Help needed in Sql developer

Hi All,
I installed oracle 11g release 2 in windows 7 . but when i tried to use sql developer , i got a pop up message like Enter the pathname for java.exe. please advise how to tackle this

provide path of java.exe
If you are asked to enter the full pathname for java.exe, click Browse and find java.exe. For example, the path might have a name similar to C:\Program Files\Java\jdk1.5.0_06\bin\java.exe. "

Similar Messages

  • Help with starting sql developer

    Hi everyone
    I have had oracle express and sql developer on my laptop before untill my hard drive went, now iv installed them again but when I start sql developer I make a new connection then go to create a new user, but when I click create new user, there is no list under the "Roles" tab as there should be, its just a blank grey screen. Has anyone had this problem before who might be able to help?
    I am kind of in a rush because I need it for a college assesment on monday so any help will be really appreciated:)
    Thanks
    Ryan

    Welcome to the forum!
    Whenever you post you need to provide the full sql developer that you are using and all of the details about what you are doing and the problem you are having.
    You haven't provided the version, what user you are connnecting as, what type of connection it is (normal, sysdba), the type of connection you are connecting as (thin, oci), the JDBC jar version if using one, the Oracle client or server versions.

  • Help Needed in SQL QPAC

    Hi there,
    I need some help regarding the SQL QPAC which is a built in QPAC in Adobe Livecycle Workflow. The SQL QPAC takes MYSQL as the default database. Suppose if we need to connect to the SQL Server or any other database, what is the procedure to do that.
    Suraj

    Hi Suraj
    You need to deploy a second copy of the SQL QPAC, and point it at a different datasource. The datasource is defined as a deployment parameter (it will prompt you when you deploy the new version of the qpac).
    You will also need to define the datasource in your application server. This is done in different ways for different application servers - for details, please see: standards_based_qpacs.pdf (part of the Workflow SDK), page 12, "Creating a JNDI datasource".
    Alternately, you can try out our SQLPlus QPAC. This allows you to directly specify connection url, driver, username and password. The SQLPlus QPAC does a lot of other things that the regular SQL QPAC doesn't do, such as handling multiple rows, testing your query, and outputting the data in a variety of ways.
    Details at: http://www.avoka.com/avoka/qpac_library.shtml
    Howard

  • Help in installing Sql Developer

    Hello gdmrng to all
    am very much interested in oracle and now going to take ocp.i want to install Oracle Sql developer 3.0 on my windows 7. i download it from OTN.But i dont how to make a new connection on it. In new connection i give these details
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    Username: hr
    Password: <password>
    Hostname: localhost
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    SID: <?????>
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    Helios, IMO you've moved this thread too quickly. The issue really isn't with sqldev, but with the DB installation, so it should go to the Installation forum instead (Database Installation

  • Which Java download needed for SQL Developer

    I am running Windows 7 Professional, (64) and have downloaded and unzipped sqldeveloper64-3.2.20.09.87-no-jre.zip. When I execute sqldeveloper.exe I enter this path to the Java JDK: C:\Program Files (x86)\Java\jdk1.6.0_37\bin\java.exe and a message responds:
    Oracle SQL Developer
    Unable to launch the Java Virtual Machine Located at path C:\Program Files (x86)\Java\jdk1.6.0_37\bin\msvcr71.dll
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    The jdk I installed: jdk-6u37-windows-i586.exe.
    I would have hoped that Oracle bundled the SQLDev with the Java.
    Your help would be much appreciataed.
    Edited by: user606303 on Nov 30, 2012 2:34 PM
    Edited by: user606303 on Nov 30, 2012 2:35 PM

    Hi,
    I would have hoped that Oracle bundled the SQLDev with the Java.Note that the very first download offered is Windows 32-bit - zip file includes the JDK1.6.0_35 (also 32-bit). See here...
    http://www.oracle.com/technetwork/developer-tools/sql-developer/downloads/index.html
    Since you opted to
    downloaded and unzipped sqldeveloper64-3.2.20.09.87-no-jre.zipyou are expected to specify a 64-bit JDK, which gets installed to
    C:\Program Files\Java\jdk1.6.0_37\binrather than
    C:\Program Files (x86)\Java\jdk1.6.0_37\binThe basic rules:
    1. 32-bit JDK/App on 32-bit Windows;
    2. 32-bit JDK/App (runs under WoW64) or 64-bit Java/App on 64-bit Windows.
    Regards,
    Gary
    SQL Developer Team

  • VCM installation help needed on SQL DB and Reporting server

    Hi All,
    I'm new to VCM and now i got stuck at the SQL DB and Report server portion.
    I'm running the vcm server on VM and the SQL is a physical server, both are sitting on the same LAN.
    I have create the SQL DB but VCM just fail to validate the DB and report server.
    I login to VCM using a Domain account for installation, and i tried to testing the DB using ODBC from the window, result fail.
    Error message as attach.
    I'm now totally lost on SQL portion.
    My Question:
    Is there any configuration needed on SQL DB?
    How to get the reporting server to working?
    What port is needed to it all working??
    VCM server Ms Win2012.
    SQL version 2012.
    Many thanks to all who reply.

    Hi Simonhoo79,
    For SSRS,   first check whether the report server link is accessible from your browser : "http://s01-fes-vcm1:80/ReportServer" . If you continue to get 404 error there also, then you need to reconfigure you report server first before proceeding to vcm installation. Follow the steps on below link on how to reconfigure report server using report services configuration Manager for 404 error.
    http://social.msdn.microsoft.com/Forums/sqlserver/en-US/75910bcb-a879-4eb7-9757-acc45201fa3a/can-not-connect-to-reportserver-http-404-file-not-found?forum=sqlexpress
    For SQL server ODBC connection,
    Dont create ODBC connection for SQL Native Client. Create ODBC connection for SQL Server.
    1. Open ODBC Data Source Administrator
    2. Click User DSN tab and Click Add button.
    3. Select SQL server and click finish
    4. Give name and description and Give the SQL server name (with instance name if your using named instance) or IP in the Server text box.
    5. Click Next and select either Windows authentication or sql authentication based on your SQL server authentication mode and click next.
    6. If the details given are correct then it will proceed further and  check "Change the dafault database to" to your VCM database
    7. Click next and finish and try test data source.
    VCM 5.7.2 and below will support installation only on windows server 2008 R2  and it doesn't support windows server 2012  but it support both 2008 and 2012 sql servers.

  • Help needed for SQL query

    hello ,
    I am a beginner in terms of writing sql queries. I hope some body can help me out.
    I have two tables
    mysql> desc user_group_t;
    ---------------------------------------------------+
    | Field | Type | Null | Key | Default | Extra |
    ---------------------------------------------------+
    | userAccountId | char(8) | | PRI | | |
    | groupId | char(8) | | PRI | | |
    ---------------------------------------------------+
    2 rows in set (0.00 sec)
    mysql> desc group_t;
    ---------------------------------------------------+
    | Field | Type | Null | Key | Default | Extra |
    ---------------------------------------------------+
    | id | char(8) | | PRI | | |
    | name | char(50) | YES | | NULL | |
    | email | char(100) | YES | | NULL | |
    | description | char(254) | YES | | NULL | |
    | parentId | char(8) | YES | | NULL | |
    | creatorId | char(8) | YES | | NULL | |
    | createDate | char(20) | YES | | NULL | |
    | updateDate | char(20) | YES | | NULL | |
    | updatorId | char(8) | YES | | NULL | |
    ---------------------------------------------------+
    9 rows in set (0.00 sec)
    what I want is list of all groups with id,name and #of members(which is the # of rows in the user_group_t for any given id). Importantly I need the groups with 0 members also to be listed. In short my output should contain exactly the same number of rows as in group_t table with an additional column indicating # of members for that group.
    Any help would be greatly appreciated.
    Thanks in Advance.
    -Vasanth

    Thanks Donald,
    Actually I figured it out, with the following query:
    select id,name,sum(if(groupid is not null,1,0)) as members from group_t left join user_group_t on id=groupid group by id;
    I tried your solution, but mysql says there is an error at '+' . Anyway I modified your solution to the one below and it worked.
    select a.id, a.name, count(b.groupid) from group_t a left join user_group_t b on a.id=b.groupid group by a.id, a.name;
    I tried that before but then I used Count(*) instead of count on groupid. Your solution is elagant and I will go with yours.
    Thanks again.
    Vasanth

  • Help Needed In SQL Query

    HI All,
    Oracle sql clarification required
    Sample Table:
    empno empname Job mgr_id hire_date salary deptno
    7788 SCOTT ANALYST 7566 19-APR-87 3000 20
    7902 FORD ANALYST 7566 03-DEC-81 3000 20
    7934 MILLER CLERK 7782 23-JAN-82 1300 10
    7900 JAMES CLERK 7698 03-DEC-81 950 30
    7369 SMITH CLERK 7902 17-DEC-80 800 20
    7876 ADAMS CLERK 7788 23-MAY-87 1100 20
    Need "single / one" sql for this requirement statement:
    There will be 2 drop down boxes (1st - Job list, 2nd - empno) in the form in which the following result set is expected
    1) When user selects value from 1st drop down box (job) as "ANALYST" leaving the second drop down unselected, the result expected is 2 (no. of rows for that job)
    2) When user selects value from 1st drop down box (job) as "ANALYST" and the value from 2nd drop down box as 7902, the result expected is 1 (no of rows for that job and empno)
    Sqls which I have tried from my side (given below) didn't give the expected result and please do help me in correcting this
    select count(1) from scott.emp where job='ANALYST' and ( empno = :empno or empno is null ) ;
    Please help for this requirement. Any help is deeply appreciated.
    Thanks
    Zaheer

    Hi,
    welcome to the forum.
    Please read SQL and PL/SQL FAQ
    When you put some code or output please enclose it between two lines starting with {noformat}{noformat}
    i.e.:
    {noformat}{noformat}
    SELECT ...
    {noformat}{noformat}
    For your question the following will both work:SQL> select * from emp
    where job='ANALYST' and (empno =:empno or :empno is null)
    EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    7788 SCOTT ANALYST 7566 19/04/1987 00:00:00 3000 20
    7902 FORD ANALYST 7566 03/12/1981 00:00:00 3000 20
    2 rows selected.
    SQL> select * from emp
    where job='ANALYST' and empno =NVL(:empno, empno)
    EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    7788 SCOTT ANALYST 7566 19/04/1987 00:00:00 3000 20
    7902 FORD ANALYST 7566 03/12/1981 00:00:00 3000 20
    2 rows selected.
    Regards.
    Al                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                           

  • Help needed in SQL statement

    Hi,
    From the SQL statement below, i need help in explaining what does the line "WHERE ( lims_sys.result.result_template_id = lims_sys.result_template_limit.result_template_id (+))" do?
    This statement was written by a vendor and now i have problem displaying some new data. Only a portion of what i need is displayed.
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    "LIMS_SYS"."RESULT"."CONCLUSION",
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    FROM "LIMS_SYS"."RESULT",
    "LIMS_SYS"."RESULT_TEMPLATE_LIMIT",
    "LIMS_SYS"."RESULT_USER",
    "LIMS_SYS"."ALIQUOT",
    "LIMS_SYS"."SAMPLE",
    "LIMS_SYS"."SDG",
    "LIMS_SYS"."TEST"
    WHERE ( lims_sys.result.result_template_id = lims_sys.result_template_limit.result_template_id (+)) and
    ( "LIMS_SYS"."RESULT"."RESULT_ID" = "LIMS_SYS"."RESULT_USER"."RESULT_ID" ) and
    ( "LIMS_SYS"."SDG"."SDG_ID" = "LIMS_SYS"."SAMPLE"."SDG_ID" ) and
    ( "LIMS_SYS"."SAMPLE"."SAMPLE_ID" = "LIMS_SYS"."ALIQUOT"."SAMPLE_ID" ) and
    ( "LIMS_SYS"."ALIQUOT"."ALIQUOT_ID" = "LIMS_SYS"."TEST"."ALIQUOT_ID" ) and
    ( "LIMS_SYS"."TEST"."TEST_ID" = "LIMS_SYS"."RESULT"."TEST_ID" ) and
    ( ( LIMS_SYS."SDG"."SDG_ID" = :sdg_id ) AND
    ( LIMS_SYS."RESULT"."STATUS" <> 'X' ) AND
    ( LIMS_SYS."RESULT"."REPORTED" = 'T' ) AND
    ( LIMS_SYS."RESULT_USER"."U_RESULT_CATEGORY" in ( 'Metal' , 'Mean Metal', 'Range Metal')) )
    Thanks for all your help.

    Hi,
    After WHERE .......... is indicates an OUTER Join condition.
    In this type of join, system retrieves the data for matched and
    as well as unmatched.
    Example:
    EMP table have a column DEPTNO with the data 10, 20, 30 (total rows=14)
    DEPT table have a column DEPTNO with the data 10, 20, 30, 40, 50 (total rows=5)
    If the WHERE clause contained EMP.DEPTNO(+) = DEPT.DEPTNO
    then the output contain the data relative to 10, 20, 30, 40, 50 (total rows = 16)
    i.e. 14 rows (with matching data) and 2 rows (with unmatching data)
    Regards,
    Sailaja

  • Expert Help needed with Sql Loader !

    Hello Friends...I am using one .dat file that contains several values in a
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    You're asking sql*load to perform an unnatural act.
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    Your batch script calls sql*load, then sql*plus to run the proc.
    Must simpler. sql*load is not a procedural language.

  • Help needed with sql long names

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  • Help needed on SQL

    Hi,
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    Interview questions? some basic queries to start with would be:
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  • Help need in sql

    i have a scenario like
    bank_division sum(amount) total_percentage(calculated by : / total sum of adjacent amounts i.e(10000+2000+3000+4000) *100
    aaaa 10000
    bbb 2000
    ccc 3000
    dddd 40000
    for above thing i have written sql like
    select bank_division,sum(amount)  from bank group by bank;
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    .its like for aaaa correspoding percentage will be
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    and for bbb it will be
    2000/ total sum of adjacent amounts i.e(10000+2000+3000+4000) *100
    so on...
    can any one help me how to write in single sql

    user632733 wrote:
    in your sql you are using lag to display from existing total_sal....which cant be possible in above scenario..??? Where did you see existing total_sal? EMP table:
    SQL> select deptno,ename,sal from emp
      2  /
        DEPTNO ENAME             SAL
            20 SMITH             800
            30 ALLEN            1600
            30 WARD             1250
            20 JONES            2975
            30 MARTIN           1250
            30 BLAKE            2850
            10 CLARK            2450
            20 SCOTT            3000
            10 KING             5000
            30 TURNER           1500
            20 ADAMS            1100
        DEPTNO ENAME             SAL
            30 JAMES             950
            20 FORD             3000
            10 MILLER           1300
    14 rows selected.
    SQL> As you can see, there are multiple employees in each department. Now look at mu solution. Inner select:
             select  deptno,
                     sum(sal) total_sal
               from  emp
               group by deptnosummarizes sal for each department. If you run it separately:
    SQL>          select  deptno,
      2                   sum(sal) total_sal
      3             from  emp
      4             group by deptno
      5  /
        DEPTNO  TOTAL_SAL
            30       9400
            20      10875
            10       8750
    SQL> Outer select calculates previous department total salary and its ratio to report.
    SY.
    P.S. And if you want to display individual employees along with department level summarization:
    select  deptno,
            ename,
            total_sal,
            prev_deptno,
            last_value(total_sal) over(order by deptno range between unbounded preceding and 1 preceding) prev_dept_total_sal,
            ratio_to_report(total_sal) over () * 100
      from  (
             select  deptno,
                     ename,
                     sum(sal) over(partition by deptno) total_sal,
                     max(deptno) over(order by deptno range between unbounded preceding and 1 preceding) prev_deptno
               from  emp
      order by deptno
        DEPTNO ENAME       TOTAL_SAL PREV_DEPTNO PREV_DEPT_TOTAL_SAL RATIO_TO_REPORT(TOTAL_SAL)OVER()*100
            10 MILLER           8750                                                           6.38569604
            10 KING             8750                                                           6.38569604
            10 CLARK            8750                                                           6.38569604
            20 ADAMS           10875          10                8750                           7.93650794
            20 FORD            10875          10                8750                           7.93650794
            20 JONES           10875          10                8750                           7.93650794
            20 SMITH           10875          10                8750                           7.93650794
            20 SCOTT           10875          10                8750                           7.93650794
            30 WARD             9400          20               10875                           6.86006203
            30 TURNER           9400          20               10875                           6.86006203
            30 ALLEN            9400          20               10875                           6.86006203
        DEPTNO ENAME       TOTAL_SAL PREV_DEPTNO PREV_DEPT_TOTAL_SAL RATIO_TO_REPORT(TOTAL_SAL)OVER()*100
            30 JAMES            9400          20               10875                           6.86006203
            30 BLAKE            9400          20               10875                           6.86006203
            30 MARTIN           9400          20               10875                           6.86006203
    14 rows selected.
    SQL>

  • Help needed in sql

    Hi,
    I am getting the filename as below and i want to extract some part of the string with the filename and the output need as below
    FileName : THE_PK_SOURCE_CLASS0002_PKID5403_20130603_342342.txt 
    Output:
    ======
    5403-THE_PK_SOURCE_CLASS0002_PKID5403
    Please help me in advance
    Thx,

    That's easy. Just mark the last two parts asa optional ({0,2})
    with data as (
    select 'THE_PK_SOURCE_CLASS0002_PKID5403_20130603_342342.txt' str from dual
    union all
    select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403_20130603_342342.txt' from dual
    union all
    select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403_1222.txt' from dual
    union all
    select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403.txt' from dual
    union all
    select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403_132.txt' from dual
    union all
    select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403_20130603_342342.txt' from dual
    select
    -- all from the start to and including the last hyphen is cut off
    regexp_replace(str, '^(.+-)?([^-]+?)(\d+)(_\d+){0,2}\.txt$', '\3-\2\3') str
    from data
    from data
    STR
    5403-THE_PK_SOURCE_CLASS0002_PKID5403
    5403-THE_PK_SOURCE_CLASS0002_PKID5403
    5403-THE_PK_SOURCE_CLASS0002_PKID5403
    5403-THE_PK_SOURCE_CLASS0002_PKID5403
    5403-THE_PK_SOURCE_CLASS0002_PKID5403
    5403-THE_PK_SOURCE_CLASS0002_PKID5403
    Message was edited by: chris227 Changed to the simplified version, but it's the same for the "corrected" veriosn too.

  • Help needed in SQL Loader

    Hi,
    Am using SQL Loader to insert rows in a table.
    I have 5 cols in table A. But the data is not present in all cols always.
    Have used TRAILING NULLCOLS but with no help.. few rows are inserted and for many others it throws "ORA-01841: (full) year must be between -4713 and +9999, and not be 0" error
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    FYI -
    CONTROL FILE
    load data
    infile '/home/krkanth/test_spam_20070513.dat'
    BADFILE 'sample.bad'
    DISCARDFILE 'sample.dsc'
    into table spam_rule_stats
    fields terminated by "\t"
    optionally enclosed by '"'
    TRAILING NULLCOLS
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    RULE_START_DATE DATE 'yyyymmdd hh24:mi:ss',
    RULE_END_DATE date 'yyyymmdd hh24:mi:ss',SOURCE)
    Am getting error Rejected - Error on table SPAM_RULE_STATS, column RULE_END_DATE.
    ORA-01841: (full) year must be between -4713 and +9999, and not be 0
    SAMPLE DATA
    20070513 RULE SENDER [email protected] 534 20070214 22:02:56
    SnA_ALERTS
    20070513 RULE SENDER [email protected] 6 20070503 21:19:36 200
    70518 21:19:36 RULE_EXTENSIONS
    20070513 RULE SENDER [email protected] 519 20061105 05:40:44 SnA
    _ALERTS
    20070513 RULE SENDER [email protected] 332 20070509 02:44:51 20070524 02
    :44:51 JASD_HP_AUTOREJECT
    20070513 RULE SENDER [email protected] 928 20070512 14:49:14 20070527 14:49:14 JAS
    D_HP_AUTOREJECT
    20070513 RULE SENDER [email protected] 19875 20070507 22:30:01 20070522 22
    :30:01 RULE_EXTENSIONS
    20070513 RULE SENDER [email protected] 3 20070509 09:08:38 20070524 09:08:38
    JASD_HP_AUTOREJECT
    20070513 RULE SENDER [email protected] 10 20070503 21:19:36 200
    70518 21:19:36 RULE_EXTENSIONS
    20070513 RULE SENDER [email protected] 4 20070506 04:39:48 20070521 04
    :39:48 JASD_HP_AUTOREJECT
    Thanks.

    not sure if this will work but you may want to give it a try:
      change from:
        (MAIL_DATE date 'yyyymmdd hh24:mi:ss'
      to:
        (MAIL_DATE date 'yyyymmdd'since the first data on your file does not have the timestamps

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  • Duplicate keys handling

    I come across a problem when handling duplicate keys retrieved from query result. It is not hard I believe, but I can not find solution the problem is: I have a query that will retrieve the rows like structure product_A, aaa product_A, bbb product_A,