How can I generate compliant XHTML via ProcessXSL?

Question : Does anyone know how to generate XHTML from PLSQL processXSL command? Is there a parameter or flag I can set to specify using EndTags on all elements ?
Problem : I want to create an "HTML" document with compliant tag notation eg <IMG /> tag rather than the default <IMG>. This is obviously the same problem for BR and HR tags. But when I render my XML the processor always drops off the end tag....
Why do I want to do this? : If the HTML tags are compliant then we can use XPath notation to read our HTML reports (for Unit/System Testing purposes) and verify HTML contents is being produced properly...
Sample : I've included a sample code snippet that should run if you want to try it out.
DECLARE
lxsl VARCHAR2(32767);
buf VARCHAR2(32767);
lxml XMLDOM.DOMDocument;
lxmlclob CLOB;
lParser XMLParser.Parser;
lProcessor XSLProcessor.Processor;
lStylesheet XSLProcessor.Stylesheet;
XSLDoc XMLDOM.DOMDocument;
BEGIN
lxsl := '<?xml version="1.0" encoding="UTF-8"?>';
lxsl := lxsl ||
'<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">';
lxsl := lxsl || ' <xsl:output method="html"/>';
lxsl := lxsl || ' <xsl:template match="/">';
lxsl := lxsl || ' <html>';
lxsl := lxsl || ' <body>';
lxsl := lxsl || ' <img src="http://forums.oracle.com/forums/images/otn/otn_logo.gif" />';
lxsl := lxsl || ' </body>';
lxsl := lxsl || ' </html>';
lxsl := lxsl || ' </xsl:template>';
lxsl := lxsl || '</xsl:stylesheet>';
lxmlclob := dbms_xmlgen.getXML('select * from dual');
lParser := XMLParser.NewParser;
XMLParser.parseClob(lParser
,lxmlclob);
lxml := XMLParser.GetDocument(lParser);
XMLParser.SetPreserveWhiteSpace(lParser
,TRUE);
XMLParser.parsebuffer(lParser
,lxsl);
XSLDoc := XMLParser.GetDocument(lParser);
lStylesheet := XSLProcessor.NewStylesheet(XSLDoc
,NULL);
lProcessor := XSLProcessor.NewProcessor;
XSLProcessor.ProcessXSL(lProcessor
,lStylesheet
,lxml
,buf);
dbms_output.put_line(buf);
XSLProcessor.FreeStylesheet(lStylesheet);
XSLProcessor.FreeProcessor(lProcessor);
XMLDOM.FreeDocument(XSLDoc);
END;
resulting in an img tag with no trailing '/'....!!!!
<html>
<body><img src="http://forums.oracle.com/forums/images/otn/otn_logo.gif">
</body>
</html>

I found a work around but if anyone has a real solution please reply....
Work around is to hardcode the IMG tags
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="html"/>
 <xsl:variable name="lt"><</xsl:variable>
 <xsl:variable name="gt">></xsl:variable>
 <xsl:template match="/">
 <html>
 <body>
 old way - <img src="http://forums.oracle.com/forums/images/otn/otn_logo.gif"/>
 new way - <xsl:value-of select="$lt" disable-output-escaping="yes"/>img src="http://forums.oracle.com/forums/images/otn/otn_logo.gif"/<xsl:value-of select="$gt" disable-output-escaping="yes"/>
 <xsl:value-of select="$lt" disable-output-escaping="yes"/>br/<xsl:value-of select="$gt" disable-output-escaping="yes"/>
 <xsl:value-of select="$lt" disable-output-escaping="yes"/>hr/<xsl:value-of select="$gt" disable-output-escaping="yes"/>
 </body>
 </html>
 </xsl:template>
</xsl:stylesheet>

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