Extended Replace with Regular Expressions

I am trying to figure out how to user regular expressions in
HomeSite 5.5 extended search and replace.
I am trying to find all matches to: <span
class="someClass">FooText</span>
And replace with: <sometag>FooText</sometag>
I have been able to get the find part working with reg ex:
<span class=\"someClass\">*[A-Za-z0-9_
><.="']*</span>
However, I have not been able to figure out what to put in
the replace box. I have tried different combinations of syntax with
"\1" for the first match of the reg ex in the search field, but
nothing has worked.
Can someone help me out with the syntax for what I should
enter in the replace field?

SQL>with t as(
  2   select 1 id,'a   aa ---- ss-ee -' str from dual union
  3   select 2, 'a        aa -------- ss-ee ---- - - -' str from dual union
  4   select 3, '-' str from dual union
  5   select 4, '----- -- -a -' str from dual union
  6   select 5, '-a-a-a-a----a-a-a-' str from dual
  7  )
  8  select id,
  9  str,
10  trim(trim('-' from regexp_replace(str, '( |-){2,}', '\1'))) new_str,
11  length(str) len,
12  length(trim(trim('-' from regexp_replace(str, '( |-){2,}', '\1')))) new_len
13  from t;
ID STR                                 NEW_STR                      LEN          NEW_LEN
  1 a   aa ---- ss-ee -                 a aa ss-ee                    19               10
  2 a     aa -------- ss-ee ---- - - -  a aa ss-ee                    34               10
  3 -                                                                  1
  4 ----- -- -a -                       a                             13                1
  5 -a-a-a-a----a-a-a-                  a-a-a-a-a-a-a                 18               13

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  • Replace replace with regular expression possible?

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    What is the best way to replace input string with following rules:
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    SQL>with t as(
      2   select 1 id,'a   aa ---- ss-ee -' str from dual union
      3   select 2, 'a        aa -------- ss-ee ---- - - -' str from dual union
      4   select 3, '-' str from dual union
      5   select 4, '----- -- -a -' str from dual union
      6   select 5, '-a-a-a-a----a-a-a-' str from dual
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      5 -a-a-a-a----a-a-a-                  a-a-a-a-a-a-a                 18               13

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    I really appreciate the inclusion of the Regular Expressions in the search & replace feature. One thing I am missing is back-references in the replacement expression. For instance, in the unix tools vi or sed, I might do something like this:
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    duplicate of Grouping & Back-references with regular expressions on Replace Text window

  • Replace without regular expressions

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  • Problem with Regular Expression

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  • Replace string with regular expression

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    caesarkim1 wrote:
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  • Help with regular expression to find a pattern in clob

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    < MI>
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    < ADDR1>ADDR1
    < ADDR2>^@~*
    < CITY>CITY
    <EMPID>1
    < UNQID>123456
    < TIMESTAMP>...
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    < TITLE>^@~*
    < FIRST>ABCD
    < MI>
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    < TITLE>^@~*
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    Regards
    Etbin
    Message was edited by: Etbin
    used listagg to report more than one multiple <EMPID>

  • Help with Regular Expressions

    I have some sample code for string editing using regular expressions but I'm a little confused as to it's behavior. Here's what I have:
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    JFactor2004 wrote:
    I have some sample code for string editing using regular expressions but I'm a little confused as to it's behavior. Here's what I have:
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    JFactor2004 wrote:
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    JFactor2004 wrote:
    so shouldn't this work by just changing replaceFirst to replace?Nope, see the explanation above.

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