Evenly space shape into rows and columns

I have a vector square shape that I want to make a grid out of (basically like below). My problem is that I want to space the squares equally apart. Trying to eyeball it simply isn't precise enough and the grid snap isn't that precise either. Anyway to do this more scientifically and with more precision?

Another way
1 Draw one of the squares
2 Go to Distort and Transform>Transform> enter a horizontal move equal tothe width of the square plus the spce you want between the squares
3. Enter 3 for the number of copies
4. Select the path in the appearance panel and do the same for the vertical moves as you did for the horizontal moves
Notice below there are two transforms effect in the Appearane Panel.

Similar Messages

  • Help! Inserting a 1-D comment array into a 2-D string array at specified row AND column

    Hello everyone,
    I am writing a 2-D string array to excel and i need a way to add comments to my file like this:  
    SLAM    NAME    G Level    Comments
    1              RALF         26               
    1              RALF         26
    1              RALF         26
    1              RALF         26
    For some reason, i cannot specify a row AND column to write because: 
    When i use replace array subset it only replaces 1 element at my index. 
    When i use replace array subset with a loop, it creates empty spaces until it reaches the end of the array it is replacing.
    When i use Insert into array: i cannot wire 2 inputs for row and column.  
    In my complete VI i will need to write from row 1-1001, a different comment from 2-2002, a different comment from 3-3003, etc until a stop condition is met so i need to figure out how to do this programatically and not have it replace any elements outside of the range or it will override previous commetns. 
    I am at a loss of what to do. Any and all suggestions are greatly appreciated. 
    Thanks!
    Solved!
    Go to Solution.
    Attachments:
    array.vi ‏13 KB

    Hi proph,
    I made a small subtile change to yur VI and now it replaces all values of the 4th column…
    THINK DATAFLOW!
    Use shift registers when you need to propagate values from one loop iteration to the next!
    USE/LEARN DEBUGGING TECHNIQUES!
    There are tools like probes and highlight to understand your VI execution and to find problems…
    Go through all those free online courses offered by NI!
    Best regards,
    GerdW
    CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
    Kudos are welcome
    Attachments:
    array.vit ‏12 KB

  • How Calculate more than one value and store it into to different rows and column for each input?

    thx guys.....i have a progress now in LV
    But now i have new trouble here. Ok i attached my LV file (LV 7.0.1/7.1) and excel form. I just could'nt calculate more than one input value. I want a different result for each value that i enter ... and store it into different rows and column. But it just store at one row.
    Attachments:
    My Project.vi ‏31 KB
    rumus motor bakar.xls ‏14 KB

    duplicate post

  • How do I delete multiple rows and columns in an image?

    I am looking into how digital SLRs extract video data from a CMOS sensor. To give an example, the GH1 from Panasonic can record video at 1920 x 1080 from a 12 MPixel sensor that, say, is 4000 horizontal x 3000 vertical. How they do that seems to be not in the public domain, but there have been a few guesses (see http://www.dvxuser.com/V6/showthread.php?t=206797 and http://luminous-landscape.com/forum/index.php?showtopic=38713).
    One approach would be to simply read every second row of sensor pixels (1500 rows read from the original 3000) and once you have those in memory, delete every second column (2000 columns left). You would end up with a 2000 x 1500 image which could then be resampled to 1920 x 1080.
    I'd like to simulate what the camera appears to be doing, by generating a 4000 x 3000 test image and then asking Photoshop CS4 to delete the appropriate rows and columns. It may not necessarily be every second row; the Canon 5DMk11 appears to read every third row, so I may need to delete two out of every three rows.
    Can Photoshop do that sort of thing? If so, how?

    Thanks for the suggestions. Yes, I did take a detailed look at your images, but they weren't 100% convincing because it wasn't clear just what was happening. And Adobe's explanation, after reading it again, explains nothing at all to someone who doesn't know how Nearest Neighbor works.
    But you are correct -- Nearest Neighbor does effectively delete pixels. I proved it with the attached 6 x 6 image of coloured pixels (the tiny midget image right after this full stop -- you'll have to go to maximum zoom in PS to see it).
    These are the steps to delete every second row and then every second column.
    1. Select Image > Image Size.
    2. Set Pixel Dimensions > Height to half the original (in this case set to 3 pixels).
    3. Set Resample Image to Nearest Neighbor.
    4. Click OK and the image shoould now consist of three vertical white strips and three vertical Green-Red-Blue stripes.
    5. Repeat steps 1-4, but this time set Pixel Dimensions > Width to half the original (in this case set to 3 pixels). The image should now consist of three horizontal stripes Green-Red-Blue.
    Just to make sure the method worked for every third pixel, I repeated the above steps but with 2 pixels instead of 3 and obtained the correct White-Green, White-Green pattern.
    I resampled the Height and Width separately for the test so that I could see what was happening. In a real example, the height and width can be changed at the same time in the one step, achieving the same results as above.
    Finally, how to explain how Nearest Neighbor works in the simple cases described above?
    Division by 2
    In the case of an exact division by two (pixels numbered from top leftmost pixel), only the even numbered rows and columns remain. To put it a different way, every odd numbered row and column are deleted.
    Division by 3
    Only rows and columns 2, 5, 8, 11... remain.
    Division by N
    Only rows and columns 2, 2+N, 2+2N, 2+3N... remain.
    To put it simply, a resample using Nearest Neighbor (using an exact integer multiple) keeps every Nth row and column, starting from number two. The rest are deleted.

  • Setting number of rows and columns

    How do I set the number of rows and columns of a table, say 2348 rows by 3 columns?
    Then how do I quickly select the last row?
    Also, if I enter a formula in row 1 column 2, how do I quickly copy that formula down to row 1435, or to the end of the column? Dragging seems slow and awkward.

    I wish to add a few words to Jerrold responce.
    gjf12 wrote:
    How do I set the number of rows and columns of a table, say 2348 rows by 3 columns?
    Then how do I quickly select the last row?
    Also, if I enter a formula in row 1 column 2, how do I quickly copy that formula down to row 1435, or to the end of the column? Dragging seems slow and awkward.
    The process that you describe is inefficient.
    The efficient one is :
    create a table
    enter the formulas in a single row
    delete the rows below.
    Now, each newly inserted row will contain the formulas.
    From my point of view, it's when this is done that it will be interesting to apply a script adding rows.
    Here is a script inserting rows.
    --[SCRIPT insertRows]
    Enregistrer le script en tant que Script : insertRows.scpt
    déplacer le fichier ainsi créé dans le dossier
    <VolumeDeDémarrage>:Users:<votreCompte>:Library:Scripts:Applications:Numbers:
    Il vous faudra peut-être créer le dossier Numbers et peut-être même le dossier Applications.
    Sélectionner une cellule au-dessous de laquelle vous voulez insérer des lignes.
    menu Scripts > Numbers > insertRows
    Le script vous demande le nombre de lignes désiré puit insère celles-ci.
    --=====
    L'aide du Finder explique:
    L'Utilitaire AppleScript permet d'activer le Menu des scripts :
    Ouvrez l'Utilitaire AppleScript situé dans le dossier Applications/AppleScript.
    Cochez la case "Afficher le menu des scripts dans la barre de menus".
    --=====
    Save the script as a Script: insertRows.scpt
    Move the newly created file into the folder:
    <startup Volume>:Users:<yourAccount>:Library:Scripts:Applications:Numbers:
    Maybe you would have to create the folder Numbers and even the folder Applications by yourself.
    Select a cell below which you want to insert rows.
    menu Scripts > Numbers > insertRows
    The script ask you the number of rows to insert then it does the required insertion.
    --=====
    The Finder's Help explains:
    To make the Script menu appear:
    Open the AppleScript utility located in Applications/AppleScript.
    Select the "Show Script Menu in menu bar" checkbox.
    Save this script as a … Script in the "Folder Actions Scripts" folder
    <startupVolume>:Library:Scripts:Folder Action Scripts:
    --=====
    Yvan KOENIG (VALLAURIS, France)
    2010/01/13
    --=====
    on run
    set defaultValue to 100
    if my parleAnglais() then
    set myInteger to my askAnumber("Insert how many rows ?", defaultValue, "i")
    else
    set myInteger to my askAnumber("Combien de lignes voulez-vous insérer ?", defaultValue, "i")
    end if
    set {dName, sName, tName, rname, rowNum1, colNum1, rowNum2, colNum2} to my getSelParams()
    tell application "Numbers" to tell document dName to tell sheet sName to tell table tName
    repeat myInteger times
    add row below row rowNum2
    end repeat
    end tell
    end run
    --=====
    on getSelParams()
    local r_Name, t_Name, s_Name, d_Name, col_Num1, row_Num1, col_Num2, row_Num2
    set {d_Name, s_Name, t_Name, r_Name} to my getSelection()
    if r_Name is missing value then
    if my parleAnglais() then
    error "No selected cells"
    else
    error "Il n'y a pas de cellule sélectionnée !"
    end if
    end if
    set two_Names to my decoupe(r_Name, ":")
    set {row_Num1, col_Num1} to my decipher(item 1 of two_Names, d_Name, s_Name, t_Name)
    if item 2 of two_Names = item 1 of two_Names then
    set {row_Num2, col_Num2} to {row_Num1, col_Num1}
    else
    set {row_Num2, col_Num2} to my decipher(item 2 of two_Names, d_Name, s_Name, t_Name)
    end if
    return {d_Name, s_Name, t_Name, r_Name, row_Num1, col_Num1, row_Num2, col_Num2}
    end getSelParams
    --=====
    set {rowNumber, columnNumber} to my decipher(cellRef,docName,sheetName,tableName)
    apply to named row or named column !
    on decipher(n, d, s, t)
    tell application "Numbers" to tell document d to tell sheet s to tell table t to return {address of row of cell n, address of column of cell n}
    end decipher
    --=====
    set { d_Name, s_Name, t_Name, r_Name} to my getSelection()
    on getSelection()
    local _, theRange, theTable, theSheet, theDoc, errMsg, errNum
    tell application "Numbers" to tell document 1
    repeat with i from 1 to the count of sheets
    tell sheet i
    set x to the count of tables
    if x > 0 then
    repeat with y from 1 to x
    try
    (selection range of table y) as text
    on error errMsg number errNum
    set {_, theRange, _, theTable, _, theSheet, _, theDoc} to my decoupe(errMsg, quote)
    return {theDoc, theSheet, theTable, theRange}
    end try
    end repeat -- y
    end if -- x>0
    end tell -- sheet
    end repeat -- i
    end tell -- document
    return {missing value, missing value, missing value, missing value}
    end getSelection
    --=====
    on decoupe(t, d)
    local l
    set AppleScript's text item delimiters to d
    set l to text items of t
    set AppleScript's text item delimiters to ""
    return l
    end decoupe
    --=====
    Asks for an entry and checks that it is an floating number
    set myInteger to my askAnumber(Prompt, DefaultValue, "i")
    set myFloating to my askAnumber(Prompt, DefaultValue, "f")
    on askAnumber(lPrompt, lDefault, ForI)
    local lPrompt, lDefault, n
    tell application (path to frontmost application as string)
    if ForI is "f" then
    set n to text returned of (display dialog lPrompt & " (" & (1.2 as text) & ")" default answer lDefault as text)
    try
    set n to n as number (* try to convert the value as an number *)
    return n
    on error
    if my parleAnglais() then
    display alert "The value needs to be a floating number." & return & "Please try again."
    else
    display alert "La valeur saisie doit être un nombre décimal." & return & "Veuillez recommencer."
    end if
    end try
    else
    set n to text returned of (display dialog lPrompt default answer lDefault as text)
    try
    set n to n as integer (* try to convert the value as an integer *)
    return n
    on error
    if my parleAnglais() then
    display alert "The value needs to be an integer." & return & "Please try again."
    else
    display alert "La valeur saisie doit être un nombre entier." & return & "Veuillez recommencer."
    end if
    end try -- 1st attempt
    end if -- ForI…
    end tell -- application
    Here if the first entry was not of the wanted class
    second attempt *)
    tell application (path to frontmost application as string)
    if ForI is "f" then
    set n to text returned of (display dialog lPrompt & " (" & (1.2 as text) & ")" default answer lDefault as text)
    try
    set n to n as number (* try to convert the value as an number *)
    return n
    on error
    end try
    else
    set n to text returned of (display dialog lPrompt default answer lDefault as text)
    try
    set n to n as integer (* try to convert the value as an integer *)
    return n
    on error
    end try -- 1st attempt
    end if -- ForI…
    end tell -- application
    if my parleAnglais() then
    error "The value you entered was not numerical !" & return & "Goodbye !"
    else
    error "La valeur saisie n’est pas numérique !" & return & "Au revoir !"
    end if
    end askAnumber
    --=====
    on parleAnglais()
    local z
    try
    tell application "Numbers" to set z to localized string "Cancel"
    on error
    set z to "Cancel"
    end try
    return (z is not "Annuler")
    end parleAnglais
    --=====
    --[/SCRIPT]
    Yvan KOENIG (VALLAURIS, France) mercredi 13 janvier 2010 12:43:34

  • How can i open a PDF bank statement in numbers so that the rows and columns contain properly aligned data from statement?

    how can i open a PDF bank statement in "numbers" so that the rows and columns contain properly aligned data from statement?

    Numbers can store pdfs pages or clippings but does not directly open pdf files.  To get the bank statement into Numbers as a table I would open the bank statment in Preview (or Skim) or some pdf viewer.
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  • Is it possible to switch the rows and columns?

    Is it possible to switch the rows and columns of a table? The reason I ask is that it would be easier for me to input the data with the number at the top of a column and the fields going down. But it would be easier to read the data with the number on the left and the fields going to the right. Is it possible to switch a table in this way?

    mahongue wrote:
    Is it possible to switch the rows and columns of a table? The reason I ask is
    that it would be easier for me to input the data with the number at the top
    of a column and the fields going down. But it would be easier to read the
    data with the number on the left and the fields going to the right. Is it
    possible to switch a table in this way?
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    Table 1
        A   B   C
    ========
    1   o   p   q
    2   r   s   t
    3   u   v   w
    Table 2
        A   B   C
    ========
    1   o   r   u
    2   p   s   v
    3   q   t   w
    You are right - it would be nice to have a menu item to magically transpose a selected block of cells. But there isn't one. So...
    One way to solve this is to use the index() and transpose() functions to accomplish row and column cell transposition. If you are going to use a 1:1 cell correspondence and change the header columns and rows also, you can use this:
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       =INDEX(TRANSPOSE(Table 1 :: $A$1:$C$3),ROW(),COLUMN())
    Create a second table. Copy the modified formula above with the appropriate substitutions, select the range you wish to have your transposition inserted into (must match the transposed cell dimensions of the original range), paste the forumula and voila! the cells will be transposed.
    Cautions:
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  • Hi, how can i break the value for a row and column once i have converted the image to the array?????​??

    Hi, I would like to know how can i break the value for a row and column once i have converted the image to the array. I wanted to make some modification on the element of the array at a certain position. how can i do that?
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    Hi,
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    I manage to change the array element by changing the row and column value. But, what i want is to allow the program to change the array element at a specified row and column value, where the new value is generated automatically by the program.
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    Attachments:
    arrayrowncolumn2.JPG ‏64 KB

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    Hi Marlin..
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    working on a league table
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  • Set maximum matrix row and column size

    I hope someone can help me with this. Is there any way to set the row and column size of a matrix control? I have not been able to find a solution. The only way I've been able to set the size is by resetting matrix to its previous state if the user inputs a value outside of the bounds I would like to set. This is done in the 'value changed' event case.
    The matrix is large and therefore I cannot increase the size of the control to be the maximum size and then hide the row and column index controls. These have to be displayed.
    Any suggestions or help would be greatly appreciated. Thanks in advance.

    Here's a quick and dirty way.
    Simply hide the index controls and replace them with some fake numeric controls and set the data range accoding to your requirements.
    In the attached example (LV8.0), the fake index controls are limited to 0..2, the array size is 5x5 and the displayed array portion is 3x3. Seems to work fine.
    (Of course you could add a bit more code to set the limits automatically based on the various sizes.)
    You could also make it more fancy and turn the entire thing into an Xcontrol.
    Message Edited by altenbach on 06-06-2007 05:32 PM
    LabVIEW Champion . Do more with less code and in less time .
    Attachments:
    LimitArrayControl.vi ‏18 KB

  • I need to take elements from within 2 nested for loops and place them in an array at the specific row and column that I need.

    I have tried intializing an array and replacing elements by specifying a particular row, and column, but in the end I get an array with only one element replaced, and I suspect that it is because as the for loops are running through their iterations each time the array is re-initializing. I have a simple vi that I will post below, it is not the exact situation that I have but is a good place for me to get some understanding. I have the row and column indexes being driven by the inner and outer loop iterations, which gives me the pattern I need. I am using the inner iterations as array elements. How do I set this up so that it works and d
    oes keep re-initializing my array.
    Attachments:
    Untitled.vi ‏26 KB

    I have fixed a number of things in your vi.
    You were right in thinking that the array was continuously re-initialized. To avoid this, use a shift register (right-click the loop border), which will pass the updated array into the next iteration.
    Chilly Charly    (aka CC)
             E-List Master - Kudos glutton - Press the yellow button on the left...        
    Attachments:
    your_vi.vi.zip ‏13 KB

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