Get a value based on the max value

Question

Hi all,
would u be so kind and show me the way to get something (without having select from the main select) from the data listed below? For simplicity i've typed the result i'd like to get
data i have:
day starttime id test_value
'25.5.2007','10:00', 'A', 3
'25.5.2007','10:15', 'A', 2
'25.5.2007','10:35', 'A', 4
'25.5.2007','10:45', 'A', 1
simply get the line where is the max( test_value ) for a whole day:
ID test_value STARTTIME
'A', 4, '10:35'
thanks

Answer 1

SQL> create table mytable
  2  as
  3  select date '2007-05-25' day, '10:00' starttime, 'A' id, 3 test_value from dual union all
  4  select date '2007-05-25', '10:15', 'A', 2 from dual union all
  5  select date '2007-05-25', '10:35', 'A', 4 from dual union all
  6  select date '2007-05-25', '10:45', 'A', 1 from dual
  7  /
Tabel is aangemaakt.
SQL> var P_DATE varchar2(10)
SQL> exec :P_DATE := '2007-05-25'
PL/SQL-procedure is geslaagd.
SQL> select day
  2       , max(starttime) keep (dense_rank last order by test_value) starttime
  3       , max(id) keep (dense_rank last order by test_value) id
  4       , max(test_value) test_value
  5    from mytable
  6   where day = to_date(:P_DATE,'yyyy-mm-dd')
  7   group by day
  8  /
DAY                 START I TEST_VALUE
25-05-2007 00:00:00 10:35 A          4
1 rij is geselecteerd.And you should really think about combining the columns day and starttime into one column. A date contains a time component as well.
Regards,
Rob.
Message was edited by:
Rob van Wijk
Misread the question, so posted a new solution.