the values of kwh for min dates for each site id
Now want to create a single report based on these 3 reports which contains the column
Site|Count|KWH
IS IT POSSIBLE?
Or
Is it possible to build such report in a single one with all the required column which I mentioned?
The variables which I created to get the max & min dates,
Mx_dt= =Max([Query 2].[Hourly]) In ([Query 2].[SITE_ID])
Mn_dt= =Min([Query 3 (12)].[Hourly]) In ([Query 3 (12)].[SITE_ID])
For filtering on report used following variables:
if_st_mn=If([mn_dt])=[Hourly] Then "ok" Else "no"
if_st_mx =If([mx_dt])=[Hourly] Then "ok" Else "no"
will filter on "ok" to get the max and min date values.
rest of the variable in the snap are not usable.Yes, you can do it in one report.
I created a sample report from efashion:
Year | Lines | Sales Revenue
2001 | Accessories | $250
2003 | Accessories | $550
2001 | City Skirts | $1050
2003 | City Skirts | $1150...........
Create 2 variables 1) Count and 2) Difference:
1) Count as formula - =Count([Lines]) In Report
2) Difference as formula - =Sum([Sales revenue]) Where (Max([Year]) In Report = [Year]) - Sum([Sales revenue]) Where (Min([Year]) In Report = [Year])
You can replace the formula with your report variables. Then just drag Site ID, Count and Difference variables to your report.
Thanks
Jai -
Query about min and max and middle row of a table
suppose i have table emp and field
v_date date;
which has data in time stamp
time
10:20
10:25
10:30
10:32
10:33
10:35
10:36
10:38
I need only min time and max time and two record between min and maxI need only min time and max time and two record between min and max Like this?
SQL> create table t (id number);
Table created.
SQL>
SQL> insert into t values (1020);
1 row created.
SQL> insert into t values (1025);
1 row created.
SQL> insert into t values (1030);
1 row created.
SQL> insert into t values (1032);
1 row created.
SQL> insert into t values (1033);
1 row created.
SQL> insert into t values (1035);
1 row created.
SQL> insert into t values (1036);
1 row created.
SQL> insert into t values (1038);
1 row created.
SQL>
SQL> commit;
Commit complete.
SQL>
SQL> select * from t;
ID
1020
1025
1030
1032
1033
1035
1036
1038
8 rows selected.
SQL>
SQL>
SQL> select decode(rownum, 1, min_val, 4, max_val, next_val) your_data from (
2 select first_value (id) over (partition by 'a' order by 'a') min_val,
3 last_value (id) over (partition by 'a' order by 'a') max_val,
4 id,
5 lead(id) over (partition by 'a' order by id) next_val
6 from t
7 order by id
8 )
9 where min_val <> next_val and max_val <> next_val
10 and rownum <= 4;
YOUR_DATA
1020
1030
1032
1038
SQL> -
After installing Version 5 I get an error message about incompatibility and min and max versions.
I shutdown Zone Alarm, and deleted the contents of the file, which contained the "exe" file, then reinstalled Firefox version 5.0. I still get the XUL Runner error message about incompatibility of Version 5.0 with min and max 5.0.1. What next?
The updater wasn't able to update all the files and some were left as older versions.<br />
You need to do a clean reinstall.
Download a fresh Firefox copy and save the file to the desktop.
* Firefox 5.0.x: http://www.mozilla.com/en-US/firefox/all.html
* Uninstall your current Firefox version.
* Do not remove personal data when you uninstall the current version.
Remove the Firefox program folder before installing that newly downloaded copy of the Firefox installer.
* It is important to delete the Firefox program folder to remove all the files and make sure that there are no problems with files that were leftover after uninstalling.
Your bookmarks and other profile data are stored elsewhere in the Firefox Profile Folder and won't be affected by a reinstall, but make sure that you do not select to remove personal data if you uninstall Firefox.
* http://kb.mozillazine.org/Profile_folder_-_Firefox
* http://kb.mozillazine.org/Profile_backup -
My iMessage is not working between mine and another's iPhone. What can I do to fix it?
My iMessage is not working between mine and another's iPhone. What can I do to fix it?
What does not working mean?
-
Find more than one min and max in 2D array contain 0 rows
Hi
I have a 2D array and I would like to find the max and min elements between series of 0s. As you can see in the picture If I remove all 0s from the array and use the max and min function then I will have just one min and one max but I need to find min and max after every 0 rows so you can see from the picture ( just as an example) I will have 3 min and 3 max numbers. Would you please help me with this code. Do you now any algorithm that can find min and max between 0s?
I have also attached my code to remove 0s and then search for max and min numbers but as I mentioned I need min and max for every part
Many thanks
Attachments:
2.jpg 82 KB
3.jpg 27 KBThanks altenbach
I have attached the vi to this post. I would really apperciate if you help me with this example. The min values should be 100, 1500 and 4000 and the max values should be 1200,2600,5400 so as u mentioned the output should be this 2D array
100,1200
1500,2600
4000,5400
Attachments:
new.vi 6 KB -
In my database design and implementation module I'm at the implementation stage. I've set up all of my tables with PK and FK constraints and I'm wondering if you can enforce min and max column constraints. One of the rules of my DB is for my staff table there has to be a minimum of 10 and a maximum of 50, how would I enforce this rule as a constraint on the staff table or isn't this possible?
We have only been learning database design and SQL fundamentals so I don't think I'd be allowed to use triggers or procedures.
Many thanks
Mikemharper wrote:
thanks guys these commands were accepted
alter table staff
add constraint chk_staff_max check (staff_id <= 50);
alter table staff
add constraint chk_staff_min check (staff_id >= 10);
Thing is my staff_id's are in the format 'S110001' will these constraints only check for integers 10 - 50? maybe I need to use a count function on the column or something?
thanks again for your help!
MikeCheck constraint can also be used to check a list of values.
example:
ALTER TABLE <table_name>
ADD CONSTRAINT <constraint_name>
CHECK (<column_name> LIKE <condition>);
ALTER TABLE <table_name>
ADD CONSTRAINT <constraint_name>
CHECK (<column_name> NOT LIKE <condition>);
ALTER TABLE <table_name>
ADD CONSTRAINT <constraint_name>
CHECK (<column_name>
IN (<comma delimited list of values>);
ALTER TABLE <table_name>
ADD CONSTRAINT <constraint_name>
CHECK (<column_name>
NOT IN (<comma delimited list of values>);
ALTER TABLE <table_name>
ADD CONSTRAINT <constraint_name>
CHECK (<column_name> BETWEEN <lower_value>
AND <higher_value>);
ALTER TABLE <table_name>
ADD CONSTRAINT <constraint_name>
CHECK (<column_name>
NOT BETWEEN <lower_value> AND <higher_value>);
ALTER TABLE <table_name>
ADD CONSTRAINT <constraint_name>
CHECK (<column_name>) > (<condition>); -
Performance Issue using min() and max() in one SQL statement
I have a simple query that selects min() and max() from one column in a table in one sql statment.
The table has about 9 Million rows and the selected column has a non unique index. The query takes 10 secs. When i select min() and max() in separate statements, each takes only 10 msecs:
This statement takes 10 secs:
select min(date_key) , max(date_key)
from CAPS_KPIC_BG_Fact_0_A
where date_key != TO_DATE(('1900-1-1' ),( 'YYYY-MM-DD'))
This statement takes 10 msecs:
select min(date_key)
from MYTABLE
where date_key != TO_DATE(('1900-1-1' ),( 'YYYY-MM-DD'))
union all
select max(date_key) from MYTABLE
Because the first statement is part of an autmatic generated SQL of an application, i can't change it and i have to optimize the data model. How can i speed up the first statement?I've ran similar query on a table that has 10 milliion rows, with an index on the date column
This is what I have found:
SQL> set timing on
1 SELECT MIN(ID_DATE) MIN_DATE, MAX(ID_DATE) MAX_DATE
2 FROM MY_DATE
3* WHERE ID_DATE != TO_DATE(('1900-1-1' ),( 'YYYY-MM-DD'))
SQL> /
MIN_DATE MAX_DATE
03-APR-76 06-JAN-02
real: 43383
SQL> SELECT MIN(ID_DATE) MIN_DATE FROM MY_DATE
2 WHERE ID_DATE != TO_DATE(('1900-1-1' ),( 'YYYY-MM-DD'))
3 UNION ALL
4 SELECT MAX(ID_DATE) MAX_DATE FROM MY_DATE
5 WHERE ID_DATE != TO_DATE(('1900-1-1' ),( 'YYYY-MM-DD'))
6 /
MIN_DATE
03-APR-76
06-JAN-02
real: 20
SQL> SELECT MIN_DATE, MAX_DATE FROM
2 (SELECT MAX(ID_DATE) MAX_DATE FROM MY_DATE
3 WHERE ID_DATE != TO_DATE(('1900-1-1' ),( 'YYYY-MM-DD')) ) A,
4 (SELECT MIN(ID_DATE) MIN_DATE FROM MY_DATE
5 WHERE ID_DATE != TO_DATE(('1900-1-1' ),( 'YYYY-MM-DD')) ) B
6 /
MIN_DATE MAX_DATE
03-APR-76 06-JAN-02
real: 10
SQL> My conculsion, there is nothing you can do to the tables that will improve that particular statement.
Why can't you modify the application? -
Formula for MIN and MAX per range required in BW
Good day
Please assist with the following? I need to create a formula (CKF) in BW Query which will give me the same result as the following formula in Excel.
What I have is one Key Figure and want to calculate a Score on that key figure.
Score =Key figure/(MAX(range of ie. column B1 to B50 which contains data for the same KF)-MIN(range of ie. column B50 which contains data for the same KF).
In excel it's easy, ie" Score =TD completed/(MAX(B28:B130)-MIN(B28:B130)
If more information is required to assist, please let me know?
Always appreciated.
CorneliusThank U so much for responding so fast.
I did the MIN and MAX formula, but it is only taking the MIN or MAX from the single cell of the applicable key figure and not from a 'range' of cells. This is a further example of what I want to do:
Cell: B1 = 10
B2 = 12
B3 = 15
B4 = 0
I want to display the MIN as '0' and the MAX as '15' and then do the calculation per row.
We are in 3.2x. I want to stay away from structures as I have not done that before.
Any other assistance will be highly appreciated.
Cornelius -
To find out the min and max memory been used by each parameter under SGA_MA
Hi,
Can any please tell me how to find out the min and max memory been used by each parameter under SGA_MAX and SGA_TARGET ? below is the db CRMS65T. If any such script is there please provide me
SQL> select name from v$database;
NAME
CRMS65T
SQL> show parameter sga
NAME TYPE VALUE
lock_sga boolean FALSE
pre_page_sga boolean FALSE
sga_max_size big integer 1000M
sga_target big integer 1000MThanks in advanceCan any please tell me how to find out the min and max memory been used by each parameter under SGA_MAX and SGA_TARGET ? below is the db CRMS65T. If any such script is there please provide meI guess your question is, each memory components of SGA? if so
SQL> select * from v$sgainfo;
NAME BYTES RES
Fixed SGA Size 2088504 No
Redo Buffers 18882560 No
Buffer Cache Size 616562688 Yes
Shared Pool Size 301989888 Yes
Large Pool Size 4194304 Yes
Java Pool Size 4194304 Yes
Streams Pool Size 0 Yes
Granule Size 4194304 No
Maximum SGA Size 947912704 No
Startup overhead in Shared Pool 125829120 No
Free SGA Memory Available 0Also check
SQL> select COMPONENT,CURRENT_SIZE,MIN_SIZE,MAX_SIZE,USER_SPECIFIED_SIZE from v$sga_dynamic_components;
shared pool 301989888 301989888 0 209715200
large pool 4194304 4194304 0 4194304
java pool 4194304 4194304 0 4194304
streams pool 0 0 0 0
DEFAULT buffer cache 616562688 616562688 0 603979776
KEEP buffer cache 0 0 0 0
RECYCLE buffer cache 0 0 0 0
DEFAULT 2K buffer cache 0 0 0 0
DEFAULT 4K buffer cache 0 0 0 0
DEFAULT 8K buffer cache 0 0 0 0
DEFAULT 16K buffer cache 0 0 0 0
DEFAULT 32K buffer cache 0 0 0 0
ASM Buffer Cache 0 0 0 603979776
13 rows selected.
SQL>Edited by: CKPT on Sep 19, 2011 8:55 AM -
Highlighting Min and Max Values on each line
Hello,
Is it possible to highlight the Min and Max values on each row of a Query. For example I have sales below by product line for the last seven quarters. The user
would like the Max value (150) for Product Line ABC Highlighted as Green and the Min value (1055) color coded as Red. Like wise for each line - DEF 200 as green and 100 as red and GHI - 400 as green and 100 as red.
FYQ Q207 Q307 Q407 Q108 Q208 Q308 Q408
ABC 1500 1200 1400 1050 1100 1100 1100
DEF 1550 1000 1560 1220 1340 1640 2000
GHI 1000 2000 3000 4000 3250 2220 3750
Is this possible using Exceptions? or may be any other means? We are on Bex 7.0
Best Regards,
SanjivHello Sanjiv,
I think it can be done by JavaScript, but needs more effort
[Use of JavaScript Functions|http://help.sap.com/saphelp_nw04/helpdata/en/d9/4a853bc623c075e10000000a114084/content.htm]
Try the exception available in the BW[BW Stylesheets|http://help.sap.com/saphelp_nw04/helpdata/en/3f/ca453afbf37b54e10000000a11402f/content.htm]
SAPBEXformats - Formatting cell (scaling factors)
SAPBEXexcGood1 - Exception with priority good 1
SAPBEXexcGood2 - Exception with priority good 2
SAPBEXexcGood3 - Exception with priority good 3
SAPBEXexcCritical4 - Exception with priority critical 4
SAPBEXexcCritical5 - Exception with priority critical 5
SAPBEXexcCritical6 - Exception with priority critical 6
SAPBEXexcBad7 - Exception with priority bad 7
SAPBEXexcBad8 - Exception with priority bad 8
SAPBEXexcBad9 - Exception with priority bad 9
See this thread,
Change the colour of a cell text depending on the value Web Reports (NW04s)
Thanks
Chandran
Edited by: Chandran Ganesan on Mar 19, 2008 4:27 PM
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