Find underlying component type

Hi, I have a structure which has few components. Is it possible to find the component type of the components?
Also is it possible to determine whether the component type is a table-type or a structure?

Hi Arun,
You can try out with the help of a join on the tables DD02L and DD03L. In the DD02L, you would be having the tables and it table category (i.e., the type of the component you require INTTAB represents it as a structure and TRANSP represents transparent table.)
For example, if u have an include structure in a table, first hit the DD02L table and know whether it is a table or structure and then hit the table DD03L to know what are the include structures it is having. In this way, you can play around with it.
Please don't forget to reward points if the answer is helpful

Similar Messages

Component type in property tree

Hi Experts,
Can you please provide me the details about what is the component type in a property tree of a specification and how can we find which component type is assigned to a specification property tree.
Thanks in Advance
Regards
Kapil

Dear Kapil
you misinterpret the data model of EHS. The "Component type" is just "customizing". This customizing is used in any !! value assignmen type C (composition); We have may be 50 (or more; I do not have counted them) value assignment type of type C in STANDARD tree; so there is no answer to your question possible as component type can be used very often in different contexts
C.B.

How can i find out field for a particular component type

hi,
how can i find out for particular component name is belongs to this field.....that means REF_DOC_NO componemt is belongs to xblnr field ..../.if we know only component type ...how to find the field...
plz tell me
thanks&regards,
kalyan

keep the cursor on component
press F1
select technical information
you will find the field name and table or structure name
regards
sateesh

How to find what are the support-teams map with particular componant type

hi experts,
i am new in solution manager.. My requirement is when creating the support message in crmd_order t-code i have to give the componant type in transaction data after that in fast entry screen i have to assign support team for that componant type .. here i have to give only valid support team which are map with particular componant type .. when save the support message here i have to check that support team is map with that particular componant type (i.e that support team is belong to that componant type ) .. thats what i have to do in abap development .. so how to find the what are all the support teams mapped with particular componant type .. whether it is stored in any table or ?.. Please give solutions ..
Regards,
Kumar..

Hi Kumaresan-
I'm not sure I fully understand your requirement but I will try to help out. If you are trying to determine / associate the relevant support team according to which component they are responsible for, this might help.
The determination of the support team is maintained by configuring rule 13200137 in transaction PFAC_RESPO.
Click on the Responsibilities Tab
Create your responsibility based on your support team requirements
Assign the appropriate Support Team, this data will be taken from the settings you have maintained when creating your org chart in ppoma_crm
Highlight a responsibility and click Change
In this table you will see an entry for SAP Component, this is where you identify which support team will be determined based on component

Cant see PC's in finder shared component

Hi, Im totally new to the mac world. i have a wireless network, 3 PC's and one mac. i wish to work mainly from the mac and have all other computers as servers in the finder shared component. the problem is that i can connect to the PC only manually. i wanna see them all under shared in the finder window. what should i do?
ive search this database but couldn't find the specific solution to my problem.
Thanks
Shay

Without really knowing your network i'll try to help.
Basically you need to have a shared folder on the PC's and know their IP adress's. You then use OS X's Go to Server command and type in the IP of the PC machine. The Shared folder should then be displayed.

Proxy error- unable to find software component version for namespace-

Hi all,
I need help regarding proxy.
I am using SAP standard package for one integration PI 7.0 to SRM.
Here we need to use the datatype enhancement for adding some fields. So I create one extension_datatype in the datatype enhancement and add the fields .
( I am using Inbount interface, where I am adding the new fields in PI)
Now when I go to SRM system and Run SPROXY system to regenerate the Proxy. So that It can reload the New fields.
Then it reloads and We activate the same.
Now at one place when I clicked the data type enhancement object its giving the error that unable to find software component version for namespace" . I did not understand why its giving the error. I added the new fields in the existing running datatype enhancement. and reload the reproxy.
I have one more datatype enhancement object in the same software component and in the same name space but its not giving the error.
Please help , how to resolve it asap.
regards
ram

1.the datatype enhancement object may not be activated in the same software component .
for this try these -
after creating your data types and designing part. First close all the developement objects windows.
then click on your sw component which you have created and activate it very first.
then you will be able to activate all other objects
or when you start activating your data types a new window with list of the objects which you want to activate opens
in this new window you can see your sw component as the very last object select it first and activate it
2. update the cache in both system
i think these 2 reasons.u try it.

Creating component types in N1sps

First, I have created a simple base type called wfbSimpleBase. The contents of which are the following:
<?xml version="1.0" encoding="UTF-8"?>

<component modifier='ABSTRACT' installPath=':[installPath]' xmlns='http://www.sun.com/schema/SPS' name='wfbSimpleBase' version='5.1' description='Wells Fargo Simple Base type' xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' author='system' softwareVendor='WellsWare' xsi:schemaLocation='http://www.sun.com/schema/SPS component.xsd'>
     <varList>
          <var name='installName' default=':[sys.name]'></var>
          <var name='installPath' default=':[container:installPath]'></var>
          <var name='installUser' default=''></var>
          <var name='installGroup' default=''></var>
          <var name='installPermissions' default=''></var>
          <var name='installDeployMode' default='REPLACE'></var>
          <var name='installDiffDeploy' default='TRUE'></var>
          <var name='overrideRsrcInstallPath' default=''></var>
     </varList>
     <resourceRef modifier='ABSTRACT'>
          <installSpec deployMode=':[installDeployMode]' permissions=':[installPermissions]' name=':[installName]' user=':[installUser]' diffDeploy=':[installDiffDeploy]' path=':[overrideRsrcInstallPath]' group=':[installGroup]'></installSpec>
     </resourceRef>
     <installList>
          <installSteps name='default'>
               <deployResource></deployResource>
          </installSteps>
          <installSteps name='markOnly'></installSteps>
     </installList>
     <uninstallList>
          <uninstallSteps name='default'>
               <undeployResource></undeployResource>
          </uninstallSteps>
          <uninstallSteps name='markOnly'></uninstallSteps>
     </uninstallList>
     <snapshotList>
          <snapshot name='default'>
               <capture>
                    <addResource></addResource>
               </capture>
          </snapshot>
     </snapshotList>
</component>
This step went smoothly.
Next I tried to extend a new abstract type from it called: wfb_ct. The content of which is the following:
<?xml version="1.0" encoding="UTF-8"?>

<component xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' name='wfb_ct' version='5.1' xsi:schemaLocation='http://www.sun.com/schema/SPS component.xsd' xmlns='http://www.sun.com/schema/SPS' path='/wfbTypes'>
     <extends>
          <type name='system#container'></type>
     </extends>
</component>
When I try to change the name attribute of the type element of the extends to wfbSimpleBase as in the following:
     <extends>
          <type name='wfbSimpleBase'></type>
     </extends>
I get the error:
Unable to check in component
Unable to find component type with name "wfbSimpleBase". (023061)
It does not matter where I move wfbSimpleBase in the folder tree within the N1 repository N1 is simply unable to associate the wfbSimpleBase as the parent type for wfb_ct. When I try to supply a folder path in the name attribute I get a name format error. The only information that I have found in the 5.1 Schema reference that appears to be associated with this is:
<type> Element
The <type> element names the base component type of this component. This element is a child of the <extends>, <componentRefList>, and <componentRef> elements.
The <type> element has one required attribute of type systemName, name, which is the name of the system type component that serves as the base type. If the specified type is one that is defined by a plug-in, pluginName must be prefixed to the type name, such as pluginName#typeName.
This seems to imply that the name attribute of the type element must be a systemName? If this is true how do I get the system to recognize/honor the wfbSimpleBase as a systemName appropriate to extend to a child component?
John Seiberling

Hi,
It is very much possible to plan Non-Stock & stok items & also services in a single work order. Even you can plan stock & non-stock items for a single operation also by providing Item categories L: Stock Item & N: Non- Stock item.
Yatharth

Can't remove criteria in Find under Keywords, CS6

I wonder if anyone else has this problem. I just recently started using CS6. This bug is regarding the find "Find" function in my Keywords collection, for example, find everything with Keywords "child". Adding criteria works wonders, except that once you add it you can no longer remove it. I attached a screenshot to demonstrate. After performing a 2-criteria search, I could not remove the second criteria when I perform a new search. The "minus" button doesn't work. I tried the "plus" button and it worked, and now i'm stuck with 3 criteria! I can't leave the fields blank because I get an error message asking me to fill every field out.
I tired rebooting and purging the cache, and nothing works. Anyone experienced this or has a solution I can try?

Curt Y wrote:
This is not a bug. You are the only one with it as far as I have seen. Have Win 7 and tested it and it works perfectly. I just updated and the new version works as well. You have not said what OS you use. What version of CS6 Bridge are you using?
So there is some program interfering with Bridge, or you have a bad install. Are the minus buttons greyed out? Can not tell in the screenshot.
I'm curious if you tried "Find" under the "Keywords" section. I don't have this problem when I perform a regular search (e.g. by pressing command + F or control + F). This only happens when I right click on a keyword and find pictures that contain the keyword.
Very peculiar, but I wouldn't be too surprised if they only tested the regular search function and overlooked the right click keyword search function.
Obviously I can just do regarlar search from now on, but it's one more step to type in the keyword I want, as opposed to just right click on the keyword.

Finding a component inside jsf fragment using javascript in adf

Hello all,
I am using jdeveloper 11.1.1.5.
I want to find a component inside my jsf frgament using javascript.
Like inside jspx page I was able to find the component using
AdfPage.PAGE.findComponentByAbsoluteId("ID");
Now my requirement is I have a jsf fragment and I want to find component inside jsf frgament using javascript.
How can I find the component?
Please suggest
Thanks
Edited by: Navin K on Dec 21, 2011 4:24 PM

Hi all..
I am using Jdeveloper 11.1.2.1.0
The code i used is given below. When i run this i always getting the message (ie region not found) in the else case of java script.
How can i solve this. How can i take the region r1 in the javascript..
<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<f:view xmlns:f="http://java.sun.com/jsf/core" xmlns:af="http://xmlns.oracle.com/adf/faces/rich">
<af:document title="Index.jsf" id="d1">
<af:messages id="m1"/>
<af:form id="f1">
<af:pageTemplate viewId="/AssetTrackingTemplate.jsf" id="pt1">
<f:facet name="top"/>
<f:facet name="first">
<af:panelAccordion id="pa1">
<af:showDetailItem text="Master Details" id="sdi1">
<af:spacer width="10" height="10" id="s3"/>
<af:commandLink text="Home" id="cl8" inlineStyle="font-size:small; font-weight:bold;">
<af:setActionListener from="/WEB-INF/task-flow-Home.xml#task-flow-Home"
to="#{pageFlowScope.dynRegionBean.taskFlowId}"/>
</af:commandLink>
<af:spacer width="10" height="10" id="s1"/>
<af:tree value="#{bindings.GenTopMenu1.treeModel}" var="node"
selectionListener="#{bindings.GenTopMenu1.treeModel.makeCurrent}"
rowSelection="single" id="t1">
<f:facet name="nodeStamp">
<af:group id="g1">
<af:outputText value="#{node.Description}" id="ot2"
rendered="#{node.MenuType==1}"/>
<af:commandLink text="#{node.Description}" id="cl1"
rendered="#{node.MenuType==2}" partialSubmit="true"
immediate="false"
actionListener="#{pageFlowScope.dynRegionBean.launchTaskFlow}">
<f:attribute name="Definition" value="#{node.Definition}"/>
</af:commandLink>
</af:group>
</f:facet>
</af:tree>
</af:showDetailItem>
</af:panelAccordion>
</f:facet>
<f:facet name="middle">
<af:region value="#{bindings.dynamicRegion1.regionModel}" id="r1"/>
</f:facet>
<f:facet name="end"/>
<f:facet name="copyright">
<af:outputText value="All Rights Reserved By Innovation ITC" id="ot1"
inlineStyle="text-align:center; color:inherit;"/>
</f:facet>
</af:pageTemplate>
</af:form>
<f:facet name="metaContainer">
<af:resource type="javascript">
function customHandler(event) {
var region=AdfPage.PAGE.findComponentByAbsoluteId("r1");
if(region!=null)
alert("Region Found");
var exportCmd = region.findComponent("cb1");
var actionEvent = new AdfActionEvent(exportCmd);
actionEvent.forceFullSubmit();
actionEvent.noResponseExpected();
actionEvent.queue();
else {
alert("Region Not Found")
</af:resource>
</f:facet>
</af:document>
</f:view>
Thanks,
gtg.
Edited by: gtg on 08-Feb-2012 00:14

Crystal Report Preview vs. SAP B1 Report Preview as a Layout under Content Type

Hello good day i'm trying to create a report that will be preview under A/R Invoice but the details need is under delivery module for example i create a serialize Item and set the Management Method on Every Transaction Under Item master data, so the transaction flow will be like this SO -> Delivery -> A/R Invoice. So under delivery transaction i will choose the serial that i will deliver so that under A/R Invoice Transaction i will no longer choose again the said serial that i choose on Delivery Transaction. There for on my Report i will Based on Delivery Transaction to get the chosen Serial But the Report will be Preview under A/R Invoice.
The main concern on This is why when i preview the said Report under Crystal Report the serial is showing but when i Import it on SAP B1 as a Layout under Content type it is no longer showing the serial on the preview?

Please post to the SAP Business One Application forum
- Ludek
SCN Moderator

Exception [EJB - 10008]: Cannot find bean of type [SalesBean] using finder

I'm trying to call an entity bean froma session bean i get the error :-
7/02/27 14:35:25 javax.ejb.ObjectNotFoundException: Exception [EJB - 10008]: Cannot find bean of type [SalesBean] using finde
[findByCustID].
7/02/27 14:35:25       at oracle.toplink.internal.ejb.cmp.EJBExceptionFactory.objectNotFound(EJBExceptionFactory.java:325)
7/02/27 14:35:25       at oracle.toplink.internal.ejb.cmp.finders.Finder.checkNullResult(Finder.java:224)
My session bean looks like this :-
public class HelloBean implements SessionBean
public String helloWorld (String pzCustomerID) throws SQLException,RemoteException
     String lzRevenue=null;
     int liCustomerID=Integer.parseInt(pzCustomerID);
     try
          Context initial = new InitialContext();
          Object objref =   initial.lookup("SalesBean");
          SalesHome salesHome =(SalesHome) PortableRemoteObject.narrow(objref,SalesHome.class);
          Sales sales=salesHome.findByCustID(liCustomerID);
          lzRevenue=(String) sales.findByCustID(liCustomerID);
My entity bean looks like this:-
public class SalesBean implements EntityBean
public String factPK;
public int timeID;
public int custID;
public int locID;
public int itemID;
public int entityID;
public String currency;
public float qty;
public float unitPrice;
public float amount;
public EntityContext context;
private Connection con;
    private void makeConnection() {
        try {
            InitialContext ic = new InitialContext();
            javax.sql.DataSource ds = (javax.sql.DataSource) ic.lookup("jdbc/DSource");
            con = ds.getConnection();
        } catch (Exception ex) {
            throw new EJBException("Unable to connect to database. " +
                ex.getMessage());
public SalesBean()
public String ejbFindByCustID(int custID) throws SQLException,RemoteException,FinderException
     makeConnection();
     PreparedStatement pstmt = con.prepareStatement("select sum(amount) from sales where cust_id= ? ");
     pstmt.setInt(1, custID);
     ResultSet rset = pstmt.executeQuery();
     if (!rset.next())
          throw new RemoteException("no records present" );
     return rset.getString(1);
}My entity bean's home interface looks like this:-
public interface SalesHome extends EJBHome
public Sales create() throws RemoteException, CreateException;
public Sales findByCustID(int custID) throws SQLException,RemoteException,FinderException;
My entity bean's remote interface looks like this:-
public interface Sales extends EJBObject
     public String findByCustID(int custID) throws SQLException,RemoteException,FinderException;
my ejb-jar.xml looks like this:-
<enterprise-beans>
<session>
<description>Hello Bean</description>
<ejb-name>HelloBean</ejb-name>
<home>myEjb.HelloHome</home>
<remote>myEjb.HelloRemote</remote>
<ejb-class>myEjb.HelloBean</ejb-class>
<session-type>Stateful</session-type>
<transaction-type>Container</transaction-type>
</session>
     <entity>
          <ejb-name>SalesBean</ejb-name>
          <home>myEjb.SalesHome</home>
          <remote>myEjb.Sales</remote>
          <ejb-class>myEjb.SalesBean</ejb-class>
          <persistence-type>Container</persistence-type>
          <prim-key-class>java.lang.String</prim-key-class>
          <reentrant>False</reentrant>
          <cmp-field>
          <field-name>factPK</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>timeID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>custID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>locID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>itemID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>entityID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>currency</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>qty</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>unitPrice</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>amount</field-name>
     </cmp-field>
          <primkey-field>factPK</primkey-field>
          <resource-ref>
          <res-ref-name>jdbc/DSource</res-ref-name>
          <res-type>javax.sql.DataSource</res-type>
          <res-auth>Container</res-auth>
     </resource-ref>
     </entity>
</enterprise-beans>
please help me out of this trouble.

I'm trying to call an entity bean froma session bean i get the error :-
7/02/27 14:35:25 javax.ejb.ObjectNotFoundException: Exception [EJB - 10008]: Cannot find bean of type [SalesBean] using finde
[findByCustID].
7/02/27 14:35:25       at oracle.toplink.internal.ejb.cmp.EJBExceptionFactory.objectNotFound(EJBExceptionFactory.java:325)
7/02/27 14:35:25       at oracle.toplink.internal.ejb.cmp.finders.Finder.checkNullResult(Finder.java:224)
My session bean looks like this :-
public class HelloBean implements SessionBean
public String helloWorld (String pzCustomerID) throws SQLException,RemoteException
     String lzRevenue=null;
     int liCustomerID=Integer.parseInt(pzCustomerID);
     try
          Context initial = new InitialContext();
          Object objref =   initial.lookup("SalesBean");
          SalesHome salesHome =(SalesHome) PortableRemoteObject.narrow(objref,SalesHome.class);
          Sales sales=salesHome.findByCustID(liCustomerID);
          lzRevenue=(String) sales.findByCustID(liCustomerID);
My entity bean looks like this:-
public class SalesBean implements EntityBean
public String factPK;
public int timeID;
public int custID;
public int locID;
public int itemID;
public int entityID;
public String currency;
public float qty;
public float unitPrice;
public float amount;
public EntityContext context;
private Connection con;
    private void makeConnection() {
        try {
            InitialContext ic = new InitialContext();
            javax.sql.DataSource ds = (javax.sql.DataSource) ic.lookup("jdbc/DSource");
            con = ds.getConnection();
        } catch (Exception ex) {
            throw new EJBException("Unable to connect to database. " +
                ex.getMessage());
public SalesBean()
public String ejbFindByCustID(int custID) throws SQLException,RemoteException,FinderException
     makeConnection();
     PreparedStatement pstmt = con.prepareStatement("select sum(amount) from sales where cust_id= ? ");
     pstmt.setInt(1, custID);
     ResultSet rset = pstmt.executeQuery();
     if (!rset.next())
          throw new RemoteException("no records present" );
     return rset.getString(1);
}My entity bean's home interface looks like this:-
public interface SalesHome extends EJBHome
public Sales create() throws RemoteException, CreateException;
public Sales findByCustID(int custID) throws SQLException,RemoteException,FinderException;
My entity bean's remote interface looks like this:-
public interface Sales extends EJBObject
     public String findByCustID(int custID) throws SQLException,RemoteException,FinderException;
my ejb-jar.xml looks like this:-
<enterprise-beans>
<session>
<description>Hello Bean</description>
<ejb-name>HelloBean</ejb-name>
<home>myEjb.HelloHome</home>
<remote>myEjb.HelloRemote</remote>
<ejb-class>myEjb.HelloBean</ejb-class>
<session-type>Stateful</session-type>
<transaction-type>Container</transaction-type>
</session>
     <entity>
          <ejb-name>SalesBean</ejb-name>
          <home>myEjb.SalesHome</home>
          <remote>myEjb.Sales</remote>
          <ejb-class>myEjb.SalesBean</ejb-class>
          <persistence-type>Container</persistence-type>
          <prim-key-class>java.lang.String</prim-key-class>
          <reentrant>False</reentrant>
          <cmp-field>
          <field-name>factPK</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>timeID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>custID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>locID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>itemID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>entityID</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>currency</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>qty</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>unitPrice</field-name>
     </cmp-field>
     <cmp-field>
          <field-name>amount</field-name>
     </cmp-field>
          <primkey-field>factPK</primkey-field>
          <resource-ref>
          <res-ref-name>jdbc/DSource</res-ref-name>
          <res-type>javax.sql.DataSource</res-type>
          <res-auth>Container</res-auth>
     </resource-ref>
     </entity>
</enterprise-beans>
please help me out of this trouble.

I exited iMovie and lost my project. I am able to find it in Finder, under the Movies tab, but can not get it back to a project in iMovie. Is there a way to restore it?

Please help! I exited iMovie and lost my project that I've been working on for days... I am able to find it in "Finder" under iMovie Projects... but I am unable to open it as a Project in iMovie. I am using iMovie '11, with no time machine, and I'm on a MacBook Pro.

I fully sympathise with you, as I recently experienced the same issue (as have many others).
Projects always appear as normal in Finder in the Home folder Movies/iMovie Projects (or on an external disk at the top level in Movies/iMovie Projects). Nothing looks untoward there.
However, when iMovie is opened again after an editing session, the most recent project worked on does not appear in the listing of projects in iMovie's Project Library - although it is still listed in the Finder folder . This happens for no apparent reason - no unexpected quits, freezes, or crashes, and nothing else out of the ordinary. iMovie is simply not recognizing the project. It can't even be opened by double-clicking on the project in Finder.
Here are a number of links to other topics on this issue (there may be others I've missed):
https://discussions.apple.com/message/21370074#21370074
https://discussions.apple.com/message/21297057#21297057
https://discussions.apple.com/message/21296973#21296973
https://discussions.apple.com/message/21157327#21157327
https://discussions.apple.com/message/21177008#21177008
https://discussions.apple.com/thread/4748933?start=0&tstart=0
https://discussions.apple.com/message/21157079#21157079
Sorry to bombard you with all these links, but as you will see there are others here reporting the same problem. No solution has been forthcoming unfortunately.
Be sure to provide feedback to Apple - in iMovie's menu click on iMovie > Provide iMovie Feedback, then complete the online form.
John

How to find out which type of the driver is used in our application?

Hi all,
can anyone tell me how to find out which type of the driver is used in our application?
Thanks in advance,
Phoeniox

Hi,
Check out this...
Class.forName("com.mysql.jdbc.Driver"); //if u r using MySql
List drivers = Collections.list(DriverManager.getDrivers());
               for(int i=0;i<drivers.size();i++)
                    Driver driver = (Driver)drivers.get(i);
                    String driverName = driver.getClass().getName();
                    System.out.println("Driver "+i+":::"+driverName);
you need to load the driver and display in the same program.
Then only you'l get the required result.
prakhyath

PC server not showing up in Finder under shared

Hi
I installed Leopard on the 26th and my home windows PC is not showing up under shared and its not showing up in the network folder under mshome like it did in tiger. ive checked the PC and file sharing is enabled in the firewall and i even installed bonjour for windows but no luck.
the only way i can do it is "connect to server" (command-k) in the finer and use SMB smb://IP/shared name but it shows up under shared with an apple display icon and the PCs IP address. i was under the impression that PC servers automagically appear in the finder under shared with its shared name and a PC icon with the "blue screen of death". how do i get it to do this?
thanks

Hi,
One of the posters in this forum said that you had to do the change of workgroup in a Location profile that's not active. Then, change to that inactive Location profile for the thing to work.
Here's what I did on mine. I created a copy of the current working Location profile. Using the copy, I went to the WINS section and changed the workgroup to whatever my workgroup name was (make sure you press ENTER too for the workgroup name to stick). Then, I switched to the copy.
Regards,
Albertus

Why are my iphone4S and ipad3 no longer being seen in finder under the devices section

I am new to the Apple ecosystem and for the most part I have fallen in love with it, I have had my fill of the PC era and was on the verge of a mental breakdown using them. Well I bought a MBP 13" an ipad3 and I have an iPhone 4s. When I first got these items I was able to drag and drop files like a movie that I own and copied to the hard drive. This was done in finder, under the devices section it would show my phone and my ipad however after I installed the latest iTunes software it seems that this has disapeared and now I cannot find my devices in the finder area to drag and drop these files anymore. So, my question is this, has Apple done away with this function and if so how can I drag and drop a file to the ipad3 now? Thank you all for your help.

Care to share which OS system you are using?

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