Hiding Files with Java

Hi all. I'm trying to hide files (in Windows) using Java. The java.io.File class doesn't seem to have any facilities for changing file attributes in Windows.
The only solutions that occur to me are to use WScript or to use a batch file with attrib. Does anyone know a way to set files to hidden from within the JVM?
Thanks!
Daniel

Use JNI to call a method written in C?

Similar Messages

I can't open or save file with Java Web Start

Hi,
i can't open or save file with Java Web Start:
import java.io.*;
import java.util.*;
public class MetaDataFileCreator {
public String fileNameSpace = null;
public String fileName = null;
protected Properties file = null;
public MetaDataFileCreator(String fileNameSpace, String fileName) {
this.fileNameSpace = fileNameSpace;
this.fileName = fileName;
public void createMetaDataFile() {
try {
System.out.println("file METADATA");
ClassLoader cl = this.getClass().getClassLoader();
String nameFileMetaData = fileNameSpace + fileName + ".txt";
FileOutputStream fileOS = new FileOutputStream(cl.getResource(nameFileMetaData).getFile());
file = new Properties();
file.setProperty("aaaaa", "aaaa");
file.store(fileOS, "");
fileOS.close();
} catch (Exception e) {
System.out.println("Error writing metadata-file: " + e);
System.exit(1);
e.printStackTrace();
I have try also to open a file like this:
ClassLoader cl = this.getClass().getClassLoader();
file.load(cl.getResourceAsStream(nameFile));
also like this:
try {
fos = (FileOpenService)ServiceManager.lookup("javax.jnlp.FileOpenService");
fss = (FileSaveService)ServiceManager.lookup("javax.jnlp.FileSaveService");
} catch (UnavailableServiceException e) {
fss = null;
fos = null;
System.out.println("Error with JNLP");
System.exit(1);
if (fss != null && fos != null) {
try {
// get a FileContents object to work with from the
// FileOpenService
FileContents fc = fos.openFileDialog(null, null);
//FileContents newfc2 = fss.saveAsFileDialog(null, null, fc);
// get the OutputStream and write the file back out
if (fc.canWrite()) {
// don't append
os = fc.getOutputStream(false);
} catch (Exception e) {
e.printStackTrace();
also like this:
File f = new File((System.getProperty("user.home")+"x.txt").toString());
FileOutputStream fileX = new FileOutputStream(f);
OutputX = new PrintWriter(new BufferedWriter(new OutputStreamWriter(fileX, "UTF8")));
OutputX.println(....
but it doesn't work with Java Web Start.
Can someone help me?
How can I open or save file?
thank you.
Sebastiano

Did you specify <all-permissions/> in your JNLP file? Did you sign your code? What error are you getting?

How to use parameter file with java

Is it possible to use a parameter file with Java, and is there any class/method to make it easy to call and use these parameter from a text file, other than scanning the whole text file manually as we can do normally with visual basic/c++, so we can call the program with the parameter file, like java testing c:\\testing.ini

If I understand you correctly, you may be looking for a properties file. This is basically a text file that contains pairs of strings in the form:
parameter1=value1
parameter2=value2
parameter3=value3
...etc.
and the values are retrieved using the java.util.Properties class - see:
http://java.sun.com/j2se/1.3/docs/api/java/util/Properties.html
Sample use://Call chis method once, to load the props file.
//props file is called "demo.properties", and is
//in a directory that is included in the classpath
    private void loadMyProperties() throws Exception
     InputStream stream = getResourceAsStream("/demo.properties");
     if(stream == null)
         throw new Exception("stream is null!");
     demoProperties = new Properties();
     demoProperties.load(stream);
     stream.close();
// Then you can retrieve properties in your code using:
String param3 = demoProperties.getProperty("parameter3");
//...etc

Can't create log file with java.util.logging

Hi,
I have created a class to create a log file with java.util.logging
This class works correctly as standalone (without jdev/weblogic)
import java.io.IOException;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.logging.*;
public class LogDemo
     private static final Logger logger = Logger.getLogger( "Logging" );
     public static void main( String[] args ) throws IOException
         Date date = new Date();
         DateFormat dateFormat = new SimpleDateFormat("yyyyMMdd");
         String dateStr = dateFormat.format(date);
         String logFileName = dateStr + "SEC" + ".log";
         Handler fh;
         try
           fh = new FileHandler(logFileName);
           //fh.setFormatter(new XMLFormatter());
           fh.setFormatter(new SimpleFormatter());
           logger.addHandler(fh);
           logger.setLevel(Level.ALL);
           logger.log(Level.INFO, "Initialization log");
           // force a bug
           ((Object)null).toString();
         catch (IOException e)
              logger.log( Level.WARNING, e.getMessage(), e );
         catch (Exception e)
              logger.log( Level.WARNING, "Exception", e);
}But when I use this class...
import java.io.File;
import java.io.IOException;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.logging.FileHandler;
import java.util.logging.Handler;
import java.util.logging.Level;
import java.util.logging.Logger;
import java.util.logging.XMLFormatter;
public class TraceUtils
public static Logger logger = Logger.getLogger("log");
public static void initLogger(String ApplicationName) {
    Date date = new Date();
    DateFormat dateFormat = new SimpleDateFormat("yyyyMMdd");
    String dateStr = dateFormat.format(date);
    String logFileName = dateStr + ApplicationName + ".log";
    Handler fh;
    try
      fh = new FileHandler(logFileName);
      fh.setFormatter(new XMLFormatter());
      logger.addHandler(fh);
      logger.setLevel(Level.ALL);
      logger.log(Level.INFO, "Initialization log");
    catch (IOException e)
      System.out.println(e.getMessage());
}and I call it in a backingBean, I have the message in console but the log file is not created.
TraceUtils.initLogger("SEC");why?
Thanks for your help.

I have uncommented this line in logging.properties and it works.
# To also add the FileHandler, use the following line instead.
handlers= java.util.logging.FileHandler, java.util.logging.ConsoleHandlerBut I have another problem:
jdev ignore the parameters of the FileHandler method .
And it creates a general log file with anothers log files created each time I call the method logp.
So I play with these parameters
fh = new FileHandler(logFileName,true);
fh = new FileHandler(logFileName,0,1,true);
fh = new FileHandler(logFileName,10000000,1,true);without succes.
I want only one log file, how to do that?

Problem unzipping larger files with Java

When I extract small zip files with java it works fine. If I extract large zip files I get errors. Can anyone help me out please?
import java.io.*;
import java.util.*;
import java.net.*;
import java.util.zip.*;
public class updategrabtest
     public static String filename = "";
     //public static String filesave = "";
    public static boolean DLtest = false, DBtest = false;
     // update
     public static void main(String[] args)
          System.out.println("Downloading small zip");
          download("small.zip"); // a few k
          System.out.println("Extracting small zip");
          extract("small.zip");
          System.out.println("Downloading large zip");
          download("large.zip"); // 1 meg
          System.out.println("Extracting large zip");
          extract("large.zip");
          System.out.println("Finished.");
          // update database
          boolean maindb = false; //database wasnt updated
     // download
     public static void download (String filesave)
          try
               java.io.BufferedInputStream in = new java.io.BufferedInputStream(new
               java.net.URL("http://saveourmacs.com/update/" + filesave).openStream());
               java.io.FileOutputStream fos = new java.io.FileOutputStream(filesave);
               java.io.BufferedOutputStream bout = new BufferedOutputStream(fos,1024);
               byte data[] = new byte[1024];
               while(in.read(data,0,1024)>=0)
                    bout.write(data);
               bout.close();
               in.close();
          catch (Exception e)
               System.out.println ("Error writing to file");
               //System.exit(-1);
     // extract
     public static void extract(String filez)
          filename = filez;
        try
            updategrab list = new updategrab( );
            list.getZipFiles();
        catch (Exception e)
            e.printStackTrace();
     // extract (part 2)
    public static void getZipFiles()
        try
            //String destinationname = ".\\temp\\";
            String destinationname = ".\\";
            byte[] buf = new byte[1024]; //1k
            ZipInputStream zipinputstream = null;
            ZipEntry zipentry;
            zipinputstream = new ZipInputStream(
                new FileInputStream(filename));
            zipentry = zipinputstream.getNextEntry();
               while (zipentry != null)
                //for each entry to be extracted
                String entryName = zipentry.getName();
                System.out.println("entryname "+entryName);
                int n;
                FileOutputStream fileoutputstream;
                File newFile = new File(entryName);
                String directory = newFile.getParent();
                if(directory == null)
                    if(newFile.isDirectory())
                        break;
                fileoutputstream = new FileOutputStream(
                   destinationname+entryName);
                while ((n = zipinputstream.read(buf, 0, 1024)) > -1)
                    fileoutputstream.write(buf, 0, n);
                fileoutputstream.close();
                zipinputstream.closeEntry();
                zipentry = zipinputstream.getNextEntry();
            }//while
            zipinputstream.close();
        catch (Exception e)
            e.printStackTrace();
}

In addition to the other advice, also change every instance of..
kingryanj wrote:
          catch (Exception e)
               System.out.println ("Error writing to file");
               //System.exit(-1);
..to..
catch (Exception e)
e.printStackTrace();
}I am a big fan of the stacktrace.

Executing a file with Java?

Hi,
I wanted to know how I could execute a file with java. Here are a couple scenarios - let's say I am developing an anti-spyware utility and I wanted to first write a batch file, and then create it in a folder, then run it when they click "Run". Then afterwards I want to shutdown their computer.
My Mindset:
- FileWriter to create the .bat and write the Batch commands.
- Execute the batch file.
- Execute the shutdown.exe file to reboot their PC.
So my simple question is, how can I execute a file?
Thanks!
-Josh

Well here is the code I have:
            try
                Runtime.getRuntime().exec("cmd.exe /c test.bat");
            catch(IOException e1)
                //NOTHING
            }Now my cmd.exe is obviously in my Windows System32 folder, and my "test.bat" file is in my C:\ root directory. So I am wondering why that wont execute. I tried a fer other things too like:
Runtime.getRuntime().exec("cmd.exe c:\test.bat");that didn't work either, because you can't have a "\" in a string...
So how can I get this thing to execute the batch file?

Is it possible to play .rm and .wma file with java?

Hello Friends,
Please tell me,
how to play .rm and .wma file with java?
Thanks,
Harsh Modha

As far as I know, you can not play those files.
Here you have the complete list of supported formats. Hope this helps.
http://java.sun.com/products/java-media/jmf/2.1.1/formats.html
Maybe you should try to convert from wma or rm to a supported format before attempting to play it.

Generation of Xml file with java output

Hi i m new to xml and java combination. I have a name value pair kind of output returning from java program. I want to generate the new xml file with the data. Could some one help me out in generating xml file with the data. Could anyone send me the java code that does this task.

Let me know which parser are you using currently for reading xml files so that i assist you. For now, you can refer to STAX Parser API under this link
http://java.sun.com/webservices/docs/1.6/tutorial/doc/SJSXP3.html

[b]The challenge is on: Creating PowerPoint Files with Java[/b]

Hi, guys and geeks!!
I'm new here and generally not as skilled and talented as you guys -
that's why I am passing this challenge on to you:
I want to create a PowerPoint presentation using Java. (My Data will be in XML and I'll have to generate slides with Flow-Charts from that data)
1.
I know of only one commercial Library that seems to do this very comfortably. But it costs about $5000... (http://tonicsystems.com/) - have you used it?
2.
I know that I could use Apache's POI (http://jakarta.apache.org/poi/), as it gives me access to the MsOLE 2 compound doc. format, but their work is most developed only for Excel and Word. so I'm not sure what kind of obstracles I'd be facing....
3.
And then there is JAWIN (http://jawinproject.sourceforge.net/) which would enable me to call COM-Components... How would I do that?
Any other /better ideas?
So, please let me know your thoughts and if you know what I could do!
Also, please let me know how I should go about with it.....
I'm looking forward to seeing your "muscles" (i.e. knowledge) play...!
Cheers,
Anna ;o)

Hi i'm still working on my program to generate PowerPoint Files with Jawin. I'm trying to get the heght property on a row.
For example: rows(1).height
I can get rows. but not rows(1).
I got a jawin Exception on :
public int getRowHeight(int row) throws COMException
DispatchPtr rows;
int rowHeight;
DispatchPtr theRows = (DispatchPtr) this.getDispatchPtr().get("Rows",new Integer(1));
rowHeight = (Integer) theRows.get("Height");
return rowHeight;
Here is the stacktrace:
org.jawin.COMException: 80020003: Member not found.
at org.jawin.marshal.GenericStub.dispatchInvoke0(Native Method)
at org.jawin.marshal.GenericStub.dispatchInvoke(GenericStub.java:201)
at org.jawin.DispatchPtr.getN(DispatchPtr.java:248)
at org.jawin.DispatchPtr.get(DispatchPtr.java:194)
at pptpublisher.PPTTable.getRowHeight(PPTTable.java:117)
at pptpublisher.Main.main(Main.java:51)
Thanks for replying

How to read and parse a remote XML file with Java

Hi.
Using J2SE v1.4.2, I'd like to read and parse a remote file:
http://foo.com/file.xml
Is it possible with Java? I'd be extremely grateful if someone could provide me any webpage showing a very simple code.
Thank you very much.

How about the following?
     import java.io.InputStream;
     import java.net.URL;
     import javax.xml.parsers.DocumentBuilder;
     import javax.xml.parsers.DocumentBuilderFactory;
     import org.w3c.dom.Document;
     public static void main(String[] args) throws Exception {
          DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
          DocumentBuilder db = dbf.newDocumentBuilder();
          URL url = new URL("http://foo.com/file.xml");
          InputStream inputStream = url.openStream();
          Document document = db.parse(inputStream);
          inputStream.close();
     }-Blaise

Split XML in Multiple XML files with Java Code

Hi guys , i have following xml file as input ....
<?xml version="1.0" encoding="ISO-8859-1"?>
<T0020
xsi:schemaLocation="http://www.safersys.org/namespaces/T0020V1 T0020V1.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.safersys.org/namespaces/T0020V1">
<INTERFACE>
<NAME>SAFER</NAME>
<VERSION>04.02</VERSION>
</INTERFACE>
<TRANSACTION>
<VERSION>01.00</VERSION>
<OPERATION>REPLACE</OPERATION>
<DATE_TIME>2009-09-01T00:00:00</DATE_TIME>
<TZ>CT</TZ>
</TRANSACTION>
<IRP_ACCOUNT>
<IRP_CARRIER_ID_NUMBER>274845</IRP_CARRIER_ID_NUMBER>
<IRP_BASE_COUNTRY>US</IRP_BASE_COUNTRY>
<IRP_BASE_STATE>AR</IRP_BASE_STATE>
<IRP_ACCOUNT_NUMBER>55002</IRP_ACCOUNT_NUMBER>
<IRP_ACCOUNT_TYPE>I</IRP_ACCOUNT_TYPE>
<IRP_STATUS_CODE>100</IRP_STATUS_CODE>
<IRP_STATUS_DATE>2007-11-06</IRP_STATUS_DATE>
<IRP_UPDATE_DATE>2009-08-03</IRP_UPDATE_DATE>
<IRP_NAME>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>A P SUPPLY CO</NAME>
<IRP_ADDRESS>
<ADDRESS_TYPE>PH</ADDRESS_TYPE>
<STREET_LINE_1>1400 N OATS</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>TEXARKANA</CITY>
<STATE>AR</STATE>
<ZIP_CODE>71854</ZIP_CODE>
<COUNTY>MILLER</COUNTY>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
<IRP_ADDRESS>
<ADDRESS_TYPE>MA</ADDRESS_TYPE>
<STREET_LINE_1>P O BOX 1927</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>TEXARKANA</CITY>
<STATE>AR</STATE>
<ZIP_CODE>75504</ZIP_CODE>
<COUNTY/>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
</IRP_NAME>
</IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
and i want to take this xml file and split it into multiple files through java code like this ...
File1.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
File2.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
like wise...
Each xml file contain maximum 10 or 15 IRP_ACCOUNT.
Can somebody please help me ? How can i do it with stax like start element and all ?
thanks in advance.

Ah, sorry, strike that. You want multiple files. I think the easiest way is to simply parse with DOM. [http://www.w3schools.com/xpath/default.asp] . And here [http://www.w3schools.com/xpath/default.asp].
You can output the various XML elements using a PrintWriter or creating a separate DOM document for each file you want to create and serializing that.
- Saish

How can I encrypt files with java ?

I don't want others to see the content of my file.so,i try to encrypt the file.
but i don't know how to do .i think there may be two ways to do that .one is coding the file with some encrpytion tachniques .Another is try to add a locker to the file ,when someone try to read it ,the trigger is touched off.This trigger need you to input the password.
These are my granted think .but i don't how to do.if you know,can you please to share with me? Thank you!

The JCE is a cryptogrpahic framework for Java. There are numerous tutorials available on the web and a guide is avaiable at http://java.sun.com/j2se/1.4.2/docs/guide/security/jce/JCERefGuide.html .

Open files with java

Hi I'd like to know if there's a way that you can open a file that's been associated with your java app. I know how to read from a file and I know how to pass command line arguments but what I don't know is how to open my app with a file just by clicking it in my file browser. If needed i could settle for a Mac-specific and a Windows-specific method.

This is nothing to do with Java, and specific to the OS you're installing to. This question comes up quite regularly, from people who are under the impression it's the responsibility of their app to enforce the file association. It isn't. Your installation should ask users if they want the association made. Remember how annoying it is when something you've just installed takes over the file associations of another app, without asking? Don't do it, your users won't like it

Extracting file from a TAR file with java.util.zip.* classes

Is there a way to extract files from a .TAR file using the java.util.zip.* classes?
I tried in some ways but I get the following error:
java.util.zip.ZipException: error in opening zip file
at java.util.zip.ZipFile.<init>(ZipFile.java127)
at java.util.zip.ZipFile.<init>(ZipFile.java92)
Thank you
Giuseppe

download the tar.jar from the above link and use the sample program below
import com.ice.tar.*;
import java.util.zip.GZIPInputStream;
import java.io.*;
public class untarFiles
     public static void main(String args[]){
          try{
          untar("c:/split/20040826172459.tar.gz",new File("c:/split/"));
          }catch(Exception e){
               e.printStackTrace();
               System.out.println(e.getMessage());
     private static void untar(String tarFileName, File dest)throws IOException{
          //assuming the file you pass in is not a dir
          dest.mkdir();
          //create tar input stream from a .tar.gz file
          TarInputStream tin = new TarInputStream( new GZIPInputStream( new FileInputStream(new File(tarFileName))));
          //get the first entry in the archive
          TarEntry tarEntry = tin.getNextEntry();
          while (tarEntry != null){//create a file with the same name as the tarEntry
               File destPath = new File(
               dest.toString() + File.separatorChar + tarEntry.getName());
               if(tarEntry.isDirectory()){
                    destPath.mkdir();
               }else {
                    FileOutputStream fout = new FileOutputStream(destPath);
                    tin.copyEntryContents(fout);
                    fout.close();
               tarEntry = tin.getNextEntry();
          tin.close();
}

How to validate the Xml File With Java

Hi,
Can pls tell me. I want to validate the XML File for the Some Mandartory TAG. if that if Tag null i want to generate error xml file with error and i want move another folder with java. pls help me as soon as possible

Use a validating parser (any recent Xerces, for one) and switch on the validation feature. Very much vendor-specific, so look at the docs of your parser. Oh, you do have a schema for these documents, don't you?

Hiding Files with Java

Similar Messages

Maybe you are looking for