Hierchies and hierchies node with customer exit?

hi friends,
what scenerio we use hierchies and hierchies node  variable with customer exit ?
Thanking u
suneel.

Hierarchy variables represent hierarchies. You can use them wherever
hierarchies can be selected.
Hierarchy node variables represent a node in a hierarchy. You can use them as
an alternative to hierarchy nodes as fixed values for restricting a characteristic.
If you use a hierarchy node variable, you can make selections by hierarchy
node when you use the query.
The Customer Exit processing type for variables enables you to determine
values for variables by means of a function module exit. The function
module used is EXIT_SAPLRRS0_001.
You create a project in transaction CMOD by selecting the SAP
enhancement RSR00001 and assigning this to the enhancement project.
Activate the project.
WHEN 'HIERARCHY'.   " Hierarchy variable
         CLEAR L_S_RANGE.
         L_S_RANGE-LOW  = 'MY HIERARCHY'. " hierarchy name
         L_S_RANGE-SIGN = 'I'.
         L_S_RANGE-OPT  = 'EQ'.
         APPEND L_S_RANGE TO E_T_RANGE.
-> Only dependents of hierarchy 'MY HIERARCHY'
      WHEN 'HNODE'.   " Hierarchy node variable
         CLEAR L_S_RANGE.
         L_S_RANGE-LOW  = 'DEPT1'.  " Node name
         L_S_RANGE-HIGH = '0HIER_NODE'.   " InfoObject
         L_S_RANGE-SIGN = 'I'.
         L_S_RANGE-OPT  = 'EQ'.
         APPEND L_S_RANGE TO E_T_RANGE.
-> Node 'DEPT1', that cannot be posted to
      WHEN 'HNODEVAL'.   " Hierarchy node variable
         CLEAR L_S_RANGE.
         L_S_RANGE-LOW  = 'LEAVE1'.  " node name (node is a leaf)
         L_S_RANGE-SIGN = 'I'.
         L_S_RANGE-OPT  = 'EQ'.
         APPEND L_S_RANGE TO E_T_RANGE.
-> Node 'LEAVE1' (leaf)
Regards
Naga

Similar Messages

  • No Query Result After Using Hierarchy Node Variable (Customer Exit)

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    Regards,
    Satria B Tandyono

    Hi Satria,
    Instead of following code ---
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    try this ---
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    ELSEIF loc_var_range-low EQ '000000000000040000'
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    l_s_range-low = 'MEZBUNITMPI'.
    ENDIF.
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  • Error while trying to Execute the Query with Customer Exit

    Hi Experts,
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    Hello Kris,
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  • Prob in text variable with customer exit

    Hi to all
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    Please help me to come out
    Thanks

    Hi Stefania,
    to me it looks like your local variable num_mese is not defined with the correct data type.
    Try to change
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    Stephan

  • Variable creation in bw with customer exit

    hi experts,
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    Hi
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  • Formula Variable with customer exit

    Hi,
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    Thanks
    kri

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                I_VARTYP        type RSZGLOBV-VARTYP
                I_IOBJNM        type RSZGLOBV-IOBJNM
                I_S_COB_PRO     type RSD_S_COB_PRO
                I_S_RKB1D       type RSR_S_RKB1D
                I_PERIV         type RRO01_S_RKB1F-PERIV
                I_T_VAR_RANGE   type RRS0_T_VAR_RANGE
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        l_s_range-low = l_minper  .
        APPEND l_s_range TO e_t_range.
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  • Formel Variable - how to fill with Customer Exit from control table

    Hello Experts,
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    Regards Dieter

    Hi,
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        LOOP AT I_T_VAR_RANGE INTO L_S_RANGE.
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        SELECT SINGLE RATE into INTO GV_RATE
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                  AND   0FISCVARNT = GV_ZFISCVARNT
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                          'ZVTYPE'. name of variable representing value type
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    Regards
    Mr Kapadia
    Assigning points is the way to say thanks in SDN.

  • Variable with customer exit

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    Thanks,
    Maya

    Hi,
    The variable may be personalized with some value.
    <b>To remove the personalization for a user:</b>
    Step 1: RSA1 -> Search for ODS 0PERS_VAR
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    http://help.sap.com/saphelp_nw04/helpdata/en/01/42c73c13b0ce5be10000000a114084/content.htm
    Regards
    Happy Tony

  • Characterstic variable with customer exit

    Can u some bady help me.
    How to express about Characterstic variable with customer exit
    Edited by: chenna reddy on Aug 7, 2008 9:48 PM

    Hi,
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    <b>To remove the personalization for a user:</b>
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    Step 2: Manage -> Contents ->selective deletion
    Step 3: Put the user to remove the personalization
    http://help.sap.com/saphelp_nw04/helpdata/en/01/42c73c13b0ce5be10000000a114084/content.htm
    Regards
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  • Hierarchy Node authorization with customer exit

    Hi All,
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    Hi,
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  • Passed i_step = 2,3(Hierarchy Node Variable with Customer-Exit)

    Hellow !
    I want to insert the following ststement to force the variable to be executed with i_step = 2 or 3.
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              l_s_range-opt  = 'EQ'.
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             else.
              l_s_range-low = '#'.
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    ENDLOOP.
    However, Passed customer-exit(Enhancements for Global Variables in Reporting)  i_step =2,3
    Regards,
    Don

    Hi,
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    hope this helps...
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  • Error With Customer Exit Variable

    Hi,
    I need To Create Customer Exit For Text Variable based on Two Input Variable values.
    can any one correct my code Code is written below based on quarter and Fiscalyearvarient.
    I have to get calmonth Text value.
    I am getting the error as : "I_T_VAR_RANGE" is a table without a header line and therefore has no
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    IF i_step = 2.
    CASE i_vnam.
       WHEN 'ZTXT_CML' .
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          LOOP AT i_t_var_range INTO L_S_VNAM WHERE vnam = 'ZQUAR' AND vnam = '0periv'.
            IF i_t_Var_range-0PERIV = 'IE'.
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                l_s_range-opt = 'EQ'.
              ELSEIF i_t_var_range-ZQUAR = '2'.
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                l_s_range-opt = 'EQ'.
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                l_s_range-opt = 'EQ'.
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                l_s_range-opt = 'EQ'.
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                l_s_range-opt = 'EQ'.
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                l_s_range-sign = 'I'.
                l_s_range-opt = 'EQ'.
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                l_s_range-sign = 'I'.
                l_s_range-opt = 'EQ'.
              ELSEIF i_t_var_range-ZQUAR = '4'.
                l_s_range-low = 'OCTOBER'.
                l_s_range-sign = 'I'.
                l_s_range-opt = 'EQ'.
              ENDIF.
            ENDIF.
              APPEND l_s_range TO e_t_range.
          ENDLOOP.
      ENDCASE.
    ENDIF.

    Hi Supraja,
    You would have to declare I_T_VAR_RANGE internal table as the table with an header line.
    This you will find in data declaration segment.
    ie
    DATA : I_T_VAR_RANGE type <table name> WITH HEADER LINE.
    or
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    Use work area while performing operations in your code and later append the record to the table i_t_var_range.
    DATA : L_S_VAR_RANGE type i_t_var_range.
    Also, i_step = 3 is the right one, because you are processing the customer exit based on the values of the user input of two variables.
    Modified code below.
    DATA : l_s_range TYPE rsr_s_rangesid.
    DATA : L_S_VAR_RANGE type i_t_var_range,
    loc_var_range LIKE rrrangeexit.
    IF i_step = 3.
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    WHEN 'ZTXT_CML' .
    CLEAR: l_s_range.
    LOOP AT i_t_var_range INTO l_s_var_range WHERE vnam = 'ZQUAR' AND vnam = '0periv'.
    IF l svar_range -0PERIV = 'IE'.
    IF l_s_var_range -ZQUAR = '1'.
    l_s_range-low = 'APRIL'.
    l_s_range-sign = 'I'.
    l_s_range-opt = 'EQ'.
    ELSEIF l_s_var_range -ZQUAR = '2'.
    l_s_range-low = 'JULY'.
    l_s_range-sign = 'I'.
    l_s_range-opt = 'EQ'.
    ELSEIF l_s_var_range -ZQUAR = '3'.
    l_s_range-low = 'OCTOBER'.
    l_s_range-sign = 'I'.
    l_s_range-opt = 'EQ'.
    ELSEIFl_s_var_range -ZQUAR = '4'.
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    l_s_range-sign = 'I'.
    l_s_range-opt = 'EQ'.
    ENDIF.
    ELSEIFl_s_var_range -0PERIV = 'K4'.
    IF i_t_var_range-ZQUAR = '1'.
    l_s_range-low = 'JANUARY'.
    l_s_range-sign = 'I'.
    l_s_range-opt = 'EQ'.
    ELSEIF l_s_var_range -ZQUAR = '2'.
    l_s_range-low = 'APRIL'.
    l_s_range-sign = 'I'.
    l_s_range-opt = 'EQ'.
    ELSEIF l_s_var_range -ZQUAR = '3'.
    l_s_range-low = 'JULY'.
    l_s_range-sign = 'I'.
    l_s_range-opt = 'EQ'.
    ELSEIF l_s_var_range -ZQUAR = '4'.
    l_s_range-low = 'OCTOBER'.
    l_s_range-sign = 'I'.
    l_s_range-opt = 'EQ'.
    ENDIF.
    ENDIF.
    APPEND l_s_range TO e_t_range.
    ENDLOOP.
    ENDCASE.
    ENDIF.
    Hope it helps,
    Best regards,
    Sunmit.

  • Problem with customer exit variable in BeX Query

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    Regards,
    Rakesh

    Hi Diogo,
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          IF sy-subrc = 0.
            LOOP AT gt_pbuild INTO gs_pbuild.
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              ls_range-low = lv_pattern.
              ls_range-sign = lc_sign_i.
              ls_range-opt = 'CP'.
              APPEND ls_range TO e_t_range.
              CLEAR: ls_range,
                     lv_pattern.
            ENDLOOP.
          ENDIF.
         ENDIF.
    I have tried using '%' instead of '*' aswell but the result is same.
    Thanks,
    Rakesh

  • Issue with customer exit for copying one variable value to another

    Hello Gurus,
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    I coded as below.
      WHEN 'customer_exit_var'.
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            CLEAR L_S_RANGE.
            L_S_RANGE-LOW = LOC_VAR_RANGE-LOW.
            L_S_RANGE-HIGH = ''.
            L_S_RANGE-SIGN = 'I'.
            L_S_RANGE-OPT = 'EQ'.
            APPEND L_S_RANGE TO E_T_RANGE.
            EXIT.
          ENDLOOP.
        ENDIF.
    I used the condition <= for the customer exit variable in the report. But, it is considering only single value, but not all the values <= to the give value.
    Please help me in this regard,
    Thanks,
    Aarthi.

    Thanks for your immediate response Govind.
    My report is restricted based on two dates. Date1 and Date2. Need to consider all records whose dates are <= Date1 and <= Date2.
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    So, Please help me in solving this problem.
    Thanks,
    Aarthi.

  • Problem with customer exit variable that is input ready as well

    Hello all,
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    I have tried to enter a value or to leave it blank, no difference.
    When I run another test by just using a customer exit variable w/o input ready capability, then I have no issue, the exit does exactly what I have coded.
    Does this mean, that a customer exit variable along with input readiness dows not work ?????
    You may ask why I need this variable. Well, my intention is to use the input value of this variable A to derive other values for a complete different variable B. Afterwards I want to erase the input given into variable A to have it blank.
    Any comments are appreciated
    Thanks

    Hi Heiko,
    I assume A & B variables are defined on different Characteristics. If you wish to derive B based on A, you can create the Query Characteristic Restriction on B & have a dummy RKF restricted on A whose processing is by Manual Input; where processing of B is by Customer Exit. In istep 2 you can check for B, read A & derive B. There would not be a need to blank out A since the Query would not be restricted on A - you can hide the dummy RKF from showing in the output. Just a thought.
    --Priya

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