How do I find the max value of scrollV in AS3?

I used Ned's answer to get my 3 text fields scrolling together based on the value of one of them. Thanks Ned!
The other two text fields scroll to match the 'parent' text field, but at the end - as you reach the last scroll position - the other two do not update and the 3 text fields are out of alignment. Its just at the end of the scroll. The rest of the scroll values align. I'm thinking if I can find the max scrollV value, I can force the other two to scroll one last time when that value is reached by the 'parent' text field.

Thanks Rob! I knew it must be something available somewhere. That should allow me to do the needed calculations. Awesome.

Similar Messages

  • Finding the max value

    Hi team,
    I have the following query where i need to find the max value
    [code]
      with t as  (
       select 'L1' R_nm ,'Data' R_Data , 'Obj' R_Obj , 'Wd' r_prec , '2' val  from dual
       union all
       select 'L1' , 'Data', 'Obj' , 'No', '4' from dual
    union all
       select 'L2' , 'Data', 'Obj' , 'No', '4' from dual )
       select t.*, max(val) over(partition by r_nm,r_data,r_obj)  rk from t
    [/code]
      My expected output should be
    [code]
    r_nm    r_data     r_obj   r_prec   val     rk
    L1        Data         Obj     Wd       2       1
    L1        Data         Obj     No       4        2
    L2        Data         Obj     Yes      1       1
    [/code]
    Thank You

    Hi,
    It looks like you're not interested in the MAX at all.  It looks like you want to rank the rows, such that the one with the lowest value is assigned the number 1, the row with the 2nd lowest values gets 2, ..., and the row with the N-th lowest value gets N.  If doesn't matter if the MAX is 4, or 2, or 420.
    Here's one way to do that:
    SELECT    t.*
    ,         RANK () OVER ( PARTITION BY  r_nm, r_obj
                             ORDER BY      val
                           )  AS rk
    FROM      t
    ORDER BY  r_nm, r_obj
    ,         val
    Depending on how you want to deal with ties, you might want to use ROW_NUMBER or DENSE_RANK instead of RANK.

  • How do I find the closest value to a constant in an array

    I have an array of floating numbers and I want to find a value in that array that is closest to a floating constant.     For example if I have the array 5.9, 2.8, 3.7, 5.8, 6.9, and if I have the constant 5.4, how would I find the closest value to 5.4 in the array, which in this case would be 5.8. The only approach I can think of is to subtract each value in the array from 5.8 and find the minimum value of an array which would be created from the differences. Is there a better approach?
    Thank you.

    Just be sure to take the absolute value of the difference and your proposed method is fine.

  • How can i find the max of a column using CMP

    I urgently need a solution to How one can find the maximum of a field which is of integer/numeric type??
    I am doing it in CMP + weblogic.
    Suppose the table is STUDENTMARKS which consists of a field
    TotalMarks of Integer type..
    and i need to find the student with maximum marks..
    Should i be using EJB QL.. If so pls tell how...

    U can use aggregate function max in ejb ql

  • Finding the max value using partition by

    Hi
    I've the following requirement where i need to select the max value from the data
    WITH T AS
    (SELECT 48003 ID ,'SPR' RTNG_TP_CD , 'INS' RL_CD ,'A-' RAT_CD FROM DUAL UNION ALL
    SELECT 48003 , 'SLNG' ,'INS','A-' FROM DUAL)
    SELECT distinct  ID, RTNG_TP_CD,RL_CD,MAX(RAT_CD)  over (partition by id) RT_CD
    FROM T
    For a single id if there are 2 RTNG_TP_CD then select the max(rat_cd) by displayin rtng_tp_cd =SLNG
    Expected Output
    48003 , SLNG , INS , A-Thank You

    WITH T AS
    (SELECT 48003 ID ,'SPR' RTNG_TP_CD , 'INS' RL_CD ,'A-' RAT_CD FROM DUAL UNION ALL
    SELECT 48003 , 'SLNG' ,'INS','A-' FROM DUAL)
    SELECT distinct ID,decode((select count(*) from t where id=t.id),1,RTNG_TP_CD, 'SLNG') RTNG_TP_CD,RL_CD,MAX(RAT_CD) over (partition by id) RT_CD
    FROM T

  • Given a string, how do you find the numeric value in sparse ring?

    Situation: I receive the string value of the sparse ring, and a control reference to the same type of control, but not the control that sourced the string. How can I convert the string, into the actual numeric value of the ring? For example:
    Using the "VISA Select Event Type" ring (Functions -> Instrument I/O -> VISA -> Advanced -> Event -> Select Event Type.ctl), lets say I get the string "ServiceRequest" how do I convert that into 1073684491, the actual value of the ring?
    This is a rework of an existing function that worked fine with "normal" rings.
    Thanks.

    Unfortunately this method will not work, its a generic routine that must be able to take any ring, so I can't hardwire the cases to known outputs. And, of course, searching the array of Strings[] will just find me a useless index.
    My interm solution is this:
    1) pick a small, but likely range of possible values for the ring
    2) iterate through these values, assigning each one in turn to ring
    3) read the RingText property to see if it matches the passed string
    4) if it does, then exit. If it doesn't keep looping.
    5) if no value produces a matching string, declare defeat (raise an error or produce other output that indicates a match could not be found).
    The routine only runs in the UI so I am not too concerned about the time delay this method will i
    mpose, but I would greatly appreciate a smoother solution.
    Thanks for your suggestions.

  • How do you find the average value of all the data between two points on a single channel

    I am tring to calculate the average value of all the data points on a single plot between two seperate points
    I have attahced an illustration.
    Tim
    Solved!
    Go to Solution.
    Attachments:
    plot.jpg ‏173 KB

    Hey smoothdurban,
    I've seen Brad's code, and trust me, it's worth the effort to let him help you get it up and running - it's definitely the most ideal way to solve this problem.  However, as Brad said, there are multiple ways to tackle this - both interactive and programmatic - so in the meantime, I'll take a second to detail one of the interactive and sure-fire ways to find the average of data between two points on a single channel.
    We'll use"Flags."  Set up your VIEW graph exactly as you did on your original screenshot, using Band Cursors to approximate the beginning and ending X-values representing the range you want to examine.  Next:
    1. Click the "Set Flags" button () that is a part of your 2D Axis System.  Note that you can hold down the Shift button if you ever decide you want to do this on more than a single curve at one time.
    2. Select the "Flags: Copy Data Points" button that enables after Flags are set.
    3. This creates new channel(s) in the default (bold) group in the Data Portal that contains only the Flagged data.
    4. Select DIAdem ANALYSIS.
    5. Select Statistics » Descriptive Statistics.
    6. In the Channels input, select the newly created channel containing your Flagged Y-Data.
    7. Ensure that the Arithmetic Mean parameter is set.  You can preview the data and the result in the dialog before pressing OK to execute the calculation. 
    You may have noticed that in the Descriptive Statistics calculation, one of the parameters that you can set is the range of channel rows to operate on - so, if you know the row numbers of your beginning and ending X-values, you could just simply run the Descriptive Statistics calculation and use this parameter to operate on a row subset of your original channel instead of the entire channel.
    Derrick S.
    Product Manager
    NI DIAdem
    National Instruments

  • How do I find the max number of sessions ever recorded?

    Hi,
    I see sessions_highwater column in v$license shows the max number of sessions since the database startup time, but I'm wondering if there is a view that shows the max number of sessions ever recorded? (i.e. before the last database restart)
    Thanks!
    Jon

    You can check the number of sessions from the below query using hist views. But you can only go back upto  the retention policy setting.
    SELECT   res.snap_id, s.begin_interval_time, s.end_interval_time,
             res.instance_number, res.resource_name, res.current_utilization,
             res.max_utilization
        FROM dba_hist_resource_limit res, dba_hist_snapshot s
       WHERE s.snap_id = res.snap_id AND res.resource_name = 'sessions'
    ORDER BY s.begin_interval_time, res.instance_number

  • How to find the maximum value among four fields in a single record

    Hi Gems...
    I have a record in which there are 4 currency fields.
    Now i would like to know the maximum of these 4 fields.
    I tried with Max functions in which i put all the 4 values...but it is showing error like ") is missing" though it is there.
    Can we insert more than 2 values in Max function?
    Or else is there any other option to find the max value among the 4 values which lies in a single record
    Thanks
    Jiten

    Hi Anil,
    Say suppose i have a single record in which 4 premiums of a particular bond exists.
    for eg:
    Prem1      Prem2        Prem3          Prem4
    129000.00      388000.00   228000.00   14800.00
    Now this is a single record for a particular bond ... now i need to calculate the max value among these 4 premiums.
    How would we proceed to achieve this?
    Regards
    Jiten
    Edited by: Jitendra Yuddandi on Feb 3, 2009 1:04 PM

  • How to retrieve the max value from a cursor in procedure

    Hi,
    In a procedure, I defined a cursor:
    cursor c_emp is select empno, ename, salary from emp where ename like 'J%';
    but in the body part, I need to retrieve the max(salary) from the cursor.
    could you please tell me how I can get the max value from the cursor in the procedure.
    Thanks,
    Paul

    Here is one sample but you should just get the max directly. Using bulk processing should be a last resort.
    DECLARE
      CURSOR c1 IS (SELECT * FROM emp where sal is not null);
      TYPE typ_tbl IS TABLE OF c1%rowtype;
      v typ_tbl;
      max_sal number;
    BEGIN
      OPEN c1;
      max_sal := -9999999999999;
      LOOP                                                 --Loop added
        FETCH c1 BULK COLLECT INTO v LIMIT 3; -- process 3 records at a time
            -- process the records
           DBMS_OUTPUT.PUT_LINE('Processing ' || v.COUNT || ' records.');
            FOR i IN v.first..v.last LOOP
                 if v(i).sal > max_sal then
                   max_sal := v(i).sal;
                 end if;
                DBMS_OUTPUT.PUT_LINE(v(i).empno);
            END LOOP; 
        EXIT WHEN c1%NOTFOUND;
      END LOOP;
      DBMS_OUTPUT.PUT_LINE('Max salary was: ' || max_sal);
    END;
    Processing 3 records.
    7369
    7499
    7521
    Processing 3 records.
    7566
    7654
    7698
    Processing 3 records.
    7782
    7788
    7839
    Processing 3 records.
    7844
    7876
    7900
    Processing 2 records.
    7902
    7934
    Max salary was: 5000

  • Finding the min value in a hashtable

    Hi,
    I'm trying to work out the lowest value contained in a hashTable. So far I've got.
    import java.util.Enumeration;
    import java.util.Hashtable;
    import java.util.Vector;
    public class StoreValuesDouble extends Statistic {
          * Each object of the class (StoreValuesDouble) will have these attributes.
          * When you call the StoreValuesDouble class you can use
          * myDoubleValues (a Vector holding Double types),
          * Hashtable (a Hashtable using Double types as values and keys) and
          * nullValues (an Double currently set to 0.0).
         Vector<Double> myDoubleValues; //declare a variable myDoubleValues that is of data type Vector
         Hashtable<Double, Double> myValues; //declare a variable myvalues that is a data type Hashtable
         Double nullValues = 0.0; //Double attribute to count the number of null values contained in the vector
          * pass myDoubleValues to inValues
          * @param Vector /<Double/> a vector holding Double values
          * @param inValues the values in the vector
          * @return
         public void DoubleStat(Vector<Double> inValues) {
              myDoubleValues = inValues;
          * calculate the mean of myDoubleValues
          * @return mean of myDoubleValues as a double
         public double meanDouble() {
              double mean = 0;
              Double currentDouble;
              double nonNull = 0;
              for (double j = 0; j < myDoubleValues.size(); j++)
                   currentDouble = myDoubleValues.elementAt((int) j);
                   if (currentDouble != null) {
                        mean += currentDouble.doubleValue();
                        nonNull++;
              return mean / nonNull;
          * calculate the standard devitation of myDoubleValues
          * @return standard devitation of myDoubleValues as a double
         public double standardDeviationDouble() {
              double m = meanDouble();
              double t = 0.0;
              Double currentDouble;
              double n = 0;
              for (double j = 0; j < getDoubleValues(); j++) {
                   currentDouble = myDoubleValues.elementAt((int)j);
                   if (currentDouble != null) {
                        n = currentDouble.doubleValue();
                        t += (n - m) * (n - m);
              return Math.sqrt(t / (myDoubleValues.size() - 1.0));// n - 1 as sample varience
          * return the number of values of myDoubleValues to help calculate the mean & standard deviation
          * @return the size of myDoubleValues as a Double
         public double getDoubleValues() {
              return myDoubleValues.size();
          * compute the number of null values
          * @return a double value representing the number of null values
         public Double getDoubleNull() {
              Double nbNull = 0.0;
              // test if myIntValues is null
              if (myDoubleValues == null) {
                   System.out.println("Please enter values that are not null!");
                   return 0.0;
              // if not null, parse all values
                   // for each value, test if it is null or not
                   Double currentDouble;
                   for (double i = 0; i < myDoubleValues.size(); i++) {
                        currentDouble = myDoubleValues.elementAt((int)i);
                        if (currentDouble != null) {
                             /// nothing to do
                        else {
                             nbNull++;
              return nbNull;
    //find the MIN values in the Hashtable to give us the range (with the MAX value)
         public Double MinDouble()
              Double MinDouble = null;
              Double currentValue;
              for (double j = 0; j < myDoubleValues.size(); j++)
                   currentValue = myDoubleValues.elementAt((int) j);
                   if (currentValue != null){
                   if (currentValue <= MinDouble) {
                        MinDouble = currentValue;
              return MinDouble;
         /*find the MAX value in the Hashtable to give us the range (with the MIN value)
         public double MAX()
          * Create an instance of StoreValuesDouble to hold vector values and number of times the values
          * appear. StoreValuesDouble automatically contains the variables defined above
          * (myDoubleValues, myValues and nullValues) we have to initialise myDoubleValues and myValues
          * as they have been defined but not initialised. nullValues has been defined (int) and initialised (0).
          * @param Vector /<Double/> a vector holding Double values
          * @param inValues the values in the vector
          * @return
         public StoreValuesDouble(Vector<Double> inValues) {
              myDoubleValues = inValues; //the attribute myDoubleValues defined in the StoreValuesDouble class
              //is the inValues parameter, this allows us to store the Vector in inValues
              myValues = new Hashtable<Double, Double>(); // create an instance of/initialise Hashtable
          * Now define the methods to make the instance StoreValuesDouble do what we want it to do
          * (ie parse all the double values of the myDoubleValues Vector attribute.
         public void computeDoubleValues() {
              Double currentDouble;//local variable to store the current read Double object
               * Use a for loop to read through all the values contained in the vector
              for (double i = 0; i < myDoubleValues.size(); i++) {
                   currentDouble = myDoubleValues.elementAt((int)i);
                   //currentDouble is now the Double object stored at i
                   //to check that i is not null we use the if statment
                   if (currentDouble != null) {
                        //i is not null so we want to add it to the hashtable. Rather than writing a lot of code
                        //here to do checking and adding we just call a method that can be written seperately
                        updateDoubleTable(currentDouble);
                   else {
                        //i is null so we just count it by adding it to our nullValues attribute
                        nullValues++;
          * Update the current distribution of Doubles
          * @param Double for the value of the key
          * @param inDouble for the value entered into the Hashtable (the object)
         public void updateDoubleTable(Double inDouble) {
              //First test that variable inDouble is not null
              if (inDouble != null) {
                   //update the table myValues this involves two tasks
                   //1)see if the double object has already been seen
                   //so we create a local variable to test the Hashtable
                   boolean alreadyPresent;
                   alreadyPresent = myValues.containsKey(inDouble);
                   //here we check whether inDouble is already in myValues
                   if (alreadyPresent) {
                        //if it is present we need to increase the counter
                        Double counter = myValues.get(inDouble);
                        //local variable counter to get the value associated to the key inDouble
                        Double newCounter = new Double(counter.intValue() + 1.0);
                        //update counter values and then ...
                        myValues.put(inDouble, newCounter);
                        //put into myValues
                        //as Hashtable can store only Objects, we cannot use primitive types
                        // so we use Objects related to primitive types as Integer, Float, Double
                        // or Boolean (here, we use Double)
                   } else {
                        //store the double and set it's counter to 1
                        myValues.put(inDouble, new Double(1));
              } else {
                   //do nothing
         //now we want to display the values
         public void displayDoubleTable() {
              // to display the distribution, we need to parse all the keys of the
              // hashtable and access to the value associated to each key
              Enumeration<Double> keys = myValues.keys();
              Double currentKey;
              Double currentValue;
              System.out.println("");
              System.out.println("Hashtable Information:");
              System.out.println("");
              System.out.println(myDoubleValues.size() + " Double objects in initial vector");
              System.out.println("");
              while (keys.hasMoreElements()) {
                   currentKey = keys.nextElement();
                   currentValue = myValues.get(currentKey);
                   System.out.println("The value " + currentKey.doubleValue()
                             + " has been seen " + currentValue.doubleValue()
                             + " time(s) in the initial Vector");
              System.out.println("");
              System.out.println("There were " + nullValues
                        + " null Double object(s) in the inital Vector");
         }As part of the StoreValuesDouble class. And to display it.
    package statistics;
    import java.util.Vector;
    public class TestStatDouble {
         static Vector<Double> doubleVector;
          * Create and initialise a vector of values and compute the mean,
          * standard deviation, distribution and MIN/MAX values.
         public static void main(String[] args) {
               // initialise the values in initValues
              initValues();
              // create an instance of StoreValuesDouble taking double as the parameter
              StoreValuesDouble is = new StoreValuesDouble(doubleVector);
              //Display the results
              displayVectorContent(doubleVector);
              System.out.println("");
              System.out.println("Number of null values: " + is.getDoubleNull());
              System.out.println("Number of non-null values is: " +(is.getDoubleValues() - is.getDoubleNull()));
              System.out.println("Number of all values: " + is.getDoubleValues());
              System.out.println("The mean is: " + is.meanDouble());
              System.out.println("Standard deviation is: " + is.standardDeviationDouble());
              System.out.println("The lowest value is " + is.MinDouble());
              System.out.println("");
               * now I want to display the results from the displayTable method in the StoreValuesDouble
               * class so I create an instance of StoreValuesDouble and use the computeDoubleValues and
               * displayDoubleTable methods.
              StoreValuesDouble storeValues = new StoreValuesDouble(doubleVector);
              storeValues.computeDoubleValues();
              storeValues.displayDoubleTable();
          * create the class method initValues() to add values to the Vector doubleVector
         public static void initValues()
              doubleVector = new Vector<Double>();
              doubleVector.addElement(null);
              doubleVector.addElement(new Double(10.9));
              doubleVector.addElement(new Double(15.95));
              doubleVector.addElement(new Double(17));
              doubleVector.addElement(null);
              doubleVector.addElement(new Double(1));
              doubleVector.addElement(new Double(4));
              doubleVector.addElement(new Double(10.499));
              doubleVector.addElement(null);
              doubleVector.addElement(new Double(10.4999));
              doubleVector.addElement(new Double(17));
              doubleVector.addElement(new Double(-15));
              doubleVector.addElement(null);
              doubleVector.addElement(new Double(14));
              doubleVector.addElement(new Double(20));
              doubleVector.addElement(new Double(-3));
              doubleVector.addElement(null);
              doubleVector.addElement(new Double(9));
              doubleVector.addElement(new Double(1.5));
              doubleVector.addElement(null);
              doubleVector.addElement(new Double(10.22));
              doubleVector.addElement(new Double(15.23));
              doubleVector.addElement(new Double(17.91));
              doubleVector.addElement(null);
          * class method to print values contained in the vector doubleVector to the console.
          * @param doubleVector the Vector to be displayed
         public static void displayVectorContent(Vector doubleVector)
              Double currentDouble;
              System.out.println("Double values within the Vector:");
              for (int i=0; i<doubleVector.size();i++)
                   try
                        currentDouble = (Double) doubleVector.elementAt(i);
                        if (currentDouble != null)
                             System.out.print(currentDouble.toString() + " ");
                   catch(ClassCastException cce)
                        System.out.print(cce.getMessage() + " ");
                        cce.printStackTrace();
              System.out.println("");
         It compiles fine but when I try and run it I get a
    Exception in thread "main" java.lang.NullPointerException
         at statistics.StoreValuesDouble.MinDouble(StoreValuesDouble.java:139)
         at statistics.TestStatDouble.main(TestStatDouble.java:37)
    TestStatDouble 37 is
    System.out.println("The lowest value is " + is.MinDouble());139 is
    if (currentValue <= MinDouble) {I guess the problem's in my if loop but I'm not sure why. Any help would be appreciated.
    Message was edited by:
    Ali_D

    Couple of points about your code:
    1. Don't declare your instance variables as solid types, declare them using their interfaces (where applicable), so in your case don't specifiy that you are using Vector or Hashtable, use List and Map. This will allow you to easily change your code to use a different collection, if and when appropriate. Also the unnecessary overhead of Vectors synchronisation means that you should use ArrayList instead of vector (that means that you will have to use get(int) instead of elementAt() but that's a very small price to pay.
    2. Declare local variables as close to their point of usage as possible. (Unless you need to do this for your course work, in which case you don't have a choice).
    3. Use the appropriate data type. For your count of null values you should be using an int or a long (you can't have a fractional count value!) Also, this should have been obvious to you, when you had to cast the value to an int for use with your lists. (Using double as an index is a very bad idea... And before you go posting the question, do a search on why floating point precision may not give you the results you expect)
    4. Code defencively... e.g. in your meanDouble() method, you set nonNull to 0, and then you do a division using that value. What do you think is going to happen if your loop doesn't execute once? Division by zero... You should handle these cases, rather than letting them fail ignominiously.
    5. If you are doing code like this...    if (currentDouble != null) {
            // / nothing to do
        } else {
            nbNull++;
        } Why have the empty block? You should just do the inverse.
        if (currentDouble == null) {
            nbNull++;
        } Far simpler, and expresses exactly what you are trying to do, not what you are not trying to do.
    6. Enumeration --- What version of java is that course being run in? I can see that you are using autoboxing, so it has to be 1.5 so, WHY is your lecturer encouraging the use of Vectors, Hashtables, and Enumerations!?!?!
    Anyway, that should be enough to be going on with.

  • How can i select the duplicate values

    Hi experts ,
    how can i find the duplicate values from the table. i want to display the all duplicate the rows.
    1. Table Structure :-
    CREATE TABLE CIF_MIGRATE
      LINE_NO        NUMBER(10),
      ACCT_NO        VARCHAR2(20 BYTE),
      BRANCH_ID      VARCHAR2(1 BYTE),
      CUSTOMER_NAME  VARCHAR2(100 BYTE),
      FATHER_NAME    VARCHAR2(100 BYTE),
      GF_NAME        VARCHAR2(100 BYTE),
      TOTAL          VARCHAR2(100 BYTE),
      STATUS         VARCHAR2(100 BYTE),
      CUSTOMER_TYPE  VARCHAR2(10 BYTE),
      GENDER         VARCHAR2(10 BYTE)
    ) 2. Sample Data:-
    SET DEFINE OFF;
    Insert into CIF_MIGRATE
       (LINE_NO, BRANCH_ID, CUSTOMER_NAME, CUSTOMER_TYPE)
    Values
       (72, '1', 'Addis Belay Construction Material Rental', 'C');
    Insert into CIF_MIGRATE
       (LINE_NO, BRANCH_ID, CUSTOMER_NAME, CUSTOMER_TYPE)
    Values
       (73, '1', 'Addis Belay Construction Material Rental', 'C');
    SET DEFINE OFF;
    Insert into CIF_MIGRATE
       (LINE_NO, BRANCH_ID, CUSTOMER_NAME, FATHER_NAME, CUSTOMER_TYPE, GENDER)
    Values
       (2869, '1', 'Abraham', 'Fiseha',
        'I', 'Male');
    Insert into CIF_MIGRATE
       (LINE_NO, BRANCH_ID, CUSTOMER_NAME, FATHER_NAME, CUSTOMER_TYPE, GENDER)
    Values
       (2870, '9', 'Abraham', 'Fiseha',
        'I', 'Male');
    Insert into CIF_MIGRATE
       (LINE_NO, BRANCH_ID, CUSTOMER_NAME, FATHER_NAME, GF_NAME, CUSTOMER_TYPE, GENDER)
    Values
       (2872, '9', 'Abraham', 'Baraki',
        'Medehniye', 'I', 'Female');
    Insert into CIF_MIGRATE
       (LINE_NO, BRANCH_ID, CUSTOMER_NAME, FATHER_NAME, GF_NAME, CUSTOMER_TYPE, GENDER)
    Values
       (2873, '1', 'Abraham', 'Geber kirstos',
        'gebre medihin', 'I', 'Female');
    Insert into CIF_MIGRATE
       (LINE_NO, BRANCH_ID, CUSTOMER_NAME, FATHER_NAME, GF_NAME, CUSTOMER_TYPE)
    Values
       (2874, '1', 'Abraham', 'Gebre egziabher',
        'Negussie', 'I');
    COMMIT;4. My requirement is i need display all the duplication customer
    CUSTOMER_NAME                                 FATHER_NAME,GF_NAME
    Addis Belay Construction Material Rental   
    Addis Belay Construction Material Rental
    Abraham                                              Fiseha
    Abraham                                              Fiseha5. I tried below query but i cant reach what i want exactly
    SELECT CUSTOMER_NAME,FATHER_NAME,GF_NAME
                               FROM CIF_MIGRATE
                          GROUP BY CUSTOMER_NAME,FATHER_NAME,GF_NAME
                             HAVING COUNT (*) > 1kindly suggest me the solution
    Thanks
    Arun

    Hi,
    You're on the right track using COUNT (*), but, for this job, you want the analytic COUNT, not the aggregate COUNT.
    "GROUP BY x, y, z" means that the result set will only contain 1 row for each distinct combination of x, y and z. Most aggregate functions (including COUNT) have analytic counterparts that get the same results without reducing the number of rows.
    Here's one way you can use the analytic COUNT function:
    WITH     got_cnt          AS
         SELECT    customer_name
         ,       father_name
         ,       gf_name
         ,       COUNT (*) OVER ( PARTITION BY  customer_name
                               ,                 father_name
                         ,           gf_name
                         )     AS cnt
         FROM       cif_migrate
    SELECT    customer_name
    ,       father_name
    ,       gf_name
    FROM       got_cnt
    WHERE       cnt     > 1
    ;PARTITION BY in analytic functions corresponds to GROUP BY in aggregate functions.

  • How to find the RGB Values of a Color for Hyperion

    When customizing your Hyperion forms, we come across situations where we need the exact RGB value of a given color. This article explains a simple technique to find the RGB values using MS Paint and the Calculator applications that come as standard applications with your operating system.
    Here are the steps to find the exact RGB value of a given color.
    1) View your Hyperion form using IE, scroll down until you see the color you want to find the RGB value and press the "Print Screen" button (in your keyboard).
    2) Open MS Paint and click Edit -> Paste or simply Ctrl+V. What you saw in the browser will be copied as a new untitled image.
    3) Select the Color Picker tool and click on an area that has the color you want to match.
    4) Now go to Edit Colors... option and click on the "Define Custom Colors >>" button. The color you picked will be selected on this palette. At the bottom right hand corner you will see the Red, Green and Blue values you need. Note down the R,G,B values (given in decimal).
    5) Now we need to find out the hexa-decimal values that correspond to those decimal values. This is where we use the simple Calculator. Open the Calculator application from Program -> Accessories. Switch to the scientific mode by clicking View ->Scientific.
    6) By default it will be in the decimal number mode. Enter the R value (238 in this example) and click on the Hex radio button. The corresponding hexa-decimal value (EE in this case) will be shown in the dial.
    The selected color in this case has the same value for R, G and B. (In fact, all shades of gray has the same values for R, G and B.) Therefore, the RGB value of the background color that we need is #eeeeee. Repeat step 6 to find out the hex value for the Green and Blue elements, if they are different.
    Tip:
    If you find it difficult to pick a color, zoom the image by pressing Ctrl+PageDown or using View -> Zoom -> Custom... option.

    These tips are to find the RGB color of HFM default row where row is text and text lines in data columns are also visible to business users as Yellow as an input cell. By applying the same RGB color you can apply the same color to your data cells or rows. This post shows how to identify color from any web view-able object.
    Regards,
    Manaf

  • How to get the max value of a set of percentage values?

    Hi,
    I've tried to get the max and min value of a set of calculated percentage values. Such as
    Jan Feb March Apr May Jun    Min  Average   Max
    0,5 0,8  1,1      0,4 1      0,6     0,4   0,7         1,1
    The average value works fine. But with "min" and "max" I have a problem.
    I've tried to get the value with the following ways:
    - Create a new calc. keyfigure and make a sum of all values: (Jan + Feb + ...) and set the calculation in key figure properties to Min/Max.
    - Create a new calc. keyfigure and make a sum of all values and set the aggregation to Min/Max
    - Create a selected keyfigure with a filter to the necessary periods and set a calculation to Min (Aggregation is not possible here)
    - Create a new cal. keyfigure with all periods and the function Min. e.g. min(Jan, (min Feb, (min (....)
    None of this solutions provides the right min and max value. When I use an amount value (e.g. Euro) instead of these percentage values the keyfigure with the min and max function works. The others all provide wrong values.
    Is there a solution to get the right min and max value???
    It would be a great help when you have any hints.
    Thanks
    Claudia

    Hi Aduri,
    thanks for your answer but your solution doesn't work.
    The problem is that the periods are defined in a structure with offsets such as
    - period-11
    - period-10
    - period
    in this structure elements there is also the keyfigure "netvalue" defined.
    In the rows of the report there is another characteristic such as company code.
    Is there a solution to find the max and min values of the period values for each company code? Or must I change the data model e.g. copy the keyfigure and make a new keyfigure with another aggregation level?
    Thanks for any hints!
    Claudia

  • How to find the nearlest value in 1-D array ?

    Hi.. everybody..
    I need to seperate the raw data(1-D) into 2 group of array by the center value and then make the average value in each array. But I also still have the problem about if the center value is not the same of some value in the 1-D array. I cannot use the split function.
    "How to find the nearlest value to the center point that I calculated, in the 1-D array ?"
    Thanks a lot for anybody help

    In a general sense, since I'm not sure what your data values are or how far away your calculated center is from the true value, I would do it one of two ways:
    1) Use a threshold value and scan the array until the threshold is reached (assumes constantly increasing values in the array).
    2) Use either a) round to nearest integer b) round to + Infinity (round up) or c) round to - infinity (round down). If you don't have decimal values, you'll have to devide the values by a power of 10.
    2006 Ultimate LabVIEW G-eek.

Maybe you are looking for