Find the difference between two columns in an ssrs matrix ? MSCRM
Hi All,
I am working in reporting part of our project (On-line MSCRM 2013) & in reporting services.
I am trying to create report using fetch xml based. Below is the snap what we required the result.
Kindly help me, how to get the difference in both column. (Its a matrix table where year is grouped).
We need difference between both year Like (Plan Revenue of 2013 & Plan Revenue of 2014 difference in Plan Revenue Diff section) and same for Actual
Revenue.
https://social.microsoft.com/Forums/en-US/054d5ca4-0d38-4dc6-84a8-88866cc228fe/find-the-difference-between-two-columns-in-an-ssrs-matrix-mscrm?forum=crmdevelopment
Thanks,
Mohammad Sharique
Hi Bro,
I used parametrized option for year and done the report,Currently we are getting values in Difference column now i want to show
that value in percentage. How can we show the percentage based on that value. Means i want to show the Difference in Percentage.
Kindly help me i tried but getting some issue. Below i am mentioning the code and snap with result.
Below expression using to showing Plan Revenue in Percentage for year.
=
Sum(IIF(Fields!new_year.Value =Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
- Sum(IIF(Fields!new_year.Value =Parameters!EndYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
/IIF(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))>0,
(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0))))
,1)
)*100))
Result issue is as below in snap with highlighted in red colour.
Kindly help me on this issue also :)
Similar Messages
-
Need to find the Difference between two table
Hello ,
I have stucked in program as below scenario:-
I have two tables of huge data of same structure in a same schema.I need to find the difference exact values in tables.
By using MINUS we can find the difference between two table ,i need to find the what exact difference in the there values with colunm and value at that column.
Example TableA
Col1 col2 col3 col4 col5.... col50
10 ABC 2001 EE 444 TT
40 XYZ 3002 RR 445 TT3
80 DEF 6005 YY 446 YY8
TableB
Col1 col2 col3 col4 col5.... col50
10 ABC 2001 EE 444 TT
40 XYZ 3002 RR 445 TT3
81 DEF 6005 Yu 447 YY8
I need to the out put like this :-
The Diffence between two table is
TableA.COL1=80 TableB.Col1=81, Different
TableA.Col4=YY TableB.col4=Yu,Different
TableA.Col5=446TableB.col5=447,Different
Please suggest me to write the pl/sql program for the same
thanx in advance
KKThanx friends for all your efforts
I have a sample code for the same,this will compare the two tables for single row in each table .
what r the modification needed for the multiple rows of values in the two tables??
Please suggest!!
CREATE OR REPLACE PROCEDURE test_compare
IS
TYPE t_col
IS
TABLE OF VARCHAR2 (30)
INDEX BY PLS_INTEGER;
l_col t_col;
j NUMBER := 0;
l_sql VARCHAR2 (2000);
col1 VARCHAR2 (30);
col2 VARCHAR2 (30);
val1 NUMBER;
val2 NUMBER;
status VARCHAR2 (30);
CURSOR c1
IS
SELECT column_id, column_name
FROM all_tab_columns
WHERE table_name = 'TEST1';
BEGIN
FOR i IN c1
LOOP
j := j + 1;
l_col (j) := i.column_name;
END LOOP;
FOR k IN 1 .. j
LOOP
l_sql :=
'SELECT '
|| ''''
|| l_col (k)
|| ''''
|| ', '
|| 'TEST2.'
|| l_col (k)
|| ', '
|| ''''
|| l_col (k)
|| ''''
|| ', '
|| 'TEST1.'
|| l_col (k )
|| ', '
|| 'DECODE(TEST2.'
|| l_col (k)
|| ' -TEST1.'
|| l_col (k)
|| ', 0, ''NO CHANGE'', ''CHANGED'') FROM TEST2, TEST1';
EXECUTE IMMEDIATE l_sql INTO col1, val1,col2, val2, status;
IF status = 'CHANGED'
THEN
DBMS_OUTPUT.put_line( 'TEST2.'
|| col1
|| '='
|| val1
|| ', TEST1.'
|| col2
|| '='
|| val2
|| ', '
|| status);
END IF;
END LOOP;
EXCEPTION
WHEN OTHERS
THEN
DBMS_OUTPUT.put_line ('Error:- ' || SQLERRM);
END;
/ -
How to get the difference between two columns in a column group
Hi All,
My first time here and really new to programming. I would like to get the difference between 2 columns that are inside
a column group.
Here is my sample table below: The Column Group is PeriodNumber and can only choose 2. like 1 and 2.. I would like to have a third row which will simply calculate the difference between the amounts in PeriodNumber 1 and 2.
PeriodNumber
Account 1 2
1) Cash 10,000 15,000
2) Receivables 12,000 11,500
3) Equipment 5,000 5,500
Total Assets 27,000 32,000Hi yabgestopa,
From your description, you want to get the difference between two columns in a column group. After testing it in my environment, we can use custom code to achieve your requirement. For more details, you can refer to the following steps:
Copy the custom code below and paste it to your report. (Right-click report>Report Properties>Code)
Dim Shared Num1 As Integer
Dim shared Num2 As Integer
Public Function GetAmount(Amount as Integer, Type as String)
If Type = "1" Then
Num1=Amount
Else
Num2=Amount
End If
Return Amount
End Function
Public Function GetDif()
Return Num1-Num2
End function
Right-click the second column to insert a third column with Outside Group-Right.
Then use the expressions below in the matrix.
=Code.GetAmount(Fields!Amount.Value,Fields!PeriodNumber.Value)
=code.GetAmount(Sum(Fields!Amount.Value),Fields!PeriodNumber.Value)
=Code.GetDif()
The report looks like below.
If you have any questions, please feel free to ask.
Thanks,
Katherine Xiong
Katherine Xiong
TechNet Community Support -
Extract Time from date and Time and Need XLMOD Funtion to find the Difference between Two Time.
X6 = "1/5/15 5:16 AM" & NOW ....................difference by Only Time
not date
X6 date and Time will be changing, Its not Constant
Dim myDateTime As DateTime = X6
Dim myDate As String = myDateTime.ToString("dd/MM/yy")
Dim myTime As String = myDateTime.ToString("hh:mm tt")
Dim myDateTime1 As DateTime = Now
Dim myDate1 As String = myDateTime1.ToString("dd/MM/yy")
Dim myTime1 As String = myDateTime1.ToString("hh:mm tt")
Need to use this function to find the Difference between Two Time. due to 12:00 AM isuue
Function XLMod(a, b)
' This replicates the Excel MOD function
XLMod = a - b * Int(a / b)
End Function
Output Required
dim dd = XLMod(myTime - myTime1)
Problem is myTime & myTime1 is String Need to convert them into Time, Later use XLMOD Funtion.Induhar,
As an addendum to this, I thought I'd add this in also: If you have two valid DateTime objects you might consider using a class which I put together a few years ago
shown on a page of my website here.
To use it, just instantiate with two DateTime objects (order doesn't matter, it'll figure it out) and you'll then have access to the public properties. For this example, I'm just showing the .ToString method:
Option Strict On
Option Explicit On
Option Infer Off
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, _
ByVal e As System.EventArgs) _
Handles MyBase.Load
Dim date1 As DateTime = Now
Dim date2 As DateTime = #1/1/1970 2:35:00 PM#
Dim howOld As New Age(date1, date2)
MessageBox.Show(howOld.ToString, "Age")
Stop
End Sub
End Class
I hope that helps, if not now then maybe at some point in the future. :)
Still lost in code, just at a little higher level.
Thanx frank, can use this in Future.... -
Function Module to find the Difference between two times.
Hi All,
Wud you plz let me know the Function Module to find the Difference between two times.
Input Time1( Hours:Minutes) Time2 ( Hours:Minutes)
Need Output in Hours:Minutes only . ( No seconds Needed )
Ex :
Input :
06:00 to 18:00 Output : 12:00
and 20:00 to 06:00 Output: 10:00 with +ve sign only. No -ve sign.
Thanks,
N.L.Narayanacheck this .
data : p_timel like sy-uzeit,
p_timeh like sy-uzeit,
diff like sy-uzeit,
di(8) type c .
p_timel = '200000'.
p_timeh = '060000'.
diff = p_timeh - p_timel.
concatenate diff+0(2) ':' diff+2(2) into di.
write:/ di.
also check for this.
p_timel = '060000'.
p_timeh = '180000'.
see if this can be implemented in ur code .
or else u can try with Fm L_TO_TIME_DIFF passing startdate enddate starttime endtime with UOM as MIN
hope this helps regards,
vijay -
Find the difference between two internal table
how can i see the difference between two interal tables?
The requirement is as follows
1. We have a transparent table, which stores the employee data with EMP ID as key.
2. We load the transp table data into a interal table (B).
3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
We want to do followign things
I = A - B
D = B - A
Both A and B will have around 40k records. Hence we are trying to avoid the looping.
Please suggest the best option for us.
Thank you in advance.
Raghavendra>
RAGHAV URAL wrote:
> how can i see the difference between two interal tables?
> The requirement is as follows
>
> 1. We have a transparent table, which stores the employee data with EMP ID as key.
> 2. We load the transp table data into a interal table (B).
> 3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
>
> Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
>
> We want to do followign things
> I = A - B
> D = B - A
>
> Both A and B will have around 40k records. Hence we are trying to avoid the looping.
>
> Please suggest the best option for us.
>
> Thank you in advance.
> Raghavendra
Hi Raghavendra,
Currently as of my knowledge, these operations are only possible through LOOPs. But LOOPign can be really fast here if you properly utilize the SORTING, READ with BINARY SEARCH and FIELD-SYMBOLS usage. I would say:-
Steps for Insert:-
SORT: A, B.
LOOP AT A ASSIGNING <WA_A>.
READ TABLE B WITH TABLE KEY key = <WA_A>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_A> TO I.
ENDIF.
ENDLOOP.
Steps for Delete:-
SORT: A, B.
LOOP AT B ASSIGNING <WA_B>.
READ TABLE A WITH TABLE KEY key = <WA_B>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_B> TO D.
ENDIF.
ENDLOOP.
Regards,
Ravi. -
How to find the difference of two columns in deski
Hi Everyone,
I have a deski report which is build from a single query. The report contains two tables.
Table-1:MTK Loc
MTKnet
Table-2:WTK Loc
WTKnet
Now i need to find the difference of the columns WTKnet and MTKnet.
These two are report level variables.Their definitins are as below:
MTKnet:=Sum((<Fees Collected by Per Collected>) In Body) ForEach <vMTKLocation>
WTKnet:=Sum((<Fees Collected by Per Collected>) In Body) ForEach <vWTKLocation>
Where <Fees Collected by Per Collected> is universe variable.
Please help...
Thanks in Advance......Hi Bol,
As I understand you are taking MTK_Loc and WTK_Loc together in the report which have common values under Fees Collected by Per Collected column.
Please follow the steps mentioned below:
1. Calculate the Variables MTK_Net as
=Sum(<Fees>) IN <MTK_Loc>
2. Calculate the Variables WTK_Net as
=Sum(<Fees>) IN <WTK_Loc>
3. You will get the values based on the Locations MTK_Loc and WTK_Loc .
You are using combination of values for MTK_Loc and WTK_Loc hence you will get the variable values in combination.
Insert new column right to the WTK_Net and write the formula name it Variance.
=<MTK_Net>- <WTK_Net>
The values look like :
MTK_Loc WTK_Loc MTK_Net WTK_Net Variance
Chicago Chicago 16,696,274.43 157,168.26 16,539,106.17
Chicago Madison 16,696,274.43 274,396.12 16,421,878.31
Chicago Milvaki 16,696,274.43 16,622,870.97 73,403.46
Chicago Pennsylvania 16,696,274.43 4,299.35 16,691,975.08
Chicago Waukesha 16,696,274.43 22,067.08 16,674,207.35
Here you will see values for MTK_Net are repeated because these are based on the MTK_Loc which is same for all rows i.e. Chicago , same is the case with remaining values of MTK_Loc.
We can not calculate variabnce based on the values like Canada,Pennsylvania for all values as these values come in combination of each other and as these are all connected columns WEBI groups Measure data based on the Dimension and variable columns associated with it.
MTK_Loc WTK_Loc MTK_Net WTK_Net Variance.
Chicago Chicago 16696274.43 157168.26 16539106.17
However you can compare the values based on the values as :
1. Drag and Drop MTK_Loc and MTK_Loc separately on the report.
2. Drag and Drop WTK_Loc and WTK_Loc separately and put it on the report, Connect it to the columns MTK_Loc and MTK_Loc columns already dragged. Then you can compare the values
MTK_Loc MTK_Net WTK_LOC WTK_Net
Chicago 16,696,274.43 Chicago 157,168.26
Madison 315,705.91 Madison 274,396.12
Manitowoc 362,632.50 Manitowoc 359,978.50
Milvaki 54,172.84 Milvaki 16,622,870.97
Pennsylvania 2,966.56 Pennsylvania 4,299.35
Waukesha 9,028.03 Waukesha 22,067.08
Here I unchecked the option avoid duplicate row aggregation (select table-> format table) thatu2019s why it is showing all values as a sum of all MTK_Net and WTK_Net values corresponding to Location values..
Here we are using MTK_Loc and WTK_Loc separately and not connected because though values seems same but they are used in combination ( Chicago, Pennsylvania) in 2 separate tables in DB hence we canu2019t synchronize them by liking these 2 location columns using 2 data providers.
I Hope this is what you want....
Thanks....
Pratik -
How to do find the difference between two time stamps
Hi all,
i have a table with 2 columns called GMT time and Local time . so i need to find difference between these two time stamps.
i tried like this
select to_date(GMT_TIME,'yyyy-mm-dd hh24:hi:ss')-to_date(LOCAL_TIME,'yyyy-mm-dd hh24:hi:ss') from date_table
the result is coming as follows ..
0.291666666667
i did not under stand the out put.
In my table GMT_TIME= 2011-06-26 00:00:00 and LOCAL_TIME=2011-06-25 17:00:00 ..
please help me how to get exact hours between two dates ..
Thanks
SreedharHi Sreedhar,
Your output (0.2916666) has the unit day.
You should multiply with 24 to get the unit hour.
select ( to_date(GMT_TIME,'yyyy-mm-dd hh24:hi:ss')-to_date(LOCAL_TIME,'yyyy-mm-dd hh24:hi:ss') ) * 24 from date_table;Rgds,
Tycho -
Find the difference between two dates for the specific month and year
Hi,
I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
for that date. In this case I input Jan 2013. How can I sql this ?I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
First let me understand you:
You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
declare @for_month int = 1 --January
declare @for_year int = 2013
declare @StartDate date = '2012-12-20'
declare @EndDate date = '2013-01-04'
SELECT
CASE
WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
DATEDIFF(DAY, @StartDate,@EndDate)
WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, @StartDate,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, @StartDate) + 1, 0))) + 1
WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
DATEDIFF(DAY, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime), DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime)) + 1, 0))) + 1
ELSE
0
END as [DD]
I don't know how you calculate day range between 01/01/2013 and 04/01/2013
is 4, it is actually is 3 but if that is the case, you can add 1 from the condition. -
How to find the difference between two date?
Hi,
I currently writing a date comparision program. Below is the idea analogy,
Currently i need to find how many day differences between 30 July 2003 and 22 June 2004. How can i use java to code it?
Thanks.there doesn't seem to be a direct way but try this:int daysBetween = 0;
Calendar c = new GregorianCalendar(2004, Calendar.JULY, 30);
Calendar d = new GregorianCalendar(2003, Calendar.JUNE, 22);
while (c.get(Calendar.YEAR) != d.get(Calendar.YEAR)) {
daysBetween += 360;
d.add(Calendar.DAY_OF_YEAR, 360);
daysBetween += c.get(Calendar.DAY_OF_YEAR) - d.get(Calendar.DAY_OF_YEAR);This gives the correct result of 404 (= 8 days from June 22 to June 30 + 366 days between July 1 of 2003 and 2004 + 30 days from July 1 to July 30) -
How to find the difference between two timestamp column
Dear All,
please Solve my issue,
I have Table name Record which has the following columns,
Empid in number column, dat in timestamp
which has the following values
Expand|Select|Wrap|Line Numbers
empid dat
====== ====
101 4/9/2012 9:48:54 AM
101 4/9/2012 9:36:28 AM
101 4/9/2012 6:16:28 PM
101 4/10/2012 9:33:48 AM
101 4/10/2012 12:36:28 PM
101 4/10/2012 8:36:12 PM
101 4/11/2012 9:36:28 AM
101 4/11/2012 4:36:22 PM
Here I need to display the following columns,
empid,min(dat) as start,max(dat) as end and difference(max(dat)-min(dat) for each day,
for eg,
Empid Strart end difference
101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
like this.
Here 3 different days are exists so It should return 3 records with the above mentioned columns,
Please Help me to get this.
Thank you,
Regards,
Gurujothi
Edited by: Gurujothi on Apr 25, 2012 4:45 AM>
101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
>
why 4/9/2012 9:48:54?
why not 4/9/2012 9:36:28 AM ?
SQL>
SQL> with t as
2 (select 101 empid, to_timestamp('4/9/2012 9:48:54 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
3 select 101, to_timestamp('4/9/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
4 select 101, to_timestamp('4/9/2012 6:16:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
5 select 101, to_timestamp('4/10/2012 9:33:48 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
6 select 101, to_timestamp('4/10/2012 12:36:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
7 select 101, to_timestamp('4/10/2012 8:36:12 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
8 select 101, to_timestamp('4/11/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
9 select 101, to_timestamp('4/11/2012 4:36:22 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual
10 )
11 select empid, min(dat) as start_dat
12 , max(dat) as end_dat
13 , max(dat)-min(dat) diff
14 from t
15 group by empid, trunc(dat)
16 /
EMPID START_DAT END_DAT DIFF
101 04.09.12 09:36:28,000000000 04.09.12 18:16:28,000000000 +000000000 08:40:00
101 04.11.12 09:36:28,000000000 04.11.12 16:36:22,000000000 +000000000 06:59:54
101 04.10.12 09:33:48,000000000 04.10.12 20:36:12,000000000 +000000000 11:02:24
SQL> -
Help I need to subtract times to find the difference between two times?
Hello there, I really need help.
I'm trying to make this attendance tracking system so that when a user enters his or her ID the system wll remember his/her check in time. However I also need to find out either how late the person is or how early to store their over time and late.
So I get the time by using a timestamp, so I'm left with a timestamp that I store into the db. But the problem comes when trying to compute for the late or over time. To do that I have to get the normal login/checkin time from the employee schedules table in the db and either subtract that time from the checkInTime to compute for how late or subtract the checkIn time from it to find early.
The thing is, the schedule is stored in datetime format in the db since the db is sql. Also I have no idea on how to subtract the two dates via java. The month, date and year stored in the sql db are just fillers, all I need computed is the time difference of the hours and minutes between the checkInTime and the schedule.
I've tried to use datediff: SELECT e.employeeNumber, datediff('hh', startTime, checkInTime) as lateTime from employeeschedules e, timandattendance, contractualemployees c where c.scheduleNumber=e.scheduleNumber and t.employeeNumber=c.employeeNumber and t.checkInNumber=1;
But it keeps on giving out various errors: You have an error in your sql syntax check your manual that corresponds to your sql server version. for the right syntax to use near , checkInTime) as lateTime from employeeschedules e, timandattendance, contractualemployees c where c.scheduleNumber=e.scheduleNumber and t.employeeNumber=c.employeeNumber and t.checkInNumber=1;
My sql server is My SQL 5.0.5
Now I'm thinking of useing Gregorian instead, but I don't know how to use Gregorian and dont know the various methods. Can someone tell me what to do, provide some sample codes and references that I can use to accomplish what I need to do?NewtonsApple_2 wrote:
Now I'm thinking of useing Gregorian instead, but I don't know how to use Gregorian and dont know the various methods. Can someone tell me what to do, provide some sample codes and references that I can use to accomplish what I need to do?it may help...
GregorianCalendar -
Trying to find the difference between two sub-totals (sales - credits)
Hi Everyone,
I have the following code which essentially lists the total sales for an items on the first row, and the total credits for the same item on the second row.
SELECT T0.ItemCode, SUM(T0.LineTotal) as 'Total Sales'
FROM INV1 T0
WHERE T0.ItemCode = 'ACR2401010'
GROUP BY T0.ItemCode
UNION ALL
SELECT T1.ItemCode, SUM(T1.LineTotal) as 'Total Sales'
FROM RIN1 T1
WHERE T1.ItemCode = 'ACR2401010'
GROUP BY T1.ItemCode
The results of the query are shown below (with some alterations for confidentiality).
What I would like to do is write a code block that subtracts the total credits from the total sales, leaving me with only one row of data for the ItemCode.
If anybody can help with writing the code to achieve this it will be greatly appreciated.
Kind Regards,
DavoHi, Please take a look and tweak accordingly. You may pay attention to nulls and manipulate accordingly. Best of luck!
--Option 1
SELECT t2.ItemCode,( SUM(T2.TotalSales)-SUM(TotalCredits)) AS 'Total'
FROM
SELECT T0.ItemCode, SUM(T0.LineTotal) as 'TotalSales',SUM(0) as 'TotalCredits'
FROM INV1 as T0
WHERE T0.ItemCode = 'ACR2401010'
GROUP BY T0.ItemCode
UNION ALL
SELECT T1.ItemCode, SUM(0) as 'TotalSales', SUM(T1.LineTotal) as 'TotalCredits',
FROM RIN1 as T1
WHERE T1.ItemCode = 'ACR2401010'
GROUP BY T1.ItemCode
) AS t2
GROUP BY t2.ItemCode
--Option 2
SELECT t2.ItemCode, ( SUM(T2.TotalSales)-SUM(TotalCredits)) AS 'Total'
FROM
SELECT T0.ItemCode, SUM(T0.LineTotal) as 'TotalSales',SUM(0) as 'TotalCredits'
FROM INV1 as T0
--WHERE T0.ItemCode = 'ACR2401010'
GROUP BY T0.ItemCode
UNION ALL
SELECT T1.ItemCode, SUM(0) as 'TotalSales', SUM(T1.LineTotal) as 'TotalCredits',
FROM RIN1 as T1
--WHERE T1.ItemCode = 'ACR2401010'
GROUP BY T1.ItemCode
) AS t2
WHERE t2.ItemCode = 'ACR2401010'
GROUP BY t2.ItemCode
--Option 3
SELECT t2.ItemCode, ( SUM(T2.TotalSales)-SUM(TotalCredits) ) AS 'Total'
FROM
SELECT T0.ItemCode, T0.LineTotal as 'TotalSales', 0 as 'TotalCredits'
FROM INV1 as T0
UNION ALL
SELECT T1.ItemCode, 0 as 'TotalSales', T1.LineTotal as 'TotalCredits',
FROM RIN1 as T1
) AS t2
WHERE t2.ItemCode = 'ACR2401010'
GROUP BY t2.ItemCode
--Assuming credit part is optional..also assuming each table should return only one row else results would inflate...option 4
SELECT t0.ItemCode, ( SUM(T0.TotalSales)-SUM(T1.TotalSales)) AS 'Total'
FROM
INV1 as t0
left outer join
RIN1 as t1
ON t0.ItemCode = t1.ItemCode
WHERE t0.ItemCode = 'ACR2401010'
GROUP BY t0.ItemCode
--option 4 with grouping to ensure single row from each table
SELECT t0.ItemCode, ( isnull(T0.TotalSales,0)-isnull(T1.TotalSales,0)) AS 'Total'
FROM
SELECT T0.ItemCode, SUM(T0.LineTotal) as 'TotalSales'
FROM INV1 as T0
--WHERE T0.ItemCode = 'ACR2401010'
GROUP BY T0.ItemCode
)as t0
LEFT OUTER JOIN
( SELECT T1.ItemCode, SUM(T1.LineTotal) as 'TotalCredits',
FROM RIN1 as T1
--WHERE T1.ItemCode = 'ACR2401010'
GROUP BY T1.ItemCode
) as t1
ON t0.ItemCode = t1.ItemCode
WHERE t0.ItemCode = 'ACR2401010'
--Option 5 with grouping to ensure single row from each table.
--Also assuming that sales or credits can be optional
SELECT
ISNULL(t0.ItemCode,t0.ItemCode) AS ItemCode,
( isnull(T0.TotalSales,0)-isnull(T1.TotalSales,0)) AS 'Total'
FROM
SELECT T0.ItemCode, SUM(T0.LineTotal) as 'TotalSales'
FROM INV1 as T0
--WHERE T0.ItemCode = 'ACR2401010'
GROUP BY T0.ItemCode
)as t0
FULL OUTER JOIN
( SELECT T1.ItemCode, SUM(T1.LineTotal) as 'TotalCredits',
FROM RIN1 as T1
--WHERE T1.ItemCode = 'ACR2401010'
GROUP BY T1.ItemCode
) as t1
ON t0.ItemCode = t1.ItemCode
WHERE (t0.ItemCode = 'ACR2401010' OR t1.ItemCode = 'ACR2401010') -
Find the difference in Two Tabels in two different schema?
Hello Gurus,
In DB which have millions of records -
I have a Tabel A under Schema A and i have another Tabel B under Schema B and i have to pick the refrence from Tabel C under Schedma B altough my DB is same. Both of the tables (Table A and Table B) have exatly the same structure in both the schema and when i tried finding the difference like -
Find the refrence from Table C and pick the values which are in Tabel A under Schema A but which are not present in the Tabel B under Schema B .
I have to compare each and ever field value which is present under all of the columns under Table A to ever field value which is present under all of the columns under Table B.
then wrote the following query-
SELECT * FROM
SchemaA.Table A t1,SchemaB.Table C t2
WHERE t1.SV_ID = t2.SV_ID order by t1.SV_ID
Minus
Select * from SchemaB.TableB order by SV_ID
Then this query is not working. And display the following error -
"query block has incorrect number of result columns"
Even both of the tables have the same column's and same structure.
Kindly help me .
Looking forward for some guidance -
Thanks in advance.1-There are some 70 Columns in both of the tables so thats why i don't want to use the query based on columns as it will involve writing all of the columns.
2- By using the query something like -
select <column_name(s)> from table1
minus
select <column_name(s)> from table2, table1
where <condition>
It is throwing the error -ORA-01789: query block has incorrect number of result columns
3- Using the query
SELECT t1.*
FROM SchemaA.TableA t1,SchemaB.TableC t2
WHERE t1.SV_ID = t2.SV_ID
MINUS
SELECT t3.*
FROM SchemaB.TableB t3
order by SV_ID
It gives me the reuslt but when i corss check them individually in both of the tables then there is no difference.
4- SELECT t1.* FROM
SchemaA.Table A t1,SchemaB.Table C t2
WHERE t1.SV_ID = t2.SV_ID order by t1.SV_ID
Minus
Select * from SchemaB.TableB order by SV_ID
Query is not working.
Kindly help me to find the difference between two tables , column by column based on the condition both of the tables have the same SV_ID. -
Find the difference between loading and registering the drivers..
Dear Sir..
Could you please help me to find the difference between two activities..
1.Loading the drivers
2.Registering the drivers
What's the difference between loading and registeing the drivers and what activities take place by the JVM to do it all.Dear Sir..
Could you please help me to find the difference
between two activities..
1.Loading the drivers
2.Registering the drivers
What's the difference between loading and registeing
the drivers and what activities take place by the JVM
to do it all.You load a class - it isn't specific to a driver.
That is part of java - not JDBC.
Normally JDBC drivers register themselves when the class is loaded. This is specific to the driver and has nothing to do with a user of the driver. It is only a concern to someone who must implement a driver.
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