Help with Plsql

Question

I have a table which has employee_id, win_date, department
I need to find all employees within departments '1A', '3B' , '2A' , '2C' with their individual highest win_date and their win_date < '29-oct-2010'
If an employee has their max dates same for 2 different departments I need to pick the order as listed above. For eg. if emp_id 2 has '10/28/2010' for 3B and '10/28/2010' for 2C I would need to list 3B and not 2C.
Create table temp_emp
emp_id varchar2(5 byte),
win_date date,
department varchar2(2 byte)
insert into temp_emp
values('1','15-oct-2010', '2B');
insert into temp_emp
values('1','10-oct-2010', '3B');
insert into temp_emp
values('2','28-oct-2010', '3B');
insert into temp_emp
values('2','28-oct-2010', '2C');
insert into temp_emp
values('2','15-oct-2010', '1A');
insert into temp_emp
values('2','15-JUL-2010', '2B');
insert into temp_emp
values('3','16-oct-2010', '1A');
insert into temp_emp
values('3','19-oct-2010', '2C');
insert into temp_emp
values('4','15-JUN-2010', '2A');
insert into temp_emp
values('4','15-JUN-2010', '2B');
insert into temp_emp
values('4','12-oct-2010', '2C');
The final result should be
'1' '10-oct-2010' '3B'
'2' '28-oct-2010' '3B'
'3' '19-oct-2010' '2C'
'4' '12-oct-2010' '2C'
Thanks

Answer 1

with temp_emp as
select '1' emp_id,to_date('15-10-2010','DD-MM-YYYY') win_date, '2B' department from dual union all
select '1',to_date('10-10-2010','DD-MM-YYYY'), '3B' from dual union all
select '2',to_date('28-10-2010','DD-MM-YYYY'), '3B' from dual union all
select '2',to_date('28-10-2010','DD-MM-YYYY'), '2C' from dual union all
select '2',to_date('15-10-2010','DD-MM-YYYY'), '1A' from dual union all
select '2',to_date('15-07-2010','DD-MM-YYYY'), '2B' from dual union all
select '3',to_date('16-10-2010','DD-MM-YYYY'), '1A' from dual union all
select '3',to_date('19-10-2010','DD-MM-YYYY'), '2C' from dual union all
select '4',to_date('15-06-2010','DD-MM-YYYY'), '2A' from dual union all
select '4',to_date('15-06-2010','DD-MM-YYYY'), '2B' from dual union all
select '4',to_date('12-10-2010','DD-MM-YYYY'), '2C' from dual
select emp_id
      ,max(win_date) keep (dense_rank last order by decode(department,'1A',4,'3B',3,'2A',2,'2C',1,0) asc , win_date asc ) win_date
      ,max(department) keep (dense_rank last order by decode(department,'1A',4,'3B',3,'2A',2,'2C',1,0) asc ) department     
from temp_emp
group by emp_id;You would retrieve the same result with:
select emp_id
      ,max(win_date) keep (dense_rank last order by decode(department,'1A',1,'3B',2,'2A',3,'2C',4,5) desc , win_date asc ) win_date
      ,max(department) keep (dense_rank last order by decode(department,'1A',1,'3B',2,'2A',3,'2C',4,5) desc ) department     
from temp_emp
group by emp_id;I come to a different result for employees 2,3 and 4, because 1A comes before 3B and 2A comes before 2C in your list:
result:
1     10.10.10     3B
2     15.10.10     1A
3     16.10.10     1A
4     15.06.10     2AEdited by: hm on 11.11.2010 06:42