Help... IPhone down the loo problem again
I dropped my iPhone down the loo yesterday which seems to happen to a lot of people. I have read some of the other topics on here but I still have a question. It was down the loo for a mere second and I dried it off as best I could. It seemed to be fine and I even received a phone call on it and I was really relieved! I knew it needed charging as the battery was on red, but I have never left the battery to die I've always kept in on and charged. I had to pop out and took the phone with me, I received a phone call and a couple of texts and everything was fine. When I got back it started going funny. I didn't know if it was because it needed the charge though so plugged it in even though it had died. I then went to the forums and did all the rice stuff suggested and I haven't touched it since. It is currently residing in a bag of rice. But because I thought it was ok I had tried to turn it back on before putting it in rice and all I kept getting was a silver apple sign on a black screen and I have no idea what that means. I know from reading discussions that I should have turned it off and left it but like I said I thought it was fine because it carried on working after the incident....... Please help! Any thoughts? The battery is probably dead but do I dare plug it in? And what about the silver apple? Any help gratefully received, I feel lost without it!! :)
You need to find an Apple authorized Service Center and have it checked out. Very likely that running it prior to completely drying it out fried something (other than the battery).
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AAhmad
iPhone 4s
iOS8
Phone will not turn on after liquid spill on it
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HI ,We would like to ask you to help us with the following problem
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Regards
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This is what you can do and it will work. I found the info I had used the last time I had the same problem.
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Now click the Clear now button.
Further information can be found in the Clear your cache, history and other personal information in Firefox article. -
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Good luck. -
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Could you help me with this problem ?
Here's my code :
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Map fontAttributes = new HashMap();
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The API for TextAttribute describes WEIGHT_ULTRAWEIGHT as
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This bug (http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=4920831)
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Hello, im new here, and im a new java student.
i've written a program. however, the program asks the user a question, the user needs to answer either 1 or 2. i need the program to ask the question as long as the user doesnt enter 1 or 2. so if the user enters "2365" or "addasda" it will ask the question again.
this is the main class:
import java.util.Random;
public class Game
private String name;
private String answer;
private int numMarbles;
private int marblesTaken;
private int pcMarblesTaken;
int exit;
int exit2;
public Game(String name)
this.name = name;
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// if(exit==1)
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if(exit2 == 1 || exit2==2)
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import java.util.Random;
import java.util.Scanner;
public class GameTester
public static void main (String [] args)
Scanner input = new Scanner(System.in);
int exit;
do
System.out.print("what is your name: ");
String name = input.next();
Game howdy = new Game(name);
int exit2;
do
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exit2 = input.nextInt();
while(howdy.goodInput());
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if(exit2==1)
Random random = new Random();
int min = 10;
int max = 100;
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while(numMarbles > 1)
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int marblesTaken = input.nextInt();
numMarbles = numMarbles - marblesTaken;
System.out.println("the number of marbles left is " + numMarbles);
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Random random = new Random();
int min = 10;
int max = 100;
int diff = max - min + 1;
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while(numMarbles > 1)
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numMarbles = numMarbles - pcMarblesTaken;
System.out.println("the number of marbles left is: " + numMarbles);
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System.out.print("How many marbles you want to remove? ");
int marblesTaken = input.nextInt();
numMarbles = numMarbles - marblesTaken;
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if (numMarbles==1)
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System.out.println("It is now the computer's turn");
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exit = input.nextInt();
while(exit==1);
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How do i make the program ask the question
System.out.println("Hello " + howdy.getName() + " Do you want to go first? (1)Yes, (2)No");as long as the user enters the correct answer.
so if they enter "adsdds" or "45" it will repeat the question again.
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