Full outer join query giving error

Question

Hi I have written the below query to get the fields below as an out put but am getting the error missing keyword..am not understanding where did i missed..i have done step by step query analysis..but could not find the error.
Please help me in resolving the issue.
Expected output Columns :*
COUNTRY , TRN_TYPE ,SKU ,BIX_Customer ,PERIOD ,CURRENTSTOCK ,STOCK_VALUE ,SALES ,SALES_VALUE ,TARGET
Query :_
select (case when a.country is null then b.country when b.country is null then c.country else a.country end) AS COUNTRY,
(case when a.Sale_Type is null then b.Stk_type when b.stk_type is null then c.Stk_type else a.Sale_Type end) AS TRN_TYPE,
(case when a.sku is null then b.sku when b.sku is null then c.sku else a.sku end) AS SKU,
(case when a.bix_customer is null then b.bix_customer_code when b.bix_customer_code is null then c.bix_customer_code else a.bix_customer end)AS BIX_Customer ,
(case when a.period is null then TO_number(b.period) when b.period is null then TO_NUMBER(c.period) else a.period end) AS PERIOD,
nvl(b.CURRENTSTOCK,0) AS CURRENTSTOCK,
nvl(b.stock_value,0) AS STOCK_VALUE,
nvl(a.sales,0) AS SALES,
nvl(a.SALES_VALUE,0) AS SALES_VALUE,
nvl(c.TARGET_QTY,0) AS TARGET
from
(select UPPER(c.cust_country_name) AS COUNTRY,
DECODE(ds.account_key,7156,'SAMPLE',7157,'BONUS',7485,'SALE') AS Sale_Type,
substr(i.item_code,7) AS SKU,
c.bix_customer_code AS BIX_Customer,
ds.descr as descr ,
ds.period as period,
sum(ds.quantity) AS SALES,
sum(case when ds.local_value is null then ds.euro_value else ds.local_value END) AS SALES_VALUE
FROM distributor_sales ds, customer c, item i
where ds.customer_key=c.customer_key
and ds.item_key= i.item_key
group by ds.period,
ds.account_key,
c.cust_country_name,
substr(i.item_code,7),
c.bix_customer_code,
ds.descr) a
full outer join
(SELECT UPPER(b.cust_country_name) AS COUNTRY,
DECODE(s.stock_type,'SALE','SALE','SALES','SALE','BONUS','BONUS','SAMPLE','SAMPLE') AS Stk_type,
substr(c.item_code,7) AS SKU,
s.descr as descr,
s.period as period,
b.bix_customer_code,
sum(s.CLOSING_STOCK) CURRENTSTOCK,
sum(s.closing_stock*s.cif_price) STOCK_VALUE
FROM STOCK s, customer b, item c
WHERE s.customer_key=b.customer_key
and s.item_key= c.item_key
group by
s.descr,
s.stock_type,
s.period, b.bix_customer_code,b.cust_country_name,substr(c.item_code,7) ) b
full outer join
(SELECT UPPER(cu.cust_country_name) AS COUNTRY,
DECODE(t.description,'SALES TARGET','SALE') AS Stk_type,
substr(it.item_code,7) AS SKU,
t.channel as channel,
t.period as period,
cu.bix_customer_code as bix_customer_code,
sum(t.quantity) TARGET_QTY
FROM sales_target t, customer cu, item it
WHERE t.customer_key=cu.customer_key
and t.item_key= it.item_key
group by
t.channel,
t.description,
t.period, cu.bix_customer_code,cu.cust_country_name,substr(it.item_code,7) ) c
on a.SKU=b.SKU
and a.sku=c.SKU
and b.sku=c.SKU
and a.BIX_Customer=b.bix_customer_code
and a.BIX_Customer=c.bix_customer_code
and b.bix_customer_code=c.bix_customer_code
and a.Sale_Type=b.Stk_type
and a.Sale_Type=c.Stk_type
and b.Stk_type=c.Stk_type
and a.descr=b.descr
and b.descr=c.channel
and a.descr=c.channel
and a.country=b.country
and a.country=c.COUNTRY
and b.country=c.COUNTRY
and a.period=b.period
and a.period=c.period
and b.period=c.period;

Answer 1

<tt>Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production</tt>
You must be aware that you must cascade full outer joins
with
t1 as
(select 1 key,1.1 data from dual union all
select 3,1.3 from dual union all
select 6,1.6 from dual union all
select 7,1.7 from dual
t2 as
(select 2 key,2.2 data from dual union all
select 3,2.3 from dual union all
select 4,2.4 from dual union all
select 6,2.6 from dual
t3 as
(select 4 key,3.4 data from dual union all
select 5,3.5 from dual union all
select 6,3.6 from dual union all
select 7,3.7 from dual
select nvl(x.key,t3.key) key,
       x.data_1,
       x.data_2,
       t3.data data_3
  from (select nvl(t1.key,t2.key) key,
               t1.data data_1,
               t2.data data_2
          from t1
               full outer join
               t2
            on t1.key = t2.key
       ) x
       full outer join
       t3
    on t3.key = x.key
order by keyunless you can live with duplicate key rows you cannot avoid whenever all table pairs contain common keys (try the below using data from above)
select coalesce(t1.key,t2.key,t3.key) key,
       t1.data data_1,
       t2.data data_2,
       t3.data data_3
  from t1
       full outer join
       t2
    on t1.key = t2.key
       full outer join
       t3
    on t3.key = t1.key
   and t3.key = t2.key
order by key
select coalesce(t1.key,t2.key,t3.key) key,
       t1.data data_1,
       t2.data data_2,
       t3.data data_3
  from t2
       full outer join
       t3
    on t2.key = t3.key
       full outer join
       t1
    on t1.key = t2.key
   and t1.key = t3.key
order by key
select coalesce(t1.key,t2.key,t3.key) key,
       t1.data data_1,
       t2.data data_2,
       t3.data data_3
  from t1
       full outer join
       t3
    on t1.key = t3.key
       full outer join
       t2
    on t2.key = t1.key
   and t2.key = t3.key
order by keyRegards
Etbin
Edited by: Etbin on 10.4.2013 9:53
If you're after
select *
  from (select *
          from (select *
                  from t1
               ) a
               full outer join
               (select *
                  from t2
               ) b
            on t1.key = t2.key
       ) x
       full outer join
       t3
    on t3.key = x.key
order by keyyou're presently at
select *
  from (
               (select *
                  from t1
               ) a
               full outer join
               (select *
                  from t2
               ) b
            on t1.key = t2.key
       ) x
       full outer join
       t3
    on t3.key = x.key
order by keyORA-00933: SQL command not properly ended