Get commandButton name

hi, I have one commandButton with a action method manage bean and I need in that method get the commandButton name,
thanks in advance
luis

Hi Luis,
Bind the command button to some variable(of type RichCommandButton) in bean using binding property of table and in the action method call getText() method on the command button which returns the commandButton name.
Sample Code:
<af:commandButton binding="#{bean.richButton}" ... />
// Inside bean add a variable with name richButton of type RichCommandButton
private RichCommandButton richButton;
//Getter and setter methods for this
Inside action
just call richButton.getText()
Sireesha

Similar Messages

GET FILE NAME C:\temp\ADIBO.txt

Hi,
How to get file name?
I used Get_File_NAME, but I'am getting an error.
lv_lfilename is not the type LOGICAL_FILENAME
C:\temp\ADIBO.txt
I need to get ADIBO ??
tnh, Adibo..:)
I am using this code to download file and after that I need to get FILE_NAME:
DATA: lv_lfilename TYPE string.
PARAMETERS:
pa_lfile TYPE zlocalfile
           DEFAULT 'C:temp'.
    CONCATENATE pa_lfile ''INTO lv_lfilename.
    CALL FUNCTION 'GUI_DOWNLOAD'
         EXPORTING
              filename = lv_lfilename
              filetype = 'ASC'
         TABLES
              data_tab = it_billit_down.
    IF sy-subrc <> 0.
* MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
*         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
    ENDIF.

Hii..
You have to Maintain the Logical filenames and their Physical Paths in Tcode FILE.
Then create a program like this..
REPORT ZSEL_FILES1.
DATA : V_LOGFILE TYPE STRING.
DATA :V_PHYFILE TYPE STRING.
DATA : ITAB TYPE TABLE OF SCARR.
START-OF-SELECTION.
SELECT * FROM SCARR INTO TABLE ITAB.
**To get the Physical file based on the Logical file names - Maintained in Tcode FILE
CALL FUNCTION 'FILE_GET_NAME'
EXPORTING
   CLIENT                        = SY-MANDT
    LOGICAL_FILENAME              = VlOGFILE
OPERATING_SYSTEM              = SY-OPSYS
PARAMETER_1                   = ' '
PARAMETER_2                   = ' '
PARAMETER_3                   = ' '
USE_PRESENTATION_SERVER       = ' '
WITH_FILE_EXTENSION           = ' '
USE_BUFFER                    = ' '
ELEMINATE_BLANKS              = 'X'
IMPORTING
EMERGENCY_FLAG                =
FILE_FORMAT                   =
   FILE_NAME                     = V_PHYFILE
EXCEPTIONS
FILE_NOT_FOUND                = 1
OTHERS                        = 2
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
**To download the file to PC.
CALL FUNCTION 'GUI_DOWNLOAD'
EXPORTING
BIN_FILESIZE                    =
    FILENAME                        = V_PHYFILE
   FILETYPE                        = 'ASC'
APPEND                          = ' '
   WRITE_FIELD_SEPARATOR           = 'X'
HEADER                          = '00'
TRUNC_TRAILING_BLANKS           = ' '
WRITE_LF                        = 'X'
COL_SELECT                      = ' '
COL_SELECT_MASK                 = ' '
DAT_MODE                        = ' '
CONFIRM_OVERWRITE               = ' '
NO_AUTH_CHECK                   = ' '
CODEPAGE                        = ' '
IGNORE_CERR                     = ABAP_TRUE
REPLACEMENT                     = '#'
WRITE_BOM                       = ' '
TRUNC_TRAILING_BLANKS_EOL       = 'X'
WK1_N_FORMAT                    = ' '
WK1_N_SIZE                      = ' '
WK1_T_FORMAT                    = ' '
WK1_T_SIZE                      = ' '
IMPORTING
FILELENGTH                      =
TABLES
    DATA_TAB                        = ITAB
FIELDNAMES                      =
EXCEPTIONS
FILE_WRITE_ERROR                = 1
NO_BATCH                        = 2
GUI_REFUSE_FILETRANSFER         = 3
INVALID_TYPE                    = 4
NO_AUTHORITY                    = 5
UNKNOWN_ERROR                   = 6
HEADER_NOT_ALLOWED              = 7
SEPARATOR_NOT_ALLOWED           = 8
FILESIZE_NOT_ALLOWED            = 9
HEADER_TOO_LONG                 = 10
DP_ERROR_CREATE                 = 11
DP_ERROR_SEND                   = 12
DP_ERROR_WRITE                  = 13
UNKNOWN_DP_ERROR                = 14
ACCESS_DENIED                   = 15
DP_OUT_OF_MEMORY                = 16
DISK_FULL                       = 17
DP_TIMEOUT                      = 18
FILE_NOT_FOUND                  = 19
DATAPROVIDER_EXCEPTION          = 20
CONTROL_FLUSH_ERROR             = 21
OTHERS                          = 22
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
<b>reward if helpful</b>

HP ePrint from excel add-in: Error while getting driver name for printer

Trying to use add-in for ePrint from excel/word I get, "error while getting driver name for printer \\...HP DesignJet 800PS 42 by HP," with an option to select "OK" and that same message repeats with each printer in our network, and then it doesn't allow me to print using the add-in. However, I can print normally to HP Go Web, open up Print and Share, then print it from there. This happens with excel and word. I have Office Suite 2007.

Hello modameister,
Sorry you are having issues with this printer and the ePrint add-on. There are a couple of questions I would like you to answer please.
1. What operating system are you using? (XP,VISTA,7,MAC OS X)
2. What and how much data are you trying to print?
3. Have you tried to copy and paste the data into a different application or tried using the snip it tool?
4. Are you receiving any .dll errors (mscms.dll)
Thanks
If I have solved your issue, please feel free to provide kudos and make sure you mark this thread as solution provided!
Although I work for HP, my posts and replies are my own opinion and not those of HP.

Cisco Unity 7: Voice mail cann't get the name or Number phone of the caller

Hi,
I have installed Cisco Unity Messaging Unified version 7 and integrated with Exchange 2010.
I have two scenario, and I want to know if are normal or not:
1. If the 2 IP phones are subscribed with Cisco Unity: the first IP phone call the other IP phone and let a voice mail. When the second IP phone check his message vocal it can get the name of the caller or his number phone (the message is: You have One message from XXXX) and he get e-mail as objet: Voice Mail from XXXX.
2. If one IP phone is not subscriber with cisco unity call other Ip phone subscribed with cisco unity and let him a voice mail. The second IP phone when check his message vocal it can’t get the name of the caller or his number phone: The message is: You have one voice mail xxxx; without indicate from!! and he get a e-mail as object: Voice mail from Unknown.
Please, I want to know if the second scenario is normal ? if not, who to resolve this problem? I want that he indicate the number of caller same he isn't subscriber with cisco unity?
Thanks a lot,
Best regards,
Omar YUNSI

So for the 2nd scenerio you would want to check what your Message Subjects were set to. For Unity 7 open Web SA, click Configuration and then Message Subjects. Make sure that the Outside Caller Message has %CALLERID% in it somewhere. The value %CALLERNAME% will return unknown if we do not receive a name from the PSTN.
Try setting the Outside Caller Message to:
%U% %P% Voice Message from %CALLERID%
and that should get you your desired results.
The default Message subject is:
%U% %P% Voice Message from %CALLERNAME% (%CALLERID%). So with that it would say Voice Message fom Unknown (xxxx) if it was not able to determine the name of the user which is usually normal from a PSTN call.
Just to note, the From address is always going to say from Unity Messaging System, it will only be the subject that has the extension in it.
Bryan

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group.

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group. Through this memberof class I am trying to find full qualified name(DN) of my group.
code I have used:
//specify the LDAP search filter
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               String searchBase = "";
Also I have used,
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               String searchBase = "ou=ibmgroups,o=ibm.com";
But in both cases I am getting value for Total groups as 0.
Code Reference:
* memberof.java
* December 2004
* Sample JNDI application to determine what groups a user belongs to
import java.util.Hashtable;
import javax.naming.*;
import javax.naming.ldap.*;
import javax.naming.directory.*;
public class memberof     {
     public static void main (String[] args)     {
          Hashtable env = new Hashtable();
          String adminName = "CN=Administrator,CN=Users,DC=ANTIPODES,DC=COM";
          String adminPassword = "XXXXXXX";
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          env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
          //set security credentials, note using simple cleartext authentication
          env.put(Context.SECURITY_AUTHENTICATION,"simple");
          env.put(Context.SECURITY_PRINCIPAL,adminName);
          env.put(Context.SECURITY_CREDENTIALS,adminPassword);
          //connect to my domain controller
          env.put(Context.PROVIDER_URL,ldapURL);
          try {
               //Create the initial directory context
               LdapContext ctx = new InitialLdapContext(env,null);
               //Create the search controls
               SearchControls searchCtls = new SearchControls();
               //Specify the search scope
               searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
               //specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Andrew Anderson))";
               //Specify the Base for the search
               String searchBase = "DC=antipodes,DC=com";
               //initialize counter to total the group members
               int totalResults = 0;
               //Specify the attributes to return
               String returnedAtts[]={"memberOf"};
               searchCtls.setReturningAttributes(returnedAtts);
               //Search for objects using the filter
               NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
               //Loop through the search results
               while (answer.hasMoreElements()) {
                    SearchResult sr = (SearchResult)answer.next();
                    System.out.println(">>>" + sr.getName());
                    //Print out the groups
                    Attributes attrs = sr.getAttributes();
                    if (attrs != null) {
                         try {
                              for (NamingEnumeration ae = attrs.getAll();ae.hasMore();) {
                                   Attribute attr = (Attribute)ae.next();
                                   System.out.println("Attribute: " + attr.getID());
                                   for (NamingEnumeration e = attr.getAll();e.hasMore();totalResults++) {
                                        System.out.println(" " + totalResults + ". " + e.next());
                         catch (NamingException e)     {
                              System.err.println("Problem listing membership: " + e);
               System.out.println("Total groups: " + totalResults);
               ctx.close();
          catch (NamingException e) {
               System.err.println("Problem searching directory: " + e);
Any help will be highly appreciated.

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group. Through this memberof class I am trying to find full qualified name(DN) of my group.
code I have used:
//specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "";
Also I have used,
             String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "ou=ibmgroups,o=ibm.com";
But in both cases I am getting value for Total groups as 0.
Code Reference:
* memberof.java
* December 2004
* Sample JNDI application to determine what groups a user belongs to
import java.util.Hashtable;
import javax.naming.*;
import javax.naming.ldap.*;
import javax.naming.directory.*;
public class memberof     {
     public static void main (String[] args)     {
          Hashtable env = new Hashtable();
          String adminName = "CN=Administrator,CN=Users,DC=ANTIPODES,DC=COM";
          String adminPassword = "XXXXXXX";
          String ldapURL = "ldap://mydc.antipodes.com:389";
          env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
          //set security credentials, note using simple cleartext authentication
          env.put(Context.SECURITY_AUTHENTICATION,"simple");
          env.put(Context.SECURITY_PRINCIPAL,adminName);
          env.put(Context.SECURITY_CREDENTIALS,adminPassword);
          //connect to my domain controller
          env.put(Context.PROVIDER_URL,ldapURL);
          try {
               //Create the initial directory context
               LdapContext ctx = new InitialLdapContext(env,null);
               //Create the search controls
               SearchControls searchCtls = new SearchControls();
               //Specify the search scope
               searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
               //specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Andrew Anderson))";
               //Specify the Base for the search
               String searchBase = "DC=antipodes,DC=com";
               //initialize counter to total the group members
               int totalResults = 0;
               //Specify the attributes to return
               String returnedAtts[]={"memberOf"};
               searchCtls.setReturningAttributes(returnedAtts);
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               NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
               //Loop through the search results
               while (answer.hasMoreElements()) {
                    SearchResult sr = (SearchResult)answer.next();
                    System.out.println(">>>" + sr.getName());
                    //Print out the groups
                    Attributes attrs = sr.getAttributes();
                    if (attrs != null) {
                         try {
                              for (NamingEnumeration ae = attrs.getAll();ae.hasMore();) {
                                   Attribute attr = (Attribute)ae.next();
                                   System.out.println("Attribute: " + attr.getID());
                                   for (NamingEnumeration e = attr.getAll();e.hasMore();totalResults++) {
                                        System.out.println(" " + totalResults + ". " + e.next());
                         catch (NamingException e)     {
                              System.err.println("Problem listing membership: " + e);
               System.out.println("Total groups: " + totalResults);
               ctx.close();
          catch (NamingException e) {
               System.err.println("Problem searching directory: " + e);
Any help will be highly appreciated.

Why do I get a class conflict between the Prepare SQL.vi and the Get Column Name.vi with the SQL Toolkit compatibility vis from the Database Connectivity Toolkit?

I have done extensive programming with the SQL Toolkit with LabVIEW versions through 6.1. My customer now wants to upgrade to Windows 7, so I am trying to upgrade to LabVIEW 2009 (my latest purchased version) using the Database Connectivity Toolkit, and the SQL Toolkit Compatibility vis. Everything seemed to be going okay with the higher level SQL operations, but I ran into trouble with the Get Column Name.vi.
The pictures below show the problem. The original SQL Toolkit connected the Prepare SQL.vi with the Get Column Name.vi with a cluster of two references, one for connection, and one for sql. The new compatibility vis have a class conflict in the wire because the Prepare SQL.vi contains a cluster with connection, and command references, but the Get Column Name.vi expects a cluster with connection and recordset references.
How do I resolve this conflict?
Thank You.
Dan

I've never worked with the old version of the toolkit, so I don't know how it did things, but looking inside the SQL prep VI, it only generates a command, and the the column name VI wants a recordset. I'm not super familiar with all the internals of ADO, but my understanding is that is standard - you only have the columns after you execute the command and get the recordset back. What you can apparently do here is insert the Execute Prepared SQL VI in the middle and that will return what you need.
I'm not sure why it worked before. Maybe the execute was hidden inside the prep VI or maybe you can get the column names out of the command object before execution. In general, I would recommend considering switching to the newer VIs.
Try to take over the world!

Any Function module or BAPIs are available to get scheme name for the inter

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look at DB-VIEW "V_IVP_OR".
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Laurent

How to get the name and value of an attribute on a node/element that is not a child

Hello,
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DECLARE
@ProdID int
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<Features featureID = "1" featureName = "body">
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<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
</Features>
<features featureID = "2" featureName = "seat">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>
SET @myDoc2 ='<ProductDescription ProductID="1" ProductName="Road Bike">
<Features featureID = "1" featureName = "body">
<Warranty>2 year parts and labor</Warranty>
<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
</Features>
<features featureID = "2" featureName = "wheel">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>
I need to compare the attributes of 'ProductDescription' and 'Features' from @mydoc1 against @mydoc2 to see if they are the same based on those 2 nodes first. If they are, then i want to show the difference in the child elements.
This will eventually be an outer join to give me the differences betw the 2 docs based on those key values (node attributes).
I used node('//*') for the path, and value('local-name(../.)', 'varchar(50)') as element
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...etc...
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Are you looking for something like this:
DECLARE @myDoc1 xml
SET @myDoc1 ='<ProductDescription ProductID="1" ProductName="Road Bike">
<Features featureID = "1" featureName = "body">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
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<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
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Erland Sommarskog, SQL Server MVP, [email protected]

I name each photo buy replacing the jpeg number with the name. when I burn to disk and open disk the name is not shown. how do I get the name given to show on the burn disk?.

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Naming the Photo - or giving it a title - is not the same as naming file.
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If you want the title available in the Finder - which does not understand photo metadata - then you'll need to export the file
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or this?
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How do i get my name on the top right corner next to the search bar? I have OS X Mountain Lion 10.8.5

System Preferences > Users & Groups
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I'm trying to get my name to appear under devices in itunes for my iphone. It got deleted, and I can't get it back on.

You need iTunes version 11+.
iPad not appearing in iTunes
http://www.apple.com/support/ipad/assistant/itunes/
iOS: Device not recognized in iTunes for Mac OS X
http://support.apple.com/kb/TS1591
iOS: Device not recognized in iTunes for Windows
http://support.apple.com/kb/TS1538
How to restart the Apple Mobile Device Service (AMDS) on Windows
http://support.apple.com/kb/TS1567
IOS: Syncing with iTunes
http://support.apple.com/kb/HT1386
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How can i get the names of the controls inside a class private data?
I am using Actor Framework and trying to create a method tha will be executed when launch the actor. This method need a list o all the control names inside the class data to search for the initial value inside a configuration file (config.ini), the key on the configuration file will be the name of the control.
Thanks.
Solved!
Go to Solution.

You are already making the overriding method just because you have to write to the Bundle By Name. And then how are you going to handle all of the data types the keys could be. You are making things more difficult than it should be for really very little benefit.
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Unofficial Forum Rules and Guidelines

Need of a Webservice to get the name of the file in a Folder

Hi All,
I am in need of a Web service which should get the name of the file in a folder.
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How do I get the names of tracks I type in Adobe Audition 3 to copy to the Sony CD-RW CRX217E in myD

How do I get the names of tracks I type in Adobe Audition 3 to copy to the Sony CD-RW CRX217E in my Dell Precision Workstation 670?
I have recorded 10 tracks of voice with music using Adobe Audition 3 and Sony CD-RW CRX217E with no problem.
The problem is, however, that the names I type in Audition 3 for each of the tracks and artist do not copy to the CD I have recorded. This means that when I play the tracks on any playback equipment that shows the names of the tracks and artists, etc. all that appears on the screen is the track number, such as Track 1, Track 2, etc.
I am using a Dell Precision Workstation 670
Inter®Xeon
CPU3.2GHz
3.19GHz,2.00GB RAM
SYSTEM
Professional x64 Edition
V2003
SP 2, v.4354
Thank you
NoPro

Well, there is one possibility, but I can't absolutely confirm this. I had a look at the specification for the drive on the Dell website:
http://support.dell.com/support/edocs/storage/P89087/en/index.htm
and nowhere does it say that the drive supports CD-Text, I'm afraid. Even though all drives can in theory write this, a lot have the header hard-coded, and simply can't. Yours may be one of them, but I think you'll have to ask Dell to confirm this.

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