FM for week number of month

Hi all,
Could you suggest me a FM for for finding the week number of a month.
I can see FM which shows week number of an year .But i want the week number with reference to a month.
Thanks
Sam.

Hi,
A sample using function DATE_GET_WEEK
Report try05.
DATA: xweek(6)    TYPE n,
                    xdt      TYPE d.
xdt = '20050101'.
CALL FUNCTION 'DATE_GET_WEEK'
EXPORTING
    DATE               = xdt
IMPORTING
   WEEK               = xweek
EXCEPTIONS
   DATE_INVALID       = 1
OTHERS             = 2
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
WRITE:/ xdt.
WRITE:/ xweek.
Hope this helps.
Reward if helpful.
Regards,
Sipra

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Function module for adding number of months to the date

Hi,
Is there any function module to get the date by adding number of months...
Regards,
Yadagiri

Normally all SAP FM will return that value. As 1 month in general means 30 days only.
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add month in the date to find next date
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IPCC 7 Determine the week number of a month

Hello,
I am working towards determine the week number of month and make appropriate routing changes only for that specific week. I have tried using the trunc(), getdate() and weekday(). But i fail to get the week number of a month, but I believe I have managed to the week number of a year.
The example I have considered is: On Tuesday and Thursdays in second week of every month the calls to be routed to a different skillgroup.
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CM 4.1, CRS 3.5, ICM 7.1

Hi buddy,
Great stuff!! Your link gave me another hint of the possible solution, I was working on ICM but not sure why i did not consider CRS for this requirement , The CRS has a builtin function, I have used this builtin Methods which provided me what i expected.
The debug on the script resulted the week of the month for today which is "4".
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Show number of a week in a month

Dear all,
I want to know a number of the week in a month of my transaction.
The table has a field called transaction_date. How to write a sql which will show a number of week (1, 2, 3 or 4) in that very month where the transaction was made.
Thanks and regards,
Steve

Hi Steve,
I don't know if you know about it but there is a forum dedicated to PL / SQL which might be better for this type of question. In any case , browsing the SQL documentation at the moment there is a date time format W which appears to do what you want. There are in fact two week number formats WW and W. One is for week number in the year the other for week number in the month. Hope this helps. Here is a link:
http://download-west.oracle.com/docs/cd/B10501_01/server.920/a96529/ch7.htm#5186

Week numbers in Month view

Hi,
How can i add week number in "month view"?
I can see week number in "week view" and i see that this can be fixed with a script. But the scrit under don't work for me!
=INT(([a2]-DATE(YEAR([a2]),1,1)+(TEXT(WEEKDAY(DATE(YEAR([a2]),1,1)),"d")))/7)
Any one can help me here?
(I use SharePoint Online 2013)
Regards,
Mohsen

Hi,
According to your description, you want to display week number in “Month” scope of Calendar View.
Your formula is correct, however it can only apply to the normal list view as a calculated column.
The outcome is as below:
If you need it on the monthly view, I suggest you develop a custom solution for it.
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Variable Offsets for Weeks

We have a custom created infoobject for fiscal week, which is basically week number within fiscal variant, fiscal year, and fiscal period. So fiscal period 1 contains weeks 1-4, period 2 contains weeks 5-8, etc.
Our problem is in the use of variable offsets in query definitions. If we use 0FISCPER, BEx knows that the "-1 offset" for 2005001 is 2004012, not 2004999. Similarly, for 0CALWEEK, the week before 200501 is 200452, not 200499. So for our custom infoobject, how do tell BEx that the fiscal week before 200501 is 200452? Anyone know how we can set this up?
Thanks in advance for any info you can provide.
Rachel McGregor

Yes, we figured we would probably need to do something in the user exit. We did not create the infoobject with reference to anything else since we added some custom attributes.
What exactly should we do in the user exit? We want to create a structure with a whole bunch of selections for week number, week number-1, week number-2, week number-3, etc. all the way back to week number-104 (i.e. we want 2 years' worth), with a single prompt to the user for week number.
Any suggestions?
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Return date for a given week number in a month

Hi,
Can someone urgently post a snippet code that will return the date if the week number and the weekday (like wednesday) for a given month in an year is passed.
ex: If I say 2nd wednesday of August in 2004 , it must return the date for second wednesday. URGENT

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Calendar to get week number of current month

Hi All,
Description: Currently I am working on an application which require to calculate some data for current month from a database where I have the data of all the previous and current month of that year, I can take week number as criteria.
Help Required: I can find week of month or year using Calendar methods but how to find the first week on the current month only.
Lets suppose the current month is April so when I use, int weekofmonth = cal.get(cal.WEEK_OF_MONTH);
it will return me the number of present week however I want to get what would be the week number at the start of the month (April).
Hope I am able to describe my query properly.
Thanks in advance.
Amit

/ ====================================================
Method: Get the desired Date format for the date
Developed By: Sandip Waghole [29-Jan-2010]
==================================================== /
public String getWeekNo(String strDate)
// input Date Format : M/dd/yyyy
int weekNo=0,i=0;
String strWeekNo=null;
int noOfDaysInTheYear=365;
int WEEK_STARTS_ON = 1; // Define the day on which week starts Sunday/Monday 1:Sunday 2:Monday
int firstDayNoInFirstWeekOfPresentYear=0; // Inititalize teh day on which week is starting in present year
int firstDayOfPresentYear=0; // Inititlize the 1st day of the present year whether Sunday/Monday/.....
int[] monthDaysArray = {31,28,31,30,31,30,31,31,30,31,30,31}; // Define array of the days as per months
int todaysDayNoInPresentYear=0;
int daysLateByFirstWeekStartedAfterYearStarted=0;
int intTemp=0;
//strDate="08/24/2000"; // For test purpose
StringTokenizer strDateTok = new StringTokenizer(strDate, "/ ");
int month = Integer.parseInt(strDateTok.nextToken());
int day= Integer.parseInt(strDateTok.nextToken());
int year = Integer.parseInt(strDateTok.nextToken());
GregorianCalendar cal = new GregorianCalendar();
// Check if present year is leap year
boolean boolIsLeapYear = cal.isLeapYear(year);
// If it is boolean year then add 1 to total days in the year & add one more day to february
if(boolIsLeapYear)
noOfDaysInTheYear=noOfDaysInTheYear+1;
monthDaysArray[1]=monthDaysArray[1]1;
// Find the 1st day of this year
Calendar calObj = new GregorianCalendar(year, Calendar.JANUARY, 1);
firstDayOfPresentYear = calObj.get(Calendar.DAY_OF_WEEK);
int intRemoveNoOfDaysFromWeek=0;
// # Find the day no of prsent day
for(i=0;i<month;i+) // get no of days till present year
intTemp = intTemp monthDaysArray;
todaysDayNoInPresentYear = intTemp - (monthDaysArray[month-1]-day);
if(firstDayOfPresentYear==6 || firstDayOfPresentYear==7) // If first Day is Friday or Saturday then it is week
// Identify the the day no on which 1st week of present year is starting
firstDayNoInFirstWeekOfPresentYear = 7 - firstDayOfPresentYear WEEK_STARTS_ON 1;
// Find delay in the 1st week start after r=the year start
daysLateByFirstWeekStartedAfterYearStarted = firstDayNoInFirstWeekOfPresentYear - 1;
// Now week is starting from Sunday
weekNo = (Integer)((todaysDayNoInPresentYear-daysLateByFirstWeekStartedAfterYearStarted)/7);
// Find the day no of today
intTemp = (todaysDayNoInPresentYear-daysLateByFirstWeekStartedAfterYearStarted) % 7;
if(intTemp > 0)
weekNo=weekNo+1;
else
weekNo=weekNo;
else
// 1st week is starting on 1st Of January
firstDayNoInFirstWeekOfPresentYear=firstDayOfPresentYear;
// Remove no. of days from the 1st week as week is starting from odd Sunday/Monday/Tuesday/Wednesday/Thursday
intRemoveNoOfDaysFromWeek = 7-firstDayOfPresentYear 1; // 1 added as include start day also
// So one week will be added in no. of weeks
weekNo = (Integer)((todaysDayNoInPresentYear-intRemoveNoOfDaysFromWeek)/7);
// Find the day no of today
intTemp = (todaysDayNoInPresentYear-intRemoveNoOfDaysFromWeek) % 7;
weekNo = weekNo +1; // As 1st weeks days are reduced from the todays day no in the year
if(intTemp > 0)
weekNo=weekNo+1;
else
weekNo=weekNo;
// Remove the no. of days from the week 1
strWeekNo=Integer.toString(weekNo);
return strWeekNo;
// Any issues please mail on [email protected] or [email protected]

Get number of month, week and date between 2 dates

Hi all,
Is it possible to display number of month, week and days between 2 dates? either by using only SQL query or through PL/SQL...
Input:
From date: 01-Oct-2010
To date: 19-Oct-2010
I want output as below (Assuming the week starts from Monday to Sunday in oracle).
01-Oct-2010 -- (Since this is in mid of the week)
02-Oct-2010 -- (Since this is in mid of the week)
03-Oct-2010 -- (Since this is in mid of the week)
40 -- (Oct 4 to Oct 10 falls in 40th week of the year)
41 -- (Oct 11 to Oct 17 falls in 41th week of the year)
18-Oct-2010 -- (Since this is in mid of the week)
19-Oct-2010 -- (Since this is in mid of the week)
Note: If there is one full month between the given date, then the month number should be displayed.
After the month, the remaining date comprised with one full week, then the week number of the year should
be displayed. After displaying the week, the remaining dates should be displayed as it is..
Appreciate your help..
Thanks.
Rajan.

I suppose if it's just like a calendar type information you want then something like...
SQL> break on month skip 1
SQL> set linesize 200
SQL> set pagesize 2000
SQL> column month format a20
SQL> column week format a4
SQL> with req as (select '&Required_Year_YYYY' as yr from dual)
2      ,offset as (select case when to_char(trunc(to_date(yr,'YYYY'),'YYYY'),'IW') in ('52','53') then 1 else 0 end as offset from req
3 select lpad( Month, 20-(20-length(month))/2 ) month,
4         '('||week||')' as week, "Mo", "Tu", "We", "Th", "Fr", "Sa", "Su"
5 from (
6    select to_char(dt,'fmMonth YYYY') month,
7    case when to_char(dt, 'mm') = '12' and to_char(dt,'iw') = '01' and offset = 0 then '53'
8         when to_char(dt, 'mm') = '12' and to_char(dt,'iw') = '01' and offset = 1 then '54'
9         when to_char(dt, 'mm') = '01' and to_char(dt,'iw') in ('52','53') then '1'
10         else to_char(to_number(to_char(dt,'iw'))+offset) end as week,
11    max(decode(to_char(dt,'d'),'1',lpad(to_char(dt,'fmdd'),2))) "Mo",
12    max(decode(to_char(dt,'d'),'2',lpad(to_char(dt,'fmdd'),2))) "Tu",
13    max(decode(to_char(dt,'d'),'3',lpad(to_char(dt,'fmdd'),2))) "We",
14    max(decode(to_char(dt,'d'),'4',lpad(to_char(dt,'fmdd'),2))) "Th",
15    max(decode(to_char(dt,'d'),'5',lpad(to_char(dt,'fmdd'),2))) "Fr",
16    max(decode(to_char(dt,'d'),'6',lpad(to_char(dt,'fmdd'),2))) "Sa",
17    max(decode(to_char(dt,'d'),'7',lpad(to_char(dt,'fmdd'),2))) "Su"
18    from ( select trunc(to_date(req.yr,'YYYY'),'y')-1+rownum dt
19           from all_objects, req
20           where rownum <= add_months(trunc(to_date(req.yr,'YYYY'),'y'),12) - trunc(to_date(req.yr,'YYYY'),'y') )
21        ,offset
22    group by to_char(dt,'fmMonth YYYY'),     case when to_char(dt, 'mm') = '12' and to_char(dt,'iw') = '01' and offset = 0 then '53'
23                                                  when to_char(dt, 'mm') = '12' and to_char(dt,'iw') = '01' and offset = 1 then '54'
24                                                  when to_char(dt, 'mm') = '01' and to_char(dt,'iw') in ('52','53') then '1'
25                                                  else to_char(to_number(to_char(dt,'iw'))+offset) end
26    ) x
27 order by to_date( month, 'Month YYYY' ), to_number(x.week)
28 /
Enter value for required_year_yyyy: 2010
old   1: with req as (select '&Required_Year_YYYY' as yr from dual)
new   1: with req as (select '2010' as yr from dual)
MONTH                WEEK Mo Tu We Th Fr Sa Su
    January 2010     (1)               1 2 3
                     (2)   4 5 6 7 8 9 10
                     (3) 11 12 13 14 15 16 17
                     (4) 18 19 20 21 22 23 24
                     (5) 25 26 27 28 29 30 31
   February 2010     (6)   1 2 3 4 5 6 7
                     (7)   8 9 10 11 12 13 14
                     (8) 15 16 17 18 19 20 21
                     (9) 22 23 24 25 26 27 28
     March 2010      (10) 1 2 3 4 5 6 7
                     (11) 8 9 10 11 12 13 14
                     (12) 15 16 17 18 19 20 21
                     (13) 22 23 24 25 26 27 28
                     (14) 29 30 31
     April 2010      (14)           1 2 3 4
                     (15) 5 6 7 8 9 10 11
                     (16) 12 13 14 15 16 17 18
                     (17) 19 20 21 22 23 24 25
                     (18) 26 27 28 29 30
      May 2010       (18)                 1 2
                     (19) 3 4 5 6 7 8 9
                     (20) 10 11 12 13 14 15 16
                     (21) 17 18 19 20 21 22 23
                     (22) 24 25 26 27 28 29 30
                     (23) 31
     June 2010       (23)     1 2 3 4 5 6
                     (24) 7 8 9 10 11 12 13
                     (25) 14 15 16 17 18 19 20
                     (26) 21 22 23 24 25 26 27
                     (27) 28 29 30
     July 2010       (27)           1 2 3 4
                     (28) 5 6 7 8 9 10 11
                     (29) 12 13 14 15 16 17 18
                     (30) 19 20 21 22 23 24 25
                     (31) 26 27 28 29 30 31
    August 2010      (31)                    1
                     (32) 2 3 4 5 6 7 8
                     (33) 9 10 11 12 13 14 15
                     (34) 16 17 18 19 20 21 22
                     (35) 23 24 25 26 27 28 29
                     (36) 30 31
   September 2010    (36)        1 2 3 4 5
                     (37) 6 7 8 9 10 11 12
                     (38) 13 14 15 16 17 18 19
                     (39) 20 21 22 23 24 25 26
                     (40) 27 28 29 30
    October 2010     (40)              1 2 3
                     (41) 4 5 6 7 8 9 10
                     (42) 11 12 13 14 15 16 17
                     (43) 18 19 20 21 22 23 24
                     (44) 25 26 27 28 29 30 31
   November 2010     (45) 1 2 3 4 5 6 7
                     (46) 8 9 10 11 12 13 14
                     (47) 15 16 17 18 19 20 21
                     (48) 22 23 24 25 26 27 28
                     (49) 29 30
   December 2010     (49)        1 2 3 4 5
                     (50) 6 7 8 9 10 11 12
                     (51) 13 14 15 16 17 18 19
                     (52) 20 21 22 23 24 25 26
                     (53) 27 28 29 30 31
61 rows selected.
SQL>

Derive week number of that month

Hi,
I need to derive week number based on month.
Ex:
Sy-datum = 10.10.2010
Month: 10.2010
Calweek: 40.2010
Week no: 2
Sy-datum = 11.10.2010
Month: 10.2010
Calweek: 41.2010
Week no: 3
So for everymonth I need to store the week no in the cube
Ex
Date--Month--
calweek............weekno
10.10.2010.............10.2010.............40.2010...............2
10.10.2010.............10.2010.............40.2010...............2
10.10.2010.............10.2010.............40.2010...............2
11.10.2010.............10.2010.............41.2010...............3
11.10.2010.............10.2010.............41.2010...............3
11.10.2010.............10.2010.............41.2010...............3
So here i need to derive week number for a date in the month
Can anyone please help what logic to be applied to get the week number?
Thanks
Annie
Edited by: Annie on Oct 14, 2010 7:48 AM

Hi Annie, I'm not very sure of any function modules, but you may try this logic:
1. Date Format Stored in SAP: YYYYMMDD.
2. Use a formula X+6(2) to get the DD part.
3. Use Conversion Exit 'CONVERSION_EXIT_ALPHA_INPUT'
4. Logic: [ DATUM's DD ] MOD 7 which gives the week # ordering for the particular month.
5. Close the START Routine passing the temp value to RESULT.
DATA:var_dd type sy-datum, var_temp(2) type i.
var_dd = SOURCE_FIELDS-ZDATE+6(2).
      CALL FUNCTION 'CONVERSION_EXIT_ALPHA_INPUT'
        EXPORTING
          INPUT = var_dd
        IMPORTING
          OUTPUT = var_dd.
if sy-subrc = 0.
var_temp = var_dd MOD 7.
end if.
RESULT = var_temp.
Pls. review & let me know your comments.
Thanks.
Edited by: Arun Bala G on Oct 14, 2010 12:22 PM

Best method to determine the week number of a month - SQL Server 2012

Hi,
I'm searching the most valid and tested method to determine the week number respect to a month.
Fe, the 1st January falls in the 1st week of January, the 1st February fall in the 1st week of February, and so on.
I've found many solutions but I'd like to know possibly the best one.
Thanks

Hi Uri,
SELECT DATEPART(week, '20150104')
   - DATEPART(week, CONVERT(CHAR(6), '20150104', 112)+'01')
   + 1
returns 2 and not 1. It's a Sunday.
Waiting to be spoonfed, eh?
The one-off in my query would be very simple to figure out - I forgot to add the +1. Is too much to expect from you that you could figure it out yourself?
And likewise, in my post I said that you should use "week" for weeks starting on Sunday, and "iso_week" if your week starts on Monday. Uri neglected to observe this, but you had the information to correct it. If you had been interested
in doing some work yourself, that is.
Nevertheless, there is an issue that I overlooked:
DECLARE @day date = '20160105'
SELECT datepart(iso_week, @day) -
   datepart(iso_week, convert(char(6), @day, 112) + '01') + 1
This returns -51. This is because with ISO week numbering, Jan 1st falls into week 53 of the previous year, if it's on a Friday or later. Week 1 is always the week of Jan 4th. When you week this does not happen, as week 1 is always the week with Jan
1st. (Dec 31st is always in week 53 or 54.)
To correct for this, we need this query:
SELECT DATEPART(iso_week, @day) -
   CASE WHEN DATEPART(iso_week, CONVERT(CHAR(6), @day, 112) + '01') < 50
THEN DATEPART(iso_week, CONVERT(CHAR(6), @day, 112) + '01')
ELSE 1
   END + 1
Erland Sommarskog, SQL Server MVP, [email protected]

Get Week Number of Current Month

How can I get the week number of the current month (1-5)?
This is what I have tried and I'm not getting the expected
results.

quote:
Originally posted by:
DJ5MD
Does your go 1-5 since it's only 30 days? Is that the
difference?
I think he was referring to your comment "How can I get the
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weeks so you should take that into account.
Both the function from cflib.org and his code should return 6
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How do I set twice monthly events based on the week number

Greetings all. I can't seem to navigate this help system, so hopefully I'm not reasking something that's already been asked. But I have a problem with iCal that I just can't figure out of find an answer to. I need to create a twice monthly event, but it's based on the week number, not every two weeks. For example, I need to be able to create an event for the 2nd and 4th Mondays of the month. Is that possible with iCal? Thanks for your help... and not laughing at me
Steve

No problem.
Go to Monday select the day you want. Create new Event. Then select repeat and you will come up with how you want to repeate it. Select Monthly and then do the following:

How to determine the month from the week number?

Hi all,
in a routine i have the week number in a year and i need to find the month but i don't know the correct FM to use for this.
Is there anyone that had to face a similar problem?
I'm considering that to determine the month it will be used the first day of the week since there are weeks belonging to 2 different months...
Thank you
Stefano

Hi
If you have a Fiscal Year Variant determined for the week you can use function module PERIOD_DAY_DETERMINE by passing week,fiscal year and fiscal year variant for the week which will return fist and last date.So based on last data you can determine the month.
Regards
Srilaxmi

FM for week number of month

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