Getting file name to work in download/upload example

In the example from
http://www.oracle.com/technology/products/database/htmldb/howtos/howto_file_upload.html
I have it all working, but now that I have completed all the steps, when I click on a file to download, it now uses the schema owner as the name of the file without an extension. Is anyone else having this problem? If I save it to a file, it knows the file type, so that is getting through OK, just not the file name and extension.
Thanks!

Any ideas on this?

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GET FILE NAME C:\temp\ADIBO.txt

Hi,
How to get file name?
I used Get_File_NAME, but I'am getting an error.
lv_lfilename is not the type LOGICAL_FILENAME
C:\temp\ADIBO.txt
I need to get ADIBO ??
tnh, Adibo..:)
I am using this code to download file and after that I need to get FILE_NAME:
DATA: lv_lfilename TYPE string.
PARAMETERS:
pa_lfile TYPE zlocalfile
           DEFAULT 'C:temp'.
    CONCATENATE pa_lfile ''INTO lv_lfilename.
    CALL FUNCTION 'GUI_DOWNLOAD'
         EXPORTING
              filename = lv_lfilename
              filetype = 'ASC'
         TABLES
              data_tab = it_billit_down.
    IF sy-subrc <> 0.
* MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
*         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
    ENDIF.

Hii..
You have to Maintain the Logical filenames and their Physical Paths in Tcode FILE.
Then create a program like this..
REPORT ZSEL_FILES1.
DATA : V_LOGFILE TYPE STRING.
DATA :V_PHYFILE TYPE STRING.
DATA : ITAB TYPE TABLE OF SCARR.
START-OF-SELECTION.
SELECT * FROM SCARR INTO TABLE ITAB.
**To get the Physical file based on the Logical file names - Maintained in Tcode FILE
CALL FUNCTION 'FILE_GET_NAME'
EXPORTING
   CLIENT                        = SY-MANDT
    LOGICAL_FILENAME              = VlOGFILE
OPERATING_SYSTEM              = SY-OPSYS
PARAMETER_1                   = ' '
PARAMETER_2                   = ' '
PARAMETER_3                   = ' '
USE_PRESENTATION_SERVER       = ' '
WITH_FILE_EXTENSION           = ' '
USE_BUFFER                    = ' '
ELEMINATE_BLANKS              = 'X'
IMPORTING
EMERGENCY_FLAG                =
FILE_FORMAT                   =
   FILE_NAME                     = V_PHYFILE
EXCEPTIONS
FILE_NOT_FOUND                = 1
OTHERS                        = 2
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
**To download the file to PC.
CALL FUNCTION 'GUI_DOWNLOAD'
EXPORTING
BIN_FILESIZE                    =
    FILENAME                        = V_PHYFILE
   FILETYPE                        = 'ASC'
APPEND                          = ' '
   WRITE_FIELD_SEPARATOR           = 'X'
HEADER                          = '00'
TRUNC_TRAILING_BLANKS           = ' '
WRITE_LF                        = 'X'
COL_SELECT                      = ' '
COL_SELECT_MASK                 = ' '
DAT_MODE                        = ' '
CONFIRM_OVERWRITE               = ' '
NO_AUTH_CHECK                   = ' '
CODEPAGE                        = ' '
IGNORE_CERR                     = ABAP_TRUE
REPLACEMENT                     = '#'
WRITE_BOM                       = ' '
TRUNC_TRAILING_BLANKS_EOL       = 'X'
WK1_N_FORMAT                    = ' '
WK1_N_SIZE                      = ' '
WK1_T_FORMAT                    = ' '
WK1_T_SIZE                      = ' '
IMPORTING
FILELENGTH                      =
TABLES
    DATA_TAB                        = ITAB
FIELDNAMES                      =
EXCEPTIONS
FILE_WRITE_ERROR                = 1
NO_BATCH                        = 2
GUI_REFUSE_FILETRANSFER         = 3
INVALID_TYPE                    = 4
NO_AUTHORITY                    = 5
UNKNOWN_ERROR                   = 6
HEADER_NOT_ALLOWED              = 7
SEPARATOR_NOT_ALLOWED           = 8
FILESIZE_NOT_ALLOWED            = 9
HEADER_TOO_LONG                 = 10
DP_ERROR_CREATE                 = 11
DP_ERROR_SEND                   = 12
DP_ERROR_WRITE                  = 13
UNKNOWN_DP_ERROR                = 14
ACCESS_DENIED                   = 15
DP_OUT_OF_MEMORY                = 16
DISK_FULL                       = 17
DP_TIMEOUT                      = 18
FILE_NOT_FOUND                  = 19
DATAPROVIDER_EXCEPTION          = 20
CONTROL_FLUSH_ERROR             = 21
OTHERS                          = 22
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
<b>reward if helpful</b>

How to not append '.PART' to the file name of the currently downloading file, and just download the file with its normal filename

In Windows, when Firefox (I'm currently using 7.0) downloads a file, it appends ''.PART'' to the file name of the currently downloading file and just renames it to its original file name after it finishes downloading.
I sometimes like to watch a currently downloading video file, so it will be better if Firefox just downloads the file to its actual filename (like what Opera does), so I can easily double click the incompletely downloaded file and watch it with the video player assigned to that file extension, rather than the awkward ''Right click -> Open With -> Choose Default Program'' route with .part files.
Does anyone know how to set Firefox to do this?

It is possible that your anti-virus software is corrupting the downloaded files or otherwise interfering with downloading files by Firefox and prevents Firefox from renaming the .part file.
Try to disable the real-time (live) scanning of files in your anti-virus software temporarily to see if that makes downloading work.
See "Disable virus scanning in Firefox preferences - Windows"
* http://kb.mozillazine.org/Unable_to_save_or_download_files

How to get file names?

Hi,
I'm currently trying to use com.oreilly.servlet.MultipartRequest by Jason Hunter to handle file uploading. This is the first time i handling this using jsp. I facing problem of getting the file names. I created the upload logic in a bean and i wanted it passing back the file names.
1) The file names actually in Enumeration type. Can i know what actually is Enumeration type?
2) Is it possible i return those names by converting them into string and as an array type? then accessing it using getProperty?
Regards,
jeffcjm

jeffcjm wrote:
1) The file names actually in Enumeration type. Can i know what actually is Enumeration type?Read the java.util.Enumeration API: http://java.sun.com/j2se/1.5.0/docs/api/java/util/Enumeration.html
2) Is it possible i return those names by converting them into string and as an array type? then accessing it using getProperty?Yes.
On the other side, you may find this stuff useful too. It sets all parameters back in the HttpServletRequest#getParameter()/getParameterValues()/getParameterMap() and puts the files as attributes of the HttpServletRequest. Very useful. http://balusc.blogspot.com/2007/11/multipartfilter.html

Error in reciever file adapter , where i am getting file name dynamically

hi all,
error in reciever file adapter , where i am getting file name dynamically, please help me in this isssue , i am trying for a long time
MP: Exception caught with cause com.sap.aii.af.ra.ms.api.RecoverableException: Exception in XML Parser (format problem?):'java.lang.Exception: Message processing failed in XML parser: 'Conversion configuration error: Unknown structure 'ns0:MT_eINVOICE_RECV' found in document', probably configuration error in file adapter (XML parser error)': java.lang.Exception: Exception in XML Parser (format problem?):'java.lang.Exception: Message processing failed in XML parser: 'Conversion configuration error: Unknown structure 'ns0:MT_eINVOICE_RECV' found in document', probably configuration error in file adapter (XML parser error)'

i am getting new error
MP: Exception caught with cause com.sap.aii.af.ra.ms.api.RecoverableException: Channel has not been correctly initialized and cannot process messages
this is my strcuture
and i have changed my structure
<HEADER>
<ADDRESS1/>
<ADDRESS2/>
<ADDRESS3/>
<ADDRESS4/>
</HEADER>
<HEADER_GST>
<TAX1/>
<TAX2/>
<TAX3/>
</HEADER_GST>
<LINE>
<QTY/>
<UOM/>
<UNIT_AMT/>
<CHARGE_TO_DT/>
</LINE>
<FILENAME>
<FILENAME/>
</FILENAME>
i have given the recordset structure as
HEADER,HEADER_GST,LINE,FILE

How to get file name of the form attachment?

Hi,
is there anybody who is able to help me with the following problem???
I started my process from Workspace ES and as a first step I attached one locale file (IMG.JPG or IMG.TIF e.g.) as a form attachment. I used "Attachments" bookmark in the Workspace ES.
I need to get file name of attached file in the process!!!
I tried to use "getTaskAttachments" component to get file name of form attachment but without success. This component successfully obtained attached file an stored it in the variable (type list, subtype document) but didn't produce all file attribute informations such as basename or Content Type:
Is there some possibility to obtain file name (including file extension) by using "standard" tools and components of ALC?
Thanks for your suggestions.

Hi LekomDev,
I faced the same situation some time back and this is what I know.
Based on the file type few of the attributes will or will not be populated. (This is what the official documentation says about Document attributes)
The file name that you are looking for would mostly be in 'name' attribute of Document object. The 'wsfilename' attribute is the atrribute which gets used to show the file name into Attachments tab of the workspace.
So, if you are just interested in knowing the filenames then 'name' attribute is the place that you are looking for.
But if you are trying to solve an issue in which Attachments against a Task isn't showing the filenames properly then you would need to copy the 'name' attribute value into 'wsfilename' attribute and then the Attachmetns against a Task would have the correct names.
Tip: Use the Record and Playback option of the workbench to inspect the Document variable and you would see all of the values for a Document variable at desired step in your orchestration.
hope this helps,
cheers,
Parth Pandya
Blog: http://livecyclekarma.wordpress.com

Need to get file name and directory back from file adapter - WRITE

I am using the file adapter to write a file. I want to log the file name of the file we just created. Since we use a precise timestamp in the file name, I can't accurately guess.
I have an invoke in my BPEL process to the file adapter. My first try was to assign the jca.file.FileName property to a variable, but it never comes back. I looked around and saw plenty of ways to SET the file name for a write and GET the file name for a read, but no GET file name for WRITE.
Anyone have a solution?
Thanks in advance!

I think I got your point... You can tell FileAdapter the filename to write, but if you don't then FileAdapter can not tell you the filename that it wrote... I think it is pretty possible Oracle didn't implement the latter, as the write operation is probably asynchronous and the filename is calculated later on...
If what you want is just log, you may achieve your requirement by increasing verbosity on Adapter logs... Have a look at the link bellow...
http://docs.oracle.com/cd/E15586_01/integration.1111/e10226/ad_mon.htm#CJHHBBID
Otherwise, the solution for you will be to calculate filename yourself, and that will be a little bit of reinventing the wheel... But at least you will know the filename...
Cheers,
Vlad

For OS X 10.3.9 Panther how do you get Flash 9 to work after downloading it?...

For OS X 10.3.9 Panther how do you get Flash 9 to work after downloading Flash 9 ?... for the link at
http://www.universalhub.com/node/24494
"To watch this video you need Flash 9
You have an old version of Flash. Fortunately we can upgrade
your computer to Flash 9 without without any hassle. Just click on the
upgrade button - you don't even need to leave the page!
[ Upgrade now! ]
After Flash 9 is downloaded, you'll need to restart your browser.
[ Download and install manually. ]"

Hello Again Don,
It appears you have been struggling with this issue since November of 2008.
Have you considered upgrading to a newer version of OS X instead?
11/20/08 What workarounds are there for OS X 10.3.9 users on websites with flash
4/12/09 How do you get the current Flash to work with OS X 10.3.9 ?...
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ali b

Word cannot open this document. The document might be in use, the document might not be a valid Word document, or the file name might contain invalid characters (for example,\ /).

I recently upgraded to a new Macbook Air running Lion, from my 2007 white Macbook running Snow Leopard. I had Office for Mac 2004 on the 2007, but had to upgrade to Office for Mac 2011 to be compatible with Lion on the Air. Now when I try to open my documents on the Air that were saved under Office 2004 on the old computer, I get the following message: Word cannot open this document. The document might be in use, the document might not be a valid Word document, or the file name might contain invalid characters (for example,\ /).
Any suggestions? Thank you.

Ha,ha,ha.....I figured it out. But for anyone else who's having this problem, it seems that while Office 2004 allowed dates in this format: 00/00/00, Office 2011 doesn't like it at all. I just changed the format in the document names to 00-00-00 and all is well. Documents are opening beautifully!

Performing a mass rename on originals to get rid of backslashes in file names. Worked for most files but failed for some with OSSStatus -43. Can't find any info on error -43. Any ideas?

I'm moving all my managed files to be referenced so I can access from both Aperture and lightroom. Needed to do a rename on 16,000 files to get rid of backslashes in the file names. Most of the time it worked but for 1093 files it gave OSSStatus -43. I've tried googling the error and got nothing. Any ideas where to begin looking?
Thanks
Jim

How are you renaming the files? In the "File > Relocate original file" dialog panel? Are you using a custom name format?
Have you checked in Aperture, if the originals, that are giving you the error message, are still inside the Aperture library?

Get file name

Hello world,
Am writing a small server application that can accept files and save them locally. Now, the server is working, but am finding it very hard to get the name of the file that's been sent so that I can save the file with that name and its extension.
e.g. I want if I sent a hello.java file, then, the server will save it as hello.java. But at the moment, its not saving it like that because there is no way can get the name of the file from the client.
Here is my code:
import java.io.*;
import java.net.*;
class Server {
    static final String ToSave = "C:\\";
    static final int PORT               = 2391;
    public static void main(String args[]) {
        while ( true ) {
            try {
                ServerSocket socketServer = new ServerSocket(PORT);
                Socket socket = socketServer.accept();
                //Assuming we have a file name (FILENAME)from client
                FileOutputStream fos = new FileOutputStream(ToSave + FILENAME);//<--HERE IS WERE i WANT THE FILENAME
                BufferedOutputStream out = new BufferedOutputStream(fos);
                BufferedInputStream in = new BufferedInputStream( socket.getInputStream() );
                int i;
                while ((i = in.read()) != -1) {
                    out.write(i);
                out.flush();
                in.close();
                out.close();
                socket.close();
                socketServer.close();
                System.out.println("Transfer complete.");
            catch(Exception e) {
                System.out.print( e );
            try {
                Thread.sleep(1000);
            } catch (InterruptedException ie) {
                System.err.println("Interrupted");
}

You have to define a protocol which enables the
client to tell the server the file name.
BTW creating server sockets inside a loop is not a
good idea.
Thank you very much :)
I've got the idea on how to implement it now. All I have to do is:
first connect to the server and send a message containing the name of the file and then, at the server end, I will receive the name and use it to save to incoming file.
Thanks again.

How can I get file name using JSTL ?

Hi,
I'm now using <c:out value="${pageContext.request.requestURI}"/>
this return servlet path
How can I get just file name
or user path (in location bar) ?
thanks in advance

The original uri (before forwarding) is available in a request scoped attribute.
These attributes are given the values obtained by calling the related method on the original request received by the container.
javax.servlet.forward.request_uri
javax.servlet.forward.context_path
javax.servlet.forward.servlet_path
javax.servlet.forward.path_info
javax.servlet.forward.query_stringSo if those two above don't work for you these might.
<c:out value="${requestScope['javax.servlet.forward.request_uri']}"/>
<c:out value="${requestScope['javax.servlet.forward.servlet_path']}"/>If these values are null, then the value in the request object is the correct one.
You mentioned the value in the address bar being a .html file. Do you perchance use framesets? If so the value in the address bar is always the url used to load the frameset, and doesn't change no matter where you travel within those frames. That won't be available to the server, because it has nothing to do with the current request.
Cheers,
evnafets

Getting File Name in Automator workflow - combine PDF

I am using Automator to combine 2 PDF files.
I would like to inherit one of the file names in the new PDF and append a standard text to the front of the file name.
I am not sure how to do this. I can combine the PDFs the way I would like, but I am not sure how to plick the file name.
my workflow is as follows.
Folder Action targets folder where 1st PDF is added(I want this FILE NAME).
Ger Specified finder item selects 2nd PDF to be combined.
Sort Finder Items makes sure the new PDF pages are ordered properly.
Combine PDF Pages combines the pages.
Move Finder Items saves the files where i want it.
Name single item is whre i thought to add my standard text plus the variable of FILE NAME.
Open File in mail to set up my email.
Anyone can help with this?
thanks,
Aaron

Here is an automator workflow that does something similar so I believe you can adapt to your needs. This workflow is setup as a service workflow. It will combine PDFs in the order in which they are selected/clicked via the Shift key. The default name of the combined output file will be the name of the first file clicked. Automator can be activated by CTRL clicking any of the selected PDFs.
1. Service receives PDF files in Finder
2. Automator Action: Run AppleScript
on run {input, parameters}
          display dialog "Files will be combined in the order selected via the Shift key" as text
          return input
end run
3.. Automator Action: Trim input items
keep the first one
you will need to download and install this autotmator action from here:
http://www.menace-enterprises.com/Files/Automator/Actions/Trim%20Input%20Items.d mg
4. Automator Action: Run AppleScript
(* Note & Definitions
This Applescript extracts the basename of the first selected file without its .pdf extension
"path_basename_ext" is full path and name, e.g. User/desktop/file.pdf
"NmExt" is filename with extension, e.g. file.pdf
"baseName" is the base filename without extension, e.g. file
"Ext" is the file's extension, e.g. pdf
on run {input, parameters}
          set path_basename_ext to input
          tell (info for path_basename_ext) to set {NmExt, Ext} to {name, name extension}
          set baseName to text 1 thru ((get offset of "." & Ext in NmExt) - 1) of NmExt
baseName
          return baseName
end run
5. Automator Action: Set Value of Variable
define baseName as the variable
6. Automator Action: Get selected finder items
Options: check ignore input
7. Automator Action: Combine PDF pages
choose Combine by appending
8. Automator Action: Move Finder Items
choose To: Desktop
Options: check show this action when workflow runs
9. Name Single Items
choose Basename only to: baseName
Options: check show this action when workflow runs
10. Open Finder Items

How to get file name for failed request in JSOM

hello friends,
i am uploading files to sharepoint 2013 document library. due to some problem when a file is not uploaded request is failed and failed callback handler is executed. at this time how i can know for which file has not been uploaded.
as i am uploading multiple files so it is necessary to know for which file error occurs.
please help
Thanks in advance.
Mukesh

Hi Z..
it will be hard for any one to understand the code. how ever I have provided bellow.
theme is I need to upload multiple files selecting one by one asynchronously when a file will begin to upload It will show status of file name with processing image. similarly for other files.
ones file successfully uploaded processing image will get hidden. and delete will appear.
when error occurs for a file then processing div need to be removed for which I need file name when request failed. in failed handler
function uploadData()
var input = $("#fldFile")[0];
if (input) {
$("#uploadedfile").append("<div class='file'><label>" + input.files[0].name + "</label><div class='image'><img src='/_layouts/15/KPMG.VendorPortal.DMS/processing.gif' alt='processing..'/><img src='/_layouts/15/KPMG.VendorPortal.DMS/error.png' alt='delete' style='display:none;' /></div>");
file = input.files[0];
filename = input.files[0].name;
fr = new FileReader();
fr.onload = uploaddocument;
fr.readAsDataURL(file);
function uploaddocument()
web = clientContext.get_web();
clientContext.load(web);
list = web.get_lists().getByTitle("TempLibrary");
rootFolderUrl = list.get_rootFolder();
file = this.result;
clientContext.load(rootFolderUrl);
clientContext.executeQueryAsync(onuploaddocumentsuccess, failed);
function onuploaddocumentsuccess()
fileCreateInfo = new SP.FileCreationInformation();
fileCreateInfo.set_url(rootFolderUrl.get_serverRelativeUrl() + "/" + foldername + "/" + filename);
fileCreateInfo.set_overwrite(true);
fileCreateInfo.set_content(new SP.Base64EncodedByteArray());
// Read the binary contents of the base 64 data URL into a Uint8Array
// Append the contents of this array to the SP.FileCreationInformation
var arr = convertDataURIToBinary(file);
for (var i = 0; i < arr.length; ++i) {
fileCreateInfo.get_content().append(arr[i]);
// Upload the file to the root folder of the document library
uploadedfile= list.get_rootFolder().get_files().add(fileCreateInfo);
clientContext.load(uploadedfile);
clientContext.executeQueryAsync(documentuploaded, documentfailed);
function documentuploaded()
var fname = uploadedfile.get_name();
$("#uploadedfile").children("div").each(function () {
var flabelname = $(this).children("label").text();
if (flabelname.trim() == fname.trim())
$(this).children("div").children("img").get(0).style.display="none";
$(this).children("div").children("img").get(1).style.display="block";
alert("uploaded");
function documentfailed(sender,args)
Mukesh

Sharepoint 2010 -Script to get file name from Document Library

Hi
can anybody send be script that works in "SharePoint 2010 management Shell" to get list of file names in document library.
Thank

See my updated answer. The double quotes need to be removed. Also note that you need to use $item.File.Name
and not $item.Name to get the name of the files.
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Getting file name to work in download/upload example

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