Error in union

SELECT distinct m_product_id,m_locator_id, sum(movementqty) AS opstk,to_char('0') as clstk,to_char('0') as movementqty,to_char('0')as MI,to_char('0') as INV,to_char('0') as GR,to_char('0') as GS,to_char('0') as MO
from m_transaction
where m_product_id='1136094' and m_locator_id='1000021'
and movementdate < '09-oct-2010'
GROUP BY m_product_id,m_locator_id
union
SELECT distinct m_product_id,m_locator_id, to_char('0') as opstk,sum(movementqty) AS clstk,to_char('0') as movementqty,to_char('0')as MI,to_char('0') as INV,to_char('0') as GR,to_char('0') as GS,to_char('0') as MO
from m_transaction
where m_product_id='1136094' and m_locator_id='1000021'
and movementdate <'22-oct-2010'
GROUP BY m_product_id,m_locator_id
when using this query it shows error message in oracle 10g
"expression must have same datatypes as corresponding expression"
How to rectify it.
please give suggestions urgent.

Hi,
you use sum, but in the opposite select a "to_char('0')", so the first one will be number, the second a char. Use just a "0" for the opposite of the sum:
SELECT distinct m_product_id,m_locator_id, sum(movementqty) AS opstk, 0 as clstk, 0 as movementqty, 0 as MI, 0 as INV,0 as GR,0 as GS,0 as MO
from m_transaction
where m_product_id='1136094' and m_locator_id='1000021'
and movementdate <'22-oct-2010'
GROUP BY m_product_id,m_locator_id
union
SELECT distinct m_product_id,m_locator_id, 0 as opstk,sum(movementqty) AS clstk, 0 as movementqty, 0 as MI, 0 as INV, 0 as GR,0 as GS,0 as MO
from m_transaction
where m_product_id='1136094' and m_locator_id='1000021'
and movementdate <'22-oct-2010'
GROUP BY m_product_id,m_locator_idHerald ten Dam
http://htendam.wordpress.com

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                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                               

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    SELECT saw_0 saw_0, saw_1 saw_1, saw_2 saw_2, saw_3 saw_3, saw_4 saw_4, saw_5 saw_5, saw_6 saw_6, saw_7 saw_7, saw_8 saw_8, saw_9 saw_9, saw_10 saw_10, SUM(saw_11 BY saw_10) saw_11, SUM(saw_12 BY saw_10 ) saw_12, SUM(saw_13 BY saw_10) saw_13, SUM(saw_14 BY saw_10) saw_14, SUM(saw_15 BY saw_10) saw_15, saw_16 saw_16 FROM (SELECT "- Protocol"."Protocol #" saw_0, "- Protocol"."Working Title" saw_1, CURRENT_DATE saw_2, "- Administration"."Display Currency Code" saw_3, "- Protocol"."Managing Country" saw_4, "- Protocol".Country saw_5, "- Protocol"."Country OPS" saw_6, "- Protocol"."EU Country" saw_7, "- Protocol"."GCO Region" saw_8, "- Protocol"."GPB Region" saw_9, "- Administration"."Study Cost" saw_10, SUM (IfNull("- Budget and Payment Facts"."Protocol Cost Line Item Amount - Display CCY",0) BY "- Administration"."Study Cost" ) saw_11, SUM(IfNull("- Budget and Payment Facts"."Committed Amount - Display CCY",0) BY "- Administration"."Study Cost") saw_12, SUM(IfNull("- Budget and Payment Facts"."Actual Amount - Display CCY",0) BY "- Administration"."Study Cost") saw_13, SUM(IfNull("- Budget and Payment Facts"."Amount Paid (SP) - Display CCY",0) BY "- Administration"."Study Cost") saw_14, SUM(IfNull("- Budget and Payment Facts"."Actual Amount - Display CCY",0)-IfNull("- Budget and Payment Facts"."Amount Paid (SP) - Display CCY",0) BY "- Administration"."Study Cost") saw_15, CASE WHEN "- Administration"."Study Cost" = 'Other' THEN 1 END saw_16 FROM "SPECTRUM Reporting" WHERE ("- Administration"."Display Currency Code" = 'USD') AND ("- Protocol"."Protocol #" = 'P31248') AND ("- Payment"."Payment Number"="- Payment"."Related Payment Request Number")
    UNION SELECT "- Protocol"."Protocol #" saw_0, "- Protocol"."Working Title" saw_1, CURRENT_DATE saw_2, "- Administration". "Display Currency Code" saw_3, "- Protocol"."Managing Country" saw_4, "- Protocol".Country saw_5, "- Protocol"."Country OPS" saw_6, "- Protocol"."EU Country" saw_7, "- Protocol"."GCO Region" saw_8, "- Protocol"."GPB Region" saw_9, "- Administration"."Study Cost" saw_10, IfNull("- Budget and Payment Facts"."Protocol Cost Line Item Amount - Display CCY",0) saw_11, IfNull("- Budget and Payment Facts"."Committed Amount - Display CCY",0) saw_12, 0.00 saw_13, 0.00 saw_14, 0.00 saw_15, CASE WHEN "- Administration"."Study Cost" = 'Other' THEN 1 END saw_16 FROM "SPECTRUM Reporting" WHERE ("- Administration"."Display Currency Code" = 'USD') AND ("- Protocol"."Protocol #" = 'P31248')) T GROUP BY saw_0, saw_1, saw_2, saw_3, saw_4, saw_5, saw_6, saw_7, saw_8, saw_9, saw_10 , saw_11, saw_12, saw_13, saw_14, saw_15, saw_16 ORDER BY saw_0, saw_1, saw_2, saw_3, saw_4, saw_5, saw_6

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  • Re Creating  a chart getting an error with a 'Union All' statement

    Hi
    I have some data to chart with the following fields;
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    My SQL to create the first point on the chart is as below;
    select null link, PRODUCT label, SUM(JUL-08) "FFF"
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    GROUP by PRODUCT
    ORDER BY PRODUCT
    This works fine until I want add the second point of this line graph using a 'union all' join as follows;
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    ORA-00937: not a single-group group function
    Certain queries can only be executed when running your application, if your query appears syntactically correct, you can save your query without validation (see options below query source).
    Can anyone assist?
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    OK, I thought each month would be separated by the different months in each selct subquery, but I see what you mean.
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    I then went on to use the '[ ]' brackets to separate data but this didn't fix the problem.
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    Use the following syntax:
    SELECT LINK, LABEL, VALUE
    FROM ...
    Or use the following syntax for a query returning multiple series:
    SELECT LINK, LABEL, VALUE1 [, VALUE2 [, VALUE3...]]
    FROM ...
    LINK URL
    LABEL Text that displays along a chart axis.
    VALUE1, VALUE2, VALUE3... Numeric columns that define the data values.
    Note: The series names for Column and Line charts are derived from the column aliases used in the query.
    My script amended;
    SELECT null link, PRODUCT label, PERIOD, SUM(ABC)
    FROM
    (SELECT null link, PRODUCT, 'JUL_08' PERIOD,SUM(JUL_08)ABC
    FROM BI_A_DATA.APEX_TEST
    WHERE PRODUCT = 'ABC'
    GROUP BY PRODUCT
    UNION ALL
    SELECT null link, PRODUCT, 'AUG_08' PERIOD,SUM(AUG_08)ABC
    FROM BI_A_DATA.APEX_TEST
    WHERE PRODUCT = 'ABC'
    GROUP BY PRODUCT
    UNION ALL
    SELECT null link, PRODUCT, 'SEP_08' PERIOD,SUM(SEP_08)ABC
    FROM BI_A_DATA.APEX_TEST
    WHERE PRODUCT = 'ABC'
    GROUP BY PRODUCT)
    GROUP BY link, PRODUCT, PERIOD

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    thanks for any info
    Edited by: user11176141 on 18-May-2009 03:15

    Thanks for the input!
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    SELECT activ_I, activ_C, cases.I_OCCASTYP_CASES, cases.C_OCCASTYP_CASES FROM TOCCASE cases JOIN (
    SELECT I activ_I, C activ_C, I_OCCASE_RESULTINGFROM, C_OCCASE_RESULTINGFROM FROM TOCPROCESSINSTANCE activ JOIN (
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    AND CHANGEDATE = (SELECT MAX(z.CHANGEDATE) FROM TOCTransferActivityChange z WHERE z.I_OCACTVTY_CHANGES = x.I_OCACTVTY_CHANGES AND z.C_OCACTVTY_CHANGES = x.C_OCACTVTY_CHANGES)
    ) latest_user_tx ON activ.I = latest_user_tx.I_OCACTVTY_CHANGES AND activ.C = latest_user_tx.C_OCACTVTY_CHANGES
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    UNION ALL
    SELECT I activ_I, C activ_C, I_OCCASE_RESULTINGFROM, C_OCCASE_RESULTINGFROM FROM TOCTASK activ JOIN (
    SELECT I_OCACTVTY_CHANGES, C_OCACTVTY_CHANGES FROM TOCTransferActivityChange x
    WHERE I_TO IN (2)
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    898221 wrote:
    Hi Experts,
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    (pppr.pega_program_competitors_id IS NULL AND (ppsr.manufacturer_status=''TRIAGE'' AND ppsr.manufacturer_reason=''COMPETITOR''))
    OR
    (ppsr.manufacturer_reason IS NULL)
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    pega_patient_program_reg pppr,health_care_profs hcp1, pega_program_status_reason ppsr ,
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    (ppsr.manufacturer_reason IS NULL)
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    pppr.id NOT IN(select pppd.PEGA_PATIENT_PROGRAM_REG_ID from PEGA_PATIENT_PROGRAM_DISPENSE pppd)';
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    ''rx01'' RX_REFILL
    FROM DUAL';
    then it is giving result.

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    Hi, guys.
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    Thanks in advance.

    I'm sorry.
    I've found my error. It was just necessary adjust the column mapping long propertie.
    Now, it's working.
    Sorry, again.
    Have a nice day.
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