Exchange Query - regarding to Multiple NIC

Dear All ,, I hope you are well , my query ,,, we have in my environment exchange server , 3- Exchange , two in the same site and another in the other site , we have DAG involved all Previous server , we add new NIC to a single server with a different
subnet mask ,,, but this NIC can be reachable from other server ,,, i tested through ping,,, Tracer route ,,, ran failover cluster and everything goes well but when i see Status network card i saw just Sent Packet , Receive Dropped 0 ,,,,,
and when i go to event viewer i see error in Eventid 2604..2501..2601 ,So i need someone explain to me what is mean sent packet and no receive packet ,,,, i need help

Hi,
As far as I know, the event error is mostly likely caused by the network issue:
http://support.microsoft.com/kb/2025528
To find the root cause of no receive package, we can use Network Monitor to detect the NIC.
And here is a reference about more troubleshooting of NIC:
http://support.microsoft.com/kb/325487
Additionally, you’re welcomed to confirm the network issue on our following forum:
http://social.technet.microsoft.com/Forums/windowsserver/en-US/home?category=windowsserver
Thanks,
Angela Shi
TechNet Community Support

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Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact [email protected] .

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Ok, I will clear myself with the following example :
class First
int a;
static int b;
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synchronized((Integer) b)
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Now, first my-thoughts; kindly correct me if I am wrong :
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Ashutosh

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b) In case 2, we have a non-static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.obj1/2 don't call methods or try to obtain locks. The two different threads do that. And you mean First.b, not obj1.b and obj2.b, but see also below.
d) In case 4, we have a static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.Again, obj1/2 don't call methods or try to obtain locks. The two different threads do that. And again, you mean First.b. obj1.b and obj2.b are the same as First.b. Does that make it clearer?
Now, I have a query : what happens if the call is made in a classically static manner, i.e. using the statement "First.func_four;".That's what happens in any case whether you write obj1.func_four(), obj2.func)four(), or First.func_four(). All these are identical when func_four(0 is static.
Now, consider this, suppose we have the same reference obj1, in two threads, and the call "obj1.func_four;" happens to occur at the same time from each of these threads. Thus, we have obj1 rying to obtain lock for obj1.aNo we don't, we have a thread trying to obtain the lock on First.b.
and again obj1 trying to obtain lock for obj1.aYou mean obj2 and First.b, but obj2 doesn't obtain the lock, the thread does.
which are the same locks. So, if obj1.a of the first thread obtains the lock, then it will enter the function no-doubt, but the call from the second thread will also succeed.Of course it won't. Your reasoning here makes zero sense..Once First.b is locked it is locked. End of story.
Thus, effectively, our synchronisation is broken.No it isn't. The second thread will wait on the same First.b object that the first thread has locked.
However in any case you have a much bigger problem here. You're autoboxing your local 'int' variable to a possibly brand-new Integer object every call, so there may be no synchronization at all.
You need:
Object a = new Object();
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Regards,
Vivek V

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