How do  connect two iPods at once.

Hello, I have two iPods that I connect to one computer (1 a 5th gen ipod, and 1 a 4th gen ipod).
I can only ever connect one of the two iPod's. When ever I try and connect a 2nd iPod, iTunes disconnects the 1st iPod, and only shows the 2nd iPod, and this then gives a windows error on the 1st iPod.
Has anyone ever been able to connect two iPods at once in itunes for Windows?

i have the same problem. With one ipod and another ipod nano, the itunes doesnt works, and need to restart it.

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    return author;
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    return accinfo;
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    package hibernate.example;
    import hibernate.example.Acctinfo;
    import hibernate.example.Catalog;
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    import java.util.List;
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    import org.hibernate.SessionFactory;
    import org.hibernate.Transaction;
    import org.hibernate.cfg.Configuration;
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              //clc.deleteData();
              //clc.showData();
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              accinfo.setBalance("1000");
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              catalog.setJournal("india");
              catalog.setPublisher("indiabulls");
              catalog.setEdition("ist");
              catalog.setTitle("orbis");
              catalog.setAuthor("manoj");
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    <?xml version="1.0" encoding="UTF-8"?>
    <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
    <hibernate-configuration>
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    <property name="hibernate.connection.url">jdbc:oracle:thin:@172.16.31.25:1521:BOMBAY</property>
    <property name="hibernate.connection.username">mumbai</property>
    <property name="hibernate.connection.password">mumbai123</property>
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    <property name="connection.autocommit">true</property>
    <property name="dialect">org.hibernate.dialect.OracleDialect</property>
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    <mapping resource="Catalog.hbm.xml"/>
    </session-factory>
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    **********************error i m facing is :************************
    0 [main] WARN net.sf.ehcache.config.Configurator - No configuration found. Configuring ehcache from ehcache-failsafe.xml found in the classpath: jar:file:/C:/Documents%20and%20Settings/d.poonam/Desktop/hibernate/lib/ehcache-1.1.jar!/ehcache-failsafe.xml
    1188 [main] WARN org.hibernate.impl.SessionFactoryObjectFactory - Could not bind factory to JNDI
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         at javax.naming.InitialContext.getDefaultInitCtx(Unknown Source)
         at javax.naming.InitialContext.getURLOrDefaultInitCtx(Unknown Source)
         at javax.naming.InitialContext.getNameParser(Unknown Source)
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         at org.hibernate.impl.SessionFactoryObjectFactory.addInstance(SessionFactoryObjectFactory.java:90)
         at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:247)
         at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1043)
         at hibernate.example.CatalogClient.<init>(CatalogClient.java:24)
         at hibernate.example.CatalogClient.main(CatalogClient.java:27)
    please help me out....
    thanks in advance..
    if u know how to connect two tables plz let me know..
    its urgent....

    I made this work with MySQL. Adapt to your situation as needed. - %
    package hibernate.model;
    import hibernate.util.HibernateUtils;
    import hibernate.model.Catalog;
    import hibernate.model.Account;
    import org.apache.commons.logging.Log;
    import org.apache.commons.logging.LogFactory;
    import org.hibernate.Session;
    import hibernate.util.HibernateUtils;
    import static junit.framework.Assert.assertEquals;
    import static junit.framework.Assert.assertNotNull;
    public class CatalogTest
       private static final Log LOGGER = LogFactory.getLog(CatalogTest.class);
       public static void main(String[] args)
          Session session = null;
          try
             session = HibernateUtils.getSessionFactory().getCurrentSession();
             session.beginTransaction();
             int rowsBefore = HibernateUtils.getRowCount(session, Catalog.class);
             assertEquals("should not have any Catalogs", rowsBefore, 0);
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             catalog.addAccount(new Account(100));
             catalog.addAccount(new Account(200));
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             assertNotNull("generated id should not be null", id);
             LOGGER.info("returned id: " + id);
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             LOGGER.debug("transaction committed");
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             LOGGER.error(e);
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    import java.io.Serializable;
    import java.text.NumberFormat;
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       private Long id;
       private int balance;
       public Account()
          this(null, 0);
       public Account(int balance)
          this(null, balance);
       public Account(Long id, int balance)
          this.id = id;
          this.balance = balance;
       public Long getId()
          return id;
       private void setId(Long id)
          this.id = id;
       public int getBalance()
          return balance;
       private void setBalance(int balance)
          this.balance = balance;
       public boolean equals(Object o)
          if (this == o)
             return true;
          if (!(o instanceof Account))
             return false;
          Account account = (Account) o;
          return !(id != null ? !id.equals(account.id) : account.id != null);
       public int hashCode()
          int result;
          result = (id != null ? id.hashCode() : 0);
          result = 31 * result + balance;
          return result;
       public String toString()
          return new StringBuilder().append("Account{").append("id=").append(id).append(", balance=").append(NumberFormat.getCurrencyInstance().format(balance)).append('}').toString();
    <?xml version="1.0"?>
    <!DOCTYPE hibernate-mapping PUBLIC
          "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
          "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
    <hibernate-mapping package="hibernate.model" default-access="field" default-lazy="true">
       <class name="Account" table="accounts">
          <id name="id" column="account_id">
             <generator class="native"/>
          </id>
          <property name="balance" column="balance"/>
       </class>
    </hibernate-mapping>
    package hibernate.model;
    import java.io.Serializable;
    import java.util.Set;
    import java.util.HashSet;
    import java.util.Collections;
    public class Catalog implements Serializable
       private Long id;
       private String title;
       private Set<Account> accounts;
       public Catalog()
          this(null, "", Collections.EMPTY_SET);
       public Catalog(String title)
          this(null, title, Collections.EMPTY_SET);
       public Catalog(Long id, String title, Set<Account> accounts)
          this.id = id;
          this.title = title;
          this.accounts = new HashSet<Account>(accounts);
       public Long getId()
          return id;
       private void setId(Long id)
          this.id = id;
       public String getTitle()
          return title;
       private void setTitle(String title)
          this.title = title;
       public Set<Account> getAccounts()
          return accounts;
       private void setAccounts(Set<Account> accounts)
          this.accounts = accounts;
       public void addAccount(Account account)
          this.getAccounts().add(account);
       public void removeAccount(Account account)
          this.getAccounts().remove(account);
       public boolean equals(Object o)
          if (this == o)
             return true;
          if (!(o instanceof Catalog))
             return false;
          Catalog catalog = (Catalog) o;
          return !(id != null ? !id.equals(catalog.id) : catalog.id != null);
       public int hashCode()
          return (id != null ? id.hashCode() : 0);
       public String toString()
          return new StringBuilder().append("Catalog{").append("id=").append(id).append(", title='").append(title).append('\'').append(", accounts=").append(accounts).append('}').toString();
    <?xml version="1.0"?>
    <!DOCTYPE hibernate-mapping PUBLIC
          "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
          "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
    <hibernate-mapping package="hibernate.model" default-access="field" default-lazy="true">
       <class name="Catalog" table="catalogs">
          <id name="id" column="catalog_id">
             <generator class="native"/>
          </id>
          <property name="title" column="title"/>
          <set name="accounts" cascade="all">
             <key column="catalog_id"/>
             <one-to-many class="hibernate.model.Account"/>
          </set>
       </class>
    </hibernate-mapping>
    <!DOCTYPE hibernate-configuration PUBLIC
         "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
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          <property name="generate_statistics">true</property>
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          <property name="order_updates">false</property>
          <property name="hbm2ddl.auto">create-drop</property>
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          <mapping resource="hibernate/persistence/hibernate/Account.hbm.xml"/>
          <mapping resource="hibernate/persistence/hibernate/Catalog.hbm.xml"/>
         </session-factory>
    </hibernate-configuration>

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    See these articles about using more than one iPod on one computer, and with either one or more iTunes libraries.
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    No need for two accounts.
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    I'm just in the process of getting an ipod (waiting on delivery!) and want to know how it is possible to have two ipods using the same computer but synchronizing differently. I don't want to risk losing my partners music (he'll be very upset!) and I don't want to end up with his music on my ipod. I'd appreciate it if someone could give me a step by step guide or tell me where the best place to look for the answer is. Is it possible somehow to have two different libraries on one computer? Is that how it works?

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