Help me on message mapping

Question

Hello,
Plzz help me how do i map if below condition arise.
REFAJ123
REFCD432
here REF is Record  with 2 fields 1)REF01  2)REF02
I want to  mapping this REF record to output side record. 
Query is:   If REF01 field is AJ then i need to map REF02 field(123)  is to be map output side field. else ignore that record.
Output,
I need only value of 123 beacause( REF01 has value AJ) i dont want below REF data in Output.
Thanks,
Singh.

Answer 1

Ok fine,
Spend 5 more minutes for this.
In input file i am getting REF record 3 times.
i.e. REFCR!23
REFAJ234
REFDF345
IN output side Record has 2 field REC1 and REC2
I need output in Record REC1 has value = AJ
REC2 has value = 234.
I dont want to display 1 and 3 REF records in output.
Now in the same UDF do these things.
1. Change the code in UDF as
for(int i=0;i<REF01.length;i++)
if(REF01<i>.equals("AJ"))
result.addValue(REF02<i>);
2.in mapping change the context of REF01 and REF02 to message type.(top of records)
Right click on the REF01 and change the context on editor... same for REF02.
3.Now when mapping to Record, i.e
IN output side Record has 2 field REC1 and REC2
take REF01 and REF02 as input to UDF and out put of UDF to the Record(Target node)
Note:change context of REF01 and REF02 to message type.
2.When map to REC2...
take REF01 and REF02 as input to UDF and out put of UDF to the REC1(Target Element)
Note:Change the context here also as above.
3.When map to REC1
take REF01 and a REF01 as input to UDF and out put of UDF to the REC2(Target Element)
Note:Change the context here also as above.
Yes u r correct: when u r mapping to REC2.. u r giving REF01 as both inputs... it's just a work around.
Now Test the mapping..
This should work....
If still prblm do post..
Babu