How I can change timescale to show financial year
Hi
I am currently facing a problem for timescale. Actually my projects working according to financial years and PM's want to see the bar chart accordingly.Even they want to see the FY / quater view in time scale. Is there any way to get that view in primavera 6.2.1.
Any help would be highly appreciated.
Thanks
Nirav Sheth
Hello again Nirav,
Do you mean the on screen Gantt chart or in a print out?
For printed documents you can specify a start and finish in the Page Setup options - on screen, you can only set a start date (as far as i can tell).
If you right click on the Gantt chart and select Timescale, you get a series of options in there. But as you'll see, or probably have seen, there's no way of setting an end date. If it's just a case of showing it on screen, just resize the Gantt chart to fit the timescale you want - can't see a more intelligent way of doing it.
Hope that helps
David
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1,543 A05 24 A01 24 BAC 24 BAE 24 A02 20 BAM 20in one line but I would like to add the id and name that are stored in the table SPRIDEN
SELECT sortest_pidm,
max(decode(rn,1,sortest_tesc_code)) tesc_code1,
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max(decode(rn,2,sortest_tesc_code)) tesc_code2,
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max(decode(rn,3,sortest_tesc_code)) tesc_code3,
max(decode(rn,3,score)) score3,
max(decode(rn,4,sortest_tesc_code)) tesc_code4,
max(decode(rn,4,score)) score4,
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sortest_tesc_code,
score,
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FROM (select sortest_pidm,
sortest_tesc_code,
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Hi,
That depends on whether spriden_pidm is unique, and on what you want for results.
Whenever you have a problem, post a little sample data (CREATE TABLE and INSERT statements, relevamnt columns only) for all tables, and the results you want from that data.
If you can illustrate your problem using commonly available tables (such as those in the scott or hr schemas) then you don't have to post any sample data; just post the results you want.
Either way, explain how you get those results from that data.
Always say which version of Oracle you're using.
It looks like you're doing something similiar to the following.
Using the emp and dept tables in the scott schema, produce one row of output per department showing the highest salary in each job, for a given set of jobs:
DEPTNO DNAME LOC JOB_1 SAL_1 JOB_2 SAL_2 JOB_3 SAL_3
20 RESEARCH DALLAS ANALYST 3000 MANAGER 2975 CLERK 1100
10 ACCOUNTING NEW YORK MANAGER 2450 CLERK 1300
30 SALES CHICAGO MANAGER 2850 CLERK 950On each row, the jobs are listed in order by the highest salary.
This seems to be analagous to what you're doing. The roles played by sortest_pidm, sortest_tesc_code and sortest_test_score in your sortest table are played by deptno, job and sal in the emp table. The roles played by spriden_pidm, id and name in your spriden table are played by deptno, dname and loc in the dept table.
It sounds like you already have something like the query below, that produces the correct output, except that it does not include the dname and loc columns from the dept table.
SELECT deptno
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, MAX (DECODE (rn, 1, max_sal)) AS sal_1
, MAX (DECODE (rn, 2, job)) AS job_2
, MAX (DECODE (rn, 2, max_sal)) AS sal_2
, MAX (DECODE (rn, 3, job)) AS job_3
, MAX (DECODE (rn, 3, max_sal)) AS sal_3
FROM (
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SELECT e.deptno
, e.job
, MAX (e.sal) AS max_sal
FROM scott.emp e
, scott.dept d
WHERE e.deptno = d.deptno
AND e.job IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY e.deptno
, e.job
GROUP BY deptno
;Since dept.deptno is unique, there will only be one dname and one loc for each deptno, so we can change the query by replacing "deptno" with "deptno, dname, loc" throughout the query (except in the join condition, of course):
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, MAX (DECODE (rn, 1, job)) AS job_1
, MAX (DECODE (rn, 1, max_sal)) AS sal_1
, MAX (DECODE (rn, 2, job)) AS job_2
, MAX (DECODE (rn, 2, max_sal)) AS sal_2
, MAX (DECODE (rn, 3, job)) AS job_3
, MAX (DECODE (rn, 3, max_sal)) AS sal_3
FROM (
SELECT deptno, dname, loc -- Changed
, job
, max_sal
, ROW_NUMBER () OVER ( PARTITION BY deptno -- , dname, loc -- Changed
ORDER BY max_sal DESC
) AS rn
FROM (
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, e.job
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FROM scott.emp e
, scott.dept d
WHERE e.deptno = d.deptno
AND e.job IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY e.deptno, d.dname, d.loc -- Changed
, e.job
GROUP BY deptno, dname, loc -- Changed
;Actually, you can keep using just deptno in the analytic PARTITION BY clause. It might be a little more efficient to just use deptno, like I did above, but it won't change the results if you use all 3, if there is only 1 danme and 1 loc per deptno.
By the way, you don't need so many sub-queries. You're using the inner sub-query to compute the MAX, and the outer sub-query to compute rn. Analytic functions are computed after aggregate fucntions, so you can do both in the same sub-query like this:
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, MAX (DECODE (rn, 3, job)) AS job_3
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FROM (
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, scott.dept d
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, e.job
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;This will work in Oracle 8.1 and up. In Oracle 11, however, it's better to use the SELECT ... PIVOT feature. -
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