Get source file name in the structure itself or in the payload

Hi everyone,
I have a task regarding mapping
In my structure , i defined a field for Filename . What I need is, what ever source file name am sending, that should be mapped into this filed.
If am sending inputfile.txt.
My output file should appear like this,
<?xml version="1.0"?>
         <message id=u201DmessageIDu201D>
                 <header>
                         <filename>D:\\inputfile.txt</filename>
                 </header>
                 <body>
                          FileContent
                 </body>
         </message>
Any help would be appreciated. Do I need to create any UDF. If So please provide.
Regards,
Varun

Hi Varun,
are u using the same UDF that I replied. also note that the variable key should be declared only once.
Use this without changing any thing. It works for me...
DynamicConfiguration conf = (DynamicConfiguration) container.getTransformationParameters().get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey key = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","FileName");
String ourSourceFileName = conf.get(key);
key = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","Directory");
String dir = conf.get(key);
return dir+'/'+ourSourceFileName;
Also let us know where do you het this error..
Thanks
SaNv...

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Kind Regards,
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http://help.sap.com/saphelp_nw04s/helpdata/en/73/f61eea1741453eb8f794e150067930/frameset.htm
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Hi All,
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rajib

Hi,
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public String G_GetFileName(Container container) throws StreamTransformationException{
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Deepak.

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Hi, Im trying to get the whole path in my server, so i tried that with this following code
Get-ChildItem $sourceFolder -Recurse | ?{$_.PsIsContainer} |Get-Acl
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Al Dunbar -- remember to 'mark or propose as answer' or 'vote as helpful' as appropriate.

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Hi Experts,
I have a problem like Dynamic File name depending on the Source File Name. I will explain with example as follwos
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NK01.VR59.L2007030         VR59/Rec.l200
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Thanks in Advance,
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<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
- 
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<SAP:Category>Application</SAP:Category>
<SAP:Code area="MAPPING">EXCEPTION_DURING_EXECUTE</SAP:Code>
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<SAP:P2>com.sap.aii.utilxi.misc.api.BaseRuntimeException</SAP:P2>
<SAP:P3>Fatal Error: com.sap.engine.lib.xml.parser.Parser~</SAP:P3>
<SAP:P4 />
<SAP:AdditionalText />
<SAP:ApplicationFaultMessage namespace="" />
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<SAP:Retry>M</SAP:Retry>
</SAP:Error>

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Hi,
Iam doing FILE FILE to scenario.
My source file name is XXXX237061606.txt. (XXXX is company code)
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How to retrieve the company code from the source file name?
Thanks,
Hem.

hem chand wrote:>
> Hi Varun,
>
> Could u please provide me detailed procedure to get the company code.
>
> Reg,
DynamicConfiguration conf = (DynamicConfiguration) container.getTransformationParameters().get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey key = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","FileName");
String ourSourceFileName = conf.get(key);
This will get you the File name...TRuncate it to extract company code...
Then have a mapping program with the receivers message type which is persent under SAP BASIS component....
There map to the required receiver by getting the file name above..
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How do I map the source file name to a target table?

I am mapping a source fixed length flat file to oracle target tables. One of the tables is a parent transaction table that stores the date, record number, status, etc. and the file name of the source flat file. The file name will change daily because the date is part of the naming convention. Is there an easy way to determine the source file name and map it?
One option a co-worker is working on is writing a pre-mapping stored procedure. It would insert the file name into a table prior to the mapping. But I was hoping for a cleaner solution.
Thanks!

Hi
Use extarnel table to load the data from the file into the table.
Create a procedure which changes the external table definition as the filename chnages.
Use this proceudre in the mapping as a premapping process.
Ott Karesz
http://www.trendo-kft.hu

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I have a unique situation. In my file to file scenario, the source file name is of the format XYZ_yymmddHHMM.dat. there is field in the target file which has to filled with the date that is there in the file name of the source file (yymmdd). How can this be achieved? Normally we do the other way round using vaiable substitution where we can name a file depending on the value in any of the target field structure.
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Hi,
please prepare the udf with the following code.
i mean, dynamic configuration concept.
where u get the file name, then use substring function to capture date from right side.
//write your code here
// getFileName User Defined Function
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String filename;
filename = strFile;
try {
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.getTransformationParameters()
.get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey key = DynamicConfigurationKey.create( "http://sap.com/xi/XI/System/File", "FileName");
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warm regards
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File Sender adapter - source file name - weird

Hi all,
We have a sender file adapter polling an ftp location. The Dynamic config has been enabled to get the source file name.
The actual file name is - "hrmd.xml", but in the dynamic configuration node, in sxmb_moni, the fileName is shown as ./hrmd.xml.
This does not occur with any other file sender adapter comm channels polling ftp locations.
I guess this has something to do with the ftp server. Did anyone face this issue?

the fileName is shown as ./hrmd.xml
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See in Sender CC when you set the Adapter Specific Message Attr for file name it will send the filename in the header of the XI Message.
To acces this file name inside mapping you need to create a UDF . The type can be any thing as you desire.
You dont need to pass any variable .if suppose you want the file name (constant) e.g ABC_<timestamp>.xml
DynamicConfiguration conf = (DynamicConfiguration) container.getTransformationParameters().get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey key = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","FileName");
String fileName= conf.get(key);
//see above your key is FileName which will be sent by the sender CC automatically... You are simply accessing it here using get() method.
//now ur filename will contain name of the source file... you need to perform a substring operation to get the timestamp and create a new file name as you desire.
fileName = "New_<timestmp>.xml"; //for e.g
//set this file name again in header message using put()
conf.put(key, fileName);
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CEO: What exactly is stopping us from doing this?
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Hi ALL,
I want all image file naming like a caption in my source document. Source document contains more than 100 images.
But i got a script through the forum and tuned for my script. Still, the file naming comes for the Ist page image only.
From second page onwards the file naming not comes like a caption.
Trying script:
//To Get image file name
var tgt = app.activeDocument.rectangles;
for (i=0;i<tgt.length;i++){
    myCaption = app.activeDocument.textFrames.add();
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    myCaption.paragraphs[0].justification = Justification.CENTER_ALIGN;
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BEGINNER

If you use the add() method in conjunction with the document without specifying the page or better the spread, all objects added will end up on the first spread of your document.
But your testing scenario is also too narrow. You are expecting:
1. All your graphics are sitting in Rectangle objects (what about Ovals or Polygons?)
Therefore: All graphics placed in ovals or polygons are left out.
2. That really ALL rectangles in your document contain graphics
You are in trouble, if there happen to be empty rectangles on a page. I would suggest to test that with your script. It will give you an error, because there is no graphics[0] for this specific rectangle, where you can draw the "name" for the "itemLink".
3. That there are no graphics in anchored objects or pasted inside other objects; left alone graphics inside table cells.
And who can say that thiese three restrictions exist in all documents you want to run this script against?
So, if you want to get to all image files in the document, why don't you start with the images in the first place?
Let's see:
the Document object has an "allGraphics" property.
Use that as a starting point and you will not missing a single graphic.*
Iterate through "allGraphics" will get you:
the "name" of the placed image through its itemLink.name property;
the container of the graphic, that's the "parent" of the graphic.
Now you need one other thing:
the page, or even better(!) the spread where the graphic is located. Imagine a graphic sitting outside of a page.
If you want to handle thiese, you must know the spread.
If writing this script for InDesign CS5 or above, you are in luck. There is a "parentPage" property of the "Graphic" object, you could use for your add() method. For graphics outside of pages this property will be "null".
And another important thing:
if a graphic is copy/pasted from e.g. PhotoShop to InDesign, the "itemLink" property of that graphic is also "null".
We can handle that in a try/catch scenario…
//Scope: all graphics on all pages
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*Not exactly true, because it is missing graphics in not-active states of MultiStateObjects.
Since MSOs were introduced in InDesign CS5 the DOM documentation left out this fact so far.
//EDIT: in the first version I had a comment on a different scope. Since Document Objects have no "graphic" property, I removed that comment. Sorry.
Uwe
P.S. And a Happy New Year to all!
Message was edited by: Laubender

Same source file name with a different extension

Hi All,
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Scenaio is file to file.
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Regards,
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Hi Amareshwar,
you can write a java code (either in UDF or import in imported archive and use in imterface mapping).
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Regards,
Vishal Gupta
Plz reward points if you are satisfied with the solution.

Get source file name in the structure itself or in the payload

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