Exact same request works in browser but not in my app!!!

Question

Hello all, I have an application that posts requests through an https connection to a web server. When everything goes well, the server is supposed to send me an xml file. Once my String is encoded and ready to be sent, it looks something like this:
InputSegments=%3c%3fxml+version%3d%221.0%22+encoding%3d%22UTF-8%22%3f%3e%3cCNCustTransmitToEfx+So when I send it, I receive an error from the server saying that the request is incorrect. But when I copy paste the request String to the browser, it works great!!! I tried to change requestMethod to GET, but I still get the error message from the server. So I can't figure out what is wrong here... I am posting my function hoping that somebody will be able to help me:
private static class SecuredConnectionInstantiator extends Thread
    public boolean stop = false;
    private int returnCode = -1;
    private String securedUrl = null;
    private String xmlRequest = null;
    private String outputFile = null;
    public void run()
      try
        URL objUrl = null;
        HttpsURLConnection urlc = null;
        String inputLine = null;
        StringBuffer xmlResponse = null;
        xmlResponse = new StringBuffer();
        objUrl = new URL(securedUrl);
        urlc = (HttpsURLConnection)objUrl.openConnection();
        if (urlc == null || objUrl == null)
          throw new MalformedURLException();
        urlc.setUseCaches(false);
        urlc.setDoInput(true);
        urlc.setDoOutput(true);
        urlc.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
        urlc.setRequestMethod("POST");
        OutputStream out = urlc.getOutputStream();
        OutputStreamWriter writer = new OutputStreamWriter(out);
        String tmp = encode(xmlRequest);
        tmp = "InputSegments=" + tmp + "&cmdSubmit=Submit";
        System.out.println(tmp);
        writer.write(tmp);
        writer.flush();
        writer.close();
        //Si le thread n'a pas �t� intterompu, on obtient la r�ponse et on
        //l'enregistre sur disque.
        if (!stop)
          BufferedReader xmlResponseReader = new BufferedReader(new InputStreamReader(objUrl.openStream()));
          BufferedWriter xmlFileWriter = new BufferedWriter(new FileWriter(outputFile));
          while ((inputLine = xmlResponseReader.readLine()) != null)
            xmlResponse.append(inputLine + EOL);
            xmlFileWriter.write(inputLine);
            xmlFileWriter.flush();
          xmlResponseReader.close();
          xmlFileWriter.close();
          //La requ�te s'est termin�e normalement...
          returnCode = 0;
      catch (MalformedURLException e)
        //Erreur lors de l'appel...
        //returnCode = code d'erreur...
      catch (IOException e)
        //Erreur d'E/S...
        //returnCode = code d'erreur...
    }Your help will be greatly appreciated!
Alex

Answer 1

I solved the problem, I dont know if it's a good way to do this, but here's what I've done: Instead of opening a connection to the server and the send the request throug the stream, I open the connection and pass the request next to the server's address:
        xmlResponse = new StringBuffer();
        objUrl = new URL(securedUrl + "?InputSegments=" + URLEncoder.encode(xmlRequest, "UTF-8") + "&cmdSubmit=Submit");
        urlc = (HttpsURLConnection)objUrl.openConnection();Anyway thank you all for your help!