Heavy CPU consumer/user in Oracle 10g

Hi,
OS linux
DB 10g
How do I find the program/user that eats a lot of CPU inside the oracle engine process?
I tried to run "top" linux command, and I saw the my CPU usage is 100% and the user was the oracle kernel.
I been monitoring the performance of our DB server Linux using "top" command, and I got this monitor dislay:
top - 22:43:43 up 52 days, 1:57, 6 users, load average: 0.99, 0.49, 0.30
Tasks: 549 total,   2 running, 547 sleeping,   0 stopped,   0 zombie
Cpu(s): 12.8% us, 0.5% sy, 0.0% ni, 86.5% id, 0.2% wa, 0.0% hi, 0.0% si
Mem:   8309152k total, 8225644k used,    83508k free,     3752k buffers
Swap: 10482308k total, 1993040k used, 8489268k free, 3575124k cached
PID USER      PR NI %CPU    TIME+ %MEM VIRT RES SHR S COMMAND
12778 oradev2   25   0 100   1:57.33 1.7 1165m 135m 101m R oracle
14329 applprod 15   0    5   2:09.04 0.1 46300 7780 4204 S httpd
12960 appldev   16   0    1   0:00.25 0.0 2620 1304 784 R top
13945 oraprod   16   0    0   0:00.49 0.2 1119m 17m 15m S oracle
15100 oraprod   16   0    0   0:05.16 0.9 1121m 69m 65m S oracle
    1 root      16   0    0   0:22.47 0.0 3504 508 432 S initI can see that oradev2 has a very hi CPU utilization, I am suspecting there is an untuned sql program inside it :(
How do I find the culprit program at (Oracle Level) who is hugging all the CPUs?
Thanks a lot

oradev2 is not the program, it is the LINUX oracle user id.
the process is under the 'command' column and is 'oracle' - this usually means an oracle server process ( i don't know what you mean by an oracle 'kernel' incidentally)
if you do a ps listing for the process - e.g
$ ps -ef | grep 12778
you will get a start time for the process which MAY give you a clue.
otherwise you must use your documentation to find out about the sys view v$process - usually the SPID column is the LINUX process id - in your case, 12778
you usually link v$process to v$session. Best of luck.
johnnie d

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