Function call another function variable

Question

Is it possible to call another function variable?
Below is my Script:
f2();
function f1() { 
  var v2 = 1; 
function f2(v2) { 
  var v3= 2; 
  alert(v2);

Answer 1

Hi creativejoan0425,
Some additional notes:
> Is it possible to call access another function variable?
No, it isn't. A local variable only lives in the scope of the function (body) where it is declared. In that sense any local variable should be considered private—in OOP terms.
pixxxel schubser's solution is based on setting a global scope for the variable myA, so it is visible from every place of your code.
Another solution could be implemented using JS closure mechanism. You can create a local scope (in an anonymous function which is executed once) then return your main function and additional helpers from that scope. All inner functions have then access to the local variables that have been declared in the scope. For example, you can create your function f1 and attach a getter function to it, as follows:
var f1 = (function(/*anonymous*/__)
    // Local variable to be nested in the closure
    var v1;
    (__ = function(/*optional init value*/x)
        // Here is your *actual* function
        // do what you want with v1
        v1 = 'undefined'!=typeof x ? x : Math.random();
    ).getVar = function()
        // Here is your getter
        return v1;
    return __;
var f2 = function()
    alert( f1.getVar() );
// Process
f1('init');
f2();           // => 'init'
f1();
f2();           // => some random number
f1();
f2();           // => another random number
// etc
This way v1 remains almost private but the outer code can read it through f1.getVar().
Anyway this seems to me a complicate approach for a basic script that probably does not require high security level. Another option, really easy to set up, is to use the fact that a function is an object. Instead of declaring a local variable, just handle v1 as a (public) member of f1, as follows:
var f1 = function F(/*optional init*/x)
    // Do something with F.var
    F.v1 = 'undefined'!=typeof x ? x : Math.random();
var f2 = function()
    alert( f1.v1 );
f1('init');
f2();          // => 'init'
f1();
f2();          // => some random number
f1();
f2();          // => another random number
That's it!
> why every function need to return?
No, return is not required. By default, any function that has no return statement will simply return undefined.
@+
Marc