Finding the employees whose have the max salary

Question

i am working with a table called employee with the following fields (empno,ename,sal....), i want to find the employee/s which have the max salary i wrote the followinng sql statment
select * from employee where sal = ( select max(sal) from employee)
it works well but i am wondering if there is a more effient way to do this
please note that the table have about i million row, and there is an index on empno field

Answer 1

if there is a more effient way to do this
You can see execution plan using different queries:
SQL> set autotrace trace explain statistics
SQL> select * from
  2  (select e.*, dense_rank() over(order by sal desc) x
  3  from emp e)  where x=1;
Execution Plan
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=5 Card=14 Bytes=1400          )
   1    0   VIEW (Cost=5 Card=14 Bytes=1400)
   2    1     WINDOW (SORT PUSHED RANK) (Cost=5 Card=14 Bytes=448)
   3    2       TABLE ACCESS (FULL) OF 'EMP' (Cost=1 Card=14 Bytes=448          )
Statistics
          0  recursive calls
          2  db block gets
          1  consistent gets
          0  physical reads
          0  redo size
        864  bytes sent via SQL*Net to client
        503  bytes received via SQL*Net from client
          2  SQL*Net roundtrips to/from client
          1  sorts (memory)
          0  sorts (disk)
          1  rows processedMessage was edited by:
Jameel