Get candidate name

hi all,
I need to get the name of a candidate name using CL_HRREF_CANDIDATE class . It has 2 method GET() and GET_CAND_DESCRIPTION(). I am taking Candidate id from HRP5133.
can you please give me the steps to find the name of the candidate.
Regards,
Anirban

Hello Anirban
Below you see how you can retrieve the name of the candidate (NOTE: I found only class CL_HRHCF_CANDIDATE in our ERP):
DATA: go_candidate   TYPE REF TO cl_hrhcf_candidate.
DATA: gs_hrp5133      TYPE hrp5133.
DATA: gd_descript      TYPE BU_DESCRIP.
DATA: gd_fullname      TYPE BU_NAME1TX.
go_candidate = cl_hrhcf_candidate( user = gs_hrp5133-uname ).
gd_descript   = go_candidate->get_cand_description( ).   " Or use public attribute:
gd_fullname = go_candidate->centraldataperson-fullname.
Instead of the username you can use also use the candidate ID (persumable HRP5133-OTJID).
Regards
Uwe

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E Recruitment -Candidate applied for job but not reflected candidate name

E Recruitment
Candidate applied for job but not reflected candidate name Recruiter Dashboard
Please any one suggests me what is problem?
Regards
Eshwar

Hello Sri,
the solution to your first question might be very easy. In EhP 4 the entries in the dashboard do not appear automatically. In most cases you have to refresh the dashboard (be aware this is only effecting the current dashboard work list, not all if you do not use the refresh all button). Soclick the "My new Applications" and then refress this workset.
If this does not help we will have to look closer into this issue (overall I assume you have EhP4 SP 6 applied).
For question 2. It is a quite common requirement that an external publication is nearly only based on the posting texts while the internal publication includes much more specific information (org. management, cost center, pay scale group). As you are free in designing you own company specific internal and external publications they can look however you want (in the general restriction what a smartform can do of course). For different publication texts companies create different postings one for internal and one for external publication. The additional information are in some cases entered directly into these texts, in some cases maintained in e-rec fields not needed for other requirements, in customer own fields or directly gathered from the HR core system. It depends a bit on the exact requirement which is the best solution. For the fields you mentioned I'd probably go for OM integration for e-rec (assigning positions to requisition) and get the Information via customer RFC function module directly in the smartform (if the security guys allow the access to the HR system from the e-rec system).
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Kind Regards
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Candidate Name E-Recruiting

how can I bring a candidate name to a query in e-recruiting?
thanks in advance, Sony

Hi,
If you are in EhP4, SAP provides several Infosets with access to data on Candidates and/or Requisitions. You can use Infosets ERC_APPLICANT_MGMNT and ERC_REQUISITION_MGMNT via Ad Hoc Query or SQ01 to create your reports. ERC_APPLICANT_MGMNT does get the Candidate name from the Business partner data. You can also add other data such as posting applied for, work experience, education, etc. to your queries.
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GET FILE NAME C:\temp\ADIBO.txt

Hi,
How to get file name?
I used Get_File_NAME, but I'am getting an error.
lv_lfilename is not the type LOGICAL_FILENAME
C:\temp\ADIBO.txt
I need to get ADIBO ??
tnh, Adibo..:)
I am using this code to download file and after that I need to get FILE_NAME:
DATA: lv_lfilename TYPE string.
PARAMETERS:
pa_lfile TYPE zlocalfile
           DEFAULT 'C:temp'.
    CONCATENATE pa_lfile ''INTO lv_lfilename.
    CALL FUNCTION 'GUI_DOWNLOAD'
         EXPORTING
              filename = lv_lfilename
              filetype = 'ASC'
         TABLES
              data_tab = it_billit_down.
    IF sy-subrc <> 0.
* MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
*         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
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Hii..
You have to Maintain the Logical filenames and their Physical Paths in Tcode FILE.
Then create a program like this..
REPORT ZSEL_FILES1.
DATA : V_LOGFILE TYPE STRING.
DATA :V_PHYFILE TYPE STRING.
DATA : ITAB TYPE TABLE OF SCARR.
START-OF-SELECTION.
SELECT * FROM SCARR INTO TABLE ITAB.
**To get the Physical file based on the Logical file names - Maintained in Tcode FILE
CALL FUNCTION 'FILE_GET_NAME'
EXPORTING
   CLIENT                        = SY-MANDT
    LOGICAL_FILENAME              = VlOGFILE
OPERATING_SYSTEM              = SY-OPSYS
PARAMETER_1                   = ' '
PARAMETER_2                   = ' '
PARAMETER_3                   = ' '
USE_PRESENTATION_SERVER       = ' '
WITH_FILE_EXTENSION           = ' '
USE_BUFFER                    = ' '
ELEMINATE_BLANKS              = 'X'
IMPORTING
EMERGENCY_FLAG                =
FILE_FORMAT                   =
   FILE_NAME                     = V_PHYFILE
EXCEPTIONS
FILE_NOT_FOUND                = 1
OTHERS                        = 2
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
**To download the file to PC.
CALL FUNCTION 'GUI_DOWNLOAD'
EXPORTING
BIN_FILESIZE                    =
    FILENAME                        = V_PHYFILE
   FILETYPE                        = 'ASC'
APPEND                          = ' '
   WRITE_FIELD_SEPARATOR           = 'X'
HEADER                          = '00'
TRUNC_TRAILING_BLANKS           = ' '
WRITE_LF                        = 'X'
COL_SELECT                      = ' '
COL_SELECT_MASK                 = ' '
DAT_MODE                        = ' '
CONFIRM_OVERWRITE               = ' '
NO_AUTH_CHECK                   = ' '
CODEPAGE                        = ' '
IGNORE_CERR                     = ABAP_TRUE
REPLACEMENT                     = '#'
WRITE_BOM                       = ' '
TRUNC_TRAILING_BLANKS_EOL       = 'X'
WK1_N_FORMAT                    = ' '
WK1_N_SIZE                      = ' '
WK1_T_FORMAT                    = ' '
WK1_T_SIZE                      = ' '
IMPORTING
FILELENGTH                      =
TABLES
    DATA_TAB                        = ITAB
FIELDNAMES                      =
EXCEPTIONS
FILE_WRITE_ERROR                = 1
NO_BATCH                        = 2
GUI_REFUSE_FILETRANSFER         = 3
INVALID_TYPE                    = 4
NO_AUTHORITY                    = 5
UNKNOWN_ERROR                   = 6
HEADER_NOT_ALLOWED              = 7
SEPARATOR_NOT_ALLOWED           = 8
FILESIZE_NOT_ALLOWED            = 9
HEADER_TOO_LONG                 = 10
DP_ERROR_CREATE                 = 11
DP_ERROR_SEND                   = 12
DP_ERROR_WRITE                  = 13
UNKNOWN_DP_ERROR                = 14
ACCESS_DENIED                   = 15
DP_OUT_OF_MEMORY                = 16
DISK_FULL                       = 17
DP_TIMEOUT                      = 18
FILE_NOT_FOUND                  = 19
DATAPROVIDER_EXCEPTION          = 20
CONTROL_FLUSH_ERROR             = 21
OTHERS                          = 22
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
<b>reward if helpful</b>

HP ePrint from excel add-in: Error while getting driver name for printer

Trying to use add-in for ePrint from excel/word I get, "error while getting driver name for printer \\...HP DesignJet 800PS 42 by HP," with an option to select "OK" and that same message repeats with each printer in our network, and then it doesn't allow me to print using the add-in. However, I can print normally to HP Go Web, open up Print and Share, then print it from there. This happens with excel and word. I have Office Suite 2007.

Hello modameister,
Sorry you are having issues with this printer and the ePrint add-on. There are a couple of questions I would like you to answer please.
1. What operating system are you using? (XP,VISTA,7,MAC OS X)
2. What and how much data are you trying to print?
3. Have you tried to copy and paste the data into a different application or tried using the snip it tool?
4. Are you receiving any .dll errors (mscms.dll)
Thanks
If I have solved your issue, please feel free to provide kudos and make sure you mark this thread as solution provided!
Although I work for HP, my posts and replies are my own opinion and not those of HP.

Cisco Unity 7: Voice mail cann't get the name or Number phone of the caller

Hi,
I have installed Cisco Unity Messaging Unified version 7 and integrated with Exchange 2010.
I have two scenario, and I want to know if are normal or not:
1. If the 2 IP phones are subscribed with Cisco Unity: the first IP phone call the other IP phone and let a voice mail. When the second IP phone check his message vocal it can get the name of the caller or his number phone (the message is: You have One message from XXXX) and he get e-mail as objet: Voice Mail from XXXX.
2. If one IP phone is not subscriber with cisco unity call other Ip phone subscribed with cisco unity and let him a voice mail. The second IP phone when check his message vocal it can’t get the name of the caller or his number phone: The message is: You have one voice mail xxxx; without indicate from!! and he get a e-mail as object: Voice mail from Unknown.
Please, I want to know if the second scenario is normal ? if not, who to resolve this problem? I want that he indicate the number of caller same he isn't subscriber with cisco unity?
Thanks a lot,
Best regards,
Omar YUNSI

So for the 2nd scenerio you would want to check what your Message Subjects were set to. For Unity 7 open Web SA, click Configuration and then Message Subjects. Make sure that the Outside Caller Message has %CALLERID% in it somewhere. The value %CALLERNAME% will return unknown if we do not receive a name from the PSTN.
Try setting the Outside Caller Message to:
%U% %P% Voice Message from %CALLERID%
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The default Message subject is:
%U% %P% Voice Message from %CALLERNAME% (%CALLERID%). So with that it would say Voice Message fom Unknown (xxxx) if it was not able to determine the name of the user which is usually normal from a PSTN call.
Just to note, the From address is always going to say from Unity Messaging System, it will only be the subject that has the extension in it.
Bryan

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group.

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group. Through this memberof class I am trying to find full qualified name(DN) of my group.
code I have used:
//specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "";
Also I have used,
             String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "ou=ibmgroups,o=ibm.com";
But in both cases I am getting value for Total groups as 0.
Code Reference:
* memberof.java
* December 2004
* Sample JNDI application to determine what groups a user belongs to
import java.util.Hashtable;
import javax.naming.*;
import javax.naming.ldap.*;
import javax.naming.directory.*;
public class memberof     {
     public static void main (String[] args)     {
          Hashtable env = new Hashtable();
          String adminName = "CN=Administrator,CN=Users,DC=ANTIPODES,DC=COM";
          String adminPassword = "XXXXXXX";
          String ldapURL = "ldap://mydc.antipodes.com:389";
          env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
          //set security credentials, note using simple cleartext authentication
          env.put(Context.SECURITY_AUTHENTICATION,"simple");
          env.put(Context.SECURITY_PRINCIPAL,adminName);
          env.put(Context.SECURITY_CREDENTIALS,adminPassword);
          //connect to my domain controller
          env.put(Context.PROVIDER_URL,ldapURL);
          try {
               //Create the initial directory context
               LdapContext ctx = new InitialLdapContext(env,null);
               //Create the search controls
               SearchControls searchCtls = new SearchControls();
               //Specify the search scope
               searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
               //specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Andrew Anderson))";
               //Specify the Base for the search
               String searchBase = "DC=antipodes,DC=com";
               //initialize counter to total the group members
               int totalResults = 0;
               //Specify the attributes to return
               String returnedAtts[]={"memberOf"};
               searchCtls.setReturningAttributes(returnedAtts);
               //Search for objects using the filter
               NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
               //Loop through the search results
               while (answer.hasMoreElements()) {
                    SearchResult sr = (SearchResult)answer.next();
                    System.out.println(">>>" + sr.getName());
                    //Print out the groups
                    Attributes attrs = sr.getAttributes();
                    if (attrs != null) {
                         try {
                              for (NamingEnumeration ae = attrs.getAll();ae.hasMore();) {
                                   Attribute attr = (Attribute)ae.next();
                                   System.out.println("Attribute: " + attr.getID());
                                   for (NamingEnumeration e = attr.getAll();e.hasMore();totalResults++) {
                                        System.out.println(" " + totalResults + ". " + e.next());
                         catch (NamingException e)     {
                              System.err.println("Problem listing membership: " + e);
               System.out.println("Total groups: " + totalResults);
               ctx.close();
          catch (NamingException e) {
               System.err.println("Problem searching directory: " + e);
Any help will be highly appreciated.

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group. Through this memberof class I am trying to find full qualified name(DN) of my group.
code I have used:
//specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "";
Also I have used,
             String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "ou=ibmgroups,o=ibm.com";
But in both cases I am getting value for Total groups as 0.
Code Reference:
* memberof.java
* December 2004
* Sample JNDI application to determine what groups a user belongs to
import java.util.Hashtable;
import javax.naming.*;
import javax.naming.ldap.*;
import javax.naming.directory.*;
public class memberof     {
     public static void main (String[] args)     {
          Hashtable env = new Hashtable();
          String adminName = "CN=Administrator,CN=Users,DC=ANTIPODES,DC=COM";
          String adminPassword = "XXXXXXX";
          String ldapURL = "ldap://mydc.antipodes.com:389";
          env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
          //set security credentials, note using simple cleartext authentication
          env.put(Context.SECURITY_AUTHENTICATION,"simple");
          env.put(Context.SECURITY_PRINCIPAL,adminName);
          env.put(Context.SECURITY_CREDENTIALS,adminPassword);
          //connect to my domain controller
          env.put(Context.PROVIDER_URL,ldapURL);
          try {
               //Create the initial directory context
               LdapContext ctx = new InitialLdapContext(env,null);
               //Create the search controls
               SearchControls searchCtls = new SearchControls();
               //Specify the search scope
               searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
               //specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Andrew Anderson))";
               //Specify the Base for the search
               String searchBase = "DC=antipodes,DC=com";
               //initialize counter to total the group members
               int totalResults = 0;
               //Specify the attributes to return
               String returnedAtts[]={"memberOf"};
               searchCtls.setReturningAttributes(returnedAtts);
               //Search for objects using the filter
               NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
               //Loop through the search results
               while (answer.hasMoreElements()) {
                    SearchResult sr = (SearchResult)answer.next();
                    System.out.println(">>>" + sr.getName());
                    //Print out the groups
                    Attributes attrs = sr.getAttributes();
                    if (attrs != null) {
                         try {
                              for (NamingEnumeration ae = attrs.getAll();ae.hasMore();) {
                                   Attribute attr = (Attribute)ae.next();
                                   System.out.println("Attribute: " + attr.getID());
                                   for (NamingEnumeration e = attr.getAll();e.hasMore();totalResults++) {
                                        System.out.println(" " + totalResults + ". " + e.next());
                         catch (NamingException e)     {
                              System.err.println("Problem listing membership: " + e);
               System.out.println("Total groups: " + totalResults);
               ctx.close();
          catch (NamingException e) {
               System.err.println("Problem searching directory: " + e);
Any help will be highly appreciated.

Why do I get a class conflict between the Prepare SQL.vi and the Get Column Name.vi with the SQL Toolkit compatibility vis from the Database Connectivity Toolkit?

I have done extensive programming with the SQL Toolkit with LabVIEW versions through 6.1. My customer now wants to upgrade to Windows 7, so I am trying to upgrade to LabVIEW 2009 (my latest purchased version) using the Database Connectivity Toolkit, and the SQL Toolkit Compatibility vis. Everything seemed to be going okay with the higher level SQL operations, but I ran into trouble with the Get Column Name.vi.
The pictures below show the problem. The original SQL Toolkit connected the Prepare SQL.vi with the Get Column Name.vi with a cluster of two references, one for connection, and one for sql. The new compatibility vis have a class conflict in the wire because the Prepare SQL.vi contains a cluster with connection, and command references, but the Get Column Name.vi expects a cluster with connection and recordset references.
How do I resolve this conflict?
Thank You.
Dan

I've never worked with the old version of the toolkit, so I don't know how it did things, but looking inside the SQL prep VI, it only generates a command, and the the column name VI wants a recordset. I'm not super familiar with all the internals of ADO, but my understanding is that is standard - you only have the columns after you execute the command and get the recordset back. What you can apparently do here is insert the Execute Prepared SQL VI in the middle and that will return what you need.
I'm not sure why it worked before. Maybe the execute was hidden inside the prep VI or maybe you can get the column names out of the command object before execution. In general, I would recommend considering switching to the newer VIs.
Try to take over the world!

Any Function module or BAPIs are available to get scheme name for the inter

I have internal order no value in table AUFK-AUFNR , and the internal order corresponding Scheme value is available in IMPR-PRNAM . Now I want to inner join both the tables to extract the data , but there is no common field . Is there any Function module or BAPIs are available to get scheme name for the internal orders?

look at DB-VIEW "V_IVP_OR".
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Laurent

How to get the name and value of an attribute on a node/element that is not a child

Hello,
Can someone shed some wisdom on how I can compare 2 xml nodes for differences.
My main challenge is I need to use the attributes/values of 'ProductDescription' and 'Features' as 'key' to identify the same node in
another doc with the same layout, but different content.
I am having trouble getting the name of the attribute on the node, 'ProductDescription' and 'Features'. I can only seem to get the node names, but not the attributes on the node. I need the name, because it can be different from doc to doc, so
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Can someone please help with how to retrieve an attribute name/value on a node that is not a child. Here's an example of what
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DECLARE
@myDoc1 xml
,@mydoc2 xml
DECLARE
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<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
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<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>
SET @myDoc2 ='<ProductDescription ProductID="1" ProductName="Road Bike">
<Features featureID = "1" featureName = "body">
<Warranty>2 year parts and labor</Warranty>
<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
</Features>
<features featureID = "2" featureName = "wheel">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>
I need to compare the attributes of 'ProductDescription' and 'Features' from @mydoc1 against @mydoc2 to see if they are the same based on those 2 nodes first. If they are, then i want to show the difference in the child elements.
This will eventually be an outer join to give me the differences betw the 2 docs based on those key values (node attributes).
I used node('//*') for the path, and value('local-name(../.)', 'varchar(50)') as element
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...etc...
but that only gives me the node names, and the child elements. It does not give me back the attribute names and values from the node itself.
Thanks in advance for your help.
cee

Are you looking for something like this:
DECLARE @myDoc1 xml
SET @myDoc1 ='<ProductDescription ProductID="1" ProductName="Road Bike">
<Features featureID = "1" featureName = "body">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
</Features>
<Features featureID = "2" featureName = "seat">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>'
SELECT T.c.value('local-name(.)', 'nvarchar(50)') AS name,
T.c.value('.', 'nvarchar(50)') AS value
FROM @myDoc1.nodes('ProductDescription/@*') AS T(c)
Erland Sommarskog, SQL Server MVP, [email protected]

I name each photo buy replacing the jpeg number with the name. when I burn to disk and open disk the name is not shown. how do I get the name given to show on the burn disk?.

after I burn the files to dvd and load to view the name does not appear. How do I get the name listed to appear on the burn disk instead of the file number?

Naming the Photo - or giving it a title - is not the same as naming file.
How are you burning to dvd? With iPhoto? If so then the Title will be available in any app that understands basic metadata.
If you want the title available in the Finder - which does not understand photo metadata - then you'll need to export the file
File -> Export
In the resulting dialogue you'll see a heading for 'File Name'. Choose 'Use Title' from the drop down.
Regards
TD

How to get column names for a specific view in the scheme?

how to get column names for a specific view in the scheme?
TIA
Don't have DD on the wall anymore....

or this?
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How do i get my name on the top right corner next to the search bar? I have OS X Mountain Lion 10.8.5

System Preferences > Users & Groups
Click the lock to unlock it, if you have to.
Click "Login Options".
Enable " Show fast user switching menu as" and select "Full Name".
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How can i get my name to appear under devices in itunes. It got deleted, and I can't get it back on.

I'm trying to get my name to appear under devices in itunes for my iphone. It got deleted, and I can't get it back on.

You need iTunes version 11+.
iPad not appearing in iTunes
http://www.apple.com/support/ipad/assistant/itunes/
iOS: Device not recognized in iTunes for Mac OS X
http://support.apple.com/kb/TS1591
iOS: Device not recognized in iTunes for Windows
http://support.apple.com/kb/TS1538
How to restart the Apple Mobile Device Service (AMDS) on Windows
http://support.apple.com/kb/TS1567
IOS: Syncing with iTunes
http://support.apple.com/kb/HT1386
Apple - Support - iPad - Syncing
http://www.apple.com/support/ipad/syncing/
 Cheers, Tom

How get controls name from a class private data?

How can i get the names of the controls inside a class private data?
I am using Actor Framework and trying to create a method tha will be executed when launch the actor. This method need a list o all the control names inside the class data to search for the initial value inside a configuration file (config.ini), the key on the configuration file will be the name of the control.
Thanks.
Solved!
Go to Solution.

You are already making the overriding method just because you have to write to the Bundle By Name. And then how are you going to handle all of the data types the keys could be. You are making things more difficult than it should be for really very little benefit.
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
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Get candidate name

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