H:PanelGroup layout. Error in documentation ???

Hi,
The render kit docs clearly say:
If the "style" or "styleClass" attributes are present, and the "layout" attribute is present with a value of "block", render a "div" element
... No matter what I do, I get a span element rendered.
Can someone explain what I am missing??
Thanks!
S

Hi,
I was using RI 1.1_01 but read the 1.2 docs
hence my error
Thanks for indirectly pointing it out
S
Edited by: shandor911 on Nov 9, 2007 4:28 AM

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Hello,
I apologize in advance, while I do know programming (I'm a PHP and Perl programmer) I'm fairly new to Java so this may well be a silly question, but that's why I am here. I hope you'll show me where my error is so I can finally set this to rest before it drives me mad :)
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That is entirely against the documentation.
This is the script I wrote to test the issue:
public class MathTest {
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          float u=2, v=3, w=5, x=7, y=11;
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          System.out.println("u++ /v = " + tmp1);
          System.out.println("First ++ value for 'u': " + u);
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          System.out.println("Second ++ value for 'u': " + u);
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The output:
Initial value for 'u': 2.0
u++ /v = 1.0
First ++ value for 'u': 3.0
u++ *w= 20.0
Second ++ value for 'u': 4.0
21.0
Clearly, the ++ operation is done after the division and after the multiplication.
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>
The fact that u++ is evaluated but in the calculation itself the "previously stored" value of u is used is completely confusing.
>
Yes it can be confusing - and no one is claiming otherwise. Here are some more thread links from other users about the same issue.
Re: Code Behavior is different in C and Java.
Re: diffcult to understand expression computaion having operator such as i++
Operator Precedence for Increment Operator
>
So, when they explain that ++ has a higher precedence, the natural thing to consider is that you "do that first" and then do the rest.
>
And, as you have discovered, that would be wrong and, to a large degree, is the nut of the issue.
What you just said illustrates the difference between 'precedence' and 'evaluation order'. Precedence determines which operators are evaluated first. Evaluation order determines the order that the 'operands' of those operators are evaluated. Those are two different, but related, things.
See Chapter 15 Expressions
>
This chapter specifies the meanings of expressions and the rules for their evaluation.
>
Sections in the chapter specify the requirements - note the word 'guarantees' in the quoted text - see 15.7.1
Also read carefully section 15.7.2
>
15.7. Evaluation Order
The Java programming language guarantees that the operands of operators appear to be evaluated in a specific evaluation order, namely, from left to right.
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>
So when there are multiple operators in an expression 'precedence' determines which is evaluated first. And, the chart in your link shows 'postfix' is at the top of the list.
But, as the quote from the java language spec shows, the result of 'postfix' is the ORIGINAL value before incrementation. If it makes it easier for then consider that this 'original' value is saved on the stack or a temp variable for use in the calculation for that operand.
Then the evalution order determines how the calculation proceeds.
It may help to look at a different, simpler, but still confusing example. What should the value of 'test' be in this example?
i = 0;
test = i++; The value of 'test' will be zero. The value of i++ is the 'original' value before incrementing and that 'original' value is assigned to 'test'.
At the risk of further confusion here are the actual JVM instructions executed for your example. I just used
javap -c -l Test1to disassemble this. I manually added the actual source code so you can try to follow this
        int u = 2;
   4:iconst_2
   5:istore 5
        int v = 3;
   7:iconst_3
   8:istore          6
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10:iconst_5
11:istore          7
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        z = z = u++ / v + u++ * w;
   13: iload   5
   15: iinc    5, 1
   18: iload   6
   20: idiv
   21: iload   5
   23: iinc    5, 1
   26: iload   7
   28: imul
   29: iadd
   30: dup
   31: istore 8
   33: istore 8The Java Virtual Machine Specification has all of the JVM instructions and what they do.
http://docs.oracle.com/javase/specs/jvms/se7/jvms7.pdf
Your assignment to z and formula starts with line 13: above
13: iload 5 - 'Load int from local variable' page 466
15: iinc 5, 1 - 'Increment local variable by constant' page 465
18: iload 6 - another load
20: idiv - do the division page
21: iload 5 - load variable 5 again
23: iinc 5, 1 - inc variable 5 again
26: iload 7 - load variable 7
28: imul - do the multiply
29: iadd - do the addition
30: dup - duplicate the top stack value and put it on the stack
31: istore 8 - store the duplicated top stack value
33: istore 8 - store the original top stack value
Note the description of 'iload'
>
The value of the local variable at index
is pushed onto the operand stack.
>
IMPORTANT - now note the description of 'iinc'
>
The value const is first sign-extended to an int, and then
the local variable at index is incremented by that amount.
>
The 'iload' loads the ORIGINAL value of the variable and saves it on the stack.
Then the 'iinc' increments the VARIABLE value - it DOES NOT increment the ORIGINAL value which is now on the stack.
Now note the description of 'idiv'
>
The values are popped
from the operand stack. The int result is the value of the Java
programming language expression value1 / value2. The result is
pushed onto the operand stack.
>
The two values on the stack include the ORIGINAL value of the variable - not the incremented value.
The above three instructions explain the result you are seeing. For postfix the value is loaded onto the stack and then the variable itself (not the loaded original value) is incremented.
Then you can see what this line does
21: iload   5 - load variable 5 againIt loads the variable again. This IS the incremented value. It was incremented by the 'iinc' on line 15 that I discussed above.
Sorry to get so detailed but this question seems to come up a lot and maybe now you have enough information and doc links to explore this to any level of detail that you want.

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