How does group message work for the iphone5?

I want to send out the same message to everyone instead of creating a new thread for each person and I don't want them to see the names of the other people that I am sending it to. Does turning of group message prevent the group chat or will they still everyone's names? Thanks.

This happening because you guys are sharing the same apple id, you can continue to share it or create a separate one for each user.  You'll have to make sure that for icloud - each users have their own apple id.
Then go into settings - message - send&receive - make sure the phone number is the default.

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    Me, my husband and son all use the same iTunes account.  We all have iPhones.  Just yesterday, when I sent my husband a message, my son got it too even though he was not copied by me.  My son responded and it came to me labeled as my husband's text.
    Does this have something to do with Group Messaging?  How can we separate their accounts again so that messages from my husband are under his own name and the same with my son?

    This happening because you guys are sharing the same apple id, you can continue to share it or create a separate one for each user.  You'll have to make sure that for icloud - each users have their own apple id.
    Then go into settings - message - send&receive - make sure the phone number is the default.

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    How do I send out a group message and have the responses individual?

    > Actually, I'm trying to set up Group Policies as part of a Workstation
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    K, the Workstation Group Policy is applied first. If you have a user
    that also has a group policy it will be applied on top of the
    workstation GP. THe user settings will override the workstation policy
    settings.
    Each of the settings have 3 settings, enable, disable, and no change.
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    result is disabled. If the WS has a setting disabled and the user is
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    > I'm not sure how you can set up a group policy that expires on
    > logout....
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    Philly_Phan wrote:
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    Philly_Phan wrote:
    Drew Reece wrote:
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    I was referring to the GPS on the iPhone.
    I know how GPS works thanks, I can see 4 satellites in this hemisphere, the others are out of view 
    I was also assuming this was a wifi iPad (no cellular, no GPS) - hence the reason for the original poster surprise. However I may have simply read 'wife's iPad' as 'wifi iPad'?

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    Hi All,
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    exch2 1 Up 1 2
    PS C:\Windows\system32> (Get-Cluster).WitnessDynamicWeight
    1
    PS C:\Windows\system32> Get-ClusterResource
    Name State OwnerGroup ResourceType
    Cluster IP Address Online Cluster Group IP Address
    Cluster Name Online Cluster Group Network Name
    File Share Witness (\\fs1... Online Cluster Group File Share Witness
    (Validation test)
    Validate Quorum Configuration
    Description: Validate
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    Validating cluster quorum settings.
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    Voter Name
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    Assigned Vote
    Current Vote
    File Share Witness (\\fs1.contoso.com\dag1.contoso.com) (\\fs1.contoso.com\dag1.contoso.com)
    Online
    1
    1
    exch1
    Down
    1
    1
    exch2
    Up
    1
    1
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    the validation test is saying).
    Regards,
    Satyajit
    Please “Vote As Helpful”
    if you find my contribution useful or “Mark As Answer” if it does answer your question. That will encourage me - and others - to take time out to help you.

    Hi Simon,
    Thanks for your response.
    I have done some study, testing and what I figured out is this.
    Split brain syndrome is prevented by always requiring a majority of the DAG members (and in the case of DAGs with an even number of member, the DAG witness server) to be available and interacting for the DAG to be operational.
    All DAGs with an even number of members must use a witness server.
    Hence a 3 node cluster behaves differently than a 2 node. Exchange 2013 DAG kind of forces you to have a witness server always.
    You can specify only a name for the DAG and leave the Witness server and
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    server and configure the DAG to use that server as its witness server.
    You can
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    If you open Failover Cluster Manager in Administrative Tools, you’ll find the Database Availability Group (DAG), cluster networks and so on. Don’t try to manage the DAG
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    Unless you’re doing a DC switchover and/or being assisted by Microsoft Support services (premier)
    Now back to the point:
    When we are left with 2 nodes and 1 witness server for Exchange HA. The Dynamic Quorum functionality kind of stops dealing with it. As 2nodes/2+1=2votes this means we need to have atleast 2 votes to have quorum.
    So if we assume Dynamic Quorum triggers and removes 2 votes, 1 from Witness and 1 from nodeB.
    Then the new formula we have is 1node/2+1=1vote which would mean this would allow us to loose both the witness and the nodeB. And nodeA will be the last man standing as in this
    article.
    However having this scenario in a two node cluster brings in the split-brain problem. As if there is a full disconnect of nodeA site and nodeB+Witness can talk, they form quorum , nodeB mounts the database. Which is undesirable.
    Hence Dynamic Quorum keeps the votes to 3 in a 2nodes+1witness scenario contrary to what is expected and in turn keeps everything running fine till we have 2votes available, just like 2010,Windows2008 days.
    Regards,
    Satyajit
    Please “Vote As Helpful”
    if you find my contribution useful or “Mark As Answer” if it does answer your question. That will encourage me - and others - to take time out to help you.

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    Message Edited by wepeeler on 08-11-2008 07:10 PM
    Solved!
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  • How to group using SQL for the required output.

    hi all,
    i'm currently using oracle 10.2.0.4.0
    create table script :
    CREATE TABLE FORTEST
    ( gpno VARCHAR2(10 BYTE),
      classnumber  VARCHAR2(10 byte),
      age_min NUMBER,
      age_max NUMBER,
      amount NUMBER)insert statement:
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 01,0,29,1)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 01,30,35,2)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 01,36,40,3)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 02,0,29,1)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 02,30,35,2)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 02,36,40,5)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 03,0,29,1)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 03,30,35,2)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G123' , 03,36,40,3)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G124' , 01,0,29,1)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G124' , 01,30,35,2)
    insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
    ('G124' , 01,36,40,3) output required:
    gpno    classnumber    age_min    age_max    amount
    G123    1,3                0        29        1
    G123    1,3                30       35        2
    G123    1,3                36       40        3
    G123    2                  0        29        1
    G123    2                  30       35        2
    G123    2                  36       40        5
    G124    1                  0        29        1
    G124    1                  30       35        2
    G124    1                  36       40        3since for gpno g123, classnumber 1 and 3, the rates are same across all age_min and age_max they need to be grouped together.
    even though gpno 123 classnumber 2 has same rates as classesnumber 1 and 3 for age bands 0 to 29 and 30 to 35,
    the rates are different for age bands 36 to 40. so it should not be grouped together. how can i do this in SQL
    any help is appreciated.
    thanks in advance.

    Hi,
    Tricky problem!
    Unfortunately, LISTAGG was only introduced in Oracle 11.2. About half of the complexity here is the string aggregation, that is, forming the list of classnumbers, such as '1,3', using only functions available in Oracle 10.2.
    Here's one solution:
    WITH     got_gpno_classnumber_cnt   AS
         SELECT     gpno, classnumber, age_min, age_max, amount
         ,     COUNT (*) OVER ( PARTITION BY  gpno
                                      ,            classnumber
                          )   AS gpno_classnumber_cnt
         FROM    fortest
    --     WHERE     ...     -- If you need any filtering, this is where it goes
    ,     pairs          AS
         SELECT    a.gpno
         ,       a.classnumber
         ,       MIN (b.classnumber)
                    OVER ( PARTITION BY  a.gpno
                              ,                    a.classnumber
                      )     AS super_classnumber
         FROM       got_gpno_classnumber_cnt  a
         JOIN       got_gpno_classnumber_cnt  b  ON   a.gpno     = b.gpno
                                      AND  a.age_min     = b.age_min
                                    AND  a.age_max     = b.age_max
                                    AND  a.amount     = b.amount
                                    AND  a.gpno_classnumber_cnt
                                            = b.gpno_classnumber_cnt
         GROUP BY  a.gpno
         ,            a.classnumber
         ,       b.classnumber
         HAVING       COUNT (*)     = MIN (a.gpno_classnumber_cnt)
    ,     got_rnk          AS
         SELECT DISTINCT     
                 gpno, classnumber, super_classnumber
         ,     DENSE_RANK () OVER ( PARTITION BY  gpno
                                   ,                    super_classnumber
                                   ORDER BY          classnumber
                           )         AS rnk
         FROM    pairs
    ,     got_classnumbers     AS
         SELECT     gpno, classnumber, super_classnumber
         ,      SUBSTR ( SYS_CONNECT_BY_PATH (classnumber, ',')
                       , 2
                     )     AS classnumbers     
         FROM     got_rnk
         WHERE     CONNECT_BY_ISLEAF = 1
         START WITH     rnk             = 1
         CONNECT BY     rnk             = PRIOR rnk + 1
              AND     gpno             = PRIOR gpno
              AND     super_classnumber  = PRIOR super_classnumber
    SELECT DISTINCT
           g.gpno
    ,       c.classnumbers
    ,       g.age_min
    ,       g.age_max
    ,       g.amount
    FROM       got_gpno_classnumber_cnt  g
    JOIN       got_classnumbers         c  ON   c.gpno        = g.gpno
                                 AND  c.classnumber  = g.classnumber
    ORDER BY  g.gpno
    ,            c.classnumbers
    ;Output (just as you requested):
    GPNO       CLASSNUMBERS       AGE_MIN    AGE_MAX     AMOUNT
    G123       1,3                      0         29          1
    G123       1,3                     30         35          2
    G123       1,3                     36         40          3
    G123       2                        0         29          1
    G123       2                       30         35          2
    G123       2                       36         40          5
    G124       1                        0         29          1
    G124       1                       30         35          2
    G124       1                       36         40          3

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