Getting to first and last email quickly

Sometimes i pick up my blackberry and find that my mailbox is showing emails or texts that i got 6 months ago. i then spend 15 minutes scrolling with my trackball to get to the current day's messages. Since there must be some button which automatically gets to my oldest email, what can i do to get to my most recent email without scrolling for a long time. Thanks
Solved!
Go to Solution.

I figured out my own answer and thought I would post in case anyone else has this problem. When looking at stored emails, I can hit T to go to the top of the list(or most recent email) Imust be hitting B which automatically goes to the bottom of the list(or oldest email) Thank you to me for my help.

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How to get the first and last record

Hai All
I have table called T1 and there are more than 8 lakhs records and i have a column called Timestamp so i need to get the first record value and time stampvalue and last record and time stamp value so that i can conclude that For Example
form 13 june to 15 june data are here
Kind Regards
SrikkanthM

Something like this can also indicate the first and last rows as you query...
SQL> select empno, ename, hiredate
2        ,case row_number() over (order by hiredate)
3           when 1 then 'First Row'
4           when count(*) over () then 'Last Row'
5         end as flag
6 from emp;
     EMPNO ENAME      HIREDATE            FLAG
      7369 SMITH      17/12/1980 00:00:00 First Row
      7499 ALLEN      20/02/1981 00:00:00
      7521 WARD       22/02/1981 00:00:00
      7566 JONES      02/04/1981 00:00:00
      7698 BLAKE      01/05/1981 00:00:00
      7782 CLARK      09/06/1981 00:00:00
      7844 TURNER     08/09/1981 00:00:00
      7654 MARTIN     28/09/1981 00:00:00
      7839 KING       17/11/1981 00:00:00
      7900 JAMES      03/12/1981 00:00:00
      7902 FORD       03/12/1981 00:00:00
      7934 MILLER     23/01/1982 00:00:00
      7788 SCOTT      19/04/1987 00:00:00
      7876 ADAMS      23/05/1987 00:00:00 Last Row
14 rows selected.
SQL>

How do I easily select a group of emails in Apple Mail if I want to delete them? In other words, how do I select the first and last message and delete everything in between?

How do I easily select a group of emails in Apple Mail if I want to delete them? In other words, what do I select if I mark the first and last email to delete everything in between? Thanks.

I have this same issue. I have over 100 email addresses that I need to add to a group. The issue is not making the group, it's getting the email addresses from Mail to Contacts.
Dragging the email addresses does nothing. You can copy the addresses, but there's nowhere to put them. You can make a VCF for an email address, but then you have to find all of them to add them to the group. How do you automate this?!
I'm astounded that there's so little support for such a common issue for which people have been asking for years.

FM for First and Last Day_Current Month

Hello All,
Inorder to update the TVARV table, two new variables were needed which will get the First and Last Day of current month.
One FM i was able to find was BKK_GET_MONTH_LASTDAY which takes the Todays date and outputs the Last date of the month. IS there any FM for FIRSTDAY Current month....
Regs,
-PSK

Hi Sravan,
Following help may help you.
FM - BUILD_PERIOD_TABLE
code is mentioned below.
data: it_cperiod type table of range_prds with header line,
define one variable as range like -
ranges: r_cperiod for sy-datum,
CALL FUNCTION 'BUILD_PERIOD_TABLE'
    EXPORTING
      YEAR         = <current year>
    TABLES
      PERIOD_TABLE = it_cperiod.
read table it_cperiod with key per_id = <current month>
refresh r_cperiod.
r_cperiod-sign = 'I'.
r_cperiod-option = 'BT'.
r_cperiod-low = it_cperiod-begda.
r_cperiod-high = it_cperiod-endda.
append r_cperiod.
Now, you can see begin and end of moth in r_cperiod.
Regards,
Parag

SQL Selecting the first and last entries for each day

Hello SQL experts,
I hope you can help with this.. I have a table (could have 1M or more rows in it) see structure below. I am looking to get the first and last date/times for each employee for each day. I also need the location GUID for the first read.
EmployeeGUID (uniqueidentifier datatype)
LocationGUID (uniqueidentifier datatype)
DateTime (DateTime datatype)
12345678-0000-0000-0000-000000000000
11111111-0000-0000-0000-000000000000
04/12/2014 07:00:01
12345678-0000-0000-0000-000000000000
22222222-0000-0000-0000-000000000000
04/12/2014 10:40:05
12345678-0000-0000-0000-000000000000
22222222-0000-0000-0000-000000000000
04/12/2014 17:04:02
44422222-0000-0000-0000-000000000000
22222222-0000-0000-0000-000000000000
04/14/2014 08:00:00
44422222-0000-0000-0000-000000000000
22222222-0000-0000-0000-000000000000
04/14/2014 14:00:03
44422222-0000-0000-0000-000000000000
33333333-0000-0000-0000-000000000000
04/15/2014 07:49:00
44422222-0000-0000-0000-000000000000
11111111-0000-0000-0000-000000000000
04/15/2014 09:00:01
This would be the ideal output (I can do without the TotalTimeInHours):
EmployeeGUID (uniqueidentifier datatype)
LocationGUID (uniqueidentifier datatype)
FirstRead (DateTime datatype)
LastRead (DateTime datatype)
TotalTimeInHours
12345678-0000-0000-0000-000000000000
11111111-0000-0000-0000-000000000000
04/12/2014 07:00:01
04/12/2014 17:04:02
Total in hours between the first and last read.
44422222-0000-0000-0000-000000000000
22222222-0000-0000-0000-000000000000
04/14/2014 08:00:00
04/14/2014 14:00:03
44422222-0000-0000-0000-000000000000
33333333-0000-0000-0000-000000000000
04/15/2014 07:49:00
04/15/2014 09:00:01
I would post what I have tried so far but I have been trying many different types of queries over the last few days. In short I need the employees first and last reads for each date. They could have many entries per date or just 1. I am certain that this
is a trivial thing for a SQL expert but not trivial for me :).
Thank you in advance!

Thank you!
This is almost what I need. The LocationGUID has to be included in the output. When I include it, I have to put it in the Group By clause. When I do that the reads are based on the LocationGUID (see below).
** I added a few more data entries and included the LocationGUID in the output.
***** SQL ***********
CREATE TABLE test( EmployeeGUID uniqueidentifier, LocationGUID uniqueidentifier, DateTimeCol DateTime )Insert into test values
('12345678-0000-0000-0000-000000000000','11111111-0000-0000-0000-000000000000','04/12/2014 07:00:01')
,('12345678-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/12/2014 10:40:05')
,('12345678-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/12/2014 17:04:02')
,('12345678-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/12/2014 19:00:00')
,('44422222-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/14/2014 08:00:00')
,('44422222-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/14/2014 14:04:03')
,('44422222-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/15/2014 07:49:00')
,('44422222-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/15/2014 09:00:01')
,('12345678-0000-0000-0000-000000000000','11111111-0000-0000-0000-000000000000','04/13/2014 10:40:05')
,('12345678-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/13/2014 17:04:02')
,('12345678-0000-0000-0000-000000000000','22222222-0000-0000-0000-000000000000','04/13/2014 19:00:00')
;with mycte as (
SELECT *, row_number() OVER(partition by EmployeeGUID, Cast(DateTimeCol as date) Order by DateTimeCol) rnASC,
row_number() OVER (partition by EmployeeGUID, Cast(DateTimeCol as date) Order by DateTimeCol DESC) rnDESC
FROM test)
Select EmployeeGUID ,Cast(DateTimeCol as date) dt,LocationGUID,
Max(Case when rnASC=1 Then DateTimeCol End) minDateTimeCol
,Max(Case when rnDESC=1 Then DateTimeCol End ) maxDateTimeCol
,Datediff(minute, Max(Case when rnASC=1 Then DateTimeCol End) ,Max(Case when rnDESC=1 Then DateTimeCol End ) )/60.0 TotalTimeInHours
from mycte
Group by EmployeeGUID, LocationGUID,Cast(DateTimeCol as date)
Order by dt,EmployeeGUID
drop TABLE test
**** OUTPUT **********
EmployeeGUID
dt
LocationGUID
minDateTimeCol
maxDateTimeCol
TotalTimeInHours
12345678-0000-0000-0000-000000000000
2014-04-12
11111111-0000-0000-0000-000000000000
2014-04-12 07:00:01.000
NULL
NULL
12345678-0000-0000-0000-000000000000
2014-04-12
22222222-0000-0000-0000-000000000000
NULL
2014-04-12 19:00:00.000
NULL
12345678-0000-0000-0000-000000000000
2014-04-13
11111111-0000-0000-0000-000000000000
2014-04-13 10:40:05.000
NULL
NULL
12345678-0000-0000-0000-000000000000
2014-04-13
22222222-0000-0000-0000-000000000000
NULL
2014-04-13 19:00:00.000
NULL
44422222-0000-0000-0000-000000000000
2014-04-14
22222222-0000-0000-0000-000000000000
2014-04-14 08:00:00.000
2014-04-14 14:04:03.000
6.066666

Get First and last day of Month..

Hi Friends,
I am trying to fetch First and Last day of a month and would like to implement that in the following code:
SELECT COALESCE(Date_A, Date_B, Date_C)
FROM dual
Here Date A and B are in Format of MM DD YYYY (March 14, 2008)
and Date C is like MM YYYY (March 2008)
How can I get the Date_C as March 1, 2008 OR March 31, 2008 format if Date A and B are NULL ?
Thanks!
Edited by: user11095386 on Apr 23, 2009 10:45 AM

Hi,
In my earlier message, I thought that you were starting with strings like '03 12 2009' and that you wanted to display them as 'March 12 2009'. If what you have is just the reverse, then just reverse the format strings in my first message. Add a comma, if you want one, in the appropriate format string.
I believe this is what you want:
COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
         , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
         , TO_CHAR ( TO_DATE ( Date_C, 'fmMonth YYYY'),    'MM DD YYYY')
         )Notice how, on the 3rd line, TO_DATE is called without DD in the format string:
TO_DATE ( Date_C, 'fmMonth YYYY')When you do this, the day defaults to the 1st of the month, so this is all you have to do to convert the VARCHAR2 'March 2009' to the DATE 01-Mar-2009.
If you want the last day of the month, not the first, when Date_C is chosen, then use LAST_DAY:
COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
         , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
         , TO_CHAR ( LAST_DAY ( TO_DATE ( Date_C
                                          , 'fmMonth YYYY'
             , 'MM DD YYYY'
         )

Get first and last day given month name with combobox

hi guys ;
I loaded to month name in combobox and I want to get first and last day by the name of month from selected Combobox
So if I select to february than results get 01.02.2015 and 28.02.2015
if select March than 01.03.2015 and 31.03.2015
Thanks .

Thank you for useful post , How to change Culturinfo as a Turkish Month name ?
your's code is work if I use English month name But it was get error when use the turkish month name
If you are running your application on a Turkish Windows you could use the System.Globalization.CultureInfo.CurrentCulture:
int month = DateTime.ParseExact(monthName, "MMMM", System.Globalization.CultureInfo.CurrentCulture).Month;
Or you could use create an explicit culture object like this:
System.Globalization.CultureInfo ci = new System.Globalization.CultureInfo("tr-TR");
int month = DateTime.ParseExact(monthName, "MMMM", ci).Month;
Please remember to mark all helpful posts as answer to close your threads.

Get the first and the last date of a week

Hi all
I need to get the first and the last date of a specific week.
I need a function that returns two date passing it just one date.
The function has to calculate the first and the last date of the week of the argument date.
hope to be clear
regards

goiters,
I need to get the first and the last date of a specific week.Yup, and what's the first day of the week in your part of the world, is it Sunday or Monday?
I need a function that returns two date passing it just one date.No you don't, just add 7 days to the start of the week.
hope to be clearWell, you can hope.
Keith.
Message was edited by: corlettk - now I hope to clear ;-)

Rented film, fully downloaded (eventually) press play now then screen goes to authorizing, then goes black blank, no film , repeated process 3 times, still no joy. first and last time I rent a film with Apple, how do I get my money back ? Thanks

Rented film from Apple TV fully downloaded (eventually) press play now then screen goes to authorizing for 10 mins, then goes black blank, no film , repeated process 3 times, still no joy. first and last time I rent a film with Apple, how do I get my money back ? Thanks

First, that cannot be an iBook G4 as that machine cannot run Snow Leopard let alone Mountain Lion. To run Snow Leopard it has to be an Intel processor, not a G4. What does it show as the Model Identifier in About This Mac, More Info, System Report, Hardware, Model Identifier?
Second, if you have erased the hard drive there should not be remnants of any prior content. Even though Disk Warrior is saying nothing is wrong with the hard drive, it sounds as though there are problems. You may want to consider simply replacing the hard drive so there are no questions about faults. A good source is OWC, http://www.macsales.com where they also have on-line videos showing how to do the replacement.
Third, you could also try again to restart using the Snow Leopard DVD/CD and use Disk Utility on that install disk to erase again, and do it a couple times, then try to install. If it continues to refuse, then it sounds as though there is a fault with the hard drive.

HT202058 iphone 6+ somehow has switched my name on emails into my nephew's name. We share a first and last name but not a middle name. For example, my name might be John George Doe and his name John James Doe. How did this happen? How do I correct it.

iphone 6+ somehow has switched my name on emails into my nephew's name. We share a first and last name but not a middle name. For example, my name might be John George Doe and his name John James Doe. How did this happen? How do I correct it.

So if the solution recommended by Ralph is not working then the other option is this:
Please make sure that the emails work correctly when signed into, on a computer
Then delete the account off your phone - you will not lose the emails
Reset the phone
Re add the account back in and see if that helps the issue
Thanks

Get first and last date of month

Hi,
Is there any function module to get first and last date of month for a entered date.
Please let me know.
Regards,
SP

Hi,
Use the below FM to find the Last day of month and them u can easily calculate the first day.
DATA : v_startdate TYPE sy-datum.
DATA : v_enddate TYPE sy-datum.
DATA : v_temp TYPE dats.
v_temp = sy-datum.
CALL FUNCTION 'RP_LAST_DAY_OF_MONTHS'
    EXPORTING
      day_in            = v_temp
    IMPORTING
      last_day_of_month = v_enddate
CONCATENATE v_enddate+0(6) '01' INTO v_startdate.
Hope it helps.
Regards,
Arnab.

Getting first and last dates of a month

Jello all,
I am really sorry I am posting this topic here, not actually owned by this forum but in fundamental forum i am not getting it attended.
I am generating monthly, quartelry and yearly reports, for which I need to get first and last dates of a given Month taking in to account leap year. I searched the API and docs for Calendar class. I could not find any useful methods / fields. I wonder this being a very common requirement, how SUN has not provided these essential features. I still feel, it must be some where. Please help me and reply. Also if you came across any other forum for util package, let me know.
Thanks
Varde

Jello all,
I am really sorry I am posting this topic here, not
actually owned by this forum but in fundamental forum
i am not getting it attended.
Yes, and I can see you are a very patient person, waiting a whole half hour for a response before cross posting other boards.
Question answered.
http://forum.java.sun.com/thread.jsp?thread=514908&forum=31&message=2451646

Getting first and last day of week

Dear all .
Is there any funcion module which gives first and last day of the current week .
Eg . todays day is 15.11.2006
start date of week : 13.11.2006
end date of week : 19.11.2006
in the same way I want how many days are there in month .
Eg : for Nov month :
         30 days .
      for dec month 31 days .
Thank you in advance

Use FM GET_WEEK_INFO_BASED_ON_DATE
Import parameters               Value
DATE                            15.11.2006
                                                                                Export parameters               Value
WEEK                            200646
MONDAY                          13.11.2006
SUNDAY                          19.11.2006
Use FM HR_E_NUM_OF_DAYS_OF_MONTH
Import parameters               Value
P_FECHA                         15.11.2006
Export parameters               Value
NUMBER_OF_DAYS                    30
I hope it helps.
Best Regards,
Vibha
*Please mark all the helpful answers

How to get first and last date of previous month

To set default values in selection screen,I want first and last date of the previous month.
Also I want the first and last dates of previous quarter.
The quarters can be only january to march, apr to june, jul to sept, oct to dec.
I want to run a program on beginning of each month by job scheduling having <b>selection screens</b> for the above monthly and quarterly dates.

Hi Suhas,
Use the below code.
DATA: v_date LIKE sy-datum.
DATA: v_month_begin_date TYPE sy-datum,
      v_month_end_date TYPE sy-datum,
      v_month(2) TYPE n,
      v_month1(2) TYPE n,
      v_quarter TYPE i,
      v_year(4) TYPE n,
      v_quarter_begda TYPE sy-datum,
      v_quarter_endda TYPE sy-datum.
v_month = sy-datum+4(2).
IF v_month = '01'.
v_month = '12'.
v_year = sy-datum+0(4) - 1.
ELSE.
v_month = v_month - 1.
v_year = sy-datum+0(4).
ENDIF.
CONCATENATE v_year v_month '01' INTO v_date.
CALL FUNCTION 'HR_JP_MONTH_BEGIN_END_DATE'
EXPORTING
    iv_date             = v_date
IMPORTING
    ev_month_begin_date = v_month_begin_date
    ev_month_end_date   = v_month_end_date.
v_month1 = sy-datum+4(2).
IF v_month1 = '01' OR
   v_month1 = '02' OR
   v_month1 = '03'.
v_quarter = 1.
ELSEIF v_month1 = '04' OR
       v_month1 = '05' OR
       v_month1 = '06'.
v_quarter = 2.
ELSEIF v_month1 = '07' OR
       v_month1 = '08' OR
       v_month1 = '09'.
v_quarter = 3.
ELSEIF v_month1 = '10' OR
       v_month1 = '11' OR
       v_month1 = '12'.
v_quarter = 4.
ENDIF.
IF v_quarter = 1.
v_quarter = 4.
v_year = sy-datum+0(4) - 1.
ELSE.
v_quarter = v_quarter - 1.
v_year = sy-datum+0(4).
ENDIF.
CALL FUNCTION 'HR_99S_GET_DATES_QUARTER'
EXPORTING
    im_quarter = v_quarter
    im_year    = v_year
IMPORTING
    ex_begda   = v_quarter_begda
    ex_endda   = v_quarter_endda.
WRITE:/5 'previous month begin date : ', v_month_begin_date.
WRITE:/5 'previous month end date   : ', v_month_end_date.
WRITE:/5 'previous quarter begin date : ', v_quarter_begda.
WRITE:/5 'previous quarter end date : ', v_quarter_endda.
Message was edited by:
        Velangini Showry Maria Kumar Bandanadham

Chunk expressions: Need the first and last char position from member.word[x]?

I need to build a linear list of the string positions of the
first and last character of each word in a string. For example if I
have the string myPet = “DOG CAT FISH” then myList =
[[1,3],[5,7],[9,12]]
myPet.word[x] will let me access the individual words but
I’m not sure how to get the char position of the beginning
and end of each. Please help, it’s Friday and my brain has
left for the weekend.

Touche, Sean.
"Sean Wilson" <[email protected]> wrote in
message
news:fqa8ap$bga$[email protected]..
> Hi Craig,
>
> Your's fails if any word is repeated. Try it with "DOG
CAT FISH DOG"
>
> This one seems to work, although there are probably more
efficient ways to
> go about it. A regular expression and the PRegEx xtra
would certainly be
> quicker, especially as the string gets longer
>
> on mGetWordBoundaries aString
> -- basic error check
> if stringP(aString) = 0 then return []
> if length(aString) = 0 then return []
>
> lWhitespace = [SPACE, TAB, RETURN, numToChar(10)]
> tStart = 1
> tChar = aString.char[tStart]
> repeat while lWhitespace.getPos(tChar)
> tStart = tStart + 1
> tChar = aString.char[tStart]
> end repeat
>
> lPositions = []
> repeat with w = 1 to aString.word.count
> tEnd = tStart + aString.word[w].char.count - 1
> lPositions.append([tStart, tEnd])
> tStart = tEnd + 1
> tChar = aString.char[tStart]
> repeat while lWhitespace.getPos(tChar)
> tStart = tStart + 1
> tChar = aString.char[tStart]
> end repeat
> end repeat
> return lPositions
> end

Getting to first and last email quickly

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