Extracting a string from a URL using regular expression

Question

Given the following expression:
"^.*" + "http://www\\.xyz\\.gov/class/"+ "([0-9]+)";
I would expect that if i pass the string "http://www.xyz.gov/class/17950142?dopt=abstract" it should match to everything up to the ? character.
Why does it not do that in the following code snippet?
public class RegexTester {
  private final static String EPR_TYPE_1 = "http://www\\.xyz\\.gov/class/";
  public static void main(String args[]){
  String testRegex = "^.*" + EPR_TYPE_1 + "([0-9]+)";
  String testString = "http://www.xyz.gov/class/17950142?dopt=abstract";
  Pattern PATTERN = Pattern.compile(testRegex, Pattern.CASE_INSENSITIVE);
  Matcher m = PATTERN.matcher(testString);
  if(m.matches()) {
  System.out.println(m.group(1));
  }else{
  System.out.println("No match");
I tried the same expression and string in an online regex tester and it seems to work See example here RegExr

Answer 1

index4 = line.indexOf( "@photo" );
String strUid = line.substring(index4,-10);I assumed that index4 would be around 30 as it starts
at around the 30th character in the string line. And
then if i wanted the 10 characters preceding this to
use -10.
It throws an out of bounds exception thoughIt will as the 2nd parameter is -10 which is before the start of the string
you need
String strUid = line.substring(index4 - 10 , index4);