How 2 Run Servlet

How to run servlet in tomcat5.5?

Frd...,
After written the Servlet you shold do the mapping,
than u will use the Application or Web-Server for the servlet deployment
In mapping there is the name url pattern. that will be call in the browser.
But dear u shold go to the Tutorial ..............U will get the Step by Step
to deploy it.
saM

Similar Messages

  • How to run servlet codes in WebServer 6.1?

    I am new to Java Web Server and at our place we had installed WebServer 6.1. How to run Servlets in this - the default directory is
    http//win2000:81/Sun/WebServer6.1/docs
    I have'nt insatlled any new virtual class / servers - just running with the default class and servers.
    I could not find any virtual directory named servlet (similar to JavaWebServer 2.0) here.
    Someone kindly tell me how to post servlet files and run them.

    Refer "Sun ONE Web Server 6.1 Programmer's Guide to Web Applications"
    http://docs.sun.com/app/docs/doc/817-1833-10
    Meena

  • How to run servlet in java webserver2.0

    how to configure java webserver2.0 and how to run servlet in that

    Hi Friend,
    Try changing the servlet code to this and just tell wat happens after this.
    and wat can you see on your Browser Screen.
    import java.io.*;
    import javax.servlet.*;
    import javax.servlet.http.*;
    import java.sql.*;
    public class login extends HttpServlet {
    public void doGet(HttpServletRequest req,HttpServletResponse res) throws ServletException,IOException
    if (req.getParameter("t1") == null || req.getParameter("t2") == null)
    out.println("Enter User Name And Password");
    String uid=req.getParameter("t1");
    String pwd=req.getParameter("t2");
    res.setContentType("text/html");
    PrintWriter out=res.getWriter();
    out.println("<html>"); out.println("<head>");
    out.println("<title>Login</title>"); out.println("</head>");
    out.println("<body>");
    try { Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
    catch(ClassNotFoundException e)
    out.println("<h3>"+e+"</h3>");
    try{
    Connection con=DriverManager.getConnection("jdbc:odbc:ms","scott","tiger");
    PreparedStatement psm=con.prepareStatement("select * from reg where uid1=? and pwd=?");
    psm.setString(1,uid);
    psm.setString(1,pwd);
    ResultSet rs=psm.executeQuery();
    if(rs.next())
    { out.println("<html><head><title>WELCOME</title></head>");
    out.println("<body><b><i>Hello user "+uid+"</b></i>");
    out.println("</body></html>"); }
    else
    res.sendRedirect("http://localhost:8080/login.html");
    } catch(SQLException e)
    { e.printStackTrace();}
    rs.close();
    con.close();
    out.close();
    After this try creating a odbc for oracle database at control panel with the name ms.
    Please inform me wat happens after this and friend do give some information about wat kind of web-server are you using.Because calling of your servlets differs the way your configure your web-server and the default configurations differ from web-server to web-server.
    Regards,
    RAHUL

  • How to compile and run servlets in Eclipse?

    Does somebody known how can I compile and run servlets in Eclipse IDE? I've added and configured Tomcat's plugin. I've created a project with my example servlets source, and I don't know what farther. How do I have compile it without main method? I must add web.xml file from Tomcat's directory into projects in Eclipse and modify it?
    THX Chudzik

    Try googling for "eclipse servlet", surely someone has written instructions.

  • How to run servlet in weblogic 8.1

    hi!
    i m new to weblogic.how to run servlet in weblogic8.1.i get lot of errors when i compile it in command prompt.but when i do the same thing in tomcat,i dont get errors & it runs successfully.help me out.how to compile servlets in weblogic 8.1.some say i have to create .jar file.pls tell me the procedure.i m new to j2ee.i have installed jdk1.5 .
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  • How to Run servlet in Tomcat 5.5.9

    hi
    How to run servlet in tomcat 5.5.9?how to set context path in server.xml of conf folder in tomcat since there is no context tag in server.xml.
    Jiten

    Hi ! I have a similar problem, well, it's along the same line ...
    I'm using NetBeans 4.1, and i've coded a servlet. Using NetBeans to launch my servlet (with the bundled Tomcat 5.5.7) works fine, however i need to deploy my application unto a Tomcat 5.5.9 server.
    Thus, i copied the WAR file generated by NetBeans into the Tomcat 5.5.9 webapps directory, and Tomcat expands it.
    Problem is when i run my JSP pages with the form tags, they do not work on the Tomcat 5.5.9 environment. Anyone knows why?
    (These work on the NetBeans Tomcat bundle 5.5.7)
    My form action :
    <form name="index" method="get" action="PageServlet">
    My web.xml :
    <servlet>
    <servlet-name>PageServlet</servlet-name>
    <servlet-class>application.PageServlet</servlet-class>
    </servlet>
    <servlet-mapping>
    <servlet-name>PageServlet</servlet-name>
    <url-pattern>/PageServlet</url-pattern>
    </servlet-mapping>
    I'm really stumbed on why it doesn't work in Tomcat 5.5.9, any help is greatly appreciated, thanks in advance ^_^

  • How to run Servlet in Tomcat 5.5.7 Server

    Hi,
    How to run Servlet in Tomcat 5.5.7 Server. I mean where I should copy my *.class file.
    Thanks in Advance.
    bbye.

    In order to complile the servlet you need to tell java where to find the servlet libary (as stated above by setting the class path). or (much easier IMO)
    copy the servlet-api.jar to
    JavaInstallDirectory\jre\lib\ext

  • How to run Servlet on Tomcat 4.0.1?

    OK. I've made a simple servlet and using Tomcat 4.0.1 on Windows ME. Tomcat's root directory is C:\jakarta-tomcat-4.0.1\webapps\ROOT. I copied folder with my servlet (java's class) in tomcat's root folder. When I try to run the dialog 'File Download' is showen. Why?
    Thanks.

    I have Tomcat 4.0. I am trying to run servlet but I could not manage it. I have put my class file in webapp/root/web-inif/classes/ I can not run my servlet... how can I manage this... what should I do more?
    the errors are :
    type Exception report
    message Internal Server Error
    description The server encountered an internal error (Internal Server Error) that prevented it from fulfilling this request.
    exception
    javax.servlet.ServletException: Cannot allocate servlet instance for path /servlet/Servlet1
         at org.apache.catalina.servlets.InvokerServlet.serveRequest(InvokerServlet.java:419)
         at org.apache.catalina.servlets.InvokerServlet.doGet(InvokerServlet.java:180)
         at javax.servlet.http.HttpServlet.service(HttpServlet.java:740)
         at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
         at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:247)
         at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:193)
         at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:243)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:566)
         at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:472)
         at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:943)
         at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:190)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:566)
         at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:472)
         at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:943)
         at org.apache.catalina.core.StandardContext.invoke(StandardContext.java:2347)
         at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:180)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:566)
         at org.apache.catalina.valves.ErrorDispatcherValve.invoke(ErrorDispatcherValve.java:170)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:564)
         at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:170)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:564)
         at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:468)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:564)
         at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:472)
         at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:943)
         at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:174)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:566)
         at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:472)
         at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:943)
         at org.apache.catalina.connector.http.HttpProcessor.process(HttpProcessor.java:1027)
         at org.apache.catalina.connector.http.HttpProcessor.run(HttpProcessor.java:1125)
         at java.lang.Thread.run(Thread.java:484)
    root cause
    java.lang.NoClassDefFoundError: Servlet1 (wrong name: servlet/Servlet1)
         at java.lang.ClassLoader.defineClass0(Native Method)
         at java.lang.ClassLoader.defineClass(ClassLoader.java:486)
         at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:111)
         at org.apache.catalina.loader.WebappClassLoader.findClassInternal(WebappClassLoader.java:1643)
         at org.apache.catalina.loader.WebappClassLoader.findClass(WebappClassLoader.java:937)
         at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1372)
         at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1254)
         at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:867)
         at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:655)
         at org.apache.catalina.servlets.InvokerServlet.serveRequest(InvokerServlet.java:400)
         at org.apache.catalina.servlets.InvokerServlet.doGet(InvokerServlet.java:180)
         at javax.servlet.http.HttpServlet.service(HttpServlet.java:740)
         at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
         at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:247)
         at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:193)
         at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:243)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:566)
         at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:472)
         at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:943)
         at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:190)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:566)
         at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:472)
         at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:943)
         at org.apache.catalina.core.StandardContext.invoke(StandardContext.java:2347)
         at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:180)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:566)
         at org.apache.catalina.valves.ErrorDispatcherValve.invoke(ErrorDispatcherValve.java:170)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:564)
         at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:170)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:564)
         at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:468)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:564)
         at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:472)
         at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:943)
         at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:174)
         at org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.java:566)
         at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:472)
         at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:943)
         at org.apache.catalina.connector.http.HttpProcessor.process(HttpProcessor.java:1027)
         at org.apache.catalina.connector.http.HttpProcessor.run(HttpProcessor.java:1125)
         at java.lang.Thread.run(Thread.java:484)

  • How Can I Run Servlet in tomcat

    Hi My Friends
    Please can any one tell me how can I Run Servlet in tomcat using my own Virtual Directory � my ask about , what is the structure it must be make it in the hierarchy of the sub folder of Virtual Directory , and in watch folder it must be put the servlet files and there is any change it must be make it in any file of the tomcat files and so on
    Please give my full details about this thing
    And thanks

    What version of Tomcat are u using?

  • How I can run servlets in Apache 1.3.2.7

    hi i am using JSP as Interface..and Servlets as controller...
    also Using Apache Httpd server,verion is 1.3.2.7
    plz tell me how i can use apache to run my servlets.
    Rahul.

    To run servlets in Apache you need the mod_jk module. But as the previous post, it is better to use Tomcat and putting both, Apache and Tomcat, working together. Tomcat will serve all the java related things, and the Apache, the html, php, etc.

  • How to run servlet with tomcat

    I have a probrom that how can I run servlet with tomcat?
    I have new a folder classes in webapps\root\WEB-INF\,and put the .class
    programme in it ,but http://localhost:8080/servlet/HelloWorldExample
    can't run ,it give me a error than http:404 not found.
    could you tell me how i can solve the problem.
    Thank u very much.

    Hi,
    Make sure the class is in classpath or in WEB-INF/classes folder and make an entry for servlet tag in web.xml in WEB-INF folder.
    Regards

  • How to run servlet by using main?

    How can I use main to run servlet?
    I cannot put request and response object into doGet(request, response) method
    I want this because I want to run this servlet daily and I plan to put it in cron job
    Calvin

    Hi
    Perhaps you cannot run servlet without using browser. But you can make that program as an application in order to run in Dos or Unix shell.
    But still you can run servlet without using browser How?
    You can debug servlets with the same jdb commands you use to debug an applet or an application. The JavaTM Servlet Development Kit (JSDK) provides a standalone program
    called servletrunner that lets you run a servlet without a web browser. On most systems, this program simply runs the java sun.servlet.http.HttpServer command. You
    can, therefore, start a jdb session with the HttpServer class.
    A key point to remember when debugging servlets is that Java Web server and servletrunner achieve servlet loading and unloading by not including the servlets directory on
    the CLASSPATH. This means the servlets are loaded using a custom classloader and not the default system classloader.
    Running servletrunner in Debug Mode
    Running Java Web ServerTM in Debug Mode
    Running servletrunner in Debug Mode
    In this example, the servlets examples directory is included on the CLASSPATH. You can configure the CLASSPATH for debug mode as follows:
    Unix
    $ export CLASSPATH=./lib/jsdk.jar:./examples:$CLASSPATH
    Windows
    $ set CLASSPATH=lib\jsdk.jar;examples;%classpath%
    To start the servletrunner program you can either run the supplied startup script called servletrunner or just supply the servletrunner classes as a parameter to jdb. This
    example uses the parameter to servletrunner.
    $ jdb sun.servlet.http.HttpServer
    Initializing jdb...
    0xee2fa2f8:class(sun.servlet.http.HttpServer)
    > stop in SnoopServlet.doGet
    Breakpoint set in SnoopServlet.doGet
    > run
    run sun.servlet.http.HttpServer
    running ...
    main[1] servletrunner starting with settings:
    port = 8080
    backlog = 50
    max handlers = 100
    timeout = 5000
    servlet dir = ./examples
    document dir = ./examples
    servlet propfile = ./examples/servlet.properties
    To run SnoopServlet in debug mode, enter the following URL in a browser where yourmachine is the machine where you started servlet runner and 8080 is the port number
    displayed in the settings output.
    http://yourmachine:8080/servlet/SnoopServlet
    In this example jdb stops at the first line of the servlet's doGet method. The browser will wait for a response from your servlet until a timeout is reached.
    main[1] SnoopServlet: init
    Breakpoint hit: SnoopServlet.doGet (SnoopServlet:45)
    Thread-105[1]
    We can use the list command to work out where jdb has stopped in the source.
    Thread-105[1] list
    41 throws ServletException, IOException
    42 {
    43 PrintWriter out;
    44
    45 => res.setContentType("text/html");
    46 out = res.getWriter ();
    47
    48 out.println("<html>");
    49 out.println("<head>
    <title>Snoop Servlet
    </title></head>");
    Thread-105[1]
    The servlet can continue using the cont command.
    Thread-105[1] cont
    Running Java Web Server in Debug Mode
    The JSDK release does not contain classes available in the Java Web server and it also has its own special servlet configuration. If you cannot run your servlet from
    servletrunner, then the other option is to run the Java Web server in debug mode.
    To do this add the -debug flag for the first parameter after the java program. For example in the script bin/js change the JAVA line to look like the following. In releases prior
    to the Java 2 platform release, you will also need to change the program pointed to by the variable $JAVA to java_g instead of java.
    Before:
    exec $JAVA $THREADS $JITCOMPILER $COMPILER $MS $MX \
    After:
    exec $JAVA -debug $THREADS $JITCOMPILER
    $COMPILER $MS $MX \
    Here is how to remotely connect to the Java Web Server. The agent password is generated on the standard output from the Java Web Server so it can be redirected into a file
    somewhere. You can find out where by checking the Java Web Server startup scripts.
    jdb -host localhost -password <the agent password>
    The servlets are loaded by a separate classloader if they are contained in the servlets directory, which is not on the CLASSPATH used when starting the Java Web server.
    Unfortunately, when debugging remotely with jdb, you cannot control the custom classloader and request it to load the servlet, so you have to either include the servlets
    directory on the CLASSPATH for debugging or load the servlet by requesting it through a web browser and then placing a breakpoint once the servlet has run.
    In this next example, the jdc.WebServer.PasswordServlet is included on the CLASSPATH when Java Web server starts. The example sets a breakpoint to stop in the service
    method of this servlet, which is the main processing method of this servlet.
    The Java Web Server standard output produces this message, which lets you proceed with the remote jdb session:
    Agent password=3yg23k
    $ jdb -host localhost -password 3yg23k
    Initializing jdb...
    > stop in jdc.WebServer.PasswordServlet:service
    Breakpoint set in jdc.WebServer.PasswordServlet.service
    > stop
    Current breakpoints set:
    jdc.WebServer.PasswordServlet:111
    The second stop lists the current breakpoints in this session and shows the line number where the breakpoint is set. You can now call the servlet through your HTML page. In
    this example, the servlet is run as a POST operation
    <FORM METHOD="post" action="/servlet/PasswordServlet">
    <INPUT TYPE=TEXT SIZE=15 Name="user" Value="">
    <INPUT TYPE=SUBMIT Name="Submit" Value="Submit">
    </FORM>
    You get control of the Java Web Server thread when the breakpoint is reached, and you can continue debugging using the same techniques as used in the Remote Debugging
    section.
    Breakpoint hit: jdc.WebServer.PasswordServlet.service
    (PasswordServlet:111) webpageservice Handler[1] where
    [1] jdc.WebServer.PasswordServlet.service
    (PasswordServlet:111)
    [2] javax.servlet.http.HttpServlet.service
    (HttpServlet:588)
    [3] com.sun.server.ServletState.callService
    (ServletState:204)
    [4] com.sun.server.ServletManager.callServletService
    (ServletManager:940)
    [5] com.sun.server.http.InvokerServlet.service
    (InvokerServlet:101)
    A common problem when using the Java WebServer and other servlet environments is that Exceptions are thrown but are caught and handled outside the scope of your servlet.
    The catch command allows you to trap all these exceptions.
    webpageservice Handler[1] catch java.io.IOException
    webpageservice Handler[1]
    Exception: java.io.FileNotFoundException
    at com.sun.server.http.FileServlet.sendResponse(
    FileServlet.java:153)
    at com.sun.server.http.FileServlet.service(
    FileServlet.java:114)
    at com.sun.server.webserver.FileServlet.service(
    FileServlet.java:202)
    at javax.servlet.http.HttpServlet.service(
    HttpServlet.java:588)
    at com.sun.server.ServletManager.callServletService(
    ServletManager.java:936)
    at com.sun.server.webserver.HttpServiceHandler
    .handleRequest(HttpServiceHandler.java:416)
    at com.sun.server.webserver.HttpServiceHandler
    .handleRequest(HttpServiceHandler.java:246)
    at com.sun.server.HandlerThread.run(
    HandlerThread.java:154)
    This simple example was generated when the file was not found, but this technique can be used for problems with posted data. Remember to use cont to allow the web server
    to proceed. To clear this trap use the ignore command.
    webpageservice Handler[1] ignore java.io.IOException
    webpageservice Handler[1] catch
    webpageservice Handler[1]
    I hope this will help you.
    Thanks
    Bakrudeen

  • How to run servlet,jsp in eclipse software

    can any one tell me how to run servlet ,jsp in eclipse
    and how to start tomcat server in eclipse
    reply me
    regards
    saravana

    Can anybody help me as I wanted to know how to run servlet,jsp in eclipse software...
    If somebody can forward me the screenshots than it would be of great help....
    Thanks

  • How to run servlet,jsp in eclipseand to start tomcat in eclipse

    hi
    i want to know how to run servlet and jsp in eclipse 3.0
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    regards
    saravanakumar

    Find Lomboz J2EE plugin and a tutorial of how to use it :)

  • How to run servlets in tomcat

    Hi ,
    How to run servlets in tomcat server. I created two files html and servlet file.
    Html file
    callservlet.html
    <html>
    <body>
    <form method=post action="servletcalled.class">
    <input type=submit value="submit">
    </form>
    <body>
    </html>
    servlet file
    servletcalled.java contains
    public void doPost(HttpServletRequest req,HttpServletResponse res ){
    java.io.PrintWriter out = req.getWriter();
    out.println("Hi, executed");
    i put the callservlet.html in webapps/examples/ and servletcalled.class was in webapps/examples/Web-inf/classes/
    After starting the tomcat and running the program html file is getting exceuted but when i click on the submit button this error is prompted
    type Status report
    message servletcalled.class
    description The requested resource (servletcalled.class) is not available.
    Thanks in advance

    Thanks,
    I created a new directory in webapps
    s "webapps/test".
    Test directory contains
    1. callservlet.html file
    2. another directory Web-inf (i.e,
    webapps/test/Web-inf)
    Web-inf directory contains
    1. web.xml file
    2. another directory classes (i.e,
    webapps/test/Web-inf/calsses)
    classes directory contains
    1. servletcalled.class file
    web.xml file contains
    <?xml version="1.0" encoding="ISO-8859-1"?>
    <!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web
    Web Application 2.3//EN"
    "http://java.sun.com/dtd/web-app_2_3.dtd">
    <web-app>
    <servlet>
    <servlet-name>Example</servlet-name>
    <servlet-class>Example</servlet-class>
    </servlet>
    </web-app>
    -->should be: <servlet-class>servletcalled</servlet-called>
    then in the <web-app> scope define this:
    <servlet-mapping>
    <servlet-name>Example</servlet-name>
    <url-pattern>/servlets/Example</url-pattern>
    </servlet-mapping>
    >
    thanks in advance i am working hard on that but
    notable to get the solutionbtw by reading the documentation of tomcat and tutorials of jave on the java site (here), you would have known this!

  • How to run servlets in IIS Server

    Hi Techies,
    I had read in one book , in IIS server we can run servlets n jsp.
    Can u guys tell how can we run servlets n jsp in IIS server. Does we need to include some 3rd party software in IIS
    regards,
    KRish

    Well if you were to use apache you would use the
    mod_jk_apache2
    However, im really not sure if that is around for win32 systems. However, as i said above im not 100% on windows systems.
    If you really want to test portability set aside a 5gb partition and install linux which most standard distros already have apache2/tomcat installed.(Fedora)
    Also i have to agree this seems less and less java based and more and more system based.
    If you plan on taking the route mentioned above start a post at places like linuxquestions.org since they have more tech junkies then you could imagine.

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