Get list of files in a directory

Hello everybody,
working with Oracle 9.2 I have created a directory and i would like to implement in pl/sql a procedure that return the list of files contained.
Anybody know the general solution for this matter?
Thanks in advance

Tom Kyte has an example:
Directory List including modify date and times

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Getting list of files from Unix directory inclding files frm sub-directries

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But the trouble I am running in to is that I want the
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String sysprop = System.getProperty("whatever property");
File f = new File(sysprop);... To determine which you want, SDK v1.3.1 docs for System.getProperty():
getProperties
public static Properties getProperties()
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How to get list of file names from a directory?

How to get list of file names from a directory?
Please help

In addition, this:
String filename = files;Should be this:
String filename = files;
That's just because he didn't use the "code" tags, so [ i ] made everything following it become italicized.

Getting the list of files in a directory by their last modified date

Dear friends,
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Thanks in advance,
James.

Thanks friend,
I myself got the answer
here is my code:
public File[] getSortedFileList(File dir){
File[] originalList = dir.listFiles();
int numberOfFiles = originalList.length;
File[] sortedList = new File[numberOfFiles];
long[] lastModified = new long[numberOfFiles];
for(int i = 0; i < numberOfFiles; i++){
lastModified[i] = originalList.lastModified();
Arrays.sort(lastModified);
for(int i = 0; i < numberOfFiles; i++){
for(int k = 0; k < numberOfFiles; k++){
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Hei :)
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Is there a way that you can get a list of files in a directory that are spelt a certain way? Ex. If in a directory there are html files, txt files, et, In java can I get *.html or a html file with certain text in the name? java.html??
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US101

here are the code to list your files
 File startDir = new File("your directory goes here" );
 File[] dirList = startDir.listFiles();
 if (startDir.isDirectory());
 out.print( startDir.getPath() );
 //Start cycling through the array for the file
 for ( int count = 0; count < dirList.length; count++ )
String fileName = dirList[count].getName();
 int index = fileName.lastIndexOf('.');
 String newString = null;
 if (index >= 0)
 newString = fileName.substring(index, fileName.length());
 if ( newString.equalsIgnoreCase( ".txt"))
 if ( dirList[count].isDirectory())
 out.println( dirList[count].getName() );
 else
 out.println( dirList[count].getName());
 }//end else
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URGENT : getting attribute of files in a directory

Hello.
I use oracle 8i and I want to get attributes of files inside a directory like the "Modified" attribute which indicates the time of creation of the file.
How can I do this ?
Thank you very much.

Tom Kytes has an example with java callout
Directory List including modify date and times - casting the date problem
http://asktom.oracle.com/pls/ask/f?p=4950:8:5492560634257383293::NO::F4950_P8_DISPLAYID,F4950_P8_CRITERIA:7506780031005,

How to list the files in a directory which are recently modififed few mins

Hi,
I need command to list the files in a directory which are modified few minutes ago in SunOS. like "find . -cmin 2 -print " which list files that are modified 2 mins ago in Linux platform.
Thanks in advance.
sudha85

The find command that comes with solaris doesnt have the cmin operator. Only mtime whose option is days.
So install gnu find from sunfreeware which is the same one that comes with linux.

Problem with getting a list of files in a directory

I'm trying to get a list of files in a particular directory. The problem is I'm also getting a listing of all the sub-directories too. Here is my code:
File directory = new File(dir);
File[] filelist;
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for(int i=0;i<filelist.length;i++)
System.out.println("FileName = " + filelist.getName());
What am I doing wrong?
Thanks
Brad

You are not doing anything wrong. You just have to test whether a given file is a subdirectory:
File directory = new File(dir);
File[] filelist;
filelist = directory.listFiles();
for(int n = 0; n < filelist.length; n++) {
if (!filelist[n].isDirectory())
System.out.println("FileName = " + filelist[n].getName());
}Søren Bak

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Satish

try get something from the transaction AL11 source code: RSWATCH0 form -> fill_file_list
Regards,
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Getting list of directories within a directory - NULL

I am getting a NULL POINTER EXCEPTION when trying to get a list of directories from a directory.
<%
main_dir = new File("test_dir");
dirs = main_dir.list();
if(dir==null){
%>
ERROR: dirs is null
Main Dir: <%=index_dir%>
<% }
%>
It is returning that message that dirs is null.
The directory structure is
$TOMCAT_DIR/webapps/test_dir.jsp
$TOMCAT_DIR/webapps/test_dir
Within test_dir are two directories: test1, test2
I put the same code into a regular java code:
File f = new File ("test_dir");
String[] dirs = f.list();
if(dirs == null){
System.out.println("dirs is null");
It DOES NOT print out that message that dirs is null.
I'm just very confused. What am I doing wrong?

Pardon me but since I don't put the actual code on here sometiems there are typos.
I have a program where I open a directory. It's a search page where it displays about 10 results then has a button at the bottom says "next" for the next results.
Anyhow, one minute the webpage will be fine, open the directory with no problem. Then it will stop and say it can't open the directory when the directory is there. It's driving me nuts.
I'm using Java code within the JSP page, instead of beans so I dont' know if that causes some kind of error.
<%
index_dir = new File(master_index_dir);
indexes = index_dir.list();
if(indexes==null){
%>
ERROR: indexes is null
Master Index Dir: <%=index_dir%>
<% }
else {
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%>
Well just 5 minutes ago this worked fine, the index was open and the results shown. However just 2 minutes ago it stopped and returns the message that indexes is null.
Sometimes if I stop and start tomcat several times it starts to work again.

List all files in a directory, not including the sub directories if any

Hi,
I have been looking around php.net for a bit and can not work
out how i list the files that are in a directory i.e.
www.site.com/directory/
I would like the names of each file to be placed in an array,
but not to have the sub directories in this list should there be
any.
I was given some code a while ago that done this but it
listed the sub directories and i would like them not in this list.
I do not have this code anymore and do not know where i got
it, so i can not get it amended to what i need.
please can someone tell me what line of code i should be
using.
thank you in advance for your help.

(_seb_) wrote:
> not very clever wrote:
>> Hi,
>>
>> I have been looking around php.net for a bit and can
not work out how
>> i list the files that are in a directory i.e.
>>
>> www.site.com/directory/
>>
>> I would like the names of each file to be placed in
an array, but not
>> to have the sub directories in this list should
there be any.
>>
>> I was given some code a while ago that done this but
it listed the
>> sub directories and i would like them not in this
list.
>>
>> I do not have this code anymore and do not know
where i got it, so i
>> can not get it amended to what i need.
>>
>> please can someone tell me what line of code i
should be using.
>>
>> thank you in advance for your help.
>>
>>
>>
>
> The follwoing PHP code will do just that. Just replace
"pathToFolder"
> with the path to your folder.
> I made the list of files also link to each file. Just
remove the link
> echo if you don't them to be links.
>
> <?php
> // FUNCTION TO LIST FILES:
> function listFiles($path){
> if($handle = opendir($path)){
> while(false !== ($file = readdir($handle))){
> if (is_file($path.'/'.$file) &&
!preg_match('/^\./',$file)){
> $files_array[]=$file;
> }
> }
> }
> return($files_array);
> }
> $path = 'pathToFolder';
>
> // CALL THE FUNCTION:
> $files_array = listFiles($path);
> foreach($files_array as $file){
> echo '<a
href="'.$path.'/'.$file.'">'.$file,'</a>';
> }
>
> ?>
>
I spotted one error:
foreach($files_array as $file){
echo '<a
href="'.$path.'/'.$file.'">'.$file,'</a>';
should be:
foreach($files_array as $file){
echo '<a
href="'.$path.'/'.$file.'">'.$file.'</a>';
(a dot after $file, not a coma)
seb ( [email protected])
http://webtrans1.com | high-end web
design
Downloads: Slide Show, Directory Browser, Mailing List

Geting a list of files in a directory

ok i know how to get it if its in my own drive
but im haveing trouble doing this from a website.
im not geting any errors when i try to check the webpage
on the server it just doesnt even display the applet
can anyone see what is wrong if i cant see the error's
i have no way of knowing what im doing wrong
1.)is url.getPath the correct way to get the path to the directory ?
2.)can i use the file class as i am to get a list of files on the
server ?
String[] availabletexturelist;
URL url = getDocumentBase();
String currentpath = url.getPath();
System.out.println("currentpath = "+currentpath);
File cdir = new File(currentpath);
availabletexturelist = cdir.list(new FilenameFilter(){public boolean accept(File d,String name){return name.endsWith(".jpg");}});
for(int flp = 0;flp < availabletexturelist.length;flp ++){DynamicallyAddTexture(availabletexturelist[flp]);System.out.println(""+availabletexturelist[flp]);} any help is appreciated

yep my site
just wanted to be able to have the code read what images are
in the same directory as the applet and load them all.
but then the answer would be
i cant use file to grab a list of files
that are in the same directory as my applet on the server
that i am downloading the applet from.
however is their a way to get the path to just the directory that the
applet is being downloaded from itself ?
and then the following is true
specifying the images that i intend to use in applet parameter tags
or hardcodeing the imagenames and paths into the code is the easyiest way.
right ?

Reading List of Files in a Directory

Hi,
I'm looking for some reference or perhaps an example of how to get LabView to show the files that are in a directory so that the user can choose the appropriate one to load in the run. Right now, I'm running my program with certain specific files in the directory and the list of files written into the program.
Thank you very much,
Rob Hal

I'm sure there are a number of example programs shipped with LV or that could be downloaded from the archives. Anyway, here is a quick example that read a directory content, fills a listbox, and display the selected file content as a string.
Chilly Charly (aka CC)
E-List Master - Kudos glutton - Press the yellow button on the left...
Attachments:
Select file.vi ‏57 KB

Get list of files in a directory

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