Hierarchical query: how to find out the root node

Hi to all.
I have a table with the following values:
user manager
Tom
John
Peter Tom
Steven Peter
Sean Peter
Jim John
Bill John
Ken Bill
So my hierachical query is as follow:
SELECT rpad(' ',(level-1)*3)||user as user_root, managerFROM My_Table
START WITH manager IS NULL
CONNECT BY manager = PRIOR user
ORDER SYBLINGS BY user
user_root manager
Tom
Peter Tom
Steven Peter
Sean Peter
John
Jim John
Bill John
Ken Bill
But I want also to know the top manager of each user. I want my output to be as follows:
user_root manager top_manager
Tom
Peter Tom Tom
Steven Peter Tom
Sean Peter Tom
John
Jim John John
Bill John John
Ken Bill Ken
Any hlp will be appreciated. Thanks a lot.
Regards, Beroetz

In 9i sys_connect_by_path can help:
SQL> select empno, ename, mgr
2 from emp
3 start with mgr is null
4 connect by prior empno = mgr
5 /
     EMPNO ENAME             MGR
      7698 BLAKE
      7499 ALLEN            7698
      7521 WARD             7698
      7654 MARTIN           7698
      7844 TURNER           7698
      7900 JAMES            7698
      7839 KING
      7566 JONES            7839
      7788 SCOTT            7566
      7876 ADAMS            7788
      7902 FORD             7566
      7369 SMITH            7902
      7782 CLARK            7839
      7934 MILLER           7782
14 rows selected.
SQL> select ename, mgr,
2 substr(sys_connect_by_path(ename,'/'),
3 2,instr(sys_connect_by_path(ename,'/'),'/',2)-2) top
4 from emp
5 start with mgr is null
6 connect by prior empno = mgr
7 /
ENAME             MGR TOP
BLAKE
ALLEN            7698 BLAKE
WARD             7698 BLAKE
MARTIN           7698 BLAKE
TURNER           7698 BLAKE
JAMES            7698 BLAKE
KING
JONES            7839 KING
SCOTT            7566 KING
ADAMS            7788 KING
FORD             7566 KING
SMITH            7902 KING
CLARK            7839 KING
MILLER           7782 KING
14 rows selected.Rgds.

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