Error while executing unix shell script from java program

Question

Hi All,
I am trying to execute unix shell script from a java program using Runtime.execute() method by passing script name and additional arguments.
Code snippet :
Java Class :
try{
     String fileName ="test.ksh";
     String argValue ="satish"; // value passed to the script
     String exeParam = "/usr/bin/ksh "+fileName+" "+argValue;
     Process proc = Runtime.getRuntime().exec(exeParam);
     int exitValue = proc.waitFor();
     sop("Exit Value  is : "+exitValue);
catch(Exception e)
e.printStackTrace();
}Test.ksh
  export -- application realated paths..
  nohup  abc.exe 1> test.log 2>&1;
  $1
  exit.By running the above java class , i am getting exit Value: 139 and log file test.log of 0 bytes.
when i am running the same command (/usr/bin/ksh test.ksh satish) manually, it's calling abc.exe file successfully
and able generate the logs properly.
Pls let us know where exactly i am stuck..
Thanks in advance,
Regards,
Satish

Answer 1

Hi Sabre,
As per the guidelines provided by the article, i had done below changes..
InputStream is = null;
InputStreamReader iStreamReader = null;
BufferedReader bReader = null;
String line = null;
try{
String fileName ="test.ksh";
String argValue ="satish"; // value passed to the script
String exeParam = "/usr/bin/ksh "+fileName+" "+argValue;
Process proc = Runtime.getRuntime().exec(exeParam);
is = proc.getErrorStream();
iStreamReader = new InputStreamReader(is);
bReader = new BufferedReader(iStreamReader);
System.out.println("<ERROR>");
while((line = bReader.readLine()) != null)
System.out.println("Error is : "+line);
System.out.println("</ERROR>");
int exitValue = proc.waitFor();
sop("Exit Value is : "+exitValue);
catch(Exception e)
e.printStackTrace();
Now , it's showing something like..
<ERROR>
</ERROR>