Get count in Query

Question

Hello all,
How can i get total number of count in the below query...its always giving 1 for each rows..
Cover countofcovers
12345 1
43564 1
43535 1
i need 3 as count ..any help
select cover,count(*) countofcovers from ( SELECT A.COVER_NUMBER cover
     FROM HL01unit.COVER A,
          HL01unit.CLIENT_STAGING G,
          HL01unit.COVER_CATEGORY F
     WHERE A.POLICY_NUMBER ='10000142'
     AND F.COVER_NUMBER = A.COVER_NUMBER
AND G.POLICY_NUMBER = A.POLICY_NUMBER
     AND G.COVER_NUMBER = A.COVER_NUMBER
     AND A.PARENT_COVER_NO IS NULL
     AND UPPER(G.SURNAME) LIKE UPPER(RTRIM('R')) CONCAT '%'
UNION
     SELECT DISTINCT(A.PARENT_COVER_NO) cover
     FROM HL01unit.COVER A,
          HL01unit.CLIENT_STAGING G,
          HL01unit.COVER_CATEGORY F
     WHERE A.POLICY_NUMBER ='10000142'
     AND F.COVER_NUMBER = A.COVER_NUMBER
AND G.POLICY_NUMBER = A.POLICY_NUMBER
     AND G.COVER_NUMBER = A.COVER_NUMBER
     AND A.PARENT_COVER_NO IS NOT NULL
     AND UPPER(G.SURNAME) LIKE UPPER(RTRIM('R')) CONCAT '%'
) yTable group by cover

Answer 1

try union all instead of union
Peter
maybe a small example to explain that the inner query is
wrong and not the group by
select 1 counter from dual;
COUNTER
1
1 row selected.
select counter, count(*) from (
select 1 counter from dual
union
select 1 counter from dual)
group by counter;
COUNTER COUNT(*)
1 1
1 row selected.
select 1 counter from dual
union all
select 1 counter from dual;
COUNTER
1
1
2 rows selected.
select counter, count(*) from (
select 1 counter from dual
union all
select 1 counter from dual)
group by counter;
COUNTER COUNT(*)
1 2
1 row selected.
Message was edited by:
Peter Verhaegen