Getting names of all files in a directory.

Question

import java.io.*;
import java.util.*;
public class dir{
     public static void main(String args[]) throws IOException{
          //BufferedReader in = new BufferedReader(new FileReader(args[0]));
          PrintWriter out = new PrintWriter(new FileWriter("dir.txt"));
          File file = new File(args[0]);
          //FileFilter filefilter = "log";
          Vector x = new Vector();
          int vlength;
          x = getDirectoryContent(file);//,filefilter);
          vlength = x.size();
          for(int i=0;i<x.size();i++){
               out.println(x.elementAt(i));
          out.close();
     public static Vector getDirectoryContent(File file){//, FileFilter fileFilter){
          Vector v= new Vector();
          if (file.isDirectory()) {
               File[] content = file.listFiles();//fileFilter);
               for (int i=0; i<content.length; i++){
                    v.addElement(content);
               }//for
          }//is directory
          return v;
     }//getDirectoryContent
That is the code that I am using, what I am trying to do with it is read all the files in a directory. So I can open them and calculate all the data in all of the files at the same time.
These are the file names that are in the directory when I run the program.
L0519013.log
L0331001.log
I have the code out put the file names in a file called dir.txt
after running the program this is what I get in the output file.
[Ljava.io.File;@70ccc4b2
[Ljava.io.File;@70ccc4b2
[Ljava.io.File;@70ccc4b2
Any clue waht this means?
also I am passing in the director as args[0]

Answer 1

if possible as well...
I could not get the FileFilter to work, could not get the syntax down to get it to work when I was initializing it so for the moment it is remed out. all files in the given directory will be of type .log so there really is no need for the FileFilter. But any help on how to include that in the code would be greatly helpful.
Thankxs
Korbin